I know how to print data from database on html table but i have one task that i can not understand, and i can not do it.
I have a table in database and when i select those data i want them to display on html table but something like this:
Image http://img683.imageshack.us/img683/9350/tablea.png
To achieve a table layout like that you just need to condition the placement of the end of your table rows.
<table>
<tr>
<?php
$count = 0;
while($row = mysql_fetch_assoc($result)) :
$count++;
?>
<td><?php echo $row['value'] ?></td>
<?php if($count % 2 == 0 || $count == mysql_num_rows($res)) : ?>
</tr>
<?php if($count != mysql_num_rows($result)) : ?>
<tr>
<?php endif; ?>
<?php endif; ?>
<?php endwhile; ?>
</table>
What the above does is use the modulus operator (%, calculates the remainder from division) to print a closing and opening row tag whenever we're at an evenly numbered result.
Also, if you wanted to change your table layout to be 3 or 4 columns wide all you need to do is change the number applied to the modulus:
$count % 3 == 0 //3 columns
$count % 4 == 0 //4 columns, etc
<table>
<?php while (TRUE) { ?>
<?php
// Make an array of n rows. Trailing items may be FALSE if there
// are not enough rows to fill the table row.
//
$rows= array();
for ($i= 0; $i<n; $i++)
$rows[$i]= mysql_fetch_assoc($result);
if (!$row[0])
break;
?>
<tr>
<?php foreach ($rows as $row) { ?>
<td>
<?php if ($row) { ?>
Value: <?php echo(htmlspecialchars($row['value']); ?>
<?php } ?>
</td>
<?php } ?>
</tr>
<?php } ?>
</table>
Related
Im using tables to store content that's dynamically loaded. It's for a reservation form which will be responsive. What I'm looking to do is break each table row into two if there are more than 5 columns in order for the mobile version to fit on screen.
I'm sure this can be achieved by extending what I already have but can't get it to work.
Here's my current code:
<table>
<tr>
<?php foreach ($hostel->getAvailableDates() as $date): ?>
<th><?php echo $date->getDayOfTheWeek(); ?></th>
<?php endforeach ?>
</tr>
<tr>
<?php foreach ($hostel->getAvailableDates() as $date): ?>
<td>
<?php if($date->getAvailable()) { ?>
<b class="avail tick">Available</b>
<?php } else { ?>
<b class="avail cross">Unavailable</b>
<?php }?>
</td>
<?php endforeach ?>
</tr>
</table>
I'd need to break the loop for each row tr after 5 loops, then add a new row underneath.
I've been experimenting with
$max_loop = 5;
$count = 0;
But no luck so far.
I prefer to reorganize data:
<?php
$availDates = array();
foreach ($hostel->getAvailableDates() as $date) {
$availDates[] = $date;
}
$maxCols = 5;
$chunked = array_chunk( $availDates, $maxCols );
?>
<table>
<?php
foreach ($chunked as $chunk) {
?><tr>
<?php foreach ($chunk as $date): ?>
<th><?php echo $date->getDayOfTheWeek(); ?></th>
<?php endforeach; ?>
</tr>
<tr>
<?php foreach ($chunk as $date): ?>
<td>
<?php if($date->getAvailable()) { ?>
<b class="avail tick">Available</b>
<?php } else { ?>
<b class="avail cross">Unavailable</b>
<?php }?>
</td>
<?php endforeach; ?>
</tr><?php
}
?>
</table>
Look at the mod operator. It should give you what you need.
if($count % $max_loop == 0)
I hope this may help you. thanks.
<?php
$avDates = $hostel->getAvailableDates();
echo "<table><tr>";
foreach($avDates as $i=>$date){ {
if ($i == $max_loop) {
echo "</tr><tr>";
}
echo "<td>".($date->getAvailable() ? '<b class="avail tick">Available</b>' : '<b class="avail cross">Unavailable</b>')."</td>";
}
echo "</tr></table>";
?>
If the value returned by getAvailableDates is an array, you could use a for loop instead of a foreach, and check if the current index is a multiple of five, so you don't have to keep track of the count variable
$avDates = $hostel->getAvailableDates();
for ($i = 0; $i < count($avDates); $i++) {
$date = $avDates[$i];
//do your staff
//if multiple of five add another tr
if ($i % 5 == 0) {
}
}
I am using an HTML table to display data from a MySQL table using PHP. I need it so once the table has 10 columns, it will move on to the next row.
<?php
$result = mysqli_query($con,"SELECT * FROM table");
echo '<table width="100%" border="1px"><tr width="100%">';
while($row = mysqli_fetch_array($result))
{
?>
<td width="10%"><?php echo $row['Name']; ?></td>
<?php
}
echo "</tr></table>";
mysqli_close($con);
?>
How can this be done?
