Pagination. Why only one page is showing? - php

Question

I have been trying to get pagination to work and I have to a certain extent but it only shows one page of results.
I have 18 listings in my database and have it set to show 6 per page.
Can anyone see what the problem is?
<?php include('includes/configsql.php');
//include header template
include('layout/header.php');
//include navbar template
include('layout/navbar.php');
?>
<?php
$con = mysqli_connect($db_hostname,$db_username,$db_password,$db_database);
$sql = "SELECT COUNT(id) FROM basic WHERE status='active'";
$query = mysqli_query($con, $sql);
$row = mysqli_fetch_row($query);
$rows = $row[0];
$rows = mysqli_num_rows($query);
$page_rows = 6;
$last = ceil($rows/$page_rows);
if($last < 1){
$last = 1;
}
$pagenum = 1;
if(isset($_GET['pn'])){
$pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']);
}
if ($pagenum < 1) {
$pagenum = 1;
} else if ($pagenum > $last) {
$pagenum = $last;
}
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
$sql = "SELECT id, name, address, telephone, email, category FROM basic WHERE status='active' ORDER BY name ASC $limit";
$query = mysqli_query($con, $sql);
$textline1 = "Basic Listing (<b>$rows</b>)";
$textline2 = "Page <b>$pagenum</b> of <b>$last</b>";
$paginationCtrls = '';
if($last != 1){
if ($pagenum > 1) {
$previous = $pagenum - 1;
$paginationCtrls .= 'Previous ';
for($i = $pagenum-4; $i < $pagenum; $i++){
if($i > 0){
$paginationCtrls .= ''.$i.' ';
}
}
}
$paginationCtrls .= ''.$pagenum.' ';
for($i = $pagenum+1; $i <= $last; $i++){
$paginationCtrls .= ''.$i.' ';
if($i >= $pagenum+4){
break;
}
}
if ($pagenum != $last) {
$next = $pagenum + 1;
$paginationCtrls .= ' Next ';
}
}
$list = '';
while($row = mysqli_fetch_array($query)){
$id = $row["id"];
$name = $row["name"];
$category = $row["category"];
$list .= '<p>'.$name.' | '.$category.' - Click the link to view this business</p>';
}
mysqli_close($con);
?>
<div id="wrapper">
<div id="bizlist">
<div id="pagination">
<h2><?php echo $textline1; ?></h2>
<p><?php echo $textline2; ?></p>
<p><?php echo $list; ?></p>
<div id="pagination_controls"><?php echo $paginationCtrls; ?></div>
</div>
</div>
<?php
//include footer template
include('layout/footer.php');
?>

Answer 1

I think you have to remove the line:
$rows = mysqli_num_rows($query);
It is in beginning of the script.
Another way is if you modify the first line like this:
$sql = "SELECT * FROM basic WHERE status='active'";
And remove the next 3 rows
$query = mysqli_query($con, $sql);
$row = mysqli_fetch_row($query);
$rows = $row[0];
You have to choice one of above, but not both :)