PHP: intval() equivalent for numbers >= 2147483647 - php

In PHP 5, I use intval() whenever I get numbers as an input. This way, I want to ensure that I get no strings or floating numbers. My input numbers should all be in whole numbers. But when I get numbers >= 2147483647, the signed integer limit is crossed.
What can I do to have an intval() equivalent for numbers in all sizes?
Here's what I want to have:
<?php
$inputNumber = 3147483647.37;
$intNumber = intvalEquivalent($inputNumber);
echo $intNumber; // output: 3147483647
?>
Thank you very much in advance!
Edit: Based on some answers, I've tried to code an equivalent function. But it doesn't work exactly as intval() does yet. How can I improve it? What is wrong with it?
function intval2($text) {
$text = trim($text);
$result = ctype_digit($text);
if ($result == TRUE) {
return $text;
}
else {
$newText = sprintf('%.0f', $text);
$result = ctype_digit($newText);
if ($result == TRUE) {
return $newText;
}
else {
return 0;
}
}
}

Try this function, it will properly remove any decimal as intval does and remove any non-numeric characters.
<?php
function bigintval($value) {
$value = trim($value);
if (ctype_digit($value)) {
return $value;
}
$value = preg_replace("/[^0-9](.*)$/", '', $value);
if (ctype_digit($value)) {
return $value;
}
return 0;
}
// SOME TESTING
echo '"3147483647.37" : '.bigintval("3147483647.37")."<br />";
echo '"3498773982793749879873429874.30872974" : '.bigintval("3498773982793749879873429874.30872974")."<br />";
echo '"hi mom!" : '.bigintval("hi mom!")."<br />";
echo '"+0123.45e6" : '.bigintval("+0123.45e6")."<br />";
?>
Here is the produced output:
"3147483647.37" : 3147483647
"3498773982793749879873429874.30872974" : 3498773982793749879873429874
"hi mom!" : 0
"+0123.45e6" : 0
Hope that helps!

you can also use regular expressions to remove everything after the intial numeric parts:
<?php
$inputNumber = "3147483647.37";
$intNumber = preg_replace('/^([0-9]*).*$/', "\\1", $inputNumber);
echo $intNumber; // output: 3147483647
?>

Either use number_format($inputNumber, 0, '', '')
Or if you only want to check if its a whole number then use ctype_digit($inputNumber)
Don't use the proposed is_numeric, as also floats are numeric. e.g. "+0123.45e6" gets accepted by is_numeric

In addition to number_format, you can use sprintf:
sprintf("%.0f", 3147483647.37) // 3147483647
However, both solutions suffer from float overflow, for example:
sprintf("%.0f", 314734534534533454346483647.37) // 314734534534533440685998080

If you want to handle arbitrary-precision numbers, you will need to use the gmp extension. The function gmp_init(), for example, converts a string to a gmp resource object. the drawback is that you must use other functions of that extension to further process that object. Converting it back to a string is done using gmp_strval(), for example.
$gmpObject = gmp_init($string, 10);
if ($gmpObject === FALSE) {
# The string was not a valid number,
# handle this case here
}
echo gmp_strval($gmpObject);
You might want to only verify that the string is representing a valid number and use the string itself, if you do not intend to do any operations on the value. That can be done using a regular expression:
$containsInt = preg_match('/^\d+$/', $string);
# Or for floating point numbers:
$containsFloat = preg_match('/^\d+(.\d+)?$/', $string);
echo $string;
Another option is to use is_numeric(). But that function does more conversion than you might like. Quoting from docs of that function:
... +0123.45e6 is a valid numeric value ...

<?php
$a = 453453445435.4;
echo $bigint = floor($a);

