How would I check if a date in the format "2008-02-16 12:59:57" is less than 24 hours ago?
if (strtotime("2008-02-16 12:59:57") >= time() - 24 * 60 * 60)
{ /*LESS*/ }
Just adding another answer, using strtotime's relative dates:
$date = '2008-02-16 12:59:57';
if (strtotime("$date +1 day") <= time()) {
// Do something
}
I think this makes the code much more readable.
if ((time() - strtotime("2008-02-16 12:59:57")) < 24*60*60) {
// less than 24 hours ago
}
e.g. via strtotime and time().
The difference must be less then 86400 (seconds per day).
<?php
echo 'now: ', date('Y-m-d H:i:s'), "\n";
foreach( array('2008-02-16 12:59:57', '2009-12-02 13:00:00', '2009-12-02 20:00:00') as $input ) {
$diff = time()-strtotime($input);
echo $input, ' ', $diff, " ", $diff < 86400 ? '+':'-', "\n";
}
prints
now: 2009-12-03 18:02:29
2008-02-16 12:59:57 56696552 -
2009-12-02 13:00:00 104549 -
2009-12-02 20:00:00 79349 +
only the last test date/time lays less than 24 hours in the past.
Php has a comparison function between two date/time objects, but I don't really like it very much. It can be imprecise.
What I do is use strtotime() to make a unix timestamp out of the date object, then compare it with the output of time().
Just use it.....
if(strtotime($date_start) >= strtotime($currentDate))
{
// Your code
}
Maybe it will be more easy to understand...
$my_date = '2008-02-16 12:59:57';
$one_day_after = date('Y-m-d H:i:s', strtotime('2008-02-16 12:59:57 +1 days'));
if($my_date < $one_day_after) {
echo $my_date . " is less than 24 hours ago!";
} else {
echo $my_date . " is more than 24 hours ago!";
}
There should be you variable date Like
$date_value = "2013-09-12";
$Current_date = date("Y-m-d"); OR $current_date_time_stamp = time();
You can Compare both date after convert date into time-stamp so :
if(strtotime($current_date) >= strtotime($date_value)) {
echo "current date is bigger then my date value";
}
OR
if($current_date_time_stamp >= strtotime($date_value)) {
echo "current date is bigger then my date value";
}
You can use Simple PHP to do this:
$date = new simpleDate();
echo $date->now()->subtractHour(24)->compare('2008-02-16 12:59:57')->isBefore();
Related
How can I compare two dates in PHP?
The date is stored in the database in the following format
2011-10-2
If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?
I tried this,
$today = date("Y-m-d");
$expire = $row->expireDate //from db
if($today < $expireDate) { //do something; }
but it doesn't really work that way. What's another way of doing it?
If all your dates are posterior to the 1st of January of 1970, you could use something like:
$today = date("Y-m-d");
$expire = $row->expireDate; //from database
$today_time = strtotime($today);
$expire_time = strtotime($expire);
if ($expire_time < $today_time) { /* do Something */ }
If you are using PHP 5 >= 5.2.0, you could use the DateTime class:
$today_dt = new DateTime($today);
$expire_dt = new DateTime($expire);
if ($expire_dt < $today_dt) { /* Do something */ }
Or something along these lines.
in the database the date looks like this 2011-10-2
Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.
Just to compliment the already given answers, see the following example:
$today = new DateTime('');
$expireDate = new DateTime($row->expireDate); //from database
if($today->format("Y-m-d") < $expireDate->format("Y-m-d")) {
//do something;
}
Update:
Or simple use old-school date() function:
if(date('Y-m-d') < date('Y-m-d', strtotime($expire_date))){
//echo not yet expired!
}
I would'nt do this with PHP.
A database should know, what day is today.( use MySQL->NOW() for example ), so it will be very easy to compare within the Query and return the result, without any problems depending on the used Date-Types
SELECT IF(expireDate < NOW(),TRUE,FALSE) as isExpired FROM tableName
$today = date('Y-m-d');//Y-m-d H:i:s
$expireDate = new DateTime($row->expireDate);// From db
$date1=date_create($today);
$date2=date_create($expireDate->format('Y-m-d'));
$diff=date_diff($date1,$date2);
//echo $timeDiff;
if($diff->days >= 30){
echo "Expired.";
}else{
echo "Not expired.";
}
Here's a way on how to get the difference between two dates in minutes.
// set dates
$date_compare1= date("d-m-Y h:i:s a", strtotime($date1));
// date now
$date_compare2= date("d-m-Y h:i:s a", strtotime($date2));
// calculate the difference
$difference = strtotime($date_compare1) - strtotime($date_compare2);
$difference_in_minutes = $difference / 60;
echo $difference_in_minutes;
You can convert the dates into UNIX timestamps and compare the difference between them in seconds.
