I want to add some string before the data derived from mySQL. And output them in JSON. I can fetch out the data from mySQL right for my needs. But I cannot add the prefix string to the right format.
The expected json format
{
"message": "",//i can do this
"value": [//but I can't do this the "value":[
{
"excName": "Mark",
"excSup": "chunyun",
"excId": 20001
}, {
"excName": "orion-01",
"excSup": "orion-01",
"excId": 20000
}
]
}
PHP
while ($rec_qXcur=mysqli_fetch_assoc($sql_qXcur)){
$data[] = array(
"excId"=>$rec_qXcur['exc_id'],
"excTitle"=>$rec_qXcur['exc_name'],
"excSup"=>$rec_qXcur['exc_sup']
);
}
//return json data
echo json_encode($data);
From PHP I got this :
{
"message":"",
//"value":[//this is missing
"0":{//not need
"excId":"234",
"excTitle":"Simon Cabaret - Regular Seat ",
"excSup":"simon"
},
"1":{//not need
"excId":"245",
"excTitle":"Simon Cabaret - VIP Seat (01Nov15 - 30Apr16)",
"excSup":"simon"
}
According to the expected json format. I missed "value":[. I tried adding it to the $data but it's not working.
You are just adding them to data. You need to add them to the value array.
So json_encode() is probably creating an object literal {} because your array has both named elements and sequential elements. Once it only contains sequential elements, json_encode() should (I believe) return an array literal [];
$data = array(
'message' => 'Your message here',
'value' => array()
);
while ($rec_qXcur=mysqli_fetch_assoc($sql_qXcur)){
$data['value'][] = array(
"excId"=>$rec_qXcur['exc_id'],
"excTitle"=>$rec_qXcur['exc_name'],
"excSup"=>$rec_qXcur['exc_sup']
);
}
echo json_encode($data);
Related
I have a json that is look like this
{
"data": [
data here
]
}
and here is how i fill it up
$json = array();
foreach ($result as $key => $value) {
$json['data'][] = $value;
}
and here is how i display it
echo json_encode($json,JSON_PRETTY_PRINT);
what if the data for is empty? how can I display an empty json because my php only display [] when it is empty
like maybe something like this
{
"data": [
]
}
I would suggest explicitly defining your structure before adding records to your 'data' index. Currently, the 'data' property is only created during result iteration, which is why you're seeing a string of [] wen there are no records.
$json = array( 'data' => array() );
This will also help to avoid any warnings/notices generated by PHP.
I am using the Adobe Sign API and I need to map fields from a php array to the fields in a pdf document. I have managed to do it using the following json:
"mergeFieldInfo": [
{
"defaultValue": company['Trading Name'],
"fieldName": "Trading Name"
},
{
"defaultValue": company['Company Website'],
"fieldName": "Company Website"
}
]
The problem is I have 3 different pdf's all with 60+ fields. Is there anyway I could create this json structure by looping through the array? So far I have split the array in to two. One holds the default values and the other the field names not sure if thats the right way to be going
Solved using json_encode
foreach ($company as $key => $value){
$arr[] = ['defaultValue' => $value, 'fieldName' =>$key];
}
json = json_encode($arr);
Result:
{"defaultValue":"New Company","fieldName":"trade_name"},
{"defaultValue":"Website","fieldName":"website"}
I search a lot in stack and google try to find the answer which seems to be easy but I'm still stuck with it
I write a code to encode json with values I wanted from . and I would like to add a key / value to the JSON
the JSON is as following structure
{
- files: [
{
title: "works",
- tracks: [
{
title: "File",
format: "mp3"
}
]
},
-{
title: "season1",
tracks: [
{
title: "Button-1",
format: "wav"
},
-{
title: "Beep-9",
format: "wav"
}
]
}
]
}
I want to add to that a key and its value at the beginning to the json as properties under the title files , I mean that can be read by code as
json[files][new_key]
I tried to set that value like this
$json['new_key'] = "new_value";
but this causes adding numbers to the arrays in json , I don't why they numbered
this numbers affect my reading way of the json as JSONModel in my iOS app
so , I hope you can help me
thanks in advance
Assuming that the new value you want to add varies by file, you would need to loop through $json[files] and insert them per key/value pair.
<?php
for($i=0; $i<count($json); $i++)
$json[files][$i]["new_key"] = "value";
?>
I'm still not sure what you have exactly, but it seems you are trying to manipulate the json string.
If done correctly, that is probably the most efficient solution, but what you could also do is:
use json_decode to generate an array from your json string;
locate the correct section / sub-array where you want to add your data;
use array_unshift to prepend your new key - value pair;
use json_encode to generate a json string from your complete array.
The reason you're getting numbers appearing is because you're adding a key to an array (which functions more or less as a list in JS). So before you basically have the object "files" as a list of objects zero-indexed like any other JS array. When you add the key, JS simply adds your key to the end of your present keys (in your case 0 and 1).
