Strange IF Statement behaviour - php

I have an IF statement that consists of two separate function calls
passing values to two variables. Obviously if neither value is 'FALSE'
then the code block is executed:
<?php
class MyValidater {
static function validateString($string) {
if (preg_match("/[A-Za-z]+/", $string)) {
return $string;
} else {
return false;
}
}
}
$firstName = "Daniel";
$surname = "Simmons";
// Dodgy IF statement
if ($first = MyValidater::validateString($firstName) && $second = MyValidater::validateString($surname)) {
print("Success: $first $second");
} else {
print("Fail: $first $second");
}
?>
As you can see both the $first and $second variables should contain
the values held in $firstName and $surname after successfully being
validated by the Static method validateString.
However, the values of the two variables end up: $first = '1' and
$second = "Simmons".
The '1' should be "Daniel" but for some reason $first is being passed
the value '1' or TRUE. If you swap the two assignment statements over
so that $second is evaluated first, you end up with the opposite
outcome as before. $second = '1' and $first = "Daniel"
Can anyone explain why the String value "Daniel" being returned from
the class method is being changed into the int '1' for the first part
of the conditional statement only? I have had a quick look though the
PHP documentation but cannot find an explanation.
For the moment the workaround is to change the return value from the
static method to be true/false and then make $first = $firstName,
etc... upon success. But this involves more code and I would rather
find out why this way does not work.

You need to bracket your expressions:
if (($first = MyValidater::validateString($firstName)) && ($second = MyValidater::validateString($surname)))
What's actually happening is this:
if ($first = (MyValidater::validateString($firstName) && $second = MyValidater::validateString($surname)))
It would be much clearer to just do this (note this code isn't identical to what you have):
$first = MyValidater::validateString($firstName);
$second = MyValidater::validateString($surname);
if ($first && $second)

&& is higher then = in the operator precedence. add brackets and it will work.
http://www.php.net/manual/en/language.operators.precedence.php
you can read about operator precedence here.
Also, setting values inside of an if condition is usually bad practice. If you add the brackets, you will most probably see why (let $first set to false and $second set to a string) => the first will be evaluated, but since it is false then, it won't process further since it will go to the else anyways. => second will not be set correct if first = false.

Try using parenthesis
($first = MyValidater::validateString($firstName)) && ($second = MyValidater::validateString($surname)))
First is getting the result of the first function call AND the second function having a value.

= is for attributions
== is for comparisons, the data type doesn't matter
=== is for comparisons, the data type matters

What is happening is that PHP is assigning $first with “MyValidater::validateString($firstName)) && $second = MyValidater::validateString($surname)”
You need brackets around first compare and second, like this.
if ( ($first = MyValidater::validateString($firstName)) && ($second = MyValidater::validateString($surname))) {

Related

PHP compare strings error

I am a beginner in PHP and I am trying to separate the input based on the argument. Following is my code but it seems that my $arg variables is never set. Can someone point out my error?
$sender = $_GET['sender'];
$receiver = $_GET['receiver'];
$message = $_GET['message'];
$temp = explode( '.', $message);
$tempcnt = count($temp);
echo $temp[$tempcnt - 1];
if($tempcnt > 2)
{
if($temp[$tempcnt-1] === 'mp4')
{$arg = 3;}
elseif($temp[$tempcnt-1]==='jpg')
{$arg = 2;}
else
{$arg = 1;}
}
echo "Value of arg is" . $arg;
I have even tried with == and === and strcmp in if but still same issue.
Try This:
<?php
$temp strrchr("foo.jpg",".");
if($temp==".mp4")
$arg = 3;
elseif($temp==".jpg")
$arg = 2;
else $arg = 1;
?>
See also the other answers, but one possibility that hasn't been mentioned is that == and === and strcmp all compare case sensitively. So they won't find extensions like .MP4.
The solution in that case would be to use strcasecmp.
However, the first thing to do with problems like this is to output some more diagnostics, so that you can see for yourself what goes wrong. In this example, echo $tempcnt; after its assignment, or else echo "did nothing" after the outer if {..} block.
That way you'll be able to follow what the program flow is.
Issue was caused since i didn't realize i had compared for args > 2. Made it >=2 and viola it done!!
Thanks to #barmar for pointing that out!

