moving around uploaded files in PHP - php

I need to resize an uploaded image.
The class that resizes needs to get the location of the image to be worked with.
It returns the image in a variable.
However, when I try to get the path to the image, I get from $_FILES['profile_upload']['tmp_name'] the following: C:\xampp\tmp\php1C5.tmp
I don't get the actual file, even though the tmp folder contains it!
How can I get the actual filename? Another question - for how long are the files stored in tmp, and when do they get deleted?
By the way, does the Zend Framework have a good image manipulation interface?

You should complete the whole file upload setup with something similar and then the variable $_FILES['uploadedfile']['name'] will also contain the original file name:
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}

To address your second point: Files are stored until the script they were uploaded to finishes.

Related

parameters explanation of $_FILES in php

I am new to this site and i am sorry if anything wrong in my way of asking question.
I want to know about the parameters of $_FILES in php.
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path))
{
//some code
}
By the above code, what is
['uploadedfile']['name'] in $_FILES
also in move_uploaded_file($FILES['uploadedfile']['tmpname'])
what is tmpname?
Please explain in detail. Thanks in advance.
$_FILES['name'] is the Actual file name (as named on your computer).
$_FILES['tmp_name'] is the temporary files name.
You computer automatically creates a temporary copy of the file that you are uploading in a temporary directory.
This is the actual physical file uploaded by your computer.
try this to learn about the content of $_FILES:
echo '<pre>';
print_r($_FILES);
echo '</pre>';

File path issues with move_uploaded_file

I am trying to upload pictures on my site. However, I am trying to find the correct filepath to the folder I need to send the pictures too. I continue to get a 500 server internal error when move_uploaded_file() is called. I tried playing around with a couple of things, and I believe the problem is that I am not using the correct destination folder.
<?php
$target_path = "G:\\PleskVhosts\\missed-moments.com\\httpdocs\\uploads\\";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
echo $_SERVER["DOCUMENT_ROOT"] . "<br/>";
echo $target_path;
echo getcwd()."<br/>";
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name'])." has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
?>
I tried to find the path of the folder I was in by using :
echo $_SERVER["DOCUMENT_ROOT"] . "<br/>";
echo getcwd()."<br/>";
And then I tried to hardcode the same address with the addition of the folder that I want to save the pictures in it. I was hoping somebody could give me some other suggestions on how to resolve this issue.
Thank you in advance!

move_uploaded_file

I have a form with 3 tabs, one for pictures, one for music and one for youtube.
The first 2 are forms where people can upload files, the second is just for a youtube link.
When people hit the 'upload' button they are sent to a second page where the actual uploading is done. Now uploading musc works, but using the same code for the pictures it doesn't seem to work.
if (isset($_POST['submitfoto'])) {
// uploaden
$target_path = "uploads/";
$target_path = $target_path . time() . $_SERVER['REMOTE_ADDR'] . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
// Here I do a bunch of stuff with the database, but it never gets that far.
echo "Thanks for uploading this file.";
} else{ echo "File upload failed";} }
Now I get File upload failed all the time. But the exact same code seems to work for uploading .mp3 file.
How is this possible?

PHP File Upload / Host System

I have currently made a script which allows uploading for files within our company. I am looking to improve this script to allow for the directory of the uploaded file to masked within the download link (Don't really want people knowing the directory structure) Is there a way I can encode the link and then once a successful upload is made echo out the masked URL available for our clients to download.
<?php
$target = "upload/";
$target = $target . basename( $_FILES['uploaded']['name']) ;
$ok=1;
//This is our size condition
if ($uploaded_size > 350000)
{
echo "Your file is too large.<br>";
$ok=0;
}
//This is our limit file type condition
if ($uploaded_type =="text/php")
{
echo "No PHP files<br>";
$ok=0;
}
//Here we check that $ok was not set to 0 by an error
if ($ok==0)
{
Echo "Sorry your file was not uploaded";
}
//If everything is ok we try to upload it
else
{
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded";
}
else
{
echo "Sorry, there was a problem uploading your file.";
}
}
?>
Thanks Guys :)
I won't give you the code, but here is my strategy for implementing file sharing without giving away their location.
Create a file that takes as a parameter the name of the file to be retrieved. It's only purpose is to open the file and stream it out. It should know ahead of time what to do with the file, where to look for it, and how to return it(stream). Let's call it getFile($filename)
In your main PHP file, call the function and store the result in a variable:
$file = getFile($_POST['filename']);
Now send the user the file, and he will be none the wiser about where it came from.
You could make a script that the file bounces. It just accepts the filename as parameter. Something like:
download.php?file=myfile.txt
that way you don't say where you put your files, and it's easy to implement. You could add headers to actually download the file.

Error uploading file from HTML form

Here is a problem.
I have an HTML form with several fields in it.
One of the fields - 'Upload file'.
When I upload a file, everything works properly. But when I choose to submit the form without a file, it gives me the error message: "There was an error uploading the file, please try again". Looks to me that the script thinks that uploading a file is mandatory.
How do I change it?
Here is my PHP:
//File upload
// Where the file is going to be placed
$target_path = "uploads/";
// Add the original filename to our target path.
//Result is "uploads/filename.extension"
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
//End of file upload
Thank you!
You should check using the function is_uploaded_file
try adding the following condition before calling the function move_uploaded_file
if (is_uploaded_file($_FILES['uploadedfile']['tmp_name'])) {
The target path of move_uploaded_files should be a folder, not a file.
You should also check if the folder is_writeable and is_dir.
move_uploaded_file returns a bool, true or false, depending on the success of the operation.
A solution would be to check more rigorously, e.g. if a file was uploaded at all via is_uploaded_file function.
For proper working, the function is_uploaded_file() needs an argument like $_FILES['userfile']['tmp_name'], - the name of the uploaded file on the clients machine $_FILES['userfile']['name'] does not work.

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