$today_date=date("Y-m-d");
$entered_date=$_POST['date'];
$dateTimestamp1 = strtotime($today_date);
$dateTimestamp2 = strtotime($entered_date);
$diff= $dateTimestamp1-$dateTimestamp2;
//echo $diff;
if ($diff<=0)
{
echo "Enter a valid date";
}
I had that problem too and I solve it by:
$today = date("Ymd");
$expire = str_replace('-', '', $row->expireDate); //from db
if(($today - $expire) > $NUMBER_OF_DAYS)
{
//do something;
}
Here's my spin on how to get the difference in days between two dates with PHP.
Note the use of '!' in the format to discard the time part of the dates, thanks to info from DateTime createFromFormat without time.
$today = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
$wanted = DateTime::createFromFormat('!d-m-Y', $row["WANTED_DELIVERY_DATE"]);
$diff = $today->diff($wanted);
$days = $diff->days;
if (($diff->invert) != 0) $days = -1 * $days;
$overdue = (($days < 0) ? true : false);
print "<!-- (".(($days > 0) ? '+' : '').($days).") -->\n";
Found the answer on a blog and it's as simple as:
strtotime(date("Y"."-01-01")) -strtotime($newdate))/86400
And you'll get the days between the 2 dates.
This works because of PHP's string comparison logic. Simply you can check...
if ($startdate < $date) {// do something}
if ($startdate > $date) {// do something}
Both dates must be in the same format. Digits need to be zero-padded to the left and ordered from most significant to least significant. Y-m-d and Y-m-d H:i:s satisfy these conditions.
If you want a date ($date) to get expired in some interval for example a token expiration date when performing a password reset, here's how you can do:
$date = $row->expireDate;
$date->add(new DateInterval('PT24H')); // adds 24 hours
$now = new \DateTime();
if($now < $date) { /* expired after 24 hours */ }
But in your case you could do the comparison just as the following:
$today = new DateTime('Y-m-d');
$date = $row->expireDate;
if($today < $date) { /* do something */ }
first of all, try to give the format you want to the current date time of your server:
Obtain current date time
$current_date = getdate();
Separate date and time to manage them as you wish:
$current_date_only = $current_date[year].'-'.$current_date[mon].'-'.$current_date[mday];
$current_time_only = $current_date['hours'].':'.$current_date['minutes'].':'.$current_date['seconds'];
Compare it depending if you are using donly date or datetime in your DB:
$today = $current_date_only.' '.$current_time_only;
or
$today = $current_date_only;
if($today < $expireDate)
hope it helps
How can I compare two dates in PHP?
The date is stored in the database in the following format
2011-10-2
If I wanted to compare today's date against the date in the database to see which one is greater, how would I do it?
I tried this,
$today = date("Y-m-d");
$expire = $row->expireDate //from db
if($today < $expireDate) { //do something; }
but it doesn't really work that way. What's another way of doing it?
If all your dates are posterior to the 1st of January of 1970, you could use something like:
$today = date("Y-m-d");
$expire = $row->expireDate; //from database
$today_time = strtotime($today);
$expire_time = strtotime($expire);
if ($expire_time < $today_time) { /* do Something */ }
If you are using PHP 5 >= 5.2.0, you could use the DateTime class:
$today_dt = new DateTime($today);
$expire_dt = new DateTime($expire);
if ($expire_dt < $today_dt) { /* Do something */ }
Or something along these lines.
in the database the date looks like this 2011-10-2
Store it in YYYY-MM-DD and then string comparison will work because '1' > '0', etc.
Just to compliment the already given answers, see the following example:
$today = new DateTime('');
$expireDate = new DateTime($row->expireDate); //from database
if($today->format("Y-m-d") < $expireDate->format("Y-m-d")) {
//do something;
}
Update:
Or simple use old-school date() function:
if(date('Y-m-d') < date('Y-m-d', strtotime($expire_date))){
//echo not yet expired!
}
I would'nt do this with PHP.
A database should know, what day is today.( use MySQL->NOW() for example ), so it will be very easy to compare within the Query and return the result, without any problems depending on the used Date-Types
SELECT IF(expireDate < NOW(),TRUE,FALSE) as isExpired FROM tableName
$today = date('Y-m-d');//Y-m-d H:i:s
$expireDate = new DateTime($row->expireDate);// From db
$date1=date_create($today);
$date2=date_create($expireDate->format('Y-m-d'));
$diff=date_diff($date1,$date2);
//echo $timeDiff;
if($diff->days >= 30){
echo "Expired.";
}else{
echo "Not expired.";
}
Here's a way on how to get the difference between two dates in minutes.