It seems like you have a list of multimedia objects where each has a title and a list of tracks. The most straightforward way to solve your issue would be as follows:
$fileItem['title'] = 'works';
$fileItem['tracks'] = array(
array(
'title' => 'File',
'format' => 'mp3'
)
);
$json['files'][] = $fileItem;
$fileItem['title'] = 'season1';
$fileItem['tracks'] = array(
array(
'title' => 'Button-1',
'format' => 'wav'
),
array(
'title' => 'Beep-9',
'format' => 'wav'
)
);
$json['files'][] = $fileItem;
Then you JSON encode it and return it as you normally would. You can put the above in a loop as well. I lack enough context to recommend exactly how.
Using jQuery 1.7.2 and jQuery UI 1.8.18. If I use local data for the source attribute, everything works as expected. According to the documentation, a source array can be an array of string values or an array of objects:
Array: An array can be used for local data. There are two supported
formats:
An array of strings: [ "Choice1", "Choice2" ]
An array of objects with label and value properties: [ { label: "Choice1", value:
"value1" }, ... ]
Additionally, the source attribute can be a URL that responds with JSON data formatted as shown above:
String: When a string is used, the Autocomplete plugin expects that
string to point to a URL resource that will return JSON data. It can
be on the same host or on a different one (must provide JSONP). The
Autocomplete plugin does not filter the results, instead a query
string is added with a term field, which the server-side script should
use for filtering the results. For example, if the source option is
set to "http://example.com" and the user types foo, a GET request
would be made to http://example.com?term=foo. The data itself can be
in the same format as the local data described above.
If my JSON responder returns a simple array of strings, autocomplete works exactly as it should. If, however, my JSON responder returns an array of objects formatted as above, the request is made to the URL but the dropdown list is never populated. The JavaScript console shows no errors.
The autocomplete invocation looks like this:
var source_url = '/json/codes.php?type=globalcode&cid=25';
$('.gcode').autocomplete({
minLength: 2,
source: source_url
});
The responder is written in PHP. It is just a stub until I get this problem solved:
header('Content-Type: application/json, charset=UTF-8');
...
if( !$_REQUEST['type'] || !$_REQUEST['cid'] ){
echo('[]');
return false;
}
if( $_REQUEST['type'] == 'globalcode' ){
$cid = sprintf("%d", $_REQUEST['cid']);
$stub = "[ { label: 'Label for 1234', value: '1234' }, { label: 'Label for 5678', value: '5678' } ]";
echo( $stub );
return false;
}
Again, it works with both kinds of arrays when the data is local and it works with an array of string values when the data is remote. When the data is a remote array of objects, the list is never populated and JavaScript throws no errors.
You have invalid JSON, this is never logged in the console.
JSON cannot have single quotes, use double quotes, also use JSONLint to check your JSON.
This is the valid version of your JSON:
[
{
"label": "Labelfor1234",
"value": "1234"
},
{
"label": "Labelfor5678",
"value": "5678"
}
]
You could use json_encode() instead
$stub = array(
array(
"label"=>"Labelfor1234",
"value"=>"1234"
),
array(
"label"=>"Labelfor5678",
"value"=>"5678"
)
);
echo json_encode($stub);
I am trying to dynamicaly generate data in json for jQuery gantt chart. I know PHP but am totally green with JavaScript. I have read dozen of solutions on how dynamicaly add data to json, and tried few dozens of combinations and nothing. Here is the json format:
var data = [{
name: "Sprint 0",
desc: "Analysis",
values: [{
from: "/Date(1320192000000)/",
to: "/Date(1322401600000)/",
label: "Requirement Gathering",
customClass: "ganttRed"
}]
},{
name: " ",
desc: "Scoping",
values: [{
from: "/Date(1322611200000)/",
to: "/Date(1323302400000)/",
label: "Scoping",
customClass: "ganttRed"
}]
}, <!-- Somoe more data-->
}];
now I have all data in php db result. Here it goes:
$rows=$db->fetchAllRows($result);
$rowsNum=count($rows);
And this is how I wanted to create json out of it:
var data='';
<?php foreach ($rows as $row){ ?>
data['name']="<?php echo $row['name'];?>";
data['desc']="<?php echo $row['desc'];?>";
data['values'] = {"from" : "/Date(<?php echo $row['from'];?>)/", "to" : "/Date(<?php echo $row['to'];?>)/", "label" : "<?php echo $row['label'];?>", "customClass" : "ganttOrange"};
}
However this does not work. I have tried without loop and replacing php variables with plain text just to check, but it did not work either. Displays chart without added items. If I add new item by adding it to the list of values, it works. So there is no problem with the Gantt itself or paths. Based on all above I assume the problem is with adding plain data to json. Can anyone please help me to fix it?