Related

Check if whole string contains same character

I want to check if a string contains a character repeated zero or more times, for example:
If my string is aaaaaa, bbbb, c or ***** it must return true.
If it contains aaab, cd, or **%*** it must return false.
In other words, if the string has 2 or more unique characters, it must return false.
How to go about this in PHP?
PS: Is there a way to do it without RegEx?
You could split on every character then count the array for unique values.
if(count(array_count_values(str_split('abaaaa'))) == 1) {
echo 'True';
} else {
echo 'false';
}
Demo: https://eval.in/760293
count(array_unique(explode('', string)) == 1) ? true : false;
You can use a regular expression with a back-reference:
if (preg_match('/^(.)\1*$/', $string)) {
echo "Same characters";
}
Or a simple loop:
$same = true;
$firstchar = $string[0];
for ($i = 1; $i < strlen($string); $i++) {
if ($string[$i] != $firstchar) {
$same = false;
break;
}
}
For the fun of it:
<?php
function str2Dec($string) {
$hexstr = unpack('H*', $string);
$hex = array_shift($hexstr);
return hexdec($hex);
}
function isBoring($string) {
return str2Dec($string) % str2Dec(substr($string, 0, 1)) === 0;
}
$string1 = 'tttttt';
$string2 = 'ttattt';
var_dump(isBoring($string1)); // => true
var_dump(isBoring($string2)); // => false
Obviously this works only in small strings because once it gets big enough, the INT will overflow and the mod will not produce the correct value. So, don't use this :) - posting it just to show a different idea from the usual ones.
strlen(str_replace($string[0], '', $string)) ? false : true;
You can check that the number of unique characters is greater than 1. This will perform well even if the input string is empty: (Demo)
$string = 'aaaba';
var_export(
strlen(count_chars($string, 3)) < 2 // false
);
Alternatively, you can trim the string by its first character, but this will generate warnings/notices if the input string has no length. (Demo)
$string = 'aaaba';
var_export(
!strlen(trim($string, $string[0])) // false
);
p.s. Yes, you could use !strlen(trim($string, #$string[0])) to prevent warnings/notices caused by a zero-length string, but I avoid error suppression like the plague because it generally gives code a bad smell.
Regex: ^(.)\1{1,}
^: Starting of string
(.): Match and capture single characted.
\1{1,}: using captured character one or more than once.
For this you can use regex
OR:
PHP code demo
$string="bbbb";
if($length=strlen($string))
{
substr_count($string,$string[0]);
if($length==substr_count($string,$string[0]))
{
echo "Do something";
}
}

check php post value is numeric and well formatted

I need to check POST value is numeric and well formatted. My expected format is
number.number
1.0
11.5
If POST value comes without .(DOT) only 1 then I would want that php convert that to 1.0
I tried this code but it doesn't work.
$foo = '2';
$foo = preg_match('/\\d{2}\\:\\d{2}\\.\\d{2}/', $foo);
Thanks :)
Working code
//$value = '22';
$value = $_POST["input_value"];
if (is_numeric($value)) {
$new_value = number_format($value, 1);
} else {
$new_value = "$value is not numeric. <br>";
}
echo $new_value;
You basically want to check if the variable from the POST array is a float/double or not (float/double is a type of number in the format of x.x).
Cheking if a string is a float/double number
To do that, use this php built-in function: is_double or more accurate:is_float, that will tell you if the string is a float/double.
Checking if a string is an integer and converting it to a double/float value
If it's not a double, check if it's an integer (regular number): is_int, and if it's indeed an int, cast it to double by using number_format, look at the usage here: integer to double/float in php.
Example
$final_value;
$value = $_POST["wanted_value"];
if (is_float($value))
{
$final_value = $value;
}
else if (is_int($value))
{
$final_value = number_format($value, 1); // or 2 instead of 1 (2.0 or 2.00)
}
else
{
$final_value = "ERROR";
}
Hope this helps!

How can one check in PHP if a string can be converted into a whole number?

For instance, "000", "404", and "0523" can be converted into whole numbers in PHP, but "42sW" and "423 2343" cannot be converted into whole numbers.
Use the ctype_digit function. is_numeric will also permit floating point values.
$numArray = array("1.23","156", "143", "1w");
foreach($numArray as $num)
{
if (ctype_digit($num)) {
// Your Convert logic
} else {
// Do not convert print error message
}
}
}
PHP's is_numeric() can determine if a given param is a number or a number string. Have a read through the manual for some examples.
ctype_digit should be what you're looking for.
42Sw can be converted to a number by using intval()
echo intval("42sW"); // prints 42
use is_numeric():
if (is_numeric("string")) {
echo "This can be converted to a number";
}
You could try something like this.
<?php
if (is_numeric($string)) {
//functions here
}
else{
//functions2 here
}
?>
$test = "42sW";
if (ctype_digit($test)) {
echo "The string $test consists of all digits.\n";
} else {
echo "The string $test does not consist of all digits.\n";
}
//OR
is_numeric($test); // false

How do I convert a string to a number in PHP?

