i'm trying to use str_replace to edit urls in a csv import in Wordpress, using WP All Import.
This code works
[str_replace("https://oldsite.com/wp-content/uploads/2022/10/Image-Download.jpg", "http://newsite.com/wp-content/uploads/", {title_slider[1]})]
The problem is that not all the uploads in the old site rest in 2022/10 ... so i was wondering if there was any way to use a wildcard to replace 2022 for any year and 10 for any month ?
I tried uploads/*
I hoped that it might accept that but what is being produced is a mixed URL of both oldsite and newsite.
I know this would not work in a browser to navigate to the file, but i only require str_replace.
Current outcome https://oldsite.com/newsite.com/wp-content/uploads/2022/10/Image.jpg
Looking up the documentation for that plugin, confirms that the syntax you're using is running an ordinary PHP function.
So to find the direct answer to your question, we can look up the PHP manual for the str_replace function. It's rather straight-forward:
This function returns a string or an array with all occurrences of search in subject replaced with the given replace value.
No special syntax for wildcards or pattern matching. However, that page does link a couple of times to another function, preg_replace, which:
Searches subject for matches to pattern and replaces them with replacement.
That sounds more promising, right? Specifically, it uses regular expressions, which are a common and very powerful way to specify text patterns.
If you haven't heard of "regular expressions" before, the details might be confusing, but there are lots of tutorials and cheat sheets online.
For example, to match "exactly two digits" you can write \d\d, or \d{2}. In PHP, you would write that like this - note the special / or # delimiters around the pattern, inside the quotes; they can be pretty much any character, but if it appears in the pattern, it has to be "escaped", so best to choose something that doesn't appear:
$new_value = preg_replace('/\d\d/', '99', $old_value);
// or
$new_value = preg_replace("/\d\d/", "99", $old_value);
// or
$new_value = preg_replace('#\d\d#', '99', $old_value);
// or
$new_value = preg_replace("#\d\d#", "99", $old_value);
Translating that example into the plugin's syntax, and noting this from the plugin manual:
You must use double quotes when executing PHP functions from within WP All Import.
You would have this:
[preg_replace("/\d\d/", "99", {something[1]})]
// or
[preg_replace("#\d\d#", "99", {something[1]})]
Hopefully you can work out the rest from there.
Related
Something I have noticed on the StackOverflow website:
If you visit the URL of a question on StackOverflow.com:
"https://stackoverflow.com/questions/10721603"
The website adds the name of the question to the end of the URL, so it turns into:
"https://stackoverflow.com/questions/10721603/grid-background-image-using-imagebrush"
This is great, I understand that this makes the URL more meaningful and is probably good as a technique for SEO.
What I wanted to Achieve after seeing this Implementation on StackOverflow
I wish to implement the same thing with my website. I am happy using a header() 301 redirect in order to achieve this, but I am attempting to come up with a tight script that will do the trick.
My Code so Far
Please see it working by clicking here
// Set the title of the page article (This could be from the database). Trimming any spaces either side
$original_name = trim(' How to get file creation & modification date/times in Python with-dash?');
// Replace any characters that are not A-Za-z0-9 or a dash with a space
$replace_strange_characters = preg_replace('/[^\da-z-]/i', " ", $original_name);
// Replace any spaces (or multiple spaces) with a single dash to make it URL friendly
$replace_spaces = preg_replace("/([ ]{1,})/", "-", $replace_strange_characters);
// Remove any trailing slashes
$removed_dashes = preg_replace("/^([\-]{0,})|([\-]{2,})|([\-]{0,})$/", "", $replace_spaces);
// Show the finished name on the screen
print_r($removed_dashes);
The Problem
I have created this code and it works fine by the looks of things, it makes the string URL friendly and readable to the human eye. However, it I would like to see if it is possible to simplify or "tightened it up" a bit... as I feel my code is probably over complicated.
It is not so much that I want it put onto one line, because I could do that by nesting the functions into one another, but I feel that there might be an overall simpler way of achieving it - I am looking for ideas.
In summary, the code achieves the following:
Removes any "strange" characters and replaces them with a space
Replaces any spaces with a dash to make it URL friendly
Returns a string without any spaces, with words separated with dashes and has no trailing spaces or dashes
String is readable (Doesn't contain percentage signs and + symbols like simply using urlencode()
Thanks for your help!
Potential Solutions
I found out whilst writing this that article, that I am looking for what is known as a URL 'slug' and they are indeed useful for SEO.
I found this library on Google code which appears to work well in the first instance.
There is also a notable question on this on SO which can be found here, which has other examples.
I tried to play with preg like you did. However it gets more and more complicated when you start looking at foreign languages.
