I have a PHP page(registration.php) from where i would submit a file to another form(preocess.php) .So that in the next page that page will send that file as an attachment to an email id. Can i Call a function in another file and pass this file to that function ?
It is some think like passing a stream to a function. (I am not sure .) Can anyone guide me on this ?
Absolutely, just include the file that originally calls the function.
<?php include ('file_with_function.php'); ?>
Should not pass a file around, better to handle it in the background.
store the file
put some id (in worst case the path) into session
forward the user to the next step (process.php)
Better yet to review and refactor the code if necessary to make the processing in one step.
This way you can avoid half-processed things, entry to the processing pipeline in the middle and similar common multi-page form handling problems.
If you're trying to email the file to someone, PHPMailer (http://phpmailer.codeworxtech.com/index.php?pg=methods) has a function addAttachment that works really well.
If you're just trying to process the file in some way, file_get_contents will get the content of the file as a string, which can be useful if it's text. You do, however, need to be careful that it's a small file, otherwise you'll run out of memory pretty quickly.
Related
I am new to PHP and very likely I am using the incorrect approach because I am not used to think like a PHP programmer.
I have some files that include other files as dependencies, these files need to have global code that will be executed if $_POST contains certain values, something like this
if (isset($_POST["SomeValue"]))
{
/* code goes here */
}
All the files will contain this code section, each one it's own code of course.
The problem is that since the files can be included in another one of these files, then the code section I describe is executed in every included file, even when I post trhough AJAX and explicitly use the URL of the script I want to POST to.
I tried using the $_SERVER array to try and guess which script was used for the post request, and even though it worked because it was the right script, it was the same script for every included file.
Question is:
Is there a way to know if the file was included into another file so I can test for that and skip the code that only execute if $_POST contains the required values?
Note: The files are generated using a python script which itself uses a c library that scans a database for it's tables and constraints, the c library is mine as well as the python script, they work very well and if there is a fix for a single file, obviously it only needs to be performed to the python script.
I tell the reader (potential answerer) about this because I think it makes it clear that I don't need a solution that works over the already existant files, because they can be re-generated.
From the sounds of it you could make some improvements on your code structure to completely avoid this problem. However, with the information given a simple flag variable should do the trick:
if (!isset($postCodeExecuted) && isset($_POST["SomeValue"]))
{
/* code goes here */
$postCodeExecuted = true;
}
This variable will be set in the global namespace and therefore it will be available from everywhere.
I solved the problem by doing this
$caller = str_replace($_SERVER["DOCUMENT_ROOT"], "", __FILE__);
if ($_SERVER["REQUEST_METHOD"] === "POST" and $caller === $_SERVER["PHP_SELF"])
performThisAction();
I have managed to write a small, compilable extension for php, that prints "test" on every ZEND_RINIT.
I tested it with an php-file that loads multiple other files, which again load others [...]. The problem is, that the extension just prints "test" once, so I assume it does not fire each time a new file is loaded, how can i get my extension to do so?
Also the event is fired before the file is loaded, that is what i want, but therefore zend_get_executed_filename() is empty and I am not able to get the file content...
My final goal is to validate each file before executing the script. I planned on doing so by validating a file signature that is appended to the file.
Pseudocode Validation:
decrypt(signature, rsa.pub) = sha(filecontent)
Pseudocode Signing:
signature = encrypt(sha(filecontent), rsa.priv)
file += signature
Or is there an even better way to validate the files (i want them to be signed) before executing the script in them?
Thanks in advance!
ZEND_RINIT is called on request startup, that is when you execute your php-file. It will never be called again during execution of your PHP file. Only on next startup.
You have to find a way to hook into all of the file load functions of PHP.
Is it possible to load a php file as text with jquery?
$('#loader').load('somefile.php', function(e){
console.log(e);
});
This always interprets/execute the php file but I'm looking for a way to only load it as text, without to resort to renaming my php file as .txt
Is it possible?
Cheers
It is not possible without making any server side modification. The web server will always interpret the php file and return the output. However does not matter what solution you find it'll be very dangereous since you'll be dumping content of your php file to public.