Untested but something like this should work or get you started in a good direction:
<?php
$result = mysqli_query($con,"SELECT * FROM table");
echo '<table width="100%" border="1px"><tr width="100%">';
$x=0;
while($row = mysqli_fetch_array($result))
{
if($x==0){
echo "<tr>\n";
}elseif($x%10){
echo"</tr><tr>\n";
}
?>
<td width="10%"><?php echo $row['Name']; ?></td>
<?php
$x++;
}
echo "</tr></table>";
mysqli_close($con);
?>
Add a counter to your loop starting at one.
Each time through the loop if the remainder after dividing the counter value by 10 is 1
add the <tr>. If the remainder is 0 then add a </tr> Then after the loop a </tr> if the remainder is not evenly divisible by 10.
<?php
echo '<table width="100%" border="1px"><tr width="100%">';
$i = 0;
while($row = mysqli_fetch_array($result))
{
$i++;
?>
<?php if ($i%10 ==1): ?><tr><?php endif; ?>
<td width="10%"><?php echo $row['Name']; ?></td>
<?php if ($i%10 ==0): ?></tr><?php endif; ?>
<?php
}
if ($i%10 != 0) echo "</tr>";
echo "</tr></table>";
Using modulo (%)
After each 10th cell, if a new cell is added, the current row is closed and a new row is opened first, before outputting the cell.
<?php
$result = mysqli_query($con,"SELECT * FROM table");
echo '<table width="100%" border="1px"><tr>';
$cell = 0;
while($row = mysqli_fetch_array($result))
{
if ($cell++ % 10 == 0 && $cell > 1)
{
?>
</tr><tr>
<?php
}
?>
<td width="10%"><?php echo $row['Name']; ?></td>
<?php
}
echo "</tr></table>";
mysqli_close($con);
?>
The extra condition && $cell > 1 seems to be a little odd, but without it, you will get an empty row to start with. Eliminating it by putting ++ before $cell will cause the first row to be 9 cells instead of 10. Putting $cell > 0 && in front of the modulo will cause cell never to be incremented, because the first part of the expression is always false. Moving the if to execute it after outputting the cell, would cause the risk of ending with an empty row. It could be solved using a do..while loop, but you'd have to check up front if you have one row at least.
Long story short: use the code above. :)
Using a simple counter and reset it after each row
I think it's even more readable without the modulo, though you'd have to initialize $cell to -1 to prevent the first row to be 9 cells. Nevertheless, I think this is cleaner:
<?php
$result = mysqli_query($con,"SELECT * FROM table");
echo '<table width="100%" border="1px"><tr>';
$cell = -1;
while($row = mysqli_fetch_array($result))
{
if (++$cell == 10)
{
$cell = 0;
?>
</tr><tr>
<?php
}
?>
<td width="10%"><?php echo $row['Name']; ?></td>
<?php
}
echo "</tr></table>";
mysqli_close($con);
?>
<table>
<tr>
<?php
$endRow = 0;
$columns = 10; // number of columns
$hloopRow1 = 0;
do {
if($endRow == 0 && $hloopRow1++ != 0) echo "<tr>";
?>
<td>
<?php echo $row['Name']; ?>
</td>
<?php $endRow++; if($endRow >= $columns) { ?>
</tr>
<?php $endRow = 0; }
} while ($row = mysql_fetch_assoc($result));
if($endRow != 0) {
while ($endRow < $columns) {
echo("<td> </td>");
$endRow++;
}
echo("</tr>");
}
?>
</table>
This should work fine. Hope this helps.
I have a simple table, that echos results of a query, and a bit of PHP that alternates the colour of the rows in the table (could not use CSS3 as I need it to work with IE8) and what I have, works. However, in some cases there aren't any records returned. What is the best way to amend the code, so that if there aren't any records to display, it just says "none". Or is this possible via the mysql query instead.....
<?php $count = 0; do { ?>
<tr>
<?php $count++;?>
<td colspan = "5" class="<?php echo (($count % 2) == 0) ? 'even' : 'odd'; ?>">
<?php echo $row_RecordSet1['result']; ?>
</td>
</tr>
<?php } while ($row_RecordSet1 = mysql_fetch_assoc($RecordSet1)); ?>`
Trying to stick with your coding style, I guess this is how I would do it...
