Query in CodeIgniter:
$this->db->select('comments.created_at, comments.section_id, comments.submittedby_id, users.username, comments.text, sections.name');
$this->db->order_by('comments.created_at', 'desc');
$this->db->where('comments.submittedby_id', 'users.user_id');
$this->db->where('comments.section_id', 'sections.id');
$query = $this->db->get(array('comments', 'users', 'sections'),10);
Produce SQL Request:
SELECT pdb_comments.created_at,
pdb_comments.section_id,
pdb_comments.submittedby_id,
pdb_users.username,
pdb_comments.text,
pdb_sections.name FROM
(pdb_comments, pdb_users,
pdb_sections) WHERE
pdb_comments.submittedby_id =
'users.user_id' AND
pdb_comments.section_id =
'sections.id' ORDER BY
pdb_comments.created_at desc LIMIT
10
The issue is that the database prefix (pdb_) does not get added in the WHERE clause. I can manually insert the prefix by appending $this->db->dbprefix, but this doesn't fix the main problem.
Quotes:
`pdb_comments`.`submittedby_id` = 'pdb_users.user_id'
The quotes on the right side are not accurate, and generate 0 results for me. Is there any way to make CodeIgniter recognize the second half of the where clause as a piece of my table; thereby adding the database prefix, and properly placing the quotes by avoiding two joins? Is there another way to do this? Thanks in advance.
--
Jon
Use:
$this->db->select('comments.created_at, comments.section_id, comments.submittedby_id, users.username, comments.text, sections.name');
$this->db->from('comments');
$this->db->join('users', 'comments.submittedby_id=users.user_id');
$this->db->join('sections', 'comments.section_id=sections.id');
$this->db->order_by('comments.created_at', 'desc');
$query = $this->db->get();
instead.
Possibly a dumb question, but why don't you just write the SQL directly? The interface doesn't look like it's giving you anything but clutter.
Related
I'm unsure what whereRaw is in PHP Laravel framework. Could you provide good and easily understandable example, please?
WhereRaw() is a function of Laravel query builder which puts your input as it is in the SQL query's where clause.
Think of it as the where() function whose input argument will not be processed before inserting into queries.
See the example below:
$Query = DB::table('some_table')->where('YEAR(date)', 'YEAR(CURRENT_DATE)');
In this Laravel will resolve your arguments to build a query. Which will result in the following query because your input will be treated as some field and its its value :
SELECT * FROM `some_table` WHERE `YEAR(date)` = `YEAR(CURRENT_DATE)`
Which is not desired.
And now if you use whereRaw like:
$Query = DB::table('some_table')->whereRaw('YEAR(date) = YEAR(CURRENT_DATE)');
Now Laravel put this where clause as it is in your query, like below:
SELECT * FROM `some_table` WHERE YEAR(date) = YEAR(CURRENT_DATE)
Hope it helped (:
WhereRaw: Sometimes you may need to use a raw expression in a query. These expressions will be injected into the query as strings.
If you are unable to generate the query you need via the fluent interface, feel free to use whereRaw()
Ex:
$users = User::whereRaw('age > ? and votes = 100', array(25))->get();
which is equals to:
"SELECT * FROM users WHERE age > 25 AND votes = 100";
Reference
In laraval we use query builder. But Sometime you need to execute raw sql query.
So you can inject it to whereRaw as this example :
whereRAW('YEAR(event_datetime) =?', [$year])
Here is my join query for getting data from two tables.
$this->db->select('*');
$this->db->from('george_hotel_bkd_customers');
$this->db->where('george_hotel_bookings.bookingref',$ref);
$this->db->join('george_hotel_bookings', 'george_hotel_bookings.user_id = george_hotel_bkd_customers.user_id');
$query = $this->db->get();
According to my where condition it returns only one row but it will returns all the rows with matches the join condition.
Seems like my where condition is not executed here.
please help me
What does $ref =, how many results should it pick up roughly?
what do you get when you omit the where? if you get full result then must be an issue with $ref value, or, that is the result.
Just a note, you don't need to select(*), this is default, if this is an just for examples sake, sorry for picking up. You can also add the ->from(whaterver_table) to ->get(whatever_table) You need to add ->get() anyway, so why not remove the ->from() line, just a choice of readability, but i did not realise you could do this for a while, so thought id add it to my answer.
Or another problem solving path is whether the join should be 'left' as 3rd arg. IE is there always a join?
Altering the position or the join in the statement would not make any difference, as Anant suggested
$this->db->select('*');
$this->db->from('george_hotel_bkd_customers');
$this->db->join('george_hotel_bookings', 'george_hotel_bookings.user_id = george_hotel_bkd_customers.user_id');
$this->db->where('george_hotel_bookings.bookingref',$ref);
$query = $this->db->get();
always where is last
I'm trying to get mysql query into Code Igniter's Active Record syntax but am having a bit of a hard time.
The query is as a result of this question: Multiple mysql ORDER BY's for multidimensional ordering/grouping
I've attempted to format the query myself, have tackled a couple of errors, but am unsure how to progress. I had to add in the get_compiled_select() function to DB_active_rec.php myself and change the _reset_select() from protected to public to get it to run at all.
