How can I merge this code together to get working pagination? - php

Question

I have two sets of code for a blog type website. One shows the list of articles and the other is for a pagination. I can't figure out how to get the pagination and article list code working together. The article list code works to generate the information needed from a SQL Database for my website. However, I have no clue what needs to be changed so that it will respond to the pagination code. The pagination will generate, though the current page does not show as a button.
Article List:
<?php
include ('database-connect.php');
include ('database-query-topic2.php');
// this runs the query
// needs to have the mysql connection info passed as $con
// the second argument is the number of articles to return
$articles = list_articles($con, 5); //
// if articles are found
if ($articles) {
while ($row = mysqli_fetch_row($articles)){
?>
<!-- loop here for articles -->
<div class="article-list-item-info">
<div class="a-l-i-i-left">
<h2 class="article-title">
<?php print( $row[1]); ?>
</h2>
<div class="article-list-preview">
<?php print($row[3]); ?>
</div>
<div class="article-list-author-date">
<address class="article-list-author">
<?php print($row[4]); ?>
</address>
<time class="article-list-date"> <?php print($row[8]); ?> </time>
</div>
</div>
<img class="article-image" src=<?php print($row[6]); ?> >
</div>
<!-- end loop for articles -->
<?php
}
}
// Closing the connection
mysqli_close($con);
?>
<div class="a-l-l-m-b-container">
<?php include ("article-pagination.php"); ?>
<!--<button class="a-l-load-more-button">Load More</button>-->
</div>
database-connect.php:
<?php
$servername = "ip address";
$username = "user";
$password = "password";
$dbname = "database name";
// Create Connection
$con = mysqli_connect('ip address', 'user', 'password', 'database name');
?>
database-query-topic2.php:
<?php
//gets list of articles
// $con is the sql connection
// $limit is the number of articles to return
function list_articles($con, $limit){
// Executing the multi query
$query =
"SELECT * FROM table
WHERE article_category='category'
ORDER BY article_id DESC LIMIT $limit";
$result = mysqli_query($con, $query);
return $result;
}
article-pagination.php:
<?php
include("database-connect.php");
$query=mysqli_query($con,"select count(article_id) from `table`");
$row = mysqli_fetch_row($query);
$rows = $row[0];
$page_rows = 5; //
$last = ceil($rows/$page_rows);
if($last < 1){
$last = 1;
}
$pagenum = 1;
if(isset($_GET['pn'])){
$pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']);
}
if ($pagenum < 1) {
$pagenum = 1;
}
else if ($pagenum > $last) {
$pagenum = $last;
}
//
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
$nquery=mysqli_query($con,"SELECT * FROM table
WHERE article_category='category'
ORDER BY article_id DESC LIMIT $limit");
//
$paginationCtrls = '';
$paginationCtrls .= '<nav aria-label="Page navigation example">';
$paginationCtrls .= '<ul class="pagination">';
if($last != 1){
if ($pagenum > 1) {
$previous = $pagenum - 1;
$paginationCtrls .= '<li class="page-item">Previous</li> ';
for($i = $pagenum-4; $i < $pagenum; $i++){
if($i > 0){
$paginationCtrls .= '<li class="page-item">'.$i.'</li> ';
}
}
}
$paginationCtrls .= ''.$pagenum.' ';
for($i = $pagenum+1; $i <= $last; $i++){
$paginationCtrls .= ' <li class="page-item">'.$i.'</li> ';
if($i >= $pagenum+4){
break;
}
}
if ($pagenum != $last) {
$next = $pagenum + 1;
$paginationCtrls .= ' <li class="page-item">Next</li> ';
}
}
echo $paginationCtrls;
'</ul>';
'</nav>';
?>

Answer 1

Looks like here is error
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
$nquery=mysqli_query($con,"SELECT * FROM table
WHERE article_category='category'
ORDER BY article_id DESC LIMIT $limit");
You are using LIMIT two times
First in $limit = 'LIMIT ....'
And second
DESC LIMIT $limit"