I am writing a php function for wordpress that is executed through an XML feed. Therefore we are excepting a feed and then based on the nodes placing those in our website. What I need help with is we have a bunch of different images of credentials (i.e BBB, chamber of commerce etc) What I need therefore is when there is a link to a BBB then it should display a picture, if not then it should be blank. The problem I am running into is because the BBB links will be random based on different businesses. Any help would be greatly appreciated. Thanks.
If URL "pic"
else "no pic"
Do you mean this? Otherwise please explain your problem better.
if (!empty($url)) {
echo '<img src="' .$url. '" />';
}
else {
echo ' ';
}
Check here when empty returns false (and therefore !empty is true) and really consider if this fits your needs.
Maybe I'm missing something, but wouldn't this do?
if($license1) { print "<img src=\"/path/to/bbb.logo\" alt=\"BBB Logo\" />"; }
A method would be creating an array
like $feeds = array("pic","xml");
then testing if its in array like
if in_array($url,$feeds)
// your code;
or the second method would be creating an temp var like $tmp = $url =="pic" ? "pic" : "nopic";
or to set just an boolean $tmp = $url =="pic" ? TRUE : FALSE;
then you can test it like this
if($url) // if its == "pic" it would return true otherwise false
//make your url
Also a shorthand way is to do
But when the given var is an array I think you need to use is_array(), or if it's a class objec,t use is_object() to verify that it has content.
Related
I currently use:
if(strpos($command->href,§current_view) !== false){
echo '<pre>true</pre>';
} else {
echo '<pre>false</pre>';
}
$command->href will output something like this: /path/index.php?option=com_component&view=orders Whereas
§current_view is outputting orders. