Why PHP is not showing exception? - php

I am using following code. When the query crashes, it is not displaying the ALERT that I defined in the "catch" block.
<?php
error_reporting(E_ALL ^ E_NOTICE);
require_once("../Lib/dbaccess.php");
//Retrieve values from Input Form
$CategoryName = $_POST["inCategory"];
$TotalMembers = $_POST["inTotalMembers"];
$Details = $_POST["inDetails"];
$CategoryName = $_POST["inCategory"];
$Chairman = $_POST["inChairman"];
$InsertQuery = "REPLACE INTO electioncategorymaster (ecname, ecdescription, ectotalmembers, ecchairman, lastupdated) VALUES ('".$CategoryName."','".$Details."',".$TotalMembers.",'".$Chairman."',now())";
try
{
$Result = dbaccess::InsertRecord($InsertQuery);
}
catch(exception $ex)
{
echo "<script type='text/javascript'>alert('".$ex."');</script>";
}
?>

If you want to get the message of the exception, you should use :
$ex->getMessage();
And not only $ex.
Also, you should escape the quotes in that string, to be sure to have some valid Javascript string -- addslashes might help, here.
If that doesn't change a thing :
are you sure there is an exception thrown ?
can you take a look at the output of your script ? ("view source" in your browser)
Also, if you want to get the full stack-trace of the exception, you might want to use something like this, instead of doing a JS alert :
echo '<pre>';
var_dump($ex);
echo '</pre>';
And, as always : installing the great Xdebug extension can help a lot, on a development server ;-)

For future reference, when outputting values to JavaScript from PHP it's usually best just to use json_encode. This removes the need to encapsulate it in quotes and escape it.

Related

Get attribute with file_get_contents PHP

I have a sql query that I store in a variable and I displayed. I get the contents of this with file_get_contents from another file, I would like to recover some of this code (which is html) in order to make link. More precisely retrieve the id.
My api.php
$base = mysql_connect ('localhost','root','');
mysql_select_db('administrations', $base);
if(isset($_GET['cp']))
{
$sql = 'SELECT NOM_organisme, ID_organisme
FROM organismes
WHERE code_postal LIKE "%'.$_GET['cp'].'%"
ORDER BY NOM_organisme;';
$req = mysql_query($sql) or die('SQL Error !<br>'.$sql.'<br />'.mysql_error());
}
while ($data = mysql_fetch_array($req))
{
echo '<p id="'.$data['ID_organisme'].'"'.
$data['NOM_organisme'].'</br>'.
$data['ID_organisme'].'</p></br>';
}
I want to get the id="I WANT THIS".
And my index.php (part of my code that retrieves the contents).
if(isset($_POST['cp']))
{
$api = "http://mywebsite.fr/api.php?cp=".$_POST['cp'];
$var = file_get_contents($api);
echo $var;
}
How can I get the id="" in my index.php ?
please look at php get documentation. you need to link to your script with url parameters and access them in your php code.
http://php.net/manual/en/reserved.variables.get.php
echo ''.$data['NOM_organisme'].'</br>'.$data['ID_organisme'].'</br>';
php
if(isset($_GET['id']))
{
$api = "http://mywebsite.fr/api.php?cp=".$_GET['id'];
$var = file_get_contents($api);
echo $var;
}
if you dont want to use url parameter you can use post values
http://php.net/manual/en/reserved.variables.post.php
I understand what your trying to do, but dont find it logical without knowing the purpose of this tiny code :)
Do you have a link or some sort?
Basicly what i should do is:
$base = mysql_connect ('localhost','root','');
mysql_select_db('administrations', $base);
if(isset($_POST['cp']))
{
$sql = 'SELECT NOM_organisme, ID_organisme FROM organismes WHERE code_postal LIKE "%'.$_GET['cp'].'%" ORDER BY NOM_organisme;';
$req = mysql_query($sql) or die('SQL Error !<br>'.$sql.'<br />'.mysql_error());
while ($data = mysql_fetch_array($req))
{
echo '<p id="'.$data['ID_organisme'].'"'.$data['NOM_organisme'].'</br>'.$data['ID_organisme'].'</p></br>';
}
} else {
echo 'show something else';
}
If I get you correctly, you are
Sending a GET request in index.php using file_get_contents() to your website.
The website (api.php) performs an SQL query and prints the result in HTML.
index.php takes this HTML output and stores it in the variable $var.
You want to retrieve all values contained inside the id attribute of the paragraph.
In this case, you probably want to use regular expressions. preg_match_all seems to be appropriate. It should work for you like this:
$out = array();
preg_match_all("/id=\"([^\"]*?)\"/U", $var, $out);
foreach ($out as $value) {
echo 'I found some id ' . htmlspecialchars($out[$value][2]) . '<br />';
}
And additionally:
A decent HTML parser would be much more appropriate in this case (eg. it would not match id="X" in flow text).
Your PHP code is vulnerable to SQL injections.
You should sanitize plain text to HTML appropriately.
First of all, you should try to display your API reply as a JSON-string, this is much more convenient.
If you still want to use your api.php, you first need to close your opening paragraph! You did forget a '>'!
echo '<p id="'.$data['ID_organisme'].'">'.
$data['NOM_organisme'].'</br>'.
$data['ID_organisme'].'</p></br>';
Then you need to parse your paragraph.
You can do it like that:
if(isset($_POST['cp']))
{
$api = "http://mywebsite.fr/api.php?cp=".$_POST['cp'];
$var = file_get_contents($api);
preg_match("#<p id='(.*)'#", $var, $matches);
id = $matches[1];
echo $id;
}