What is a shorthand way for checking that multiple variables are ALL equal to the same value in an IF statement? (PHP)

Is there a shorthand way of writing the code below?
if (($tstat=='no_prices')&&($l1stat=='no_prices')&&($l2stat=='no_prices')&&($l3stat=='no_prices'))
{
//do something
}
I tried using the below code,but it did something when one of the variables was not equal to 'no_prices'.
if (($tstat && $l1stat && $l2stat && $l3stat)=='no_prices')
{
//do something
}
To check that the strings weren't causing problems I tried substituting 0 for 'no_prices' and 1 for other values, but the result was the same.
array_flip is several times faster than array_unique:
function all_equal($arr, $value) {
return array_keys(array_flip($arr)) == array($value);
}
$arr = array($tstat, $l1stat, $l2stat, $l3stat);
echo all_equal($arr, 'no_prices');
A quick profile for the answers given thus far, for 1000 iterations on array length 1000:
array_flip: 0.07321620 seconds
array_unique: 0.32569408 seconds
foreach: 0.15136194 seconds
array_filter: 0.41404295 seconds
The code used to profile is here: http://codepad.org/szgNfWHe
Note: As #cypherabe rightly points out, array_flip does not overtake array_unique until the array has at least 5 elements, and does not overtake foreach until the array has at least 10 elements.
Unless I'm mistaken, there's no native way of doing this. If this is something that you have to check for often, try using a custom function for it, e.g.:
function allEquals($chkstr, $vals) {
if (!is_array($vals)) { die('allEquals() $vals not an array'); }
foreach ($vals AS $v) {
if ($chkstr != $v) { return false; }
}
return true;
}
My first idea would go into PHP's Array API:
// $tstadt, $l1stat, … are all "no_prices"
$isAllNoPrice = array_unique(array($tstat, $l1stat, …)) == array("no_prices"));
if ($isAllNoPrice) {
// …
}
Documentation is mandatory otherwise nobody (including yourself) will understand the code.
If efficiency might be a concern others pointed out that array_unique() seems to be slow. Using the keys of the hash table would be a next approach:
// $tstadt, $l1stat, … are all "no_prices"
$varsMap = array(
$tstat => null,
$l1stat => null,
// …
);
if (array_keys($varsMap) == array("no_prices")) {
// …
}
But now the wall of code is growing. PHP offers one operator which nearly does what you want and is chainable: &
$v1 = "no_prices";
$v2 = "no_prices";
$v3 = "no_prices";
var_dump(($v1 & $v2 & $v3) == "no_prices"); // bool(true)
$v3 = "prices";
var_dump(($v1 & $v2 & $v3) == "no_prices"); // bool(false)
I said it nearly does what you want: There are cases in which you will have false positives:
$v1 = 1;
$v2 = 1;
$v3 = 3;
var_dump(($v1 & $v2 & $v3) == 1); // bool(true)
For Strings it seems to cut the bitmask to the shortest string:
$v1 = "abcd";
$v2 = "ab";
$v3 = "abc";
var_dump($v1 & $v2 & $v3); // "ab"
var_dump(($v1 & $v2 & $v3) == "ab"); // bool(true)
So I don't recommend this as a general purpose solution. Only if you know (=unit tested) that your values are in a set where no combination never results to a false positive (e.g. {"dog", "cat", "horse"}) you might consider this solution. I gave it a second thought and must say don't use that at all. Imagine how your colleagues will love you for searching a bug introduced by that method.
In your case you can do:
if (count(array_unique($tstat, $l1stat, $l2stat, $l3stat)) == 1 //Check if all share the same value (i.e., number of unique values is 1
&& $tstat == 'no_prices')) //If everything is the same and $stat == 'no_prices', then everything is 'no_prices'
{
}
<?php
$tstat = $l1stat = $l2stat = $l3stat = 'no_prices';
$testVars = array($tstat,$l1stat,$l2stat,$l3stat);
if(count(array_filter($testVars, function($x) { return $x === 'no_prices'; })) == count($testVars))
{
print("Correct");
}
Use array_filter with a anonymous callback, and check if its length is greater is equal to original array i.e. all conditions passed,
or if length is greater than zero i.e. any one condition passed
No, this code won't work:
if (($tstat&&$l1stat&&$l2stat&&$l3stat)=='no_prices')
{
//do something
}
Why? Because condition in parentheses, will check result itself - You are comparing boolean to string. So in pseudo-code, thats what your code looks like:
if ( ($tstat is true, $l1stat is true, $l2stat is true, $l3stat is true) == 'no_prices' )
^ whole thing returns true ^ ^ true ^
If you wan't to achieve this, you can use count() and array_unique():
if ($tstat == 'no_prices' && count(array_unique(array($tstat, $l1stat, $l2stat, $l3stat))) == 1)
try this:
$arr = array($tstat,$l1stat,...); //make an array
$arr =array_unique($arr);//unique this array
if(count($arr) == 1 && $arr[0] = 'no_prices'){ // check if only one array element have with same value
echo "got it";
}
demo example
The answer is "no". There's no shorthand to the given condition that will make your code more readable, which should be your top priority. You can improve it though:
define('MYAPP_NO_PRICES', 'no_prices');
if ($tstat === MYAPP_NO_PRICES
&& $l1stat === MYAPP_NO_PRICES
&& $l2stat === MYAPP_NO_PRICES
&& $l3stat === MYAPP_NO_PRICES) {
// do something
}
Having all these vars to check individually is a code smell; you might want to rethink this design so you never have to do this.

