I'm trying to make a PHP script to find the next occurence of a date (say 5-1). However, if I put that into strtotime() on 5-2 it comes up with the date from this year. I simply want to make it always return the next date possible. How can I make this work? I'm using codeigniter if that helps.
EDIT: Here's some code I came up with, if some humble soul runs across the same problem:
if (strtotime($date) < strtotime("now")) {
$realseconds = strtotime($date) + 31556926; //add one year in seconds
} else {
$realseconds = strtotime($date);
}
You could check whether the date returned is earlier than the current time, and, if it is, add one year to it.
You could also pass some date in the next year as the second parameter to strtotime.
What is 5-1 or 5-2?!
Try doing this instead:
strtotime('next October');
Assuming 5-2 means february fifth, you could do
strtotime("february 5 +1 year")
Code:
$x=strtotime($inputString);
$YEAR=60*60*24*30*12;
while($x<$time()) $x+=$YEAR;
Basically, it adds one year if the date returned by strtotime is in the past... because i used while() it will never return a date in tha past even if it was explicitly stated like that
Related
Currently, I'm trying to parse out dates when messages were received into timestamps. I have the month and day but the year is not specified. The event always occurs at the most recent (human) reading of the time. It works great in most cases to do this:
$time = strtotime("Jan 2 8:38pm");
That returns a date for this year, which is correct. Unfortunately, I get problems when I try to do for example:
$time = strtotime("Dec 31 8:38pm");
That returns a date which hasn't happened yet, and wont happen for the whole rest of the year. Obviously, my message was not sent in the future. I need it to return December 31st of last year.
For weekdays, I had a solution by prepending 'last' before the weekday like so:
$time = strtotime("Last Saturday 8:38pm");
That always returned the time of the last Saturday. However, trying to do the same thing here doesn't work:
$time = strtotime("Last Dec 31 8:38pm");
This returns false. I know to decrement a date by 1 year, I can do this:
$time = strtotime("Dec 31 8:38pm -1 year");
And that works great for Dec 31. However, Jan 2 will now fail:
$time = strtotime("Jan 2 8:38pm -1 year");
One solution I thought of was to subtract off a year (86400 * 365) from the resulting value if it is past today's date. However, this result will fail if we passed over February of a leap year. In that case, we would end up with a time that was ahead by a day.
The best solution I came up with so far is this:
$time = strtotime($raw_time);
if ($time > time()) {
$time = strtotime($raw_time." -1 year");
}
It seems kind of wasteful to make two calls to strtotime which I know is probably not a very efficient function. Is this the most elegant solution?
Is anyone aware of an option in strtotime which forces the dates to be in the past instead of in the future?
Is there another way to parse these dates that I should consider?
Efficiency is important for this because I am going to be parsing a lot of dates with it, but I would also like simple and readable code so I can understand it later.
Your approach is fine, as there is no date format to get what you want. Another approach could be using the DateTime class:
$datetime = new DateTime($raw_time);
if ($datetime > new DateTime()) {
$datetime->modify('-1 year');
}
You could test which one of the two approaches is faster. My guess is that this is a micro-optimization that won't make a lot of difference.
In My SQL Database I have a Timestamp Column with values like this one representing the Date of the last edit:
2015-01-17 08:55:34.000000
I want to compare the Date with the current date and when is the same day I want to echo Today and otherwise I want to Display the Date of the last edit:
$timefromdb = '2015-01-17 08:55:34.000000'
$edit = strtotime($timefromdb);
if($edit > $_SERVER['REQUEST_TIME']){echo "Today";}
else{
echo strftime("on %A, the %d %B %Y", $edit);
}
echo " at ".date('h:i',$edit)
It always Displays 01/01/1970. There must be a Problem with strtotime. I did a bit of research and it seems like my Timestamp Format isn't a valid one: http://php.net/manual/en/datetime.formats.php
Around the web are a lot of Questions about converting Timestamps but I just can't find the right one: I also got a bit confused by all the functions to convert date stuff.
So can someone Tell me how to get a valid Timestamp for using it in strftime and to compare it to the REQUEST_TIME.
Thanks in Advance!
UPDATE: As Always: The Problem sits in Front of the PC. I declared the Variable but never assgined the Timestamp to it :)
Chop off the .000000 from the date as it makes the date a format strtotime() cannot work with. There's several ways to do this. A simple substr is one of them.
