Using while() display even with NULLS - php

Question

I have a table and I am displaying its contents using PHP and a while(); I have about three fields in the table that are NULL but can be change, but I want them to still display all the results in my table.
But, it only shows the records with data in EVERY field. Anyone how I can display it? I get a count of the table and it gives me 2, but only displays one.
<h3>Viewing All Updates</h3>
<h4>Below are all active updates for COTC</h4>
<table>
<thead>
<tr>
<th>Site Name</th>
<th>Page</th>
<th>Flag</th>
<th>Date Sent</th>
<th>View</th>
</tr>
</thead>
<tbody>
<?php
$sql = "SELECT sname,page_name,date_submitted,u_id,clients.c_id,flag,completed FROM updates INNER JOIN clients ON updates.c_id = clients.c_id INNER JOIN pages ON updates.page = pages.p_id ORDER BY date_submitted DESC";
$query = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_array($query)){
$completed = $row['completed'];
if($completed == 1){
print '<tr class="quiet">';
}else{
print '<tr>';
}
print '<td>'.$row['sname'].'</td>';
print '<td>'.$row['page_name'].'</td>';
print '<td>'.$row['flag'].'</td>';
print '<td>'.$row['date_submitted'].'</td>';
print '<td class="center"><img src="images/page_edit.png" alt="Edit entry!" /></td>';
print '</tr>';
}
?>
</tbody>
</table>

Answer 1

Your PHP is correctly printing every row returned. I believe your problem is in the query.
SELECT sname,page_name,date_submitted,u_id,clients.c_id,flag,completed
FROM updates INNER JOIN clients ON updates.c_id = clients.c_id
INNER JOIN pages ON updates.page = pages.p_id
ORDER BY date_submitted DESC
This query will only return a row in updates if it has a matching one in clients and a matching one in pages. If you want the clients or the pages joins to be optional (a updates row that has c_id or page of NULL will still return) change them from INNER JOINs to LEFT JOINs.