I want to convert these types of values, '3', '2.34', '0.234343', etc. to a number. In JavaScript we can use Number(), but is there any similar method available in PHP?
Input Output
'2' 2
'2.34' 2.34
'0.3454545' 0.3454545
You don't typically need to do this, since PHP will coerce the type for you in most circumstances. For situations where you do want to explicitly convert the type, cast it:
$num = "3.14";
$int = (int)$num;
$float = (float)$num;
There are a few ways to do so:
Cast the strings to numeric primitive data types:
$num = (int) "10";
$num = (double) "10.12"; // same as (float) "10.12";
Perform math operations on the strings:
$num = "10" + 1;
$num = floor("10.1");
Use intval() or floatval():
$num = intval("10");
$num = floatval("10.1");
Use settype().
To avoid problems try intval($var). Some examples:
<?php
echo intval(42); // 42
echo intval(4.2); // 4
echo intval('42'); // 42
echo intval('+42'); // 42
echo intval('-42'); // -42
echo intval(042); // 34 (octal as starts with zero)
echo intval('042'); // 42
echo intval(1e10); // 1410065408
echo intval('1e10'); // 1
echo intval(0x1A); // 26 (hex as starts with 0x)
echo intval(42000000); // 42000000
echo intval(420000000000000000000); // 0
echo intval('420000000000000000000'); // 2147483647
echo intval(42, 8); // 42
echo intval('42', 8); // 34
echo intval(array()); // 0
echo intval(array('foo', 'bar')); // 1
?>
In whatever (loosely-typed) language you can always cast a string to a number by adding a zero to it.
However, there is very little sense in this as PHP will do it automatically at the time of using this variable, and it will be cast to a string anyway at the time of output.
Note that you may wish to keep dotted numbers as strings, because after casting to float it may be changed unpredictably, due to float numbers' nature.
Instead of having to choose whether to convert the string to int or float, you can simply add a 0 to it, and PHP will automatically convert the result to a numeric type.
// Being sure the string is actually a number
if (is_numeric($string))
$number = $string + 0;
else // Let the number be 0 if the string is not a number
$number = 0;
Yes, there is a similar method in PHP, but it is so little known that you will rarely hear about it. It is an arithmetic operator called "identity", as described here:
Aritmetic Operators
To convert a numeric string to a number, do as follows:
$a = +$a;
If you want get a float for $value = '0.4', but int for $value = '4', you can write:
$number = ($value == (int) $value) ? (int) $value : (float) $value;
It is little bit dirty, but it works.
You can use:
(int)(your value);
Or you can use:
intval(string)
In PHP you can use intval(string) or floatval(string) functions to convert strings to numbers.
You can always add zero to it!
Input Output
'2' + 0 2 (int)
'2.34' + 0 2.34 (float)
'0.3454545' + 0 0.3454545 (float)
Just a little note to the answers that can be useful and safer in some cases.
You may want to check if the string actually contains a valid numeric value first and only then convert it to a numeric type (for example if you have to manipulate data coming from a db that converts ints to strings). You can use is_numeric() and then floatval():
$a = "whatever"; // any variable
if (is_numeric($a))
var_dump(floatval($a)); // type is float
else
var_dump($a); // any type
Here is the function that achieves what you are looking for. First we check if the value can be understood as a number, if so we turn it into an int and a float. If the int and float are the same (e.g., 5 == 5.0) then we return the int value. If the int and float are not the same (e.g., 5 != 5.3) then we assume you need the precision of the float and return that value. If the value isn't numeric we throw a warning and return null.
function toNumber($val) {
if (is_numeric($val)) {
$int = (int)$val;
$float = (float)$val;
$val = ($int == $float) ? $int : $float;
return $val;
} else {
trigger_error("Cannot cast $val to a number", E_USER_WARNING);
return null;
}
}
If you want the numerical value of a string and you don't want to convert it to float/int because you're not sure, this trick will convert it to the proper type:
function get_numeric($val) {
if (is_numeric($val)) {
return $val + 0;
}
return 0;
}
Example:
<?php
get_numeric('3'); // int(3)
get_numeric('1.2'); // float(1.2)
get_numeric('3.0'); // float(3)
?>
Source: https://www.php.net/manual/en/function.is-numeric.php#107326
I've been reading through answers and didn't see anybody mention the biggest caveat in PHP's number conversion.
The most upvoted answer suggests doing the following:
$str = "3.14"
$intstr = (int)$str // now it's a number equal to 3
That's brilliant. PHP does direct casting. But what if we did the following?
$str = "3.14is_trash"
$intstr = (int)$str
Does PHP consider such conversions valid?
Apparently yes.
PHP reads the string until it finds first non-numerical character for the required type. Meaning that for integers, numerical characters are [0-9]. As a result, it reads 3, since it's in [0-9] character range, it continues reading. Reads . and stops there since it's not in [0-9] range.
Same would happen if you were to cast to float or double. PHP would read 3, then ., then 1, then 4, and would stop at i since it's not valid float numeric character.
As a result, "million" >= 1000000 evaluates to false, but "1000000million" >= 1000000 evaluates to true.
See also:
https://www.php.net/manual/en/language.operators.comparison.php how conversions are done while comparing
https://www.php.net/manual/en/language.types.string.php#language.types.string.conversion how strings are converted to respective numbers
In addition to Boykodev's answer I suggest this:
Input Output
'2' * 1 2 (int)
'2.34' * 1 2.34 (float)
'0.3454545' * 1 0.3454545 (float)
Only multiply the number by 1 so that the string is converted to type number.
//String value
$string = "5.1"
if(is_numeric($string)){
$numeric_string = $string*1;
}
Alright so I just ran into this issue. My problem is that the numbers/strings in question having varying numbers of digits. Some have no decimals, others have several. So for me, using int, float, double, intval, or floatval all gave me different results depending on the number.