The suggested query is:
select
t.id,
t.group,
t.date,
t.comlete
from
YourTable t
left join
(select
m.group,
min(m.date) as mindate,
min(t.complete) as groupcomplete
from
YourTable m) mt on mt.group = t.group
order by
coalesce(mt.groupcomplete, t.complete),
coalesce(mt.mindate, t.date),
t.group,
t.complete,
t.date
My translation looks like this (note that there's a 'where' clause not in the original, and that 'date' is actually 'due'):
// Sub query
$this->db->select('m.group, min(m.due) as mindate, min(t.complete) as groupcomplete');
$this->db->from('task m');
$this->db->where('property', $property);
$subquery = $this->db->get_compiled_select();
$this->db->_reset_select();
// Main query
$this->db->select('*');
$this->db->where('property', $property);
$this->db->from('task t');
$this->db->join('($subquery) mt','mt.group = t.group');
$this->db->order_by('coalesce(mt.groupcomplete, t.complete)');
$this->db->order_by('coalesce(mt.mindate, t.due)');
$this->db->order_by('t.group');
$this->db->order_by('t.complete');
$this->db->order_by('t.due');
$query = $this -> db -> get();
// Return
return $query->result();
Unfortunately this is just throwing an error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'mt ON `mt`.`group` = `t`.`group` WHERE `property` = '7' ORDER BY coalesce(mt.gr' at line 3
The query as reported by CI looks like:
SELECT * FROM (`task` t) JOIN ($subquery) mt ON `mt`.`group` = `t`.`group` WHERE `property` = '7' ORDER BY coalesce(mt.groupcomplete, `t`.`complete)`, coalesce(mt.mindate, `t`.`date)`, `t`.`due`, `t`.`complete`, `t`.`date`
Anyone able to lend some advice as to how to get this formatted correctly? My mysql skills are, unfortunately, pretty bare, so this is pushing my abilities. Much of the approach of my translation is from answers on Stack Overflow, as I have no experience combining queries in this way (with the subquery).
The problem (or 'one of the problems') is here:
$this->db->join('($subquery) mt','mt.group = t.group');
You use single quotes, so the variable $subquery doesn't get expanded.
This can also be seen in the query that is outputted by CodeIgniter.
When you have multiple order by statements u separate them by comma like this
$this->db->order_by('coalesce(mt.groupcomplete, t.complete), coalesce(mt.mindate, t.date), t.due, t.complete, t.date');
Probably quite a simple one, but I'm not having any luck in the docs or searches.
I'm trying to add an order by clause to just one of my ActiveRecord queries as follows:
$result = $this->db->get('mytable');
$this->db->order_by('age', 'ASC');
It works, however I get errors because the order by clause is being applied to all my other queries and I get errors because my age column is not present in all tables.
So how do it limit $this->db->order_by('age', 'ASC') to just that one specific query?
Thanks.
You should have $this->db->order_by(); before $result = $this->db->get('mytable');
It should be in this format
$this->db->where("tablename.column", $task_id);
$this->db->order_by('tablename.column', 'ASC'); // or 'DESC'
$this->db->from('table');
I have a controller action that uses a sql query:
$tag = $this->params['tag'];
$this->set('projects', $this->Project->query('SELECT * FROM projects INNER JOIN projects_tags ON projects.id = projects_tags.project_id INNER JOIN tags on projects_tags.tag_id = tags.id WHERE tags.tag LIKE $tag'));
As you can see at the end I want to use a where clause with the $tag variable but I'm not sure how the syntax would go. As I'm getting the error
Unknown column '$tag' in 'where clause'
Can someone steer me in the right direction?
Ta,
Jonesy
I would strongly advise you to use the Cake ORM instead of raw queries, especially if you're going to plug URL parameters into it. Conditions on HABTM tables can be tricky, but you can build your joins using Cake's ORM syntax as well!
Read the manual, section 3.7.6.9 Joining tables.
Should you want to use Cake's ORM, the following code should provide results equivalent to your raw SQL query:
$this->loadModel('ProjectsTag'); // Load the joining table as pseudo-model
// Define temporary belongsTo relationships between the pseudo-model and the two real models
$this->ProjectsTag->bindModel(array(
'belongsTo' => array('Project','Tag')
));
// Retrieve all the join-table records with matching Tag.tag values
$result_set = $this->ProjectsTag->find('all',array(
'conditions' => array('Tag.tag LIKE' => "%{$tag}%")
));
// Extract the associated Project records from the result-set
$projects = Set::extract('/Project', $result_set);
// Make the set of Project records available to the view
$this->set(compact('projects'));
in php there's a difference between single and double quotes... basically, single quotes dont evaluate the variables... use double quotes instead
And i think that LIKE will need also single quotes.. i'm not really sure
"SELECT * FROM projects INNER JOIN projects_tags ON projects.id = projects_tags.project_id INNER JOIN tags on projects_tags.tag_id = tags.id WHERE tags.tag LIKE '$tag'"
i know.. i know.. people will start talkin' about sql injection.. and the need to scape the caracters... that's another question =)
good luck!
I would at least consider using the cakephp sanitize functions on your tag strings if they are user sourced. See http://book.cakephp.org/view/1183/Data-Sanitization or if using mysql as the db at least consider using http://www.php.net/manual/en/function.mysql-escape-string.php or do something to filter your user input. But the best thing is to make use of the CakePHP orm stuff.
Modify your query as:
$this->set('projects',
$this->Project->query("SELECT * FROM projects
INNER JOIN projects_tags
ON projects.id = projects_tags.project_id
INNER JOIN tags ON projects_tags.tag_id = tags.id
WHERE tags.tag LIKE '" . $tag . "'") //problem was here
);
and it will work.