<?php $count = 0; ?>
<?php while ($row_RecordSet1 = mysql_fetch_assoc($RecordSet1)) { ?>
<?php $count++;?>
<tr>
<td colspan="5" class="<?php echo (($count % 2) == 0) ? 'even' : 'odd'; ?>"><?php echo $row_RecordSet1['result']; ?></td>
</tr>
<?php } ?>
<?php if ($count == 0) { ?>
<tr>
<td colspan="5">No results found.</td>
</tr>
<?php } ?>
Firstly I'd suggest you use a while loop, you could still maintain your $count variable.
$count = 0;
while($row_RecordSet1 = mysql_fetch_assoc($RecordSet1)){
//this way, if the recordset is empty -- the loop will never run
++$count;
//your normal processing continues here
}
if($count === 0){
//there was no content or result from the database
echo '<tr><td>None</td></tr>';
}
I believe that should solve your problem.
Before displaying your results, you can check the number of rows with mysql_num_rows(BTW , read carefully the warning in red about mysql extension !)
if(mysql_num_rows($RecordSet1) == 0) {//no results
//display none
} else {
//display your results
}
I have a while loop which displays records in a table. Works OK, but there is an extra table row at the top of the table which is empty.
<table width="100%" border="0" cellpadding="5">
<?php do {
$count++;
?>
<tr bgcolor=<?php echo processRow($count); ?>>
<td><?php echo $row['title']; ?></td>
<td width="8%">edit</td>
<td width="12%">delete</td>
</tr>
<?php
if($count == 2){
$count = 0;
}
} while ($row = mysql_fetch_assoc($result));
?>
</table>
The first time the loop starts $row = mysql_fetch_assoc($result) is not yet executed therefore no result is being fetched.
Add $row = mysql_fetch_assoc($result); at the beginning of the file (before the loop) or convert the do-while loop into a while to solve the problem.
the do {} while() construct goes over the contents of the block first, before evaluating what is passed to while. if you write it like this, is should get rid of the empty row:
<?php while ($row = mysql_fetch_assoc($result)): ?>
<? $count++; ?>
<tr bgcolor=<?php echo processRow($count); ?>>
<td><?php echo $row['title']; ?></td>
<td width="8%">edit</td>
<td width="12%">delete</td>
</tr>
<?php
if($count == 2){ $count = 0; }
endwhile;
?>
I need to generate a table with php, that will display the images - names stored on database. It has to display 3 images in a row. The images are added to the database all the time, so I need that to be automatically generated, instead of hard coding the tables. I am not sure how do I do that? Please help!
You need to cycle the result recordset and print out the new row every 3rd element.
For example:
<table>
<tr>
<?php $i=0; foreach ($images as $image): ?>
<td><?php echo $image['name'] ?> <img src="<?php echo $image['path'] ?>" /></td>
<?php if(++$i%3==0): ?>
</tr><tr>
<?php endif ?>
<?php endforeach ?>
</tr>
</table>
suppose u get the all images name from database in an array
$img_array = array(
1=>'f.jpg',
2=>'s.jpg',
3=>'t.jpg',
4=>'f.jpg',
5=>'e.jpg'
);
// now create dynamic table via php
<table border="1" cellpadding="2" cellspacing="2" width="100%">
<tr>
<?php
$i=0;
foreach($img_array as $k){
if($i%3==0) { ?> </tr><tr> <?php } ?>
<td><img src="<?php echo $k?>" border="0"></td>
<?php $i++; } ?>
</tr>
</table>
Note: please write full path of image in src before <?php echo $k?>
Iterate the image records, using modulo 3 to change to the next table row.
Something like:
echo '<table><tr>';
foreach ($images) {
echo '<td>$image</td>';
if ($i % 3 == 0) {
echo '</tr><tr>';
}
}
echo '</tr></table>';
A simple table like that would be like
<table>
<tr><td>1</td><td>2</td><td>3</td></tr>
<tr><td>1</td><td>2</td><td>3</td></tr>
</table>
To generate this automatically you need to store where you are in the table, first col, 2nd col or 3th col.
<?php
$pos = 1;
print "<table>"
for ($i=0; $i<=10;$i++)
{
if ($pos==1)
{
print "<tr><td>1</td>";
$pos=2;
}
else if ($pos==2)
{
print "<td>2</td>";
$pos=3;
}
else if ($pos==3)
{
print "<td>3</td></tr>";
$pos=1;
}
}
if ($pos==2 || $pos==3)
print "</tr>";
print "</table>"
Keep in mind that if you use the options with $i%3 from the other comments, that your table will start end/or finish with an empty row. This would need additional checks. The $i%3 will give the remainder of the division of $i and 3. So when $i/3 == 0, means it is true on every third row.