Possible solutions with server side modifications:
Create a PHP file that dumps the content of a file, which name is specified by a url argument
Rename the file (I know the op does not want this, just included since it's an option)
As #nicholas-young suggested, get rid of the PHP tags.
I'm not sure why you need this type of need but I want to emphasize that this might not be a good idea in most of the cases since you'll be make a working PHP file available to public. If you can explain more why you need this we might offer better solutions.
Update:
Create a dumper.php that requires authorization and call this file from the javascript side with passing the filename that you want to be dumped as a parameter (dumper.php?file=index.php)
echo file_get_contents($_GET['file']);
It is of course not possibile.
.load will make an HTTP request to yourwebsite.com/somefile.php hence you will obtain the result of your script not the PHP code inside it.
If you really need the raw code inside your javascript as a string you should output it from the php itself:
<script>
var yourCode = <?=json_encode(file_get_contents('somefile.php')) ?>;
</script>
NO! Would be a major security problem if possible. The header will not matter. If making request towards php file, it will execute prior to delivery.
Use some parameter to print out contents from file instead. But do it in the file itself.
From what I understand using something like require_once will essentially copy and paste the code from one file into another, as if it was in the first file originally.
Meaning if I was to do something like this it would be valid
foo.php
<?php
require_once("bar.php");
?>
bar.php
<?php
print "Hello World!"
?>
running php foo.php will just output "Hello World!"
Now my question is, if I include require_once inside a method, will the file that is included be loaded when the script is loaded, or only when the method is called?.
And if it is only when the method is called, is there any benefit performance wise. Or would it be the same as if I had kept all the code into one big file.
I'm mainly asking as I've created an API file, which handles a large amount of calls, and I wan't to simplify the file. (I know I can do this just be creating separate classes, but I thought this would be good to know)
(Sorry if this has already been asked, I wasn't sure what to search for)
It will only include when the method is called, but have you looked at autoloading?
1) Only when the method is called.
2) I would imagine there's an intangible benefit to loading on the fly so the PHP interpreter doesn't have to parse extra code if it's not being used.
I usually use the include('bar.php'); i use it for when i use databvase information, i have a file called database.php with login info and when the file loads it calls it right up. I don't need to call up the function. It may not be the most effective and efficient but it works for me. You can also use include_once... include basically does what you want it to, it copies the code essencially..
As others have mentioned, yes, it's included just-in-time.
However, watch out for variable definitions (require()ing from a method will only allow access to local variables in that method's scope).
Keep in mind you can also return values (i.e. strings) from the included file, as well as buffer output with ob_start() etc.
So I've got all of this really neato PHP code and I've started doing some reuse with functions out of necessity. I'm debugging, trying to figure out why I can't delete comments on my website while I'm deleting folder (because who wants orphaned comments?)
So I have a call to deletefolder( $parent) inside a file called deletefolder.php. This a function that will recursively traverse my tree structure.
I've include another file inside deletefolder.php. The file is call helpers.php, and it contains the deletefolder function.
The deletefolder function calls deletecomments (kills all the comments per file) and delete file (which kills the file itself).
Now, all of it is just slathered with echo statements to help me figure out what's going on. When I call this combination of functions from other locations I don't seem to have a problem getting messages. But when I call them from the deletefolder.php page I don't get any. Does anybody know why this would be the case?
A few things you might want to verify.
Check the source of the output. You might be echoing straight in a middle of a HTML comment or a tag which is hiding the output.
Are you using output buffering (ob_start()) ? You might be clearing the buffer at some point in your code and forgot all about it.
Different files with the same name but not in the same directory. Do a die() in your function to make sure it actually reaches your code. You might be editing/including a copy of your file (happened to me quite a few times).
Well, I seriously doubt you've found a bug in the echo command, so the problem is with your program logic somewhere. Without seeing your code, it's impossible to say really. Perhaps there's some variable being set or unset unexpectedly, or you're not actually include()ing the files properly.