I have a advertisement website with alot of records stored in a mysql db.
On my main page, I have a form where users may specify their search criteria.
Action is set to myPhp.php file.
myPhp.php contains NO HTML, only php code, and it is basically something like this:
1- get values from FORM and build a SQL query
2- query MYSQL db.
3-display all results in a table using
`while($row=mysql_fetch_array($res))`
4- echo the table.
In this table which is created in PHP, I have several links also, and whenever they are clicked, a javascript function on the parent page is called, which sets a hidden input value to something, and then submits the form again with the chosen variable.
Ex: Whenever users want to go to the next page in the search results, they have to click on a 'next' link created in PHP, and then the javascript gets called, which sets a hidden input value to 'next', and then the form is submitted again, and PHP file GETS the variable from the hidden input and detects that its value is set to 'NEXT' and then displays the next results.
Is there really not another way to do all this ? (that is, a better way when it comes to performance and reliability)
Im still learning so I am very thankful for your help!
I will update this Question whenever you need more input.
Thanks
Replace the next javascript call with a link to
http://yourdomain/myPhp.php?page=2
Then check the get parameter in myPhp.php:
if(isset($_GET['page']) AND is_numeric($_GET['page'])){
$limit = (int) $_GET['page'] * MAX_RECORDS . ', ' . MAX_RECORDS;
} else {
$limit = MAX_RECORDS;
}
//...
$query .= 'LIMIT '. $limit;
Of course you have to change it as your constants change and such.
This method called paginating. Take a look at the Zend Framework's Paginator module to the better understanding.
When creating the link you can use a querystring to specify the parameter that you would like to send to the server rather than submitting a form. So if you have a hidden input in a form called next then you can accompish the same thing like this:
Next
On the myPhp.php page you can get the value of next in a similar way as when you send a form.
If these links have at least one same class across board (with a title attribute) you can attach to them to can attach all these links to a single click event and test to see what title is on the element clicked.
With that you can use a switch to trigger the right function to perform the task (I suppose using JQuery/Ajax).
This should work. At least no hidden fields.
Example:
Next
Ad Details
Related
I'm working on big site and it has filtering of cars in it. I'll explain how the form filtering works:
so the user chooses filter options, car number and so and presses go, which makes GET request to server (php) i've changed every variable from $_GET to $_POST and changed form submission method, the problem is that when form returns big number of items it might have more than 2 pages, so when the user clicks on second or third page all this code does is add page number to the request like this: www.example.com/GET_REQUEST_VARIABLES -> www.example.com/pagenumber&GET_REQUEST_VARIABLES. that way server returns second page items and so.
but when i send post request, it isn't saved in the url so server doesn't know what to return,
can you help me solve this problem?
i can explain better if you ask questions i don't know if i explained clearly here
Is there a reason you are using POST instead of GET? Using GET is more SEO friendly in this case. And since you aren't sending sensitive data in the form submission, I don't see a reason to use POST. Another advantage of using GET is that you can directly link to search results. (For instance, if I search for a Honda Fit, and want to show my wife, I have a direct link to the page)
(Look HERE for a bullet-point explination of the difference bewteen POST and GET).
To answer your other question, POST does not use the URL. Only GET does So if you need the form data to be serialized into the URL, you'll need to use GET. Since you changed the form submission method to POST, you'll need to change the server side logic as well to accommodate. I can't be of much use without knowing what server-side technology you are using. Assuming you are using PHP, you could start here
If you aren't much for MAN pages, just change all the $_GET['fieldName'] calls in PHP to $_POST['fieldName']
You could always POST the first page, and use GET ONLY for the page number. In the form you would just do this
<form method="post" action="www.foo.com/search?page=1">
Then you can store your POSTed variables into the $_SESSION super-global. BOOM. POSTed pagination. It would be a breeze to render it on the fly with PHP
$nextPageURL = 'www.foo.com/search?page=' . $_GET['page'] + 1;
if($_GET['page'] !== '0'){
$lastPageURL = 'www.foo.com/search?page=' . $_GET['page'] - 1;
}
I have a bit of an odd/unique situation, where I am currently looking for a way to 're-populate' checkboxes on my page.