json encode using php not able to get [] brackets

here is my code
<?
include '../dbConnect.php';
$amp=trim($_POST['amp']);
//$amp='AMP8';
//$sql=mysql_query("select tblRepairQueue.ackNo,tblRepairQueue.repairStatus,tblRepairQueue.savedAt from tblRepairQueue,AMPcustomers where AMPcustomers.phone1=tblRepairQueue.phoneNo and AMPcustomers.id='".$amp."'");
$sql=mysql_query("select phone1 from AMPcustomers where id='".$amp."'");
$response = array();
while($row=mysql_fetch_array($sql))
{
$sql_query=mysql_query("select ackNo,repairStatus,savedAt from tblRepairQueue where phoneNo='".$row['phone1']."'");
while($row1=mysql_fetch_array($sql_query)){
$ackNo=$row1['ackNo'];
$repairStatus=$row1['repairStatus'];
$savedAt=$row1['savedAt'];
$response[]=array('ackNo'=>$ackNo,'repairStatus'=>$repairStatus,'savedAt'=>$savedAt);
}}
print json_encode($response);
?>
output m getting as
{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25",{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}
but i want the output to look like
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}]
Can anyone plz help in finding the mistake or what has to be done to get square brackets at the end
This is a bit strange because I have this code:
<?php
$array = array();
$array[] = array("ackNo"=>"26101211236759","repairStatus"=>"Closed and Complete","savedAt"=>"2012-10-26 00:55:25");
$array[] = array("ackNo"=>"26101211236780","repairStatus"=>"Closed and Complete","savedAt"=>"2012-10-26 10:55:25");
echo json_encode($array);
?>
And I get this correct form:
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"26101211236780","repairStatus":"Closed and Complete","savedAt":"2012-10-26 10:55:25"}]
This code should indeed output [{...},...]. So we can't really tell you what went wrong on your side. check the structure of the $response variable before the conversion to Json to see what went wrong.
Note that the code allows SQL injection. You must change it so that the parameters $amp and $row['phone1'] are escaped in the SQL queries. Even if you're relying on magic qoutes now, this solution is not future-proof (now-proof really) as support for this is was removed in PHP 5.4.
What you have written should work:
http://ideone.com/ErV9fr
// How many to add
$response_count=3;
// Your response, just templated
$response_template=array(
'response_number'=>0,
'ackNo'=>'dffdgd',
'repairStatus'=>'$repairStatus',
'savedAt'=>'$savedAt'
);
// Your empty response array
$response = array();
for($i=0;$i<$response_count;$i++) {
$response_template['response_number'] = $i; // Set the 'response number' to the itteration.
$response[]= $response_template; // Add the template to the collection
}
print json_encode($response);
Result:
[{"response_number":0,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"},{"response_number":1,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"},{"response_number":2,"ackNo":"dffdgd","repairStatus":"$repairStatus","savedAt":"$savedAt"}]
In addition to this, you should sanitize your $amp variable. In it's current form it would be trivial for a user to escape your query and execute an arbitrary query against your DB.
http://www.php.net/manual/en/mysqli.real-escape-string.php
Please recheck it can not give you the output like that {"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25",{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}
as it is creating an array of array so it can not print like that.
It will always print like
[{"ackNo":"26101211236759","repairStatus":"Closed and Complete","savedAt":"2012-10-26 00:55:25"},{"ackNo":"031212102614381","repairStatus":"Closed and Complete","savedAt":"2012-12-02 23:05:54"}]

