I have this function :
<?php
function getmypost($number)
{
query_posts('p=1828');
while (have_posts()) : the_post();
the_title('<h1>', '</h1>');
the_content();
endwhile;
}
?>
I need to make the 1828 as a variable
I have tried this:
query_posts('\'p='. $number .'\'');
But it does not work. What would be the right way to do this?
If I understand you correctly
query_posts('p='.$number);
should work.
If you need a single quote ' in the string you'd escape the '
query_posts('p=\''.$number.'\'');
or using double quotes (more elegant, and you can put the variable straight in. Dominik already suggested this in his answer)
query_posts("p='$number'");
You could use
query_posts("'p=$number'");
Related
I'm using WordPress. I appreciate being shown the code, but this is one I am interested in straight out learning how to do myself too - so if you know where I can find a tutorial or can give me information I'd appreciate it!
I'm calling posts and want to include a PHP code within a PHP code, this is for a theme options panel.
<?php
query_posts('cat=-51&posts_per_page=3&paged='.$paged);
if (have_posts()) :
?>
Where the 51 is I want to put:
<?php echo get_option('to_postc_home'); ?>
Where the 3 is I want to put:
<?php echo get_option('to_posti_home'); ?>
If I'm interpreting right, this is what you need, use the concatenation operator . to use those functions in place of plain text ex: 'this is text' versus 'this '.get_option('stuff').' text'
<?php
query_posts('cat='.get_option('to_postc_home').'&posts_per_page='.get_option('to_posti_home').'&paged='.$paged);
if (have_posts()) :
?>
To include a php file from another file you use the include function
You can use it whereever you want
<?php
query_posts('cat=-51&posts_per_page=3&paged='.$paged);
if (have_posts()) :
?>
hello world
<?php echo get_option('to_postc_home');
endif;
<?php
$a = get_option('to_postc_home');
$b = get_option('to_posti_home');
query_posts("cat={$a}&posts_per_page={$b}&paged={$paged}");
if (have_posts())
?>
That is called string concatenation, and you are already using that on the first line of your code, when you concatenate the literal string 'cat=-51&posts_per_page=3&paged=' with the variable $paged. In PHP, the . operator does that.
So, in your code, you can do this:
<?php
query_posts('cat=-' . get_option('to_postc_home') . '&posts_per_page=' . get_option('to_posti_home') . '&paged='.$paged);
?>
This will inject the output of the function calls at the places you indicated.
<?php
$cat = get_option('to_postc_home');
$per_page = get_option('to_posti_home');
query_posts("cat=${cat}&posts_per_page=${per_page}&paged=".$paged);
if (have_posts())
?>
In a little trouble with this, is they any way i can get to echo's working together see code below,
<?php $youtube_vimeo_player = get_post_meta($post->ID,'_youtube_vimeo_player',TRUE); ?>
<?php echo $video->embed(' <?php echo $youtube_vimeo_player['url']; ?> ', '', ''); ?>
I'm wanting the info brought from the vimeo_player url to be entered into the video->embed section.
Any help on this would much be appreciated : )
try it like this:
<?php $youtube_vimeo_player = get_post_meta($post->ID,'_youtube_vimeo_player',TRUE); ?>
<?php echo $video->embed( $youtube_vimeo_player['url'], '', ''); ?>
Replace
' <?php echo $youtube_vimeo_player['url']; ?> '
with
"{$youtube_vimeo_player['url']}"
You dont need echoing inside the php string. Note that { and } are the special way to embed array index, or object method call into the string, they are not present in final string.
Btw, it's sufficient to just do
echo $video->embed($youtube_vimeo_player['url'], '', '');
As $youtube_vimeo_player['url'] already shoud be the string
<?php echo $video->embed("'".$youtube_vimeo_player['url']."'", '', ''); ?>
PHP isn't that crazy, but thanks for remembering us it could seem to.
Thou shall write:
<?php
$youtube_vimeo_player = get_post_meta($post->ID,'_youtube_vimeo_player',TRUE);
$url=$youtube_vimeo_player['url'];
$video->embed($url, '', '');
?>
Educate yourself on the concept of variable, and remember, php has only one level of embedding (that is one level of <?php ... ?> — no nesting)
And believe it, it's better this way.
<?php
$total=3;
echo '
<div class="idsdiv">.$total.<div> ';
?>
i want to appear $total variable number in the link.why is this script not working?
Enclose the whole string with double quotes to embed variables inside:
echo "<div class=\"idsdiv\">$total<div>";
You need to use double quotes around your HTML and single quotes around your attributes or do this...
echo '<div class="idsdiv">' . $total . '<div> ';
PHP doesn't process variable names in strings enclosed in single quotes.
<?php
$total=3;
echo '<div class="idsdiv">',$total,'<div>';
?>
Look at the string section of php.net (http://php.net/string) they talk about how to use each of the types. One of quote being the ' where nothing is parsed.
<?php $total=3;
echo "<div class=\"idsdiv\">$total<div> ";
?>
you had errors with your quotes
You can print HTML without printing it, like so:
<?php
$total = 3;
?>
<div class="idsdiv"><?php echo $total; ?></div>
When I still did PHP, I found it much easier to manage than escaping tons of quotes and things like that.
You can even do it inside of an if block too:
<?php
if ($foo == 'bar') {
?>
<div>Foo is bar</div>
<?php
}
?>
The method I like is
<?php
$total=3;
echo "<div class='idsdiv'><a href='profile.php?id={$total}'>{$total}</a><div>";
?>
It is my method, but there are plenty of ways to do it. Maybe even too many. If you want more information you can always refer to the documentation.
<?php
$total=3;
echo '<div class="idsdiv">'.$total.'<div>';
?>
You're quote are missing before and after the $total
Simple question, but couldn't find the answer.
When the function 'enkelpost'is called anywhere in WP the passed value($one_p) is gonne be the post ID displayed. But how to put this in the function itself. This is in the functions.php:
<?php
function enkelpost($one_p)
{
query_posts('p= $one_p '); //how to make line this work?
while (have_posts()) : the_post();
global $more; $more = FALSE;
the_content('Read more...');
endwhile;
}
?>
Lets say we want the singe post with id 150:
<?php enkelpost('150') ?>
Variables are not parsed when they are enclosed with single quote, put them in double quotes.
query_posts("p= $one_p");
OR
Do not use quotes for variables at all
query_posts("p=".$one_p);
Well I think this will be easier way!
<?php if (function_exists('enkelpost')): ?>
I'm calling a function like this:
<?php print get_thumbnail('http://url.com/?skin=rss'); ?>
Being a php newbie, I'm wondering if there is a way to change the http://url.com part based on a custom metadata I have set up in Wordpress. So I guess it would look something like this:
<?php print get_thumbnail('<?=$video_src?>/?skin=rss'); ?>
Is something like this possible?
Yes, you have the right idea, you just don't need to re-open PHP tags since you're already inside some. You can use . to concatenate (join together) the value of $video_src and "?skin=rss".
<?php print get_thumbnail($video_src . "?skin=rss"); ?>
Try this:
<?php print get_thumbnail($video_src . '/?skin=rss'); ?>
Keep in mind that <?= $foo ?> is shorthand for <?php echo $foo; ?>. <?= ?> won't be expanded in strings, but you can achieve something similar using double quoted strings:
<?php print get_thumbnail("$video_src/?skin=rss"); ?>
Yes, except within PHP, you don't need to enter the PHP tags again.
<?php print get_thumbnail($video_src . '/?skin=rss'); ?>