PHP: Populating an array with the names of the next 12 months - php

Question

for($x=0; $x<12; $x++)
{
$month = mktime(0, 0, 0, date("m")+$x, date("d"), date("Y"));
$key = date('m', $month);
$monthname = date('F', $month);
$months[$key] = $monthname;
}
I know for sure I'm doing the math incorrectly for the 4th parameter of mktime. I'm starting with the current month number ( 7 being July ) and adding 1 for each next month, sometimes it ends up being that the same month is returned twice, maybe because I'm not setting it to the beginning of the month? How would you improve/recode this?
Result is that $months would result in an array where 07 = July 08 = August, 09 = September. Right now it populates October twice. I think it has to do with today being the 31st and it incorrectly adds and reaches the next month.

Answer 1

Just fixed your code slightly, this should work pretty well:
$months = array();
$currentMonth = (int)date('m');
for ($x = $currentMonth; $x < $currentMonth + 12; $x++) {
$months[] = date('F', mktime(0, 0, 0, $x, 1));
}
Note that I took out the array key, as I think it's unnecessary, but you can change that of course if you need it.

Answer 2

An alternative would be to use strtotime:
for ($x=0; $x < 12; $x++) {
$time = strtotime('+' . $x . ' months', strtotime(date('Y-M' . '-01')));
$key = date('m', $time);
$name = date('F', $time);
$months[$key] = $name;
}
In my opinion this code is easier to read.

Answer 3

Less complicated, no loops, generic array keys:
function stackoverflow_get_monthname($x){
return date("F",mktime(NULL, NULL, NULL, (int)date("n") + ($x+1), NULL, NULL));
}
$months = array_map("stackoverflow_get_monthname", range(1,12) );
var_dump($months);

Answer 4

Given 2592000 is 30 days.
$month_time = 60*60*24*30; // 30 Days
for($x=0; x<12; $x++)
{
$time = time()+($month_time*$x);
$key = date('m', $time);
$month[$key] = date('F', $time);
}
In an answer on StackOverflow, can't find it right now, someone compared the performance of multiple methods of creating a time 1 week from now. Directly using numbers was much more efficient than any other method.

Answer 5

You might be getting the last day of the month (the 31st) bug - which led to two months with the same link - that Eddy very nicely figured out for me with this answer:
$current_month = date('n');
$MONTHS = array();
for ($m=0; $m<12; $m++) {
$display_month = $m + $current_month;
$MONTHS[] = date('F',mktime(1,1,1,$display_month,1,date("Y")));

Answer 6

"Result is that $months would result in an array where 07 = July 08 = August, 09 = September."
for ($key = 1; $key <=12; $key++) {
$months[str_pad($key, 2, '0', STR_PAD_LEFT)] = date('F', strtotime('2000-' . $key));
}
If you're okay with 7 = July 8 = August, 9 = September, then:
for ($key = 1; $key <=12; $key++) {
$months[$key] = date('F', strtotime('2000-' . $key));
}

Answer 7

Sometime you need to be careful on your locale, so this is my solution (in a function):
$months = [];
for ($x=1; $x < 13; $x++) {
$time = mktime(0, 0, 0, $x, 1);
$key = date('m', $time);
$name = ucfirst(strftime('%B', $time));
$months[(int)$key] = $name;
}
return $months;

Answer 8

Here is a simple script to go forward 12 months from the current date. It includes the year with it.
# Set Number of Months to Traverse
$num_months = 12;
# Set Current Month as the 1st
$current_month = date('Y-m').'-01';
for ($count = 0; $count <= $num_months; $count++) {
# Fetch Date for each as YYYY-MM-01
$dates[] = date('Y-m', strtotime($current_month.' + '.$count.' Months')).'-01';
}
You could turn this into a select list with the current month selected by dropping this in:
echo '<select name="month">';
foreach ($dates as $d) {
echo '<option value="'.$d.'"';
if ($d == date('Y-m').'-01') echo 'selected="selected"';
echo '>'.date('F, Y', strtotime($d)).'</option>';
}
echo '</select>';