I have a Date object ( from Pear) and want to subtract another Date object to get the time difference in seconds.
I have tried a few things but the first just gave me the difference in days, and the second would allow me to convert one fixed time to unix timestamp but not the Date object.
$now = new Date();
$tzone = new Date_TimeZone($timezone);
$now->convertTZ($tzone);
$start = strtotime($now);
$eob = strtotime("2009/07/02 17:00"); // Always today at 17:00
$timediff = $eob - $start;
** Note ** It will always be less than 24 hours difference.
Still gave somewhat wrong values but considering I have an old version of PEAR Date around, maybe it works for you or gives you an hint on how to fix :)
<pre>
<?php
require "Date.php";
$now = new Date();
$target = new Date("2009-07-02 15:00:00");
//Bring target to current timezone to compare. (From Hawaii to GMT)
$target->setTZByID("US/Hawaii");
$target->convertTZByID("America/Sao_Paulo");
$diff = new Date_Span($target,$now);
echo "Now (localtime): {$now->format("%Y-%m-%d %H:%M:%S")} \n\n";
echo "Target (localtime): {$target->format("%Y-%m-%d %H:%M:%S")} \n\n";
echo $diff->format("Diff: %g seconds => %C");
?>
</pre>
Are you sure that the conversion of Pear Date object -> string -> timestamp will work reliably? That is what is being done here:
$start = strtotime($now);
As an alternative you could get the timestamp like this according to the documentation
$start = $now->getTime();
To do it without pear, to find the seconds 'till 17:00 you can do:
$current_time = mktime ();
$target_time = strtotime (date ('Y-m-d'. ' 17:00:00'));
$timediff = $target_time - $current_time;
Not tested it, but it should do what you need.
I don't think you should be passing the entire Date object to strtotime. Use one of these instead;
$start = strtotime($now->getDate());
or
$start = $now->getTime();
Maybe some folks wanna have the time difference the facebook way. It tells you "one minute ago", or "2 days ago", etc... Here is my code:
function getTimeDifferenceToNowString($timeToCompare) {
// get current time
$currentTime = new Date();
$currentTimeInSeconds = strtotime($currentTime);
$timeToCompareInSeconds = strtotime($timeToCompare);
// get delta between $time and $currentTime
$delta = $currentTimeInSeconds - $timeToCompareInSeconds;
// if delta is more than 7 days print the date
if ($delta > 60 * 60 * 24 *7 ) {
return $timeToCompare;
}
// if delta is more than 24 hours print in days
else if ($delta > 60 * 60 *24) {
$days = $delta / (60*60 *24);
return $days . " days ago";
}
// if delta is more than 60 minutes, print in hours
else if ($delta > 60 * 60){
$hours = $delta / (60*60);
return $hours . " hours ago";
}
// if delta is more than 60 seconds print in minutes
else if ($delta > 60) {
$minutes = $delta / 60;
return $minutes . " minutes ago";
}
// actually for now: if it is less or equal to 60 seconds, just say it is a minute
return "one minute ago";
}
Related
PHP Function to convert time() seconds to time format Hour:Minutes
function secondsToTime($seconds) {
$dtF = new \DateTime('#0');
$dtT = new \DateTime("#$seconds");
// return $dtF->diff($dtT)->format('%a days, %h hours, %i minutes and %s seconds');
return $dtF->diff($dtT)->format('%h:%i');
}
echo secondsToTime(time());
I need a function for something like:
If time now is 23:41 (hour:minute) to show 23:40
If time now is 23:46 (hour:minute) to show 23:45
If time now is 23:47 (hour:minute) to show 23:45
If time now is 23:49 (hour:minute) to show 23:45
If time now is 23:52 (hour:minute) to show 23:50
But the output to be show by time() format seconds so this way i can check via mysql how many rows updated from time() format show 23:45 if time now is 23:49 so in past 4 minutes ...
You need to round the minutes and then reformat your output date.
There's some gotchas hidden in here. As you can end up with 60 minutes (should be 00) and 24 hours (also should be 00). So special checks are put in place to catch that.