First some background on how the page/app works.
1.) state1: You get simple search form. Enter in first or last or state, etc., hit submit.
It queries a DB and posts back to the SAME Page (?mode=results).
Inside of a MAIN container DIV, I loop through the returned records, and create (echo) a TABLE with a certain tabular layout to parse the values from each record/row (name, date, ID#, etc).
If I have 5 records returned from DB, I loop through and create 5 tables right after each other, populating each with the unique data from the record/row.
In each one of these tables I create, along with the data from the DB record/row. I also create/add in several check boxes.
Using some jQuery and on $(document).ready, I listend for the onClick event for all these checkboxes. So when clicked, I grab some data from the checkbox, as well as some parent info, and do the following:
a.) I create/add another element to the stage
b.) Make an Ajax call to an external .php script, so that I can update the SESSION with my array I have build (collecting all the user checks/input)
I build the array in JS/jQuery and use the Ajax call to get this data into my PHP session (anyone knows a way to NOT use this external .php script to update the SESSION var, let me know please!)
So to re-cap so far: There is no "FORM" (tags), just check boxes in multiple tables. There really is no 1-button (submit) event that POSTS all the checkbox data anywhere at one time. Each time a checkbox is clicked (or un-clicked), I update my SESSION array. That if/when a user IS ready to 'check out' (for lack of better term) (leave the page and go to another page), the SESSION data/array is 'current' and the data is ready to be used on any following pages.
so far everything posted above works just fine.
The question I have is: If the user wants to go BACK to this MAIN PAGE with all the checkboxes, what nice, simple/elegant solutions do I have to re-populate all these checkboxes?
I'm thinking the only approach I have is the check and see if this SESSION array exists when main page loads (meaning it's a re-visit, not the first time), and try to loop through this array and somehow target elements on my stage to find the correct table, then the checkbox ID?
Usually use jQuery to walk the DOM - not PHP?
And what about toggling the checkbox with PHP?
Is there a nice way to do this?
I don't really see your problem. I recapitulate:
You have a page with several <table> coming from your database (1 row = 1 <table>)
In these tables you have checkboxes
When you click on a checkbox, you do an ajax call to save the clicked checkbox in session
Your question is: how can I repopulate checkboxes when the use come again on the page
I think you already have the answer: just use what you stored in your session. When you build your <table>, and your checkboxes, test if they are in session:
<input type="checkbox" <?php if (!empty($_SESSION['blabla'][$myCurrentCheckboxID])) echo 'checked'; ?> />
If you want something more elegant, just create a nice PHP class or list of functions to generate your checkbox.
thanks for the suggestions.. this is what worked for me in the end (so far)
function sessionCheck($recordID, $checkBoxID){
for($r = 0; $r< count($_SESSION['userPicks']); $r++){
if($_SESSION['userPicks'][$r]['recordid'] == $recordID){
for($z=0; $z < count($_SESSION['userPicks'][$r]['itemsordered']); $z++){
if($_SESSION['userPicks'][$r]['itemsordered'][$z]['name'] == $checkBoxID){
return 'checked="checked"';
}else{
return "";
}
}
}else{
return "";
}
}
}
usage for MY project is like this:
<?=sessionCheck($row["id"] ."-A","Testimonial History") ?>
I need to take form data from user input- i.e. radio buttons and use that to apply search filters to a database search.
However there are specific parameters which are giving me difficulty.
Specifically: The search filter options pane is a static fixture on the main page of the site. The query to be modified by the search filters is a separate php page which is called by an ajax function to display search results in the middle of the page without page refresh.
Is it even possible to submit variable values to another php page without going to that page and processing the php immediately? Or will the variables not be stored like that?
