Laravel: 8.51
Nova: 3.24
PHP Version: 7.4.20
I have problem with trying to solve this situation:
I have a action that uses a KeyValue to handle array of pairs: "product_id" and "amount"
field looks like:
KeyValue::make(__('Order details'), 'details')
->rules('json'),
also in model i added cast:
protected $casts = [
'details' => 'array',
];
I convert it to json and store in database like that
foreach ($fields->details as $key => $value)
{
$order_details[$key] = $value;
}
//(...)
DB::table('orders')->InsertGetId([
'details' => json_encode($order_details),
]);
finnaly my json field in database looks like:
{"1":"6","2":"7","3":"8"}
To this point everything works great.
Now I want to change what I see as product_id (in above example 1, 2, 3) to be from other resource like belongsTo('products')
I was considering how to be able to use BelongsTo or Select in key part of KeyValue field.
I tried few ways to display it somehow in stack field like:
Stack::make('Details', [
Text::make('details', function () {
return $this->details($key); // how to properly read $key from json in fields?
}),
Text::make('amount',function () {
return $this->details($value); // how to properly read $value from json in fields?
}),
]),
or
BelongsTo::make(__('Product'), 'user', Products::class)
->withMeta([
'belongsToId' => $this->details($key), // again i dont know how to properly read $key here from json.
]),
I am using the Adobe Sign API and I need to map fields from a php array to the fields in a pdf document. I have managed to do it using the following json:
"mergeFieldInfo": [
{
"defaultValue": company['Trading Name'],
"fieldName": "Trading Name"
},
{
"defaultValue": company['Company Website'],
"fieldName": "Company Website"
}
]
The problem is I have 3 different pdf's all with 60+ fields. Is there anyway I could create this json structure by looping through the array? So far I have split the array in to two. One holds the default values and the other the field names not sure if thats the right way to be going
Solved using json_encode
foreach ($company as $key => $value){
$arr[] = ['defaultValue' => $value, 'fieldName' =>$key];
}
json = json_encode($arr);
Result:
{"defaultValue":"New Company","fieldName":"trade_name"},
{"defaultValue":"Website","fieldName":"website"}
I am setting up a Jquery autosuggest using ajax and I have a simple query to the database which returns 5 suggestions. The fields are company and id, so I get
$result['id']
$result['company']
for each row of the returned database suggestiions
This works fine and currently I loop over the results
foreach ($result as $item) {
$suggest[] = $item['company'];
}
echo json_encode($suggest);
I want though to add these so the company is a label and id is a value, something like
"value": "A Company", "data": "20"
This I can then encode and use in my autosuggest.
Thanks in advance!
You have to save an array to main array like this
foreach ($result as $item) {
$suggest[] = [
'value' => $item['company'],
'data' => $item['id'],
]
}
echo json_encode($suggest);
And it should return something like this
[
{
'value': 'Some value',
'data' : item id
}
]
i will recommend you create an array, next create 2 more arrays as values for the value and data keys.
like this.
$arr=array();
$arr['value']=array();
$arr['data']=array();
while($suggest=mysql_fetch_assoc($result)){
array_push($arr['value'],$suggest['id']);
array_push($arr['data'],$suggest['company']);
}
echo "<pre>";
print_r($arr);
note that with this solution, if you delete an entry in either value or data
be ready to delete the corresponding entry in the other array.
others may be able to improve this or even offer a better approach.
I want to add some string before the data derived from mySQL. And output them in JSON. I can fetch out the data from mySQL right for my needs. But I cannot add the prefix string to the right format.