Also, you way of getting the current time is very convoluted. Getting "now" gets the same value which is what DateTime() gets by default.
function secondsToTime() {
$now = new \DateTime();
$cminutes = $now->format('i');
$hour = $now->format('H');
$nminutes = (round($cminutes)% 5 === 0) ? round($cminutes) : round(($cminutes + 5 / 2) / 5 ) * 5;
if ($nminutes > $cminutes) {
$nminutes -= 5;
}
if ($nminutes === 60) {
$nminutes = 0;
$hour++;
}
if ($hour === 24) {
$hour = 0;
}
return sprintf('%02d:%02d', $hour, $nminutes);
}
echo secondsToTime();
Demo
I am creating a timesheet whereby it shows expected and actual hours.
The durations are saved like the below
23:15 - 23 hours and 15 mins
25:45 - 25 hours and 45 mins
I need to work out the difference in hours and mins between the two (extra hours worked)
I have tried the below
$acutal=='23:15';
$expected=='25:45';
$start_time = new DateTime("1970-01-01 $acutal:00");
$time = $start_date->diff(new DateTime("1970-01-01 $expected:00"));
This does work, however when the hours are over 24:00 it throws an error (obviously because it's reading it as time)
Uncaught exception 'Exception' with message 'DateTime::__construct():
Failed to parse time string (1970-01-01 25:45:00)
Is there another way to do this?
You could check if the number of hours are greater than 24, and if so, add a day, and remove 24 hours.
$actual='23:15';
$expected='25:45';
$day = 1;
list($hrs, $min) = explode(':', $expected);
if ($hrs > 24) { $day += 1; $hrs -= 24; }
$start_time = new DateTime("1970-01-01 $actual:00");
$time = $start_time->diff(new DateTime("1970-01-$day $hrs:$min:00"));
echo $time->format('%hh %Im');
Output:
2h 30m
Please also note that == is used to compare, not to assign.
You can also change the if ($hrs > 24) by while(), if there is 48 hours or more.
edit
As pointed out by #CollinD, if the time exceed the number of days of the month, it will fail. Here is another solution:
$actual='23:15';
$expected='25:45';
list($hrs, $min) = explode(':', $actual);
$total1 = $min + $hrs * 60;
list($hrs, $min) = explode(':', $expected);
$diff = $min + $hrs * 60 - $total1;
$start_time = new DateTime();
$expected_time = new DateTime();
$expected_time->modify("+ $diff minutes");
$time = $start_time->diff($expected_time);
echo $time->format('%hh %Im');
You can do it manually by keeping track of the number of minutes worked - this will be exact and will also allow you to show negative differences.
<?php
// get the difference in H:mm between two H:mm
function diff_time($actual, $expected) {
$diff_mins = mins($actual) - mins($expected);
return format_mins($diff_mins);
}
// convert a HH:mm to number of minutes
function mins($t) {
$parts = explode(':', $t);
return $parts[0] * 60 + $parts[1];
}
// convert number of minutes into HH:mm
function format_mins($m) {
$mins = $m % 60;
$hours = ($m - $mins) / 60;
// format HH:mm
return $hours . ':' . sprintf('%02d', abs($mins));
}
var_dump(diff_time('23:15', '25:45'));
var_dump(diff_time('25:15', '23:45'));
This outputs:
string(5) "-2:30"
string(4) "1:30"
.. first, 2:30 less than expected, for the second 1:30 more than expected.
You can try using datetime functions but it seems a lot more straightforward to me to treat the times as string, use split or explode to get hours and minutes, convert to integers, get the difference in minutes and convert it back to hours and minutes (integer divide by 60 and remainder).
$t1=explode(':',$expected);
$t2=explode(':',$actual);
$d=60*($t1[0]-$t2[0])+t1[1]-t2[1];
$result=str_pad(floor($d/60),2,'0',STR_PAD_LEFT).':'.str_pad($d%60,2,'0',STR_PAD_LEFT);
I am creating time stamps in PHP using time();
I have the $current_time and $purchase_time. How do I make sure that purchase_time is less than 24 hours of current time?
If they are UNIX timestamps, then you can calculate this by yourself really easy, as they are seconds.
