I am wanting to find out the time difference in minutes between two dates which is in the format d-m-Y H:i (14-04-2009 12:15) using php?
Parse the times into timestamps using strtotime() and then simply subtract one from the other.
After that you can get the number of minutes, days and so on by using math functions.
For example:
// $date1 and $date2 are given
// the difference is in seconds
$difference = strtotime($date1) - strtotime($date2);
// getting the difference in minutes
$difference_in_minutes = $difference / 60;
Reference: strtotime()
date_default_timezone_set('Asia/Kolkata');
$currentDateTime = date('m/d/Y H:i:s');
$model_current_time = date('Y-m-d H:i:s',
strtotime($currentDateTime));
echo $model_current_time."------";
$date = DateTime::createFromFormat('d/m/Y h:i:s A',
$row['model_creation_time']);//get from resouses
$new_date_format = $date->format('m/d/Y H:i:s');
$model_creation_time = date('Y-m-d H:i:s',
strtotime($new_date_format));
echo $model_creation_time;
$datetime1 = new DateTime($model_current_time);
$datetime2 = new DateTime($model_creation_time);
$interval = $datetime1->diff($datetime2);
echo $interval->d;
echo $interval->h;
echo $interval->s;
Related
I have the following code:
$now = date("Y-m-d H:m:s");
$date = date("Y-m-d H:m:s", strtotime('-24 hours', $now));
However, now it gives me this error:
A non well formed numeric value encountered in...
why is this?
$date = (new \DateTime())->modify('-24 hours');
or
$date = (new \DateTime())->modify('-1 day');
(The latter takes into account this comment as it is a valid point.)
Should work fine for you here. See http://PHP.net/datetime
$date will be an instance of DateTime, a real DateTime object.
strtotime() expects a unix timestamp (which is number seconds since Jan 01 1970)
$date = date("Y-m-d H:i:s", strtotime('-24 hours', time())); ////time() is default so you do not need to specify.
i would suggest using the datetime library though, since it's a more object oriented approach.
$date = new DateTime(); //date & time of right now. (Like time())
$date->sub(new DateInterval('P1D')); //subtract period of 1 day
The advantage of this is that you can reuse the DateInterval:
$date = new DateTime(); //date & time of right now. (Like time())
$oneDayPeriod = new DateInterval('P1D'); //period of 1 day
$date->sub($oneDayPeriod);
$date->sub($oneDayPeriod); //2 days are subtracted.
$date2 = new DateTime();
$date2->sub($oneDayPeriod); //can use the same period, multiple times.
Carbon (update 2020)
Most popular library for processing DateTimes in PHP is Carbon.
Here you would simply do:
$yesterday = Carbon::now()->subDay();
you can do this in many ways...
echo date('Y-m-d H:i:s',strtotime('-24 hours')); // "i" for minutes with leading zeros
OR
echo date('Y-m-d H:i:s',strtotime('last day')); // 24 hours (1 day)
Output
2013-07-17 10:07:29
Simplest way to sub or add time,
<?php
**#Subtract 24 hours**
$dtSub = new DateTime('- 24 hours');
var_dump($dtSub->format('Y-m-d H:m:s'));
**#Add 24 hours**
$dtAdd = new DateTime('24 hours');
var_dump($dtAdd->format('Y-m-d H:m:s'));die;
?>
This may be helpful for you:
//calculate like this
$date = date("Y-m-d H:m:s", (time()-(60*60*24)));
//check the date
echo $date;
this should work, too
$date = date("Y-m-d H:m:s", strtotime('-24 hours'));
$now = date("Y-m-d H:i:s");
$date = date("Y-m-d H:i:s", strtotime('-24 hours', strtotime($now)));
Add "strtotime" before $now,
and Y-m-d H:m:s replace with Y-m-d H:i:s
You can simply use time() to get the current timestamp.
$date = date("Y-m-d H:m:s", strtotime('-24 hours', time()));
In same code use strtotime() its working.
$now = date("Y-m-d H:i:s");
$date = date("Y-m-d H:i:s", strtotime('-2 hours', strtotime($now)));
Try this :
$now = time();
$date = date("Y-m-d H:m:s", strtotime('-24 hours', $now));
all you have to do is to alter your code to be
$now = strtotime(date("Y-m-d H:m:s"));
$date = date("Y-m-d H:m:s", strtotime('-24 hours', $now));
I need to be able to find out the difference between two unix epoch times.