// set dates
$date_compare1= date("d-m-Y h:i:s a", strtotime($date1));
// date now
$date_compare2= date("d-m-Y h:i:s a", strtotime($date2));
// calculate the difference
$difference = strtotime($date_compare1) - strtotime($date_compare2);
$difference_in_minutes = $difference / 60;
echo $difference_in_minutes;
You can convert the dates into UNIX timestamps and compare the difference between them in seconds.
$today_date=date("Y-m-d");
$entered_date=$_POST['date'];
$dateTimestamp1 = strtotime($today_date);
$dateTimestamp2 = strtotime($entered_date);
$diff= $dateTimestamp1-$dateTimestamp2;
//echo $diff;
if ($diff<=0)
{
echo "Enter a valid date";
}
I had that problem too and I solve it by:
$today = date("Ymd");
$expire = str_replace('-', '', $row->expireDate); //from db
if(($today - $expire) > $NUMBER_OF_DAYS)
{
//do something;
}
Here's my spin on how to get the difference in days between two dates with PHP.
Note the use of '!' in the format to discard the time part of the dates, thanks to info from DateTime createFromFormat without time.
$today = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
$wanted = DateTime::createFromFormat('!d-m-Y', $row["WANTED_DELIVERY_DATE"]);
$diff = $today->diff($wanted);
$days = $diff->days;
if (($diff->invert) != 0) $days = -1 * $days;
$overdue = (($days < 0) ? true : false);
print "<!-- (".(($days > 0) ? '+' : '').($days).") -->\n";
Found the answer on a blog and it's as simple as:
strtotime(date("Y"."-01-01")) -strtotime($newdate))/86400
And you'll get the days between the 2 dates.
This works because of PHP's string comparison logic. Simply you can check...
if ($startdate < $date) {// do something}
if ($startdate > $date) {// do something}
Both dates must be in the same format. Digits need to be zero-padded to the left and ordered from most significant to least significant. Y-m-d and Y-m-d H:i:s satisfy these conditions.
If you want a date ($date) to get expired in some interval for example a token expiration date when performing a password reset, here's how you can do:
$date = $row->expireDate;
$date->add(new DateInterval('PT24H')); // adds 24 hours
$now = new \DateTime();
if($now < $date) { /* expired after 24 hours */ }
But in your case you could do the comparison just as the following:
$today = new DateTime('Y-m-d');
$date = $row->expireDate;
if($today < $date) { /* do something */ }
first of all, try to give the format you want to the current date time of your server:
Obtain current date time
$current_date = getdate();
Separate date and time to manage them as you wish:
$current_date_only = $current_date[year].'-'.$current_date[mon].'-'.$current_date[mday];
$current_time_only = $current_date['hours'].':'.$current_date['minutes'].':'.$current_date['seconds'];
Compare it depending if you are using donly date or datetime in your DB:
$today = $current_date_only.' '.$current_time_only;
or
$today = $current_date_only;
if($today < $expireDate)
hope it helps
Okay so I have a function that compares the hours from 00:00:00 - 24:00:00 to tell the closing time. Now the issue I have is, lets say the store opens at 8AM and closes at midnight, well 00:00:00is going to be less than 23:00:00. How would I go about making sure that it recognizes that midnight is greater?
Here is what I am doing:
if((strtotime($openTime) < time()) && (strtotime($closeTime) > time()))
{
$response['data_retrieved']['store'][$i]['store_settings']['open'] = 1;// open
}
else
{
$response['data_retrieved']['store'][$i]['store_settings']['open'] = 0; //close
}
Suggestions?
Since there is no 24:00:00, you'll need the full date string Y-m-d H:i:s to do an accurate comparison.
Even just adding in the date won't be enough, as it will break when looking at the last day of the month ('31 08:00:00' < '1 00:00:00').
PHP has a very good DateTime support. Its better to use that instead of reinventing things. Also like #mopo922 suggested, you'll need the full Y-m-d H:i:s
The answer #mopo922 provided above is the most foolproof and most correct answer.
Another method would be to "add" 24 hours to the $closeTime if $startTime > $closeTime. It's quite dodgy but still solves the problem.
<?php
date_default_timezone_set('Australia/Sydney');
$openTime = strtotime('08:00');
$currentTime = strtotime('23:00');
$closeTime = strtotime('10:00');
echo 'open: ' .$openTime . '<br>' .
'time(): ' . $currentTime . '<br>' .
'close: ' . $closeTime . '<br>';
// 1 day = 86400 seconds
if ($closeTime < $openTime) {
$closeTime += 86400;
}
if($openTime < $currentTime && $closeTime > $currentTime)
{
echo 'open';
}
else
{
echo 'closed';
}
?>
I am trying to check if a certain time is in the past. Solution 1 works but the solutions 2 and 3 using strtotime do not. Any ideas why the strtotime solutions fail with this date when they work fine when the date is not that distant (f.ex. using 27.05.2035 works)?