$seconds = $current_time - $purchase_time
$hours = floor($seconds/3600);
if ($hours < 24){
//success
}
Since UNIX timestamps are just numbers of seconds, just use the difference:
$purchasedToday = $current_time - $purchase_time < 24 * 60 * 60;
if ($purchasedToday) {
echo 'You just bought the item';
} else {
echo 'You bought the item some time ago';
}
You can construct a DateTime object and then use it's diff() method to calculate the difference between $current_time and $purchase_time:
$currentTime = new DateTime();
$purchaseTime = new DateTime('2011-10-14 12:34:56');
// Calculate difference:
$difference = $currentTime->diff($purchaseTime);
if ($difference->days >= 1) {
echo 'More than 24 hours ago.';
}
This is more reliable than calculating the difference yourself, as this method takes care of timezones and daylight saving time.
Something like this:
$difference=time() - $last_login;
I had use something like this:
<?php
if(date("U", strtotime("-24 hours", $current_time) > date("U", $purchase_time)) {
echo "More then 24 hours you purchased this radio";
}
?>
This works even if the time stamp not is a UNIX-timestamp.
This question already has answers here:
Get interval seconds between two datetime in PHP?
(8 answers)
Closed last year.
HI, i have a couple of posts in my MySql database server, one of the info content in each post is the date and time in the format datetime (Ex. 2010-11-26 21:55:09) when the post was made.
So, i want to retrive the actual date and time from the SQL server with the function NOW() and calculates how many seconds or minutes or hours or days ago was post the info.
I dont know how to create this php script but i know that for sure is allready made, so thanks for any help.
you could use the date_diff() function
http://php.net/manual/en/function.date-diff.php
Something like...
<?php
$now = time();
$then = $posttime;
$diff = date_diff($now,$then);
echo $diff->format('%R%d days'); #change format for different timescales
?>
edit --
I actually solve this issue on one of my twitter apps using this function...
function time_since ( $start )
{
$end = time();
$diff = $end - $start;
$days = floor ( $diff/86400 ); //calculate the days
$diff = $diff - ($days*86400); // subtract the days
$hours = floor ( $diff/3600 ); // calculate the hours
$diff = $diff - ($hours*3600); // subtract the hours
$mins = floor ( $diff/60 ); // calculate the minutes
$diff = $diff - ($mins*60); // subtract the mins
$secs = $diff; // what's left is the seconds;
if ($secs!=0)
{
$secs .= " seconds";
if ($secs=="1 seconds") $secs = "1 second";
}
else $secs = '';
if ($mins!=0)
{
$mins .= " mins ";
if ($mins=="1 mins ") $mins = "1 min ";
$secs = '';
}
else $mins = '';
if ($hours!=0)
{
$hours .= " hours ";
if ($hours=="1 hours ") $hours = "1 hour ";
$secs = '';
}
else $hours = '';
if ($days!=0)
{
$days .= " days ";
if ($days=="1 days ") $days = "1 day ";
$mins = '';
$secs = '';
if ($days == "-1 days ") {
$days = $hours = $mins = '';
$secs = "less than 10 seconds";
}
}
else $days = '';
return "$days $hours $mins $secs ago";
}
You pass it in a unix timestamp of the time to check (the post time) and it returns the various string.
As billythekid said, you can use the date_diff() function if you are using PHP5.3+, if you are not then there are various methods. As shown by other posters. The quickest method in MySQL if you want to know the time split in to the "hours:mins:secs" hierarchy is to use the TIMEDIFF() function.
SELECT TIMEDIFF(NOW(), '2010-11-26 12:00:00');
If you want it as seconds, use the unix timestamp features in MySQL or in PHP, you can convert MySQL dates to PHP quickly using strtotime().
Usually, you do this kind of thing in a query, but MySQL isn't very good with intervals (it would be very easy with PostgreSQL). You could convert it to unix timestamp, then it would give the number of seconds between the two dates :
SELECT UNIX_TIMESTAMP() - UNIX_TIMESTAMP(your_datetime_column);
I thought about DATEDIFF, but it only returns the number of days between the two dates.
You can do it in PHP, for instance, with DateTime class :
$date1 = new DateTime();
$date2 = new Datetime('2010-11-26 12:00:00');
var_dump($date1->diff($date2));
(There's a procedural way to do this, if you're not a fan of OOP.)