So, simple solution... divide the string by 1 server-side. This forces it to a number and retains all digits while trimming unnecessary 0's. It's not pretty, but it works.
"your number string" / 1
Input Output
"17" 17
"84.874" 84.874
".00234" .00234
".123000" .123
"032" 32
Here is a function I wrote to simplify things for myself:
It also returns shorthand versions of boolean, integer, double and real.
function type($mixed, $parseNumeric = false)
{
if ($parseNumeric && is_numeric($mixed)) {
//Set type to relevant numeric format
$mixed += 0;
}
$t = gettype($mixed);
switch($t) {
case 'boolean': return 'bool'; //shorthand
case 'integer': return 'int'; //shorthand
case 'double': case 'real': return 'float'; //equivalent for all intents and purposes
default: return $t;
}
}
Calling type with parseNumeric set to true will convert numeric strings before checking type.
Thus:
type("5", true) will return int
type("3.7", true) will return float
type("500") will return string
Just be careful since this is a kind of false checking method and your actual variable will still be a string. You will need to convert the actual variable to the correct type if needed. I just needed it to check if the database should load an item id or alias, thus not having any unexpected effects since it will be parsed as string at run time anyway.
Edit
If you would like to detect if objects are functions add this case to the switch:
case 'object': return is_callable($mixed)?'function':'object';
$a = "10";
$b = (int)$a;
You can use this to convert a string to an int in PHP.
I've found that in JavaScript a simple way to convert a string to a number is to multiply it by 1. It resolves the concatenation problem, because the "+" symbol has multiple uses in JavaScript, while the "*" symbol is purely for mathematical multiplication.
Based on what I've seen here regarding PHP automatically being willing to interpret a digit-containing string as a number (and the comments about adding, since in PHP the "+" is purely for mathematical addition), this multiply trick works just fine for PHP, also.
I have tested it, and it does work... Although depending on how you acquired the string, you might want to apply the trim() function to it, before multiplying by 1.
Late to the party, but here is another approach:
function cast_to_number($input) {
if(is_float($input) || is_int($input)) {
return $input;
}
if(!is_string($input)) {
return false;
}
if(preg_match('/^-?\d+$/', $input)) {
return intval($input);
}
if(preg_match('/^-?\d+\.\d+$/', $input)) {
return floatval($input);
}
return false;
}
cast_to_number('123.45'); // (float) 123.45
cast_to_number('-123.45'); // (float) -123.45
cast_to_number('123'); // (int) 123
cast_to_number('-123'); // (int) -123
cast_to_number('foo 123 bar'); // false
function convert_to_number($number) {
return is_numeric($number) ? ($number + 0) : FALSE;
}
You can use:
((int) $var) ( but in big number it return 2147483647 :-) )
But the best solution is to use:
if (is_numeric($var))
$var = (isset($var)) ? $var : 0;
else
$var = 0;
Or
if (is_numeric($var))
$var = (trim($var) == '') ? 0 : $var;
else
$var = 0;
Simply you can write like this:
<?php
$data = ["1","2","3","4","5"];
echo json_encode($data, JSON_NUMERIC_CHECK);
?>
There is a way:
$value = json_decode(json_encode($value, JSON_NUMERIC_CHECK|JSON_PRESERVE_ZERO_FRACTION|JSON_UNESCAPED_SLASHES), true);
Using is_* won't work, since the variable is a: string.
Using the combination of json_encode() and then json_decode() it's converted to it's "true" form. If it's a true string then it would output wrong.
$num = "Me";
$int = (int)$num;
$float = (float)$num;
var_dump($num, $int, $float);
Will output: string(2) "Me" int(0) float(0)
Now we are in an era where strict/strong typing has a greater sense of importance in PHP, I use json_decode:
$num = json_decode('123');
var_dump($num); // outputs int(123)
$num = json_decode('123.45');
var_dump($num); // outputs float(123.45)
You can change the data type as follows
$number = "1.234";
echo gettype ($number) . "\n"; //Returns string
settype($number , "float");
echo gettype ($number) . "\n"; //Returns float
For historical reasons "double" is returned in case of a float.
PHP Documentation
If you don't know in advance if you have a float or an integer,
and if the string may contain special characters (like space, €, etc),
and if it may contain more than 1 dot or comma,
you may use this function:
// This function strip spaces and other characters from a string and return a number.
// It works for integer and float.
// It expect decimal delimiter to be either a '.' or ','
// Note: everything after an eventual 2nd decimal delimiter will be removed.
function stringToNumber($string) {
// return 0 if the string contains no number at all or is not a string:
if (!is_string($string) || !preg_match('/\d/', $string)) {
return 0;
}
// Replace all ',' with '.':
$workingString = str_replace(',', '.', $string);
// Keep only number and '.':
$workingString = preg_replace("/[^0-9.]+/", "", $workingString);
// Split the integer part and the decimal part,
// (and eventually a third part if there are more
// than 1 decimal delimiter in the string):
$explodedString = explode('.', $workingString, 3);
if ($explodedString[0] === '') {
// No number was present before the first decimal delimiter,
// so we assume it was meant to be a 0:
$explodedString[0] = '0';
}
if (sizeof($explodedString) === 1) {
// No decimal delimiter was present in the string,
// create a string representing an integer:
$workingString = $explodedString[0];
} else {
// A decimal delimiter was present,
// create a string representing a float:
$workingString = $explodedString[0] . '.' . $explodedString[1];
}
// Create a number from this now non-ambiguous string:
$number = $workingString * 1;
return $number;
}
All suggestions lose the numeric type.
This seems to me a best practice:
function str2num($s){
// Returns a num or FALSE
$return_value = !is_numeric($s) ? false : (intval($s)==floatval($s)) ? intval($s) :floatval($s);
print "\nret=$return_value type=".gettype($return_value)."\n";
}
//Get Only number from string
$string = "123 Hello Zahid";
$res = preg_replace("/[^0-9]/", "", $string);
echo $res."<br>";
//Result 123

