PHP str_replace - php

Question

I'm currently using str_replace to remove a usrID and the 'comma' immediately after it:
For example:
$usrID = 23;
$string = "22,23,24,25";
$receivers = str_replace($usrID.",", '', $string); //Would output: "22,24,25"
However, I've noticed that if:
$usrID = 25; //or the Last Number in the $string
It does not work, because there is not a trailing 'comma' after the '25'
Is there a better way I can be removing a specific number from the string?
Thanks.

Answer 1

YOu could explode the string into an array :
$list = explode(',', $string);
var_dump($list);
Which will give you :
array
0 => string '22' (length=2)
1 => string '23' (length=2)
2 => string '24' (length=2)
3 => string '25' (length=2)
Then, do whatever you want on that array ; like remove the entry you don't want anymore :
foreach ($list as $key => $value) {
if ($value == $usrID) {
unset($list[$key]);
}
}
var_dump($list);
Which gives you :
array
0 => string '22' (length=2)
2 => string '24' (length=2)
3 => string '25' (length=2)
And, finally, put the pieces back together :
$new_string = implode(',', $list);
var_dump($new_string);
And you get what you wanted :
string '22,24,25' (length=8)
Maybe not as "simple" as a regex ; but the day you'll need to do more with your elements (or the day your elements are more complicated than just plain numbers), that'll still work :-)
EDIT : and if you want to remove "empty" values, like when there are two comma, you just have to modifiy the condition, a bit like this :
foreach ($list as $key => $value) {
if ($value == $usrID || trim($value)==='') {
unset($list[$key]);
}
}
ie, exclude the $values that are empty. The "trim" is used so $string = "22,23, ,24,25"; can also be dealt with, btw.

Answer 2

Another issue is if you have a user 5 and try to remove them, you'd turn 15 into 1, 25 into 2, etc. So you'd have to check for a comma on both sides.
If you want to have a delimited string like that, I'd put a comma on both ends of both the search and the list, though it'd be inefficient if it gets very long.
An example would be:
$receivers = substr(str_replace(','.$usrID.',', ',', ','.$string.','),1,-1);

Answer 3

An option similar to Pascal's, although I think a bit simipler:
$usrID = 23;
$string = "22,23,24,25";
$list = explode(',', $string);
$foundKey = array_search($usrID, $list);
if ($foundKey !== false) {
// the user id has been found, so remove it and implode the string
unset($list[$foundKey]);
$receivers = implode(',', $list);
} else {
// the user id was not found, so the original string is complete
$receivers = $string;
}
Basically, convert the string into an array, find the user ID, if it exists, unset it and then implode the array again.

Answer 4

I would go the simple way: add commas around your list, replace ",23," with a single comma then remove extra commas. Fast and simple.
$usrID = 23;
$string = "22,23,24,25";
$receivers = trim(str_replace(",$usrID,", ',', ",$string,"), ',');
With that said, manipulating values in a comma separated list is usually sign of a bad design. Those values should be in an array instead.

Answer 5

Try using preg:
<?php
$string = "22,23,24,25";
$usrID = '23';
$pattern = '/\b' . $usrID . '\b,?/i';
$replacement = '';
echo preg_replace($pattern, $replacement, $string);
?>
Update: changed $pattern = '/$usrID,?/i'; to $pattern = '/' . $usrID . ',?/i';
Update2: changed $pattern = '/' . $usrID . ',?/i to $pattern = '/\b' . $usrID . '\b,?/i' to address onnodb's comment...

Answer 6

Simple way (providing all 2 digit numbers):
$string = str_replace($userId, ',', $string);
$string = str_replace(',,','', $string);