How to fix Array overwritten after foreach loop php - php

I am having issue data Array overwritten in foreach loop. Result I am getting like this wrongRight together .Right answer is showing but also wrong for example ZucchiniCauliflower.Please help
CODE 1
$data = array();
$dis_07= null;
$dis_03 = null;
if (is_array($row)) {
foreach ($row as $value) {
$gccat_id = $value->gccat_id;
$ccat_id = $value->ccat_id;
$cat = $value->cat_id;
if (isset($gccat_id) && $gccat_id == $id) {
$dis_07 = $value->category;
$dis_02 = $value->child_id;
}
if (isset($ccat_id) && $ccat_id == $id) {
$dis_03 = $value->category;
$dis_02 = $value->parent_id;
}
}
}
$data['Dis_03'] = $dis_03;
$data['Dis_07'] = $dis_07;
if (isset($data['Dis_03'])) {
echo $data['Dis_03'];
}
if (isset($data['Dis_07'])) {
echo $data['Dis_07'];
}
First I tried this way But In one I was getting right in second link I am getting right So Tried the code previous one .In the prvious I am getting correct and wrong one together EExample ZucchiniCauliflower
CODE 2
if (isset($id)) {
$db = Database::newInstance();
$data = array();
$data['cat_status'] = 1;
$sql = "SELECT * FROM category WHERE cat_status=:cat_status ";
$row = $db->read($sql,$data);
$data['id'] = $crypt->decryptId($id);
echo $data['id'];
$id=$data['id'];
if (is_array($row)) {
foreach ($row as $value) {
$gccat_id=$value->gccat_id;
$ccat_id = $value->ccat_id;
$cat = $value->cat_id;
if (isset($gccat_id) && $gccat_id == $id) {
$data['Dis_03']=$value->category;
}
if (isset($ccat_id) && $ccat_id == $id) {
$data['Dis_03'] = $value->category;
break;
}
}
}
}
--------------------------READ FROM HERE------------------------
Here is a link one when I click on this link
$id=$value11->gccat_id;
$title
I expected the output is
Home>Raspberry
Here is a link Second link when I click on this link
Here id is ($value11->gccat_id)
window.open('<?= BASEURL ?>ap/'+id,'_self');
I expected the output is
Home>Cauliflower
1. WHEN I Use the Code 2 (Added break in this condition
(isset($ccat_id) && $ccat_id == $id)) Then click on link second
it gives output Home>Cauliflower which I was expecting. It is
correct.
2. But this time as I added the break in (isset($ccat_id) && $ccat_id == $id). I click on link one It gives wrong output which I was not expecting. Home>Squash which is wrong.
In one link I was expecting
Home>Cauliflower
ERROR NOTE If I add Break; then link Second gives correct output but when I remove Break; then link one give correct. I wanted Both link should give correct output.

Problem was with cat_id,ccat_id ,gccat_id.
I provided 8 digit unique number with the following output,now I am getting the correct output.
function generateUniqueNumber() {
return sprintf('%08d', mt_rand(1, 99999999));
}

Related

I want to delete top first row from table in firebase Database

I want to delete top first row from table in firebase Database when no. of rows reach to 50.
I can search this lot of time but still not found. Anyone tell that how I can do this.
Through this technique
$searchdata = "Data";
$fetchdata = $database->getReference($searchdata)->getValue();
$found = 0;
$array=0;
if($fetchdata > 0)
{
foreach($fetchdata as $Key => $row)
{
if($found == 0)
{
$del = "Data/".$Key;
$DelRef = $database->getReference($del)->remove();
$found=1;
}
else
{
break;
}
}
}

PHPExcel, If $value = $value then skip?