Check if variable has a number php

I want to check if a variable has a number in it, I just want to see if there is one I don't care if it has any thing else in it like so:
"abc" - false
"!./#()" - false
"!./#()abc" - false
"123" - true
"abc123" - true
"!./#()123" - true
"abc !./#() 123" -true
There are easy ways of doing this if you want to know that is all numbers but not if it just has one. Thanks for your help.
You can use the strcspn function:
if (strcspn($_REQUEST['q'], '0123456789') != strlen($_REQUEST['q']))
echo "true";
else
echo "false";
strcspn returns the length of the part that does not contain any integers. We compare that with the string length, and if they differ, then there must have been an integer.
There is no need to invoke the regular expression engine for this.
$result = preg_match("/\\d/", $yourString) > 0;
Holding on to spirit of #Martin, I found a another function that works in similar fashion.
(strpbrk($var, '0123456789')
e.g. test case
<?php
function a($var) {
return (strcspn($var, '0123456789') != strlen($var));
}
function b($var) {
return (strpbrk($var, '0123456789'));
}
$var = array("abc", "!./#()", "!./#()abc", "123", "abc123", "!./#()123", "abc !./#() 123");
foreach ($var as $v) {
echo $v . ' = ' . b($v) .'<hr />';
}
?>
This should help you:
$numberOfNumbersFound = preg_match("/[0-9]+/", $yourString);
You could get more out of the preg_match function, so have a look at its manual
you can use this pattern to test your string using regular expressions:
$isNumeric = preg_match("/\S*\d+\S*/", $string) ? true : false;

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