<?php
$date = "27.05.2045";
$hour = "22";
$min = "15";
// 1. This one works
$datetime = DateTime::createFromFormat('d.m.Y H:i', $date.' '.$hour.':'.$min);
$now = new DateTime();
if ($datetime < $now)
{
echo "Datetime is in the past";
}
else if ($datetime > $now)
{
echo "Datetime is in the future";
}
// 2. Does not work
if (time() > strtotime($date.' '.$hour.':'.$min))
{
echo "Datetime is in the past (strtotime)";
}
else if (time() < strtotime($date.' '.$hour.':'.$min))
{
echo "Datetime is in the future (strtotime)";
}
// 3. Using another date format but still does not work
$array = explode('.', $date);
$date_converted = $array[2].'-'.$array[1].'-'.$array[0];
if (time() > strtotime($date_converted.' '.$hour.':'.$min))
{
echo "Datetime is in the past (strtotime with converted date)";
}
else if (time() < strtotime($date_converted.' '.$hour.':'.$min))
{
echo "Datetime is in the future (strtotime with converted date)";
}
?>
The 32 bit integer maximum makes it impossible to represent dates past 19 January 2038.
The solution would be to either:
Use DateTime objects, which do not represent dates using the number of seconds passed since 1970, but using a field for each time unit.
Use the 64-bit version of PHP, where the maximum integer is much higher.
See The 2038 Year Problem for more details.
I'm trying to work with dates for the first time, I did it something about that with Flash but it's different.
I have two different dates and I'd like to see the difference in hours and days with them, I've found too many examples but not what I'm loking for:
<?php
$now_date = strtotime (date ('Y-m-d H:i:s')); // the current date
$key_date = strtotime (date ("2009-11-21 14:08:42"));
print date ($now_date - $key_date);
// it returns an integer like 5813, 5814, 5815, etc... (I presume they are seconds)
?>
How can I convert it to hours or to days?
The DateTime diff function returns a DateInterval object. This object consists of variabeles related to the difference. You can query the days, hours, minutes, seconds just like in the example above.
Example:
<?php
$dateObject = new DateTime(); // No arguments means 'now'
$otherDateObject = new DateTime('2008-08-14 03:14:15');
$diffObject = $dateObject->diff($otherDateObject));
echo "Days of difference: ". $diffObject->days;
?>
See the manual about DateTime.
Sadly, it's a PHP 5.3> only feature.
Well, you can always use date_diff, but that is only for PHP 5.3.0+
The alternative would be math.
How can I convert it [seconds] to hours or to days?
There are 60 seconds per minute, which means there are 3600 seconds per hour.
$hours = $seconds/3600;
And, of course, if you need days ...
$days = $hours/24;
If you dont have PHP5.3 you could use this method from userland (taken from WebDeveloper.com)
function date_time_diff($start, $end, $date_only = true) // $start and $end as timestamps
{
if ($start < $end) {
list($end, $start) = array($start, $end);
}
$result = array('years' => 0, 'months' => 0, 'days' => 0);
if (!$date_only) {
$result = array_merge($result, array('hours' => 0, 'minutes' => 0, 'seconds' => 0));
}
foreach ($result as $period => $value) {
while (($start = strtotime('-1 ' . $period, $start)) >= $end) {
$result[$period]++;
}
$start = strtotime('+1 ' . $period, $start);
}
return $result;
}
$date_1 = strtotime('2005-07-31');
$date_2 = time();
$diff = date_time_diff($date_1, $date_2);
foreach ($diff as $key => $val) {
echo $val . ' ' . $key . ' ';
}
// Displays:
// 3 years 4 months 11 days
TheGrandWazoo mentioned a method for php 5.3>. For lower versions you can devide the number of seconds between the two dates with the number of seconds in a day to find the number of days.
For days, you do:
$days = floor(($now_date - $key_date) / (60 * 60 * 24))
If you want to know how many hours are still left, you can use the modulo operator (%)
$hours = floor((($now_date - $key_date) % * (60 * 60 * 24)) / 60 * 60)
<?php
$now_date = strtotime (date ('Y-m-d H:i:s')); // the current date
$key_date = strtotime (date ("2009-11-21 14:08:42"));
$diff = $now_date - $key_date;
$days = floor($diff/(60*60*24));
$hours = floor(($diff-($days*60*60*24))/(60*60));
print $days." ".$hours." difference";
?>
I prefer to use epoch/unix time deltas. Time represented in seconds and as such you can very quickly divide by 3600 for hours and divide by 24*3600=86400 for days.