Unable to catch XML exception/error in PHP

I am not able to catch exception with below code. Can anyone help me with this thing?
try
{
$xml_emp_name = $xpath->evaluate("//EMPLOYEES[ID='" . $emp_id . "']/EMP-NAME/text()")->item(0)->nodeValue;
}
catch(Exception $e)
{
echo "Error: " . $e->getMessage();
}
DOMXPath::evaulate does not throw exceptions. domxpath evaluate
If the expression is malformed or the contextnode is invalid, DOMXPath::evaluate() returns FALSE.
Try
$xml_emp_name = $xpath->evaluate("//EMPLOYEES[ID='" . $emp_id . "']/EMP-NAME/text()");
if(!$xml_emp_name){
echo 'Error';
}else{
$name = $xml_emp_name->item(0)->nodeValue;
}
You try to access a property on a non-object if evaulate fails and returns false.
Your code is prone to xpath injection. Fix that first. The error then goes away automatically (because the xpath can not become syntactically invalid). Also you need to check/validate return values.
So you're missing the basic principles of input validation and return value validation. All you need to do is to take more care.
Input validation:
You directly inject the variable $emp_id into the xpath string for substitution:
"//EMPLOYEES[ID='" . $emp_id . "']/EMP-NAME/text()"
However at that place you can not have a single quote inside that string. Instead check the input value (Validation) or filter/streamline it (Sanitization). For exampe, validate that it does not contain a single quote or sanitize for a numeric value. Here the second:
$expression = sprintf('//EMPLOYEES[ID="%d"]/EMP-NAME/text()', $emp_id);
$result = $xpath->evaluate($expression);
This little call to sprintf() takes care that only numeric integer values are being used. They never contain quotes, so the expression is always valid. Invalid values that are no number will become 0. As it's the general principle to never assign the ID 0 this should normally not cause any issue in a well designed system. If you want to do the filtering more granular please see Data Filtering in the PHP manual.
return value validation
In your code you just take over the return value of the result with very little checks (actually no checks). That is wrong. For each method or function you use you need to look it up in the PHP manual and check the documentation for all possible return values. Here the method is DOMXpath::evaluate(), click the link and locate the Return Values section. You find this for each method and function in the PHP manual.
When you read the documentation also figure out which kind of error-handling a method makes use of. Does it throws exceptions (and if yes, which ones?) or does it show an error-condition with it's return value (like in your case)? This information is needed to decide whether to do try/catch as you did (and which is wrong because it does not throw exceptions) or if you need to check the return value:
$expression = sprintf('//EMPLOYEES[ID="%d"]/EMP-NAME/text()', $emp_id);
$result = $xpath->evaluate($expression);
if (!$result) {
throw new Exception(
sprintf('No such employee (id: %s)', var_export($emp_id, true))
);
}
This example turns a falsy return value into an exception with an individual exception message. You also might want to consider a different exception, the SPL offers some pre-defined exceptions.
I hope this answer helps you to deal with this issue and forthcoming ones.
->evaluate will for some reason not throw any exceptions, so what I would advise is to check if the result is false, then throw an exception:
if (($xml_emp_name = $xpath->evaluate("//EMPLOYEES[ID='" . $emp_id . "']/EMP-NAME/text()") ) !== false) {
$xml_emp_name = $xml_emp_name->item(0)->nodeValue;
}
else {
// Throw Exception
}