I'm trying to read a xlsx file using PHPExcel, however I got a problem trying to generate a navbar using column 1 values. Since Most of my column contains same type of value e.g. T-Shirt, T-Shirt... Cap, Cap, Cap.. Hoodies, Hoodies...
I got a problem filtering out the same value, does someone has any idea how to skip the same value as previous one?
Here's my code:
<?php
for ($column = 2; $column <= $highestRow; ++$column) {
$cat = $objWorksheet->getCellByColumnAndRow(0, $column)->getValue();
if ($cat == $cat) {
continue;
} else {
echo '<li>'.$cat.'</li>';
}
}
?>
Would be great if it works under <li></li> for my navbar
Try this.
//Get the value of $column -1 aka the previous column.
$previousColumn = $objWorksheet->getCellByColumnAndRow(0, $column - 1)->getValue();
$cat = $objWorksheet->getCellByColumnAndRow(0, $column)->getValue();
if ($cat == $previousColumn) {
continue;
} else {
echo '<li>'.$cat.'</li>';
}

PHP recently viewed script to session array

I've been given this bit of code:
if(isset($_GET['viewevent'])) {
if(count($_SESSION['e_lastviewed']) == 0) {
$_SESSION['e_lastviewed'][0] = $_GET['viewevent'];
} else if(!in_array($_GET['viewevent'], $_SESSION['e_lastviewed'])) {
$_SESSION['e_lastviewed'][2] = $_SESSION['e_lastviewed'][1];
$_SESSION['e_lastviewed'][1] = $_SESSION['e_lastviewed'][0];
$_SESSION['e_lastviewed'][0] = $_GET['viewevent'];
}
}
if($_GET['show']) {
$_SESSION['show'] = $_GET['show'];
} else if($_SESSION['show']=='') {
$_SESSION['show'] = "all";
}
It apparently saves ID's of recently viewed items, so i need to put these id's into an array.
Would this work?
$my_array = array($_SESSION['e_lastviewed'][2],$_SESSION['e_lastviewed'][1],$_SESSION['e_lastviewed'][0]);
I've ran it but it displays blank results (not sure if thats due to me not doing it right or incomplete code...Have i missed something? I'm not sure if i completley understand the script i was given...
try this:
if ( !isset($_SESSION['e_lastviewed']) )
$_SESSION['e_lastviewed'] = array();
// alt: while(count($_SESSION['e_lastviewed']) > 2 ) {
if(count($_SESSION['e_lastviewed']) > 2 ) {
array_shift($_SESSION['e_lastviewed']); // drop off from 3
array_unshift($_SESSION['e_lastviewed'],$_GET['viewevent']); // insert in the beginning
if($_GET['show']) {
$_SESSION['show'] = $_GET['show'];
} else if($_SESSION['show']=='') {
$_SESSION['show'] = "all";
}