$timefromdb = substr('2015-01-17 08:55:34.000000', 0, -7);
I'm not exactly understood you, but
try
1. compare gettype( $edit ) and gettype($_SERVER['REQUEST_TIME'])
2. not sure what $timefromdb will be more then $_SERVER['REQUEST_TIME'], because IMHO when user edited data, time of it action will me less then current time.
strtotime() returns number of seconds since so and so date. OK. So it's all in seconds. Now, if you give a date format which consists of only day, month and year, what time does it return in terms of seconds. The very first second of the day, the last second or undefined in between? The manual does not provide any guidance and common sense would assume the first second. Why is this significant? It could be when comparing or computing time interval between a fully defined date and a partially defined datetime (one without hours, minutes and seconds).
strtotime("1/1/2014")
Is this "guaranteed," as opposed to expected, to return the very first second of the new year?
It will return the time from 00:00:00, e.g. strtotime("1/1/2014"); = strtotime("1/1/2014 00:00:00");
In case you need to be sure, just use:
strtotime("1/1/2014 00:00:00");
Yes, it will always return first second of that day:
echo date('Y-m-d H:i:s', strtotime("1/1/2014"));
# 2014-01-01 00:00:00
demo
but to be sure, just enforce time like #Pekka suggested:
echo strtotime("1/1/2014 00:00:00");
I've some problem with make a simple PHP function to work on my webspace meanwhile it works like expected at my localhost server.
The problem is the following calculation:
echo $Formated = date("Ymd",strtotime("last day of next month"));
This script dosen't seem to work b/c i simply gets the default date 19691231 instead of the correct one 20110630 when running it on my server.
I use windows (XAMP) as my localhost server so i guess there must be some form of problem that lies within the two platforms way of handling it?
strtotime is notoriously problematic going cross-version, so I'd recommend a vast simplification. You can use the 't' character in the date format to represent the last day of the month, then reduce your strtotime call to simply return some timestamp for the next month.
echo $Formated = date("Ymt", strtotime("next month"));
dont use of if month name is not given
try with
date('m/d/y', strtotime('last day next month'));
OR
date('m/d/y', strtotime('last day of march')); // give the month name with of
Reference
Forget Migration and Deployment, in fact strtime is not reliable. Navigate PHP's official site: Check the strtotime manual, especially this comment.
If you have a MySQL connection available, SELECT DATE_ADD( '2011-05-31', INTERVAL 1 MONTH ) would be less redundant since the (correct) functionality is already implemented without you having to implement it yourself.
Hi guys I was wondering if anyone could help me with the following:
I have two dates entered in two different fields > startDate and endDate.
As they are entered I would like to show a warning if:
the second one is a date before the first one. So it is wrong.
and that between the first one and the second one there a minimum gap of at least 3 days during certain period of the year and 7 days during other periods of the year.
I was thinking to write a PHP function but how do I call it as soon as the second date is entered?
Many many thank for you help
Francesco
Convert your dates to Julian day with gregoriantojd.
/**
* Get the Julian day of a date. The Julian day is the number of days since
* January 1, 4713 BC.
*/
function datetojd($date)
{
return gregoriantojd(idate('m', $date),
idate('d', $date),
idate('Y', $date));
}
// you can use strtotime to parse a lot of date formats, assuming they are text
$startDate = strtotime('22nd Nov 2009');
$finishDate = strtotime('26nd Nov 2009');
$diff = datetojd($finishDate) - datetojd($startDate);
if ($diff < 0) {
// oops, $finishDate is before $startDate
}
else {
// check $diff is at least 3 or 7 depending on the dates
}
Do the check on the client side with Javascript.
Then perform the same checks server side which can present a message after the form has been submitted (for those few users running with Javascript disabled?).
I'm not sure if you can call it as soon as the second date is entered, unless you reload the page or have the function on another page which could get a tad complicated
The way i would check the dates is to use php's mktime function, which will give you the unix time. Then if the second one is less that the first, the second date is before and if the second one is less that the first + 3 * 24 *60 * 60 (seconds in 3 days) then it isn't 3 days apart
1° case:
SELECT [whatever you need from the table] WHERE endDate < startDate
2°case:
SELECT [whatever you need from the table] WHERE (endDate - startDate) >= IF([select that define in wich period of the year the data are],3, 7)
This ill do the trick, but probably your problem cant be solved sql-side.
Please, describe better what you need to do.
EDIT:
Ok, then as someone else suggested, first check htem by js (for convenience, not for safely: never rely only on js validation!)
Use strtotime for the comparison/operation.
EDIT2 (last;) :
Go with Alex's Answer