For some reason this does not work. I have copy/paste the code, but it goes to the html-echo.php rather than displaying the result in the htmlExampleTarget
What am I doing wrong here.
Thanks
Dave
edit: sorry guys - here is the url - http://jquery.malsup.com/form/#html
<script src="js/jquery-1.3.2.js" type="text/javascript" language="javascript"></script>
<script type="text/javascript">
// prepare the form when the DOM is ready
$(document).ready(function() {
// bind form using ajaxForm
$('#htmlForm').ajaxForm({
// target identifies the element(s) to update with the server response
target: '#htmlExampleTarget',
// success identifies the function to invoke when the server response
// has been received; here we apply a fade-in effect to the new content
success: function() {
$('#htmlExampleTarget').fadeIn('slow');
}
});
});
</script>
<div style="position:absolute; top:129px; left: 400px; width:500px; border:#000000 thin solid;">
<form id="htmlForm" action="submit_form.php" method="post">
Message: <input type="text" name="message" value="Hello HTML" />
<input type="submit" value="Echo as HTML" />
</form>
Reply: <div id="htmlExampleTarget"></div>
</div>
and on the submit-form.php page
echo '<div style="background-color:#ffa; padding:20px">' . $_POST['message'] . '</div>';
You have two <script> elements. One of them loads jQuery, the other runs ajaxForm. You haven't loaded the .js file that contains the ajaxForm code.
See the documentation:
Include jQuery and the Form Plugin external script files and a short script to initialize the form
Since you haven't, the script errors when trying to run the function, so it doesn't prevent the default action. The code to make the Ajax request is missing (so that doesn't happen), and the default action runs (for the browser goes to the URI in the action attribute).
Related
I don't know how to explain this, but I will do my best...
I am trying to submit a form normally, but the request result will be displayed at a iframe. Everything goes fine to here. What I want to do (if it is possible) is to animate the form putting a message into it (like "sending...") ultil the iframe is load with the respose. I now this is so confuse, but take a look to my files:
index.php
I have ommited the header because is so obvius.
<form enctype="multipart/form-data" method="post" action="upload.php" target="my_iframe" id="form-upload">
Choose your file here:
<input name="uploaded_file" type="file"/>
<input id="send-button" type="submit" value="Subir imagen"/>
</form>
<IFRAME name="my_iframe" SRC="upload.php" width="100%" height="200px" id="iframe1" marginheight="0" frameborder="0"></iframe>
<script type="text/javascript">
$(document).ready(function(){
$('#send-button').sendImage({formid: "form-upload"});
});
</script>
upload.php
Just for testing porpuses.
<?php
if( isset($_FILES['uploaded_file']) )
echo "image sent";
animate.js
This is where I am dealing with that. Because when I access the index.php always the message sending... is showed instance of the form elements.
var conf;
jQuery.fn.sendImage = function(args) {
conf = $.extend( {
}, args);
this.on('click', function(e){
e.preventDefault();
$('#'+conf.formid).submit();
$('#'+conf.formid).html('sending...');
});
}
Once a form is submitted, all processing on the current page stops. Anything you do must be BEFORE you actually submit the form. You alternative is to submit via AJAX.
this a simple example in how to submit form using the Jquery form plugins and retrieving data using html format
html Code
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
// prepare the form when the DOM is ready
$(document).ready(function() {
// bind form using ajaxForm
$('#htmlForm').ajaxForm({
// target identifies the element(s) to update with the server response
target: '#htmlExampleTarget',
// success identifies the function to invoke when the server response
// has been received; here we apply a fade-in effect to the new content
success: function() {
$('#htmlExampleTarget').fadeIn('slow');
}
});
});
</script>
</head>
<body>
<form id="htmlForm" action="post.php" method="post">
Message: <input type="text" name="message" value="Hello HTML" />
<input type="submit" value="Echo as HTML" />
</form>
<div id="htmlExampleTarget"></div>
</body>
</html>
PHP Code
<?php
echo '<div style="background-color:#ffa; padding:20px">' . $_POST['message'] . '</div>';
?>
this just work fine
what i need to know if what if i need to Serialize the form fields so how to pass this option through the JS function
also i want show a loading message while form processed
how should i do that too
thank you
To serailize and post that to a php page, you need only jQuery in your page. no other plugin needed
$("#htmlForm").submit(function(){
var serializedData= $("#htmlForm").serialize();
$.post("post.php", { dat: serializedData}, function(data) {
//do whatever with the response here
});
});
If you want to show a loading message, you can do that before you start the post call.