using a $_GET id to filter a mysql_fetch_array in PHP

So I have a query that I am returning all of the items into a mysql_fetch_array. Now, I know I could write another query and just select the items I need into a seperate query but, is there a way to just filter from the larger query what I want dependent on $_GET?
So, in english the user comes from a hyperlink that has ?id=1 and I peform a while that gets the all the values but, only display the $_GET['id'] items in a list
<?php //give ma all values but only echo out list of the $_GET['id'] in the url
while ($row = mysql_fetch_array($result) {
$id = $rowvideo["id"];
$title = $rowvideo["title"];
$length = $rowvideo["length"];
}
echo("<li><a href='#'>". $title." " .$length. "</a></li>");
?>
Hope this makes sense. Thank you all.
If you do not want a second query to get just what you need, a simple-if-statement in your loop should work:
<?php
$getId = isset($_GET['id']) ? $_GET['id'] : false;
//give ma all values but only echo out list of the $_GET['id'] in the url
while ($row = mysql_fetch_array($result)) {
$id = $row["id"];
$title = $row["title"];
$length = $row["length"];
if ($id == $getId) {
echo("<li><a href='#'>". $title." " .$length. "</a></li>");
}
}
?>
Note that I declared $getId outside of the loop to prevent having to use isset() during every iteration. If you don't verify if it's set and attempt to use it it will throw an undefined index warning - assuming you have error_reporting turned on (with that level enabled).
Alternatively, you could use PHP's array_filter() on the data after you've parsed it all:
$results = array();
while ($row = mysql_fetch_array($result)) $results[] = $row;
if (isset($_GET['id'])) {
$filtered = array_filter($results, function($element) use ($_GET['id']) { return ($element['id'] == $_GET['id']); });
$results = $filtered;
}
foreach ($results as $result) {
echo("<li><a href='#'>". $result['title']." " .$result['length']. "</a></li>");
}
My personal opinion would be to be more efficient and write the second query though, assuming of course you don't actually need all of the results when an id is specified. It would be as simple as:
if (isset($_GET['id']) && is_numeric($_GET['id'])) {
$query = 'SELECT id, title, length FROM table WHERE id=' . (int)$_GET['id'];
} else {
$query = 'SELECT id, title, length FROM table';
}
// your existing code as-is
A little more clarity here:
This will allow the filter by id in the url by specifying id=xxx, IF xxx is an integer that is positive. So id of 'bob' or -1 will not filter the results still giving all results
$filter=false;
if(isset($_GET['id']))
{
$filter_id=intval($_GET['id']);
if($id>0) $filter=true;
}
while($row = mysql_fetch_array($result))
{
if( (!$filter) || ( ($filter) && ($filter_id==$row['id']) ) )
{
$id = $row["id"];
$title = $row["title"];
$length = $row["length"];
// do other stuff here
}
}
I also changed $rowvideo to $row as this is the array you used to fetch the results.
<?php //give ma all values but only echo out list of the $_GET['id'] in the url
while ($row = mysql_fetch_array($result)) {
$id = $rowvideo["id"];
$title = $rowvideo["title"];
$length = $rowvideo["length"];
if ($id == $_GET['id']) { // or even ===
echo("<li><a href='#'>". $title." " .$length. "</a></li>");
}
}
?>

if else simple beginner issue

Good day guys,
I've made a sweet favorites function with php mysql and ajax, and its working great. Now I want to show 'favorite' when favorite = 0 and show 'unfavorite' when favorite = 1
if ($favorites == 0) {
$favorite = 'Favorite';
}
if ($favorites == 1) {
$unfavorite = 'unFavorite';
}
and echo it in the row as :
<div id="favorites">' .($favorite). ' ' .($unfavorite). '</div>
The problem is: when favorite = 0, both $favorite and $unfavorite are being shown. When favorite = 1 only $unfavorite is being shown correctly. Of course it should be $favorite OR $unfavorite. I assume the problem is clear and simple to you, please assist :)
Thanks in advance
It's easier to use just one variable:
$text = ''
if ($favorites == 0) {
$text = 'Favorite';
} else {
$text = 'unFavorite';
}
...
echo $text;
If you want to check $favorite, you are using the wrong variable in your control statement. Also, it is better coding practice to use elseif rather than if for that second if. One more thing: it's easier to manage one resulting variable.
$output = "";
if ($favorite == 0) {
$output = 'Favorite';
}
elseif ($favorite == 1) {
$output = 'unFavorite';
}
...
echo $output; // Or whatever you want to do with your output
Is $favorites an integer?
Anyway try using three equal signs (===) or else instead of the second if:
if ( $favorites === 0 )
{
// ...
}
else // or if ($favorites === 1)
{
// ...
}
You're making a toggle, so you only need one variable:
if(empty($favourites)){
$fav_toggle = 'Favorite';
} else {
$fav_toggle = 'unFavorite';
}
echo $fav_toggle;
Same code is working on me if I assigned $favorites = 0; or $favorites = 1;
You can also use if else
$favorites = 1;
if ($favorites == 0) {
$favorite = 'Favorite';
}
else if ($favorites == 1) {
$unfavorite = 'unFavorite';
}

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