Pass whole incoming data to curl - Laravel - php

Question

I wanted to pass the whole incoming data (that is, $request) to the curl not wanted to post to a particular field in the endpoint as subjectId=>1 as am running this curl request for different endPoint everytime. The below curl request will work if CURLOPT_URL => $url . $subjectId, was given. As my input changes for every end point, i've to pass everything that comes in the input to the curl , i can't pass it as an arary $subjectId. Is there any way to do this?
Currently, dd($Response); returns null
Am giving a postman input like this:
{
"subjectId":"1"
}
Curl
public function getContentqApiPost(Request $request)
{
$token = "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.ey";
$headers = [
"Accept: application/json",
"Authorization: Bearer " . $token
];
$url="http://127.0.0.1:9000/api/courses/course-per-subject";
$subjectId = "?subjectId=$request->subjectId";
$ch = curl_init();
$curlConfig = array(
// CURLOPT_URL => $url . $subjectId,
CURLOPT_URL => $url . $request,
CURLOPT_CUSTOMREQUEST => "GET",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HTTPHEADER => $headers,
);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt_array($ch, $curlConfig);
$result = trim(curl_exec($ch));
$Response = json_decode($result, true);
if (curl_errno($ch)) {
$error_msg = curl_error($ch);
echo $error_msg;
}
curl_close($ch);
return $Response;
}

Answer 1

If you would like to pass all params of $request to curl:
$queryParams = '';
$delimeter = '?';
foreach($request->all() as $k => $v){
$queryParams .= "$delimeter$k=$v";
$delimeter = '&';
}
Also You can only pass the params you want:
foreach($request->only(['subjectId']) as $k => $v){
// code here
}
Finally you have:
CURLOPT_URL => $url . $queryParams,

Answer 2

Answer
Assuming you want to pass the entire GET query string as-is:
$query_string = str_replace($request->url(), "", $request->fullUrl());
$url = "http://localhost:9000/api/courses/course-per-subject" . $query_string;
This works because $request->url() returns the URL without the query string parameters, while $request->fullUrl() returns the URL with all the query string parameters, so we can use str_replace with an empty replacement to remove the non-query part. Note that $query_string will already start with a ? so there is no need to add that yourself.
Other suggestions
Unless your Laravel API is a 1:1 copy of the backend API, I strongly suggest writing a class that interfaces with the backend API, then provide it to your Laravel controllers using dependency injection. E.g.
class CourseCatalogApi {
public function getSubjectsInCourse(String $course){
... // your curl code here
}
}
Finally, since you are already using Laravel, there is no need to write such low level code using curl to make HTTP requests. Consider using guzzlehttp, which is already a dependency of Laravel.