This is definitely the solution I'd use if I can't do it with the RDBMS. DateTime::diff returns a DateInterval object, which contains the number of seconds, minutes, hours, days, etc. between the two dates.
You could also do it with timestamps in PHP :
$num_sec = time() - strtotime('2010-11-26 12:00:00');
Which would return the same thing as the SQL query.
An easy solution is possible from within the SQL Query:
SELECT UNIX_TIMESTAMP(NOW()) - UNIX_TIMESTAMP(post_date) AS seconds_ago FROM posts
Documentation here: MySQL Ref
I actually needed to do this in PHP myself and while billythekid's post was in the right direction it fell short. I've minimized the code though it should be clear that the second parameter is from a database with a DATETIME column type.
<?php
$interval = date_diff(date_create(date('Y-m-d H:i:s')), date_create($row1['date']));
echo $interval->format('%R%a days');
//Database: 2019-02-22
//PHP's date: 2018-07-07
//Result: +306 days
?>
A reminder of the obvious: you can also just use substr($interval->format('%R%a days'),1) if you need just the integer.
I'm trying to work with dates for the first time, I did it something about that with Flash but it's different.
I have two different dates and I'd like to see the difference in hours and days with them, I've found too many examples but not what I'm loking for:
<?php
$now_date = strtotime (date ('Y-m-d H:i:s')); // the current date
$key_date = strtotime (date ("2009-11-21 14:08:42"));
print date ($now_date - $key_date);
// it returns an integer like 5813, 5814, 5815, etc... (I presume they are seconds)
?>
How can I convert it to hours or to days?
The DateTime diff function returns a DateInterval object. This object consists of variabeles related to the difference. You can query the days, hours, minutes, seconds just like in the example above.
Example:
<?php
$dateObject = new DateTime(); // No arguments means 'now'
$otherDateObject = new DateTime('2008-08-14 03:14:15');
$diffObject = $dateObject->diff($otherDateObject));
echo "Days of difference: ". $diffObject->days;
?>
See the manual about DateTime.
Sadly, it's a PHP 5.3> only feature.
Well, you can always use date_diff, but that is only for PHP 5.3.0+
The alternative would be math.
How can I convert it [seconds] to hours or to days?
There are 60 seconds per minute, which means there are 3600 seconds per hour.
$hours = $seconds/3600;
And, of course, if you need days ...
$days = $hours/24;
If you dont have PHP5.3 you could use this method from userland (taken from WebDeveloper.com)
function date_time_diff($start, $end, $date_only = true) // $start and $end as timestamps
{
if ($start < $end) {
list($end, $start) = array($start, $end);
}
$result = array('years' => 0, 'months' => 0, 'days' => 0);
if (!$date_only) {
$result = array_merge($result, array('hours' => 0, 'minutes' => 0, 'seconds' => 0));
}
foreach ($result as $period => $value) {
while (($start = strtotime('-1 ' . $period, $start)) >= $end) {
$result[$period]++;
}
$start = strtotime('+1 ' . $period, $start);
}
return $result;
}
$date_1 = strtotime('2005-07-31');
$date_2 = time();
$diff = date_time_diff($date_1, $date_2);
foreach ($diff as $key => $val) {
echo $val . ' ' . $key . ' ';
}
// Displays:
// 3 years 4 months 11 days
TheGrandWazoo mentioned a method for php 5.3>. For lower versions you can devide the number of seconds between the two dates with the number of seconds in a day to find the number of days.
For days, you do:
$days = floor(($now_date - $key_date) / (60 * 60 * 24))
If you want to know how many hours are still left, you can use the modulo operator (%)
$hours = floor((($now_date - $key_date) % * (60 * 60 * 24)) / 60 * 60)
<?php
$now_date = strtotime (date ('Y-m-d H:i:s')); // the current date
$key_date = strtotime (date ("2009-11-21 14:08:42"));
$diff = $now_date - $key_date;
$days = floor($diff/(60*60*24));
$hours = floor(($diff-($days*60*60*24))/(60*60));
print $days." ".$hours." difference";
?>
I prefer to use epoch/unix time deltas. Time represented in seconds and as such you can very quickly divide by 3600 for hours and divide by 24*3600=86400 for days.