Problems determing if value is a number

I am doing this check on a variable:
if (empty($num) || !isset ($num) || !is_numeric ($num))
{
$population = -1;
}
else
{
$population = $num;
}
And what I was hoping for is that if num is null or not a number or doesn't exist, to make $population = -1 and in all other cases to give $population the value of $num
But that is not happening for me. Any ideas why this isn't working the way I thought it would?
Is this possibly an issue with scoping?
<?php
$num=23;
tryStuff();
function tryStuff(){
global $num; //if this line is commented out, then -1 is printed.
if (empty($num) || !isset ($num) || !is_numeric ($num))
{
$population = -1;
}
else
{
$population = $num;
}
echo "$population<br>";
}
?>
is_numeric should work good by itself. If instead of $num the value was a super global, using isset would be a good idea to avoid warnings:
$population = is_numeric ($num) ? $num : -1;
// or
$population = isset($_GET['num']) && is_numeric($_GET['num']) ? $num : -1;
post an example of $num
using regex:
$population = preg_match("/^\d+$/", $num) ? $num : -1;
I'm going to go out on a limb here and say that you're inputting the number 0 and getting unexpected results, because empty(0) is true.
I think if you change your code to:
if (!isset ($num) || !is_numeric ($num))
{
$population = -1;
}
else
{
$population = $num;
}
You will get the desired results.
EDIT Possibly you are looking for an Integer or a Float in which case you should replace is_numeric with is_int or is_float respectively.
Why not flip it around and go with a positive as a primary check?
$population = (isset($num) && is_numeric($num)) ? $num : -1;
I've never had fun with negative's and "or" statements :)
What happens if you var_dump($num);?
Personally, my guess is that PHP is interpreting something input as a number, when you are expecting it to be a string. Such examples might include things which might accidentally convert, like '0xFF' (a string of the Hex for 255).
Clearly the issue is not about isset, because if it were, you would have caught it, and you said to evolve that this happens even without empty. This means that something which you are expecting to be is_numeric($num) === FALSE can be evaluated as TRUE.

PHP - use variable as operator

I am trying to get this:
if($a[2] > $b[2] && $c[2] < 3) echo "bingo";
But because the condition is retrieved from database, I need to get the whole condition into a variable and then somehow find a way to change the variable back into a condition. I thought it will be something along this line:
$condition = "$a[2] > $b[2] && $c[2] < 3";
$evaledCondition = eval("$condition;");
if($evaledCondition) echo "bingo";
Apparently it didn't work. Am I missing something?
eval() returns NULL unless return is
called in the evaluated code
$evaledCondition = eval("return $condition;");

single = on while loop

i'm practicing php at nowadays. i have one question.
i see one = on some while loops. often on mysql queries. so what does it stands for?
two == means equal. but single = ? can you tell me the logic behind this?
Single = means "assignment". An assignment always assigns to a variable and returns the result. So, for example:
while($row = mysql_fetch_array($results)) {
// ...
}
While mysql_fetch_array($results) returns a valid array, it loops. When it returns null (meaning that's the end of the results) the loop exits.
while ($row = mysql_fetch_row($query))
{
//do stuff
}
This keeps querying the result handle until a NULL value (end of result) is found. $row then contains the row fetched from the call so it can be used for processing.
It is also "shorthand" for checking for a NULL result:
while (($row = mysql_fetch_row($query)) != null)
{
//do stuff
}
It can also replace a for loop:
for ($i = 0; $i < mysql_num_rows($query); $i++)
{
//do stuff
}
All are equivalent.
single = is for assignment
$a = 9;
== is for comparison
if($a == 9) echo 'hello';
http://www.w3schools.com/PHP/php_operators.asp
That's the assignment operator.
While the current value of 'x' can be successfully assigned to variable 'y', continue on.
Here is an alternative:
$row = mysql_fetch_assoc($thing);
while (isset($row)) {
// do stuff
$row = mysql_fetch_assoc($thing);
}
You can see that it's a bit less typing (and the code is probably more efficient) here:
while (($row = mysql_fetch_assoc($thing)) != null) {
// do stuff
}

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