Assuming you have div with id "divProgress" present in your page
HTML
<div id="divProgress" style="display:none;"></div>
Script
$(function(){
$("#htmlForm").submit(function(){
$("#divProgress").html("Please wait...").fadeIn(400,function(){
var serializedData= $("#htmlForm").serialize();
$.post("post.php", { dat: serializedData},function(data) {
//do whatever with the response here
});
});
});
});
The answer posted by Shyju should work just fine. I think the 'dat' should be given in quotes.
$.post("post.php", { 'dat': serializedData},function(data) {
...
}
OR simply,
$.post("post.php", serializedData, function(data) {
...
}
and access the data using $_POST in PHP.
NOTE: Sorry, I have not tested the code, but it should work.
Phery library does this behind the scenes for you, just create the form with and it will submit your inputs in form automatically. http://phery-php-ajax.net/
<?php
Phery::instance()->set(array(
'remote-function' => function($data){
return PheryResponse::factory('#htmlExampleTarget')->fadeIn('slow');
}
))->process();
?>
<?php echo Phery::form_for('remote-function', 'post.php', array('id' => ''); ?> //outputs <form data-remote="remote-function">
Message: <input type="text" name="message" value="Hello HTML" />
<input type="submit" value="Echo as HTML" />
</form>
<div id="htmlExampleTarget"></div>
</body>
</html>
I'm developing a plugin in Wordpress and am having difficulty trying to post data to a separate PHP file using Ajax without reloading the page. On the backend, the PHP file is relying on if( isset() ) to execute an SQL query. On the client side, the user should see individual records fadeOut and a message that records were successfully deleted.
UPDATE: The javascript is working so far, once the form button is clicked, the correct div-s fade in and fade out. However, the PHP file is not getting any value posted to it, as tested with a var_dump.
HTML Code:
<!-- problem: when setting "action" to a url, that page is automatically loaded. I want to stay on the existing page. -->
<form action='' id='form-delete-assoc' method='post'>
<input name='remove_all' type='submit' id='remove-all' value='Remove All'></input>
</form>
JQUERY: (updated with some fixes suggested by answerers)
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('tr.assoc_row').show();
$('#settings-removed-msg').hide();
$('#new-assoc-msg').hide();
$('#formdeleteassoc').submit(function(e){
e.preventDefault();
$.ajax ({
type: 'POST',
url: '<?php echo $cb_t2c_remove_all_url; ?>',
data: {removeall: 'yes'
},
success: function() {
$('#settings-removed-msg').fadeIn('fast');
$('tr.assoc_row').fadeOut('fast');
}
});
});
$('#formsavesettings').submit(function(){
$('#new-assoc-msg').fadeIn('fast');
});
});
</script>
remove_all.php:
<?php
//remove_all.php
global $wpdb;
$prefix = $wpdb->prefix;
$remove_var_dump = $_POST['removeall']; //returning NULL
var_dump($remove_var_dump);
if ( isset( $_POST['removeall'] ) ){
$wpdb->query("DELETE FROM ".$prefix."cb_tags2cats");
}
?>
Like the others said, you need to either return false or use preventDefault(). You should also move your calls to fadeOut and fadeIn into the success callback. If you don't and the request is unsuccessful for some reason, the user may be misled into thinking it was successful.
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('tr.assoc_row').show();
$('#settings-removed-msg').hide();
$('#form-delete-assoc').submit(function(e){
// prevent the form from submitting normally
e.preventDefault();
$.ajax ({
type: 'POST',
url: '/delete-assoc.php', // Relative paths work fine
data: { removeall: 'delete-all' },
success: function(){
$('tr.assoc_row').fadeOut('slow');
$('#settings-removed-msg').fadeIn('slow');
}
});
});
});
</script>
Your form submit event needs to return false, to stop the form from actually submitting.