What I ended up doing was simply trimming the title, and using urlencode
$url_slug = urlencode($title);
Also I had to add those:
$title = str_replace('/','',$title); //Apache doesn't like this character even encoded
$title = str_replace('\\','',$title); //Apache doesn't like this character even encoded
There are also 3rd party libraries such as: http://cubiq.org/the-perfect-php-clean-url-generator
Indeed, you can do that:
$original_name = ' How to get file creation & modification date/times in Python with-dash?';
$result = preg_replace('~[^a-z0-9]++~i', '-', $original_name);
$result = trim($result, '-');
To deal with other alphabets you can use this pattern instead:
~\P{Xan}++~u
or
~[^\pL\pN]++~u
I have a custom markup parsing function that has been working very well for many years. I recently discovered a bug that I hadn't noticed before and I haven't been able to fix it. If anyone can help me with this that'd be awesome. So I have a custom built forum and text based MMORPG and every input is sanitized and parsed for bbcode like markup. It'll also parse out URL's and make them into legit links that go to an exit page with a disclaimer that you're leaving the site... So the issue that I'm having is that when I user posts multiple URL's in a text box (let's say \n delimited) it'll only convert every other URL into a link. Here's the parser for URL's:
$markup = preg_replace("/(^|[^=\"\/])\b((\w+:\/\/|www\.)[^\s<]+)" . "((\W+|\b)([\s<]|$))/ei", '"$1".shortURL("$2")."$4"', $markup);
As you can see it calls a PHP function, but that's not the issue here. Then entire text block is passed into this preg_replace at the same time rather than line by line or any other means.
If there's a simpler way of writing this preg_replace, please let me know
If you can figure out why this is only parsing every other URL, that's my ultimate goal here
Example INPUT:
http://skylnk.co/tRRTnb
http://skylnk.co/hkIJBT
http://skylnk.co/vUMGQo
http://skylnk.co/USOLfW
http://skylnk.co/BPlaJl
http://skylnk.co/tqcPbL
http://skylnk.co/jJTjRs
http://skylnk.co/itmhJs
http://skylnk.co/llUBAR
http://skylnk.co/XDJZxD
Example OUTPUT:
http://skylnk.co/tRRTnb
<br>http://skylnk.co/hkIJBT
<br>http://skylnk.co/vUMGQo
<br>http://skylnk.co/USOLfW
<br>http://skylnk.co/BPlaJl
<br>http://skylnk.co/tqcPbL
<br>http://skylnk.co/jJTjRs
<br>http://skylnk.co/itmhJs
<br>http://skylnk.co/llUBAR
<br>http://skylnk.co/XDJZxD
<br>
e flag in preg_replace is deprecated. You can use preg_replace_callback to access the same functionality.
i flag is useless here, since \w already matches both upper case and lower case, and there is no backreference in your pattern.
I set m flag, which makes the ^ and $ matches the beginning and the end of a line, rather than the beginning and the end of the entire string. This should fix your weird problem of matching every other line.
I also make some of the groups non-capturing (?:pattern) - since the bigger capturing groups have captured the text already.
The code below is not tested. I only tested the regex on regex tester.
preg_replace_callback(
"/(^|[^=\"\/])\b((?:\w+:\/\/|www\.)[^\s<]+)((?:\W+|\b)(?:[\s<]|$))/m",
function ($m) {
return "$m[1]".shortURL($m[2])."$m[3]";
},
$markup
);
I know you might laugh, but actually this is a common need in most apps. Many apps that take in customer/visitor input may need to filter cuss words or vulgar terms.
Sometimes PHP changes and new stuff gets added in. For instance, just the other day I learned about MultiCurl API in PHP5. So, anyway, is there a new native function in PHP that lets me filter most common English-based cuss words in a string, as well as flip a boolean to say, "string had English-based cuss words in it"? It doesn't need to be perfect, obviously, but cut out a good bit of garbage and let me replace it with ### for instance.
If that's not part of PHP yet, then does anyone have a function that I can use which cloaks the cuss word list? For instance, I want it such that I can drop the class in a project and not have to worry about another programmer getting offended. In other words, a decently encoded cuss word list -- not one actually spelled out.
Now, obviously it needs to be flexible and let words like "rebuttal" get through.
tl;dr: Does PHP5 now have a native function that can filter obscene words? And if not, does anyone have a class that encodes a cuss word list so that it doesn't offend other programmers?
I doubt this is something that would be a high priority for the core PHP team since that treads dangerously close to censorship. Censorship in that they would have a 'master' list of 'inappropriate' language which should be filtered.
You can do this fairly simply. Make up an array of all the words you want filtered out and when a page is displayed that contains user input run a preg_filter() on the words.
$bad_words = array('bleeping', 'blooping');
$submitted_text = 'bleh blah....';
echo preg_filter($bad_words, $replace, $submitted_text);
Note: you will have to deal with the edge cases where a bad word might be inside of a good word (i.e.- 'shitzu[sic] dog')
EDIT
For the bad-words-inside-good-words issue, you can add to the regular expression to require space at the beginning and end of the bad word. If you have lots of submissions though, it's going to be a constant battle to keep up with the trolls.