I am trying this at the moment
$interval = $nextFile-$firstFile;
($nextFile would equal "1452182820", $firstFile would equal "1452004380")
This gets me a result of "178440".
Is taking away two epoch date times away from each other valid? Or should i find the difference another way.
Try This May be help ful
<?php
$nextFile = '1452182820';
$firstFile = '1452004380';
$n = date('d-m-Y H:i:s',$nextFile);
$f = date('d-m-Y H:i:s',$firstFile);
$Date1 = date("Y-m-d", strtotime($n));
$Date2 = date("Y-m-d", strtotime($f));
$datetime1 = new DateTime($Date1);
$datetime2 = new DateTime($Date2);
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
I have the following code:
$now = date("Y-m-d H:m:s");
$date = date("Y-m-d H:m:s", strtotime('-24 hours', $now));
However, now it gives me this error:
A non well formed numeric value encountered in...
why is this?
$date = (new \DateTime())->modify('-24 hours');
or
$date = (new \DateTime())->modify('-1 day');
(The latter takes into account this comment as it is a valid point.)
Should work fine for you here. See http://PHP.net/datetime
$date will be an instance of DateTime, a real DateTime object.
strtotime() expects a unix timestamp (which is number seconds since Jan 01 1970)
$date = date("Y-m-d H:i:s", strtotime('-24 hours', time())); ////time() is default so you do not need to specify.
i would suggest using the datetime library though, since it's a more object oriented approach.
$date = new DateTime(); //date & time of right now. (Like time())
$date->sub(new DateInterval('P1D')); //subtract period of 1 day
The advantage of this is that you can reuse the DateInterval:
$date = new DateTime(); //date & time of right now. (Like time())
$oneDayPeriod = new DateInterval('P1D'); //period of 1 day
$date->sub($oneDayPeriod);
$date->sub($oneDayPeriod); //2 days are subtracted.
$date2 = new DateTime();
$date2->sub($oneDayPeriod); //can use the same period, multiple times.
Carbon (update 2020)
Most popular library for processing DateTimes in PHP is Carbon.
Here you would simply do:
$yesterday = Carbon::now()->subDay();
you can do this in many ways...
echo date('Y-m-d H:i:s',strtotime('-24 hours')); // "i" for minutes with leading zeros
OR
echo date('Y-m-d H:i:s',strtotime('last day')); // 24 hours (1 day)
Output
2013-07-17 10:07:29
Simplest way to sub or add time,
<?php
**#Subtract 24 hours**
$dtSub = new DateTime('- 24 hours');
var_dump($dtSub->format('Y-m-d H:m:s'));
**#Add 24 hours**
$dtAdd = new DateTime('24 hours');
var_dump($dtAdd->format('Y-m-d H:m:s'));die;
?>
This may be helpful for you:
//calculate like this
$date = date("Y-m-d H:m:s", (time()-(60*60*24)));
//check the date
echo $date;
this should work, too
$date = date("Y-m-d H:m:s", strtotime('-24 hours'));
$now = date("Y-m-d H:i:s");
$date = date("Y-m-d H:i:s", strtotime('-24 hours', strtotime($now)));
Add "strtotime" before $now,
and Y-m-d H:m:s replace with Y-m-d H:i:s
You can simply use time() to get the current timestamp.
$date = date("Y-m-d H:m:s", strtotime('-24 hours', time()));
In same code use strtotime() its working.
$now = date("Y-m-d H:i:s");
$date = date("Y-m-d H:i:s", strtotime('-2 hours', strtotime($now)));
Try this :
$now = time();
$date = date("Y-m-d H:m:s", strtotime('-24 hours', $now));
all you have to do is to alter your code to be
$now = strtotime(date("Y-m-d H:m:s"));
$date = date("Y-m-d H:m:s", strtotime('-24 hours', $now));
I want to add 5 minutes to this date: 2011-04-8 08:29:49
$date = '2011-04-8 08:29:49';
When I use strtotime I am always getting 1970-01-01 08:33:31
How do I add correctly 5 minutes to 2011-04-8 08:29:49?