$('#form-delete-assoc').submit(function(){
... rest of your code here...
return false;
}
to post data to a separate php page without reloading current (parent or top) page, create a hidden iFrame and use it as the submit target. this type of solution allows posting and retrieving json responses. this snippet uploads a file to a php page.
<script type="text/javascript">
function init() {
document.getElementById('file_upload_form').onsubmit=function() {
document.getElementById('file_upload_form').target = 'upload_target'; //'upload_target' is the name of the iframe
}
}
window.onload=init;
</script>
</head><body>
<form id="file_upload_form" method="post" enctype="multipart/form-data" action="upload.php">
<input name="file" id="file" size="27" type="file" /><br />
<input type="submit" name="action" value="Upload" /><br />
<iframe id="upload_target" name="upload_target" src="" style="width:0;height:0;border:0px solid #fff;"></iframe>
</form>
this tutorial explains the process step by step ->
http://www.openjs.com/articles/ajax/ajax_file_upload/
follow up on how to parse the response ->
http://www.openjs.com/articles/ajax/ajax_file_upload/response_data.php
I have a file upload script which works great when opened from the calling page via window.open(). However, I'm trying to avoid the popup window and load the script into the calling page itself (via jQuery.load()).
However, although everything appears to work fine, the file does not actually get transferred. The calling page is itself a form. Could that cause the problem?
<form id="myParentPage">
<div id="myUploadPlaceholder"></div>
<input type="button" id="loadScript" value="Test" />
<script type="text/javascript">
$(document).ready(function()
{
$('#loadScript').click(function() {
$('#myUploadPlaceholder').load('myUploadScript.php?action=test' );
});
});
</script>
</form>
Try using a hidden iframe instead:
<iframe id="myUploadPlaceholder" src="_blank"></iframe>
<input type="button" id="loadScript" value="Test" />
<script type="text/javascript">
$(document).ready(function()
{
$('#loadScript').click(function() {
$('#myUploadPlaceholder').attr('src','myUploadScript.php?action=test');
});
});
</script>
Hi I'm using jQuery and Codeigniter. I'm creating a simple todo list that can add delete entries using ajax.
The problem is whenever I click on my delete anchor, it won't delete the entry. The adding of the entry feature works BTW.
Here's my code:
todo_view.php
<html>
<head>Todo List</head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#submit').click(function() {
var msg = $('#message').val();
$.post("<?= site_url('todo/add') ?>", {message: msg}, function() {
$('#content').load("<?= site_url('todo/view/ajax') ?>");
$('#message').val('');
});
});
$('a.delete').click(function() {
var id = $('input', this).val();
$.post("<?= site_url('todo/delete') ?>", {todoid: id}, function() {
$('#content').load("<?= site_url('todo/view/ajax') ?>");
});
});
});
</script>
<body>
<div id="form">
<input type="text" name="message" id="message" />
<input type="submit" name="submit" id="submit" value="Add todo" />
</div>
<div id="content">
<?php $this->load->view('message_list'); ?>
</div>
</body>
</html>
message_list.php
<ol>
<?php foreach ($todolist as $todo): ?>
<li>
<?php echo $todo->todo; ?>
<input type="hidden" value="<?=$todo->todoid ?>" />delete</li>
<?php endforeach; ?>
</ol>
Why doesn't it work?
First and foremost - to track GET/POST headers and values you should start using Firebug (an extension for Firefox). Really makes your life easy to terms of debugging ajax calls and responses.
Next (somewhat on the lines of what alimango mentioned)... the most likely cause is that the message list is being loaded AFTER your main page's DOM has already loaded. jQuery won't automatically bind the click event to elements added later. Your click binding routine has to be called AFTER the message list has been added to the DOM. Now this isn't always possible... as your list is being fetched / altered dynamically.
One solution is to use the live() bind event function that has been introduced since jQuery 1.3. This helps binds a handler to an event (like click) for all current - and future - matched element. Can also bind custom events. Fore more information, see http://docs.jquery.com/Events/live#typefn
Second solution is to use, LiveQuery - a jQuery plugin which "utilizes the power of jQuery selectors by binding events or firing callbacks for matched elements auto-magically, even after the page has been loaded and the DOM updated." You can grab it from http://plugins.jquery.com/project/livequery
Cheers,
miCRoSCoPiC^eaRthLinG