Select duplicates with PHP & MySql for merging process - php

Question

I wrote some code to select duplicates and group them using first and last names. I gather them into a multidimensional array and dedupe/merge them using jQuery/Ajax on the resulting page. I would like to ask if there is a better method of creating the array than how I'm doing it. Here is my code. Thank you.
$dataArr=fetchDups($conn, 13, 5); // get a few at a time
print '<div style="clear:both;"></div><pre>';
print_r($dataArr);
print '</pre><div style="clear:both;"></div>';
function fetchDups($conn, $client_id, $limit='')
{
$sql=' SELECT * FROM `contacts` WHERE `clientid`=\'13\' GROUP BY fname, lname ';
//$sql=' SELECT DISTICT fname, lname, * FROM `clients` WWHERE `clientid`=\'13\' ';
$res=mysql_query($sql, $conn)or die(mysql_error());
$contactsRow=array();
while($row=mysql_fetch_array($res)){
echo $row['fname'].'<br>';
$contactsRow[]=$row;
}
mysql_freeresult($res);
$dataArr=array();
$i=0;
$limitNum=0;
//----------------------------------
foreach($contactsRow AS $rowNew){
$sql=' SELECT * FROM `contacts` WHERE `clientid`=\'13\' AND `id`!=\''.$rowNew['id'].'\'
AND (`fname` = \''.$rowNew['fname'].'\' OR `lname` = \''.$rowNew['lname'].'\')
';
//echo $sql;
$res=mysql_query($sql, $conn)or die(mysql_error());
$rowCountDup=mysql_num_rows($res);
if($rowCountDup>0){
$d=0;
$dataArr[$i]=array();
$dataArr[$i][$d]=$rowNew;
while($rowNew=mysql_fetch_array($res)){
$dataArr[$i][($d+1)]=$rowNew;
$d++;
}
$i++;
$limitNum++;
}
// limit the results. too many crashes the browser
if($limitNum==$limit){
break;
}
}
mysql_freeresult($res);
return $dataArr;
}

Answer 1

For this kind of things, you should probably try using:
SELECT * FROM contacts refC JOIN contacts allC USING (fname, lname) WHERE refC.clientid='13'
This does a self-join on contacts based on first and last name, so allC aliases to the list of all contacts that share refC's first and last names (including himself).
This way, you get all the information you're looking for in only one SQL query. Tuning may be achieved on the query by adding an index on columns fname and lname of table contacts, so the join doesn't have to parse the whole table to match.
--edit: You may get to specify more finely how you join your tables as for instance:
SELECT *
FROM contacts refC
JOIN contacts allC ON (allC.fname LIKE CONCAT(refC.fname, '%') AND allC.lname LIKE CONCAT(refC.lname, '%'))
WHERE refC.clientid='13'
Which is strictly equivalent (but IMO easier to read than) to:
SELECT *
FROM contacts refC,contacts allC
WHERE allC.fname LIKE CONCAT(refC.fname, '%')
AND allC.lname LIKE CONCAT(refC.lname, '%')
AND refC.clientid='13'

Answer 2

If you just want to avoid displaying duplicates and not actually removing them from your db, use DISTINCT SQL keyword.

Answer 3

Or you could try something like the second query here which uses a derived table:
mysql> select * from contacts ;
+----+--------+---------+
| id | fname | lname |
+----+--------+---------+
| 1 | Annie | Haddock |
| 2 | Annie | Haddock |
| 3 | Ginger | Mole |
| 4 | Ted | Ted |
| 5 | Ted | Ted |
+----+--------+---------+
5 rows in set (0.01 sec)
mysql> select id, fname, lname, total from
(select *, count(*) as total
from contacts group by fname, lname) people
where total > 1;
+-----------+--------------+--------------+--------------+
| people.id | people.fname | people.lname | people.total |
+-----------+--------------+--------------+--------------+
| 1 | Annie | Haddock | 2 |
| 4 | Ted | Ted | 2 |
+-----------+--------------+--------------+--------------+
2 rows in set (0.01 sec)
then just iterate through it with foreach. Note that "people" above is an alias for the derived table created by the inner select