The expected json format
{
"message": "",//i can do this
"value": [//but I can't do this the "value":[
{
"excName": "Mark",
"excSup": "chunyun",
"excId": 20001
}, {
"excName": "orion-01",
"excSup": "orion-01",
"excId": 20000
}
]
}
PHP
while ($rec_qXcur=mysqli_fetch_assoc($sql_qXcur)){
$data[] = array(
"excId"=>$rec_qXcur['exc_id'],
"excTitle"=>$rec_qXcur['exc_name'],
"excSup"=>$rec_qXcur['exc_sup']
);
}
//return json data
echo json_encode($data);
From PHP I got this :
{
"message":"",
//"value":[//this is missing
"0":{//not need
"excId":"234",
"excTitle":"Simon Cabaret - Regular Seat ",
"excSup":"simon"
},
"1":{//not need
"excId":"245",
"excTitle":"Simon Cabaret - VIP Seat (01Nov15 - 30Apr16)",
"excSup":"simon"
}
According to the expected json format. I missed "value":[. I tried adding it to the $data but it's not working.
You are just adding them to data. You need to add them to the value array.
So json_encode() is probably creating an object literal {} because your array has both named elements and sequential elements. Once it only contains sequential elements, json_encode() should (I believe) return an array literal [];
$data = array(
'message' => 'Your message here',
'value' => array()
);
while ($rec_qXcur=mysqli_fetch_assoc($sql_qXcur)){
$data['value'][] = array(
"excId"=>$rec_qXcur['exc_id'],
"excTitle"=>$rec_qXcur['exc_name'],
"excSup"=>$rec_qXcur['exc_sup']
);
}
echo json_encode($data);
I am trying to dynamicaly generate data in json for jQuery gantt chart. I know PHP but am totally green with JavaScript. I have read dozen of solutions on how dynamicaly add data to json, and tried few dozens of combinations and nothing. Here is the json format:
var data = [{
name: "Sprint 0",
desc: "Analysis",
values: [{
from: "/Date(1320192000000)/",
to: "/Date(1322401600000)/",
label: "Requirement Gathering",
customClass: "ganttRed"
}]
},{
name: " ",
desc: "Scoping",
values: [{
from: "/Date(1322611200000)/",
to: "/Date(1323302400000)/",
label: "Scoping",
customClass: "ganttRed"
}]
}, <!-- Somoe more data-->
}];
now I have all data in php db result. Here it goes:
$rows=$db->fetchAllRows($result);
$rowsNum=count($rows);
And this is how I wanted to create json out of it:
var data='';
<?php foreach ($rows as $row){ ?>
data['name']="<?php echo $row['name'];?>";
data['desc']="<?php echo $row['desc'];?>";
data['values'] = {"from" : "/Date(<?php echo $row['from'];?>)/", "to" : "/Date(<?php echo $row['to'];?>)/", "label" : "<?php echo $row['label'];?>", "customClass" : "ganttOrange"};
}
However this does not work. I have tried without loop and replacing php variables with plain text just to check, but it did not work either. Displays chart without added items. If I add new item by adding it to the list of values, it works. So there is no problem with the Gantt itself or paths. Based on all above I assume the problem is with adding plain data to json. Can anyone please help me to fix it?
First of all you're adding properties to string instead of building object. If you really want to do that this way:
var data = [], row;
<?php foreach ($rows as $row) : ?>
row = {};
row.name ="<?php echo $row['name'];?>";
row.desc ="<?php echo $row['desc'];?>";
row.values = {"from" : "/Date(<?php echo $row['from'];?>)/", "to" : "/Date(<?php echo $row['to'];?>)/", "label" : "<?php echo $row['label'];?>", "customClass" : "ganttOrange"};
data.push(row);
<?php endforeach; ?>
Anyway it is unsafe (and result is normal JS code, not proper JSON object - but as you're assigning it to variable then I suppose it does not have to be in strict JSON format)
Better approach would be to build data structure in PHP and use json_encode function to generate JSON data for JavaScript:
<?php
$data = array();
foreach ($rows as $row) {
$data[] = array(
'name' => $row['name'],
'desc' => $row['desc'],
'values' => array(array(
'from' => '/Date('.$row['from'].'>)/',
'to' => '/Date('.$row['to'].')/',
'label' => $row['label'],
'customClass' => 'ganttOrange',
))
);
}
?>
var data = <?php echo json_encode($data); ?>;
Quick Answer
As stated previously, this problem is easily resolved using the PHP json_encode function.