The code is too long but I'll give basic pseudocode:
Form action="Query Page to receive user input.php"
Some radio buttons:
20
15
10
Submit button--> Submits the radio button value to QueryPage.php but does not redirect
User clicks a category link (i.e. fitness) that calls the ajax function which displays the output of QueryPage.php. At this point QueryPage.php should perform the search with the specific user input filters that were selected earlier.
Is this possible?
Let me see if I understand correctly:
You're basically saying that your radio buttons will modify the search results, based on the what user selected?
If that's the case, I can think of 2 options:
1- When you make the ajax request for the search, first, grab the user input and send it to the QueryPage.php file with the search query. Do you have access to that function?
2- Post the user input using ajax (are you using jQuery or some other library for this?) to a UserInput.php file, where you'll store that data on the session, and then from QueryPage.php you just access the session and grab the values sent previously.
Does that answer your question? Sorry if it doens't, it's a bit hard to understand the problem.
You can use JQUERY and its events method. For example change,click,hover. In your case you want to use radio buttons, so you might wanna use the click event for that.
$("#radio").click(function () {
// SEND HTTP REQUEST
});
http://www.mkyong.com/jquery/how-to-select-a-radio-button-with-jquery/
Yes. You could just use .ajax(), or .post() or cURL. This will post your data to the specified page without redirecting.
Example using .post()
$.post("test.php", { name: "John", time: "2pm", fieldname: "your value" } );
I'm displaying tabular data populated via loop from a database.
I know that I could edit/delete etc in the usual manner, where
Edit Record
But I would really like to do this using the modal-message feature of jquery.
However, what I can't seem to figure out is how to indicate to the modal-message window/div the correct record number from the database (whereas in php, I'm simply using the print function.
Is it feasible to set maybe an onClick event that sets a variable ($id) to equal whatever the $row['abstract_id'] number is?
The idea being that when I click on the Edit button, I can put php within the div and it will call up the correct record.
EDIT for clarity: I don't want to actually edit it, it's to pull up the text of the abstracts, which are too big to fit in the tabular format (but there are too many abstracts to give each submission its own page).
The key here is how I can pass the record id from the database/php side to the javascript side even if it's setting/resetting some variable. I thought about using .load(read_abstract.php) but then realized that I don't think that .load(read_abstract.php?id=' . $row['abstract_id']') would work- and don't know what the JS equivalent would be (or if it exists).
You can move the id into a data attribute in the HTML tag:
echo '<span class="edit-button" data-abstract-id="'.$row['abstract_id'].'">edit</span>'
Then in the modal, you'll be able to reference it with:
jQuery('.edit-button').click(function() {
id = jQuery(this).attr('data-abstract-id');
});
i found it difficult,,,, fetching data from database while a buttons are randomly generated in for each how can i fetch
Without understanding what your question really is, you could go trough the mysql query result like this:
// button_text is a database column in this example
while ($row = mysql_fetch_row($result)){
echo "<button type="button">".$row['button_text']."</button>";
}
But to really help you, you need to rephrase your question!
I'll make some assumptions for what you are trying to do:
1. You have buttons that fetch more info from a db
2. The buttons are "randomly" generated, and each calls different info (pets, cars, etc).
You may or may not be using ajax, but I will describe it basically assuming straight php, and you are using a single page (for clarity in my explanation).
What you need to do is have each button either be a link or a submit for a form. This just depends on whether you want to use GET or POST. The buttons will have php generated links (if GET) or values (if POST). For example, using get the link could be "www.file.php?cat=cars". The button would just have the value of "Cars", and since bother are generated, that shouldn't be an issue keeping them the same.
When the page is now reloaded based on the click, the top of the page has a query in it to get the new info. For example, it would run a query looking for all items that have the car category. Then the new information would be displayed, and the new random buttons would show.
VERY IMPORTANT: Sanitize all GET and POST values before using them in a query