<?php
$badwords = "fuc";
$replacebad = "****";
$string = $_POST['something'];
$filtered = str_ireplace($badwords, $replacebad, "$string");
echo $filtered;
?>
something like this ?
Edit:
sorry I didn't noticed the php5 part ..
I'm trying to extract one or more urls from a plain text string in php. Here's some examples
"mydomain.com has hit the headlines again"
extract " http://www.mydomain.com"
"this is 1 domain.com and this is anotherdomain.co.uk but sometimes http://thirddomain.net"
extract "http://www.domain.com" , "http://www.anotherdomain.co.uk" , "http://www.thirddomain.net"
There are two special cases I need - I'm thinking regex, but dont fully understand them
1) all symbols like '(' or ')' and spaces (excluding hyphens) need to be removed
2) the word dot needs to be replaced with the symbol . , so dot com would be .com
p.s I'm aware of PHP validation/regex for URL but cant work out how I would use this to achieve the end goal.
Thanks
In this case it will be hard to get 100% correct results.
Depending on the input you may try to force matching just most popular first level domains (add more to it):
(?:https?://)?[a-zA-Z0-9\-\.]+\.(?:com|org|net|biz|edu|uk|ly|gov)\b
You may need to remove the word boundary (\b) to get different results.
You can test it here:
http://bit.ly/dlrgzQ
EDIT: about your cases
1) remove from what?
2) this could be done in php like:
$result = preg_replace('/\s+dot\s+(?=(com|org|net|biz|edu|and_ect))/', '.', $input);
But I have few important notes:
This Regex are more like guidance, not actual production code
Working with this kind of loose rules on text is wacky for the least - and adding more special cases will make it even more looney. Consider this - even stackoverflow doesn't do that:
http://example.org
but not!
example.org
It would be easier if you'd said what are you trying to achieve? Because if you want to process some kind of text that goes somewhere on the WWW later, then it is very bad idea! You should not do this by your own (as you said - you don't understand Regex!), as this would be just can of XSS worms. Better think about some kind of Markdown language or BBCore or else.
Also get interested in: http://htmlpurifier.org/
I'm trying to put together a plug-in for vBulletin to filter out links to filesharing sites. But, as I'm sure you often hear, I'm a newb to php let alone regexes.
Basically, I'm trying to put together a regex and use a preg_replace to find any urls that are from these domains and replace the entire link with a message that they aren't allowed. I'd want it to find the link whether it's hyperlinked, posted as plain text, or enclosed in [CODE] bb tags.
As for regex, I would need it to find URLS with the following, I think:
Starts with http or an anchor tag. I believe that the URLS in [CODE] tags could be processed the same as the plain text URLS and it's fine if the replacement ends up inside the [CODE] tag afterward.
Could contain any number of any characters before the domain/word
Has the domain somewhere in the middle
Could contain any number of any characters after the domain
Ends with a number of extentions such as (html|htm|rar|zip|001) or in a closing anchor tag.
I have a feeling that it's numbers 2 and 4 that are tripping me up (if not much more). I found a similar question on here and tried to pick apart the code a bit (even though I didn't really understand it). I now have this which I thought might work, but it doesn't:
<?php
$filterthese = array('domain1', 'domain2', 'domain3');
$replacement = 'LINKS HAVE BEEN FILTERED MESSAGE';
$regex = array('!^http+([a-z0-9-]+\.)*$filterthese+([a-z0-9-]+\.)*(html|htm|rar|zip|001)$!',
'!^<a+([a-z0-9-]+\.)*$filterthese+([a-z0-9-]+\.)*</a>$!');
$this->post['message'] = preg_replace($regex, $replacement, $this->post['message']);
?>
I have a feeling that I'm way off base here, and I admit that I don't fully understand php let alone regexes. I'm open to any suggestions on how to do this better, how to just make it work, or links to RTM (though I've read up a bit and I'm going to continue).
Thanks.
You can use parse_url on the URLs and look into the hashmap it returns. That allows you to filter for domains or even finer-grained control.
I think you can avoid the overhead of this in using the filter_var built-in function.
You may use this feature since PHP 5.2.0.
$good_url = filter_var( filter_var( $raw_url, FILTER_SANITIZE_URL), FILTER_VALIDATE_URL);
Hmm, my first guess: You put $filterthese directly inside a single-quoted string. That single quotes don't allow for variable substitution. Also, the $filterthese is an array, that should first be joined:
var $filterthese = implode("|", $filterthese);
Maybe I'm way off, because I don't know anything about vBulletin plugins and their embedded magic, but that points seem worth a check to me.
Edit: OK, on re-checking your provided source, I think the regexp line should read like this:
$regex = '!(?#
possible "a" tag [start]: )(<a[^>]+href=["\']?)?(?#
offending link: )https?://(?#
possible subdomains: )(([a-z0-9-]+\.)*\.)?(?#
domains to block: )('.implode("|", $filterthese).')(?#
possible path: )(/[^ "\'>]*)?(?#
possible "a" tag [end]: )(["\']?[^>]*>)?!';