The trick to understanding how to do this easily is to understand the composite data structure that you are trying to work with.
Overview
What you are dealing with is a general programming concept called a "composite data structure". The trick to understanding this is to realize that the PHP and the JavaScript that you are attempting to manage are just two different representations of the exact same thing.
Once this concept sinks in, it will be easy to relate to what the users Musa and dev-null-dweller have already explained.
The straightforward way to solve this issue is to simply build a composite data structure in PHP and then translate it into JSON (aka JavaScript) using the built-in native methods of PHP's json_encode and json_decode.
Instead of doing all the statements, you should treat each $row as a composite data structure and use the PHP json functions.
The following example should give you a head start, simply compare it to the data you are trying to work with and change accordingly.
Example 001
// This is a PHP composite data structure [ a nested array ]
// represented in PHP. When you run this code you will get the
// output of Result 001
$user_profile = Array(
main => Array(
first_name => "_blank_",
last_name => "_blank_",
sex => "_blank_",
age => "_blank_",
),
guardian => Array(
first_name => "",
last_name => "",
),
children => Array(
0 => Array(
first_name => "Sally",
last_name => "Shaw",
),
1 => Array(
first_name => "Scott",
last_name => "Shaw",
),
),
);
// This is some sample PHP code you can use to modify
// the composite data structure (modify the "_blank_" values)
//
$user_profile["main"]["first_name"] = "Archibald";
$user_profile["main"]["last_name"] = "Shaw";
$user_profile["main"]["age"] = "33";
$user_profile["main"]["sex"] = "male";
// This is some sample PHP code you can use to modify
// the composite data structure (add a new child)
//
$user_profile["children"][2] = Array();
$user_profile["children"][2]["first_name"] = "Carrie";
$user_profile["children"][2]["last_name"] = "Shaw";
// This is the PHP code you can use to transform from PHP to JSON
$result = json_encode( $user_profile );
print_r( $result );
Result 001 (formatted for easy readability)
{
"main":{
"first_name":"Archibald",
"last_name":"Shaw",
"sex":"male",
"age":"33"
},
"guardian":{
"first_name":"",
"last_name":""
},
"children":[
{
"first_name":"Sally",
"last_name":"Shaw"
},
{
"first_name":"Scott",
"last_name":"Shaw"
},
{
"first_name":"Carrie",
"last_name":"Shaw"
}
]
}
Conclusion
Using the example above, you should first do a print_r of the PHP variable you are trying to work with and get an idea of the overall structure. Once you know this, it is an easy step to convert it to JSON using the built-in PHP json_encode function.
References
http://en.wikibooks.org/wiki/PHP_Programming/Data_Structures#The_Basics
http://en.wikipedia.org/wiki/Composite_type
var data=[];
<?php
foreach ($rows as $row)
{
$obj = array(
'name' => $row['name'],
'desc' => $row['desc'],
'values' => array(
array(
"from" => "/Date({$row['from']})/",
"to" => "/Date({$row['to']})/",
"label" => $row['label'],
"customClass" => "ganttOrange",
)
)
);
$objJson = json_encode($obj);
echo "data.push({$objJson});\n";
}
?>
You should create the data structure in php and echo it out with json_encode.
<?php
$data = array();
foreach ($rows as $row){
$item = array();
$item['name']=$row['name'];
$item['desc']=$row['desc'];
$item['values']= array("from" => "/Date{$row['from']})/",
"to" => "/Date({$row['to']})/",
"label" => $row['label'],
"customClass" => "ganttOrange");
$data[] = $item;
}
echo "\nvar data = ".json_encode($data).";\n";