$date = '2011-04-8 08:29:49';
$currentDate = strtotime($date);
$futureDate = $currentDate+(60*5);
$formatDate = date("Y-m-d H:i:s", $futureDate);
Now, the result is 2011-04-08 08:34:49 and is stored inside $formatDate
Enjoy! :)
Try this:
echo date('Y-m-d H:i:s', strtotime('+5 minutes', strtotime('2011-04-8 08:29:49')));
$expire_stamp = date('Y-m-d H:i:s', strtotime("+5 min"));
$now_stamp = date("Y-m-d H:i:s");
echo "Right now: " . $now_stamp;
echo "5 minutes from right now: " . $expire_stamp;
Results in:
2012-09-30 09:00:03
2012-09-30 09:05:03
$date = '2011-04-8 08:29:49';
$newDate = date("Y-m-d H:i:s",strtotime($date." +5 minutes"))
For adding
$date = new DateTime('2014-02-20 14:20:00');
$date->add(new DateInterval('P0DT0H5M0S'));
echo $date->format('Y-m-d H:i:s');
It add 5minutes
For subtracting
$date = new DateTime('2014-02-20 14:20:00');
$date->sub(new DateInterval('P0DT0H5M0S'));
echo $date->format('Y-m-d H:i:s');
It subtract 5 minutes
If i'm right in thinking.
If you convert your date to a unix timestamp via strtotime(), then just add 300 (5min * 60 seconds) to that number.
$timestamp = strtotime($date) + (5*60)
Hope this helps
more illustrative for simple and clear solution
$date = '2011-04-8 08:29:49';
$newtimestamp = strtotime($date. ' + 5 minute');//gets timestamp
//convert into whichever format you need
$newdate = date('Y-m-d H:i:s', $newtimestamp);//it prints 2011-04-08 08:34:49
In certain situations I want to add 1 day to the value of my DATETIME formatted variable:
$start_date = date('Y-m-d H:i:s', strtotime("{$_GET['start_hours']}:{$_GET['start_minutes']} {$_GET['start_ampm']}"));
What is the best way to do this?
There's more then one way to do this with DateTime which was introduced in PHP 5.2. Unlike using strtotime() this will account for daylight savings time and leap year.
$datetime = new DateTime('2013-01-29');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.3
$datetime = new DateTime('2013-01-29');
$datetime->add(new DateInterval('P1D'));
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.4
echo (new DateTime('2013-01-29'))->add(new DateInterval('P1D'))->format('Y-m-d H:i:s');
// Available in PHP 5.5
$start = new DateTimeImmutable('2013-01-29');
$datetime = $start->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
If you want to do this in PHP:
// replace time() with the time stamp you want to add one day to
$startDate = time();
date('Y-m-d H:i:s', strtotime('+1 day', $startDate));
If you want to add the date in MySQL:
-- replace CURRENT_DATE with the date you want to add one day to
SELECT DATE_ADD(CURRENT_DATE, INTERVAL 1 DAY);
The DateTime constructor takes a parameter string time. $time can be different things, it has to respect the datetime format.
There are some valid values as examples :
'now' (the default value)
2017-10-19
2017-10-19 11:59:59
2017-10-19 +1day
So, in your case you can use the following.
$dt = new \DateTime('now +1 day'); //Tomorrow
$dt = new \DateTime('2016-01-01 +1 day'); //2016-01-02
Use strtotime to convert the string to a time stamp
Add a day to it (eg: by adding 86400 seconds (24 * 60 * 60))
eg:
$time = strtotime($myInput);
$newTime = $time + 86400;
If it's only adding 1 day, then using strtotime again is probably overkill.
You can use
$now = new DateTime();
$date = $now->modify('+1 day')->format('Y-m-d H:i:s');
You can use as following.
$start_date = date('Y-m-d H:i:s');
$end_date = date("Y-m-d 23:59:59", strtotime('+3 days', strtotime($start_date)));
You can also set days as constant and use like below.
if (!defined('ADD_DAYS')) define('ADD_DAYS','+3 days');
$end_date = date("Y-m-d 23:59:59", strtotime(ADD_DAYS, strtotime($start_date)));
I suggest start using Zend_Date classes from Zend Framework. I know, its a bit offtopic, but I'll like this way :-)
$date = new Zend_Date();
$date->add('24:00:00', Zend_Date::TIMES);
print $date->get();
Using server request time to Add days. Working as expected.
25/08/19 => 27/09/19
$timestamp = $_SERVER['REQUEST_TIME'];
$dateNow = date('d/m/y', $timestamp);
$newDate = date('d/m/y', strtotime('+2 day', $timestamp));
Here '+2 days' to add any number of days.
One liner !
echo (new \DateTime('2016-01-01 +1 day'))->format('Y-m-d H:i:s');