First of all you're adding properties to string instead of building object. If you really want to do that this way:
var data = [], row;
<?php foreach ($rows as $row) : ?>
row = {};
row.name ="<?php echo $row['name'];?>";
row.desc ="<?php echo $row['desc'];?>";
row.values = {"from" : "/Date(<?php echo $row['from'];?>)/", "to" : "/Date(<?php echo $row['to'];?>)/", "label" : "<?php echo $row['label'];?>", "customClass" : "ganttOrange"};
data.push(row);
<?php endforeach; ?>
Anyway it is unsafe (and result is normal JS code, not proper JSON object - but as you're assigning it to variable then I suppose it does not have to be in strict JSON format)
Better approach would be to build data structure in PHP and use json_encode function to generate JSON data for JavaScript:
<?php
$data = array();
foreach ($rows as $row) {
$data[] = array(
'name' => $row['name'],
'desc' => $row['desc'],
'values' => array(array(
'from' => '/Date('.$row['from'].'>)/',
'to' => '/Date('.$row['to'].')/',
'label' => $row['label'],
'customClass' => 'ganttOrange',
))
);
}
?>
var data = <?php echo json_encode($data); ?>;
Quick Answer
As stated previously, this problem is easily resolved using the PHP json_encode function.
The trick to understanding how to do this easily is to understand the composite data structure that you are trying to work with.
Overview
What you are dealing with is a general programming concept called a "composite data structure". The trick to understanding this is to realize that the PHP and the JavaScript that you are attempting to manage are just two different representations of the exact same thing.
Once this concept sinks in, it will be easy to relate to what the users Musa and dev-null-dweller have already explained.
The straightforward way to solve this issue is to simply build a composite data structure in PHP and then translate it into JSON (aka JavaScript) using the built-in native methods of PHP's json_encode and json_decode.
Instead of doing all the statements, you should treat each $row as a composite data structure and use the PHP json functions.
The following example should give you a head start, simply compare it to the data you are trying to work with and change accordingly.
Example 001
// This is a PHP composite data structure [ a nested array ]
// represented in PHP. When you run this code you will get the
// output of Result 001
$user_profile = Array(
main => Array(
first_name => "_blank_",
last_name => "_blank_",
sex => "_blank_",
age => "_blank_",
),
guardian => Array(
first_name => "",
last_name => "",
),
children => Array(
0 => Array(
first_name => "Sally",
last_name => "Shaw",
),
1 => Array(
first_name => "Scott",
last_name => "Shaw",
),
),
);
// This is some sample PHP code you can use to modify
// the composite data structure (modify the "_blank_" values)
//
$user_profile["main"]["first_name"] = "Archibald";
$user_profile["main"]["last_name"] = "Shaw";
$user_profile["main"]["age"] = "33";
$user_profile["main"]["sex"] = "male";
// This is some sample PHP code you can use to modify
// the composite data structure (add a new child)
//
$user_profile["children"][2] = Array();
$user_profile["children"][2]["first_name"] = "Carrie";
$user_profile["children"][2]["last_name"] = "Shaw";
// This is the PHP code you can use to transform from PHP to JSON
$result = json_encode( $user_profile );
print_r( $result );
Result 001 (formatted for easy readability)
{
"main":{
"first_name":"Archibald",
"last_name":"Shaw",
"sex":"male",
"age":"33"
},
"guardian":{
"first_name":"",
"last_name":""
},
"children":[
{
"first_name":"Sally",
"last_name":"Shaw"
},
{
"first_name":"Scott",
"last_name":"Shaw"
},
{
"first_name":"Carrie",
"last_name":"Shaw"
}
]
}
Conclusion
Using the example above, you should first do a print_r of the PHP variable you are trying to work with and get an idea of the overall structure. Once you know this, it is an easy step to convert it to JSON using the built-in PHP json_encode function.
References
http://en.wikibooks.org/wiki/PHP_Programming/Data_Structures#The_Basics
http://en.wikipedia.org/wiki/Composite_type
var data=[];
<?php
foreach ($rows as $row)
{
$obj = array(
'name' => $row['name'],
'desc' => $row['desc'],
'values' => array(
array(
"from" => "/Date({$row['from']})/",
"to" => "/Date({$row['to']})/",
"label" => $row['label'],
"customClass" => "ganttOrange",
)
)
);
$objJson = json_encode($obj);
echo "data.push({$objJson});\n";
}
?>
You should create the data structure in php and echo it out with json_encode.
<?php
$data = array();
foreach ($rows as $row){
$item = array();
$item['name']=$row['name'];
$item['desc']=$row['desc'];
$item['values']= array("from" => "/Date{$row['from']})/",
"to" => "/Date({$row['to']})/",
"label" => $row['label'],
"customClass" => "ganttOrange");
$data[] = $item;
}
echo "\nvar data = ".json_encode($data).";\n";