Always get an empty array in foreach loop

There are two columns in the database table "system". I have the systemId and want to get the mobileSystemId. But the variable $mobileSystemIds which I already defined as global is always empty.
EDIT: Now array_map doesn´t work. I always get my Exception output "Arrayfehler ArrayMap"
I have the following code :
$mobileSystemIds=array();
function getMobileSystemId($systemId)
{
global $mysqli;
global $mobileSystemIds;
$query="SELECT mobileSystemId FROM system WHERE systemId ='" .$systemId ."'";
if(!$result=$mysqli->query($query))
{
echo "Datenbankfehler DB-QUery";
exit(0);
}
if (!$mobileSystemId=$result->fetch_assoc())
{
echo "Datenbankfehler DB-Fetch";
exit(0);
}
$mobileSystemId=$mobileSystemId["mobileSystemId"];
echo "mobile System ID: " .$mobileSystemId ."<br />";
return $mobileSystemId;
}
if(!$mobileSystemIds=array_map("getMobileSystemId",$systemList))
{
echo "Arrayfehler ArrayMap";
}
In this case, using a return in your function would be much cleaner.
Nothing to do with your problem, but is your $systemId var trusted ? (To prevent SQL injection).
Update:
if(!$mobileSystemIds=array_map("getMobileSystemId",$systemList))
{
echo "Arrayfehler ArrayMap";
}
ought to read (just checked; it works for me):
$mobileSystemIds = array_map('getMobileSystemId', $systemsList);
if (empty($mobileSystemIds))
{
if (empty($systemsList) || !(is_array($systemsList)))
echo "OK: no mobile IDs, but no systems either";
else
echo "THIS now is strange :-(";
}
else
{
echo "Alles OK";
var_dump($mobileSystemIds);
}
I tried this by returning a dummy value based on input; if it does not work for you, there must be something strange in the database.
(Update: the text below refers to your original code, which did not use array mapping)
Your code ought to be working as it is. You put several $mobileSystemId 's into a single $mobileSystemId.
It works: I tested with a simpler code, removing the DB calls but leaving your code, and spelling, untouched.
So, the error must be elsewhere. I would guess that this code is included into something else, and:
the $mobileSystemIds = array(); declaration gets executed more than once, thereby losing all its data;
the $mobileSystemIds = array(); declaration is itself included in a more local scope and you read it from outside, reading an empty value or a totally different value.
Try replacing the first part of your code with:
GLOBAL $mobileSystemsIds;
if (defined($mobileSystemsIds))
trigger_error("mobileSystemsId defined more than once", E_USER_ERROR);
else
$mobileSystemsIds = array();
and also, in the function body:
if (!defined($mobileSystemsId))
trigger_error("mobileSystemsId should have been defined", E_USER_ERROR);

Assigning php POST array to Javascript array

I know this may sound similar to some past Q/As, I think mine is slightly different though.. I have a webpage which I want to dynamically load text file information. I upload the text file through an iframe and I want to save this information from php to Javascript. Whenever I try to save this as a regular variable it doesn't work so I have tried to do this by saving this information as a part of the $_POST array under a hidden form named $_POST['hidden_form']. Whenever I try to read the php into Javascript, I keep getting an error "Unexpected token ILLEGAL." I have tried the following two codes:
for($i=0;$i< count($_POST['hidden_form']) ;$i++)
{
echo "saved_form[$i]='" . $_POST['hidden_form'][$i]. "';\n";
}
and
saved_form = <?php echo json_encode($_POST['hidden_form']); ?>;
Assigning a php array into a javascript array
I think the error has to do with the " ' " needed to specify the array but not sure. I have no idea where to go from here so any help would be GREATLY appreciated. If there are better methods to do this please let me know. Thanks in advance!
saved_form = '<?php echo addslashes(json_encode($_POST['hidden_form'])); ?>';
Or
for($i=0;$i< count($_POST['hidden_form']) ;$i++)
{
echo "saved_form[$i]='" . addslashes($_POST['hidden_form'][$i]) . "';\n";
}
Both should work, probably had quotes breaking something?
the best way i have used is,
text/javascript
var saved_form = <?php echo json_encode($_POST['hidden_form']) ?>
Please note there are no Quotes around the php so your saved_form is an Object not a string json string witch would require you to to use var form_object = eval(saved_form)
#Lee might have meant this?
Just a note though i would not use the Raw $_POST pass it to a function that can loop though and addSlashes every value inside the post some thing like
<?php
function arr_addSlashes($array){
$ret = array();
foreach($array as $k => $v){
$ret[$k] = addSlashes($v);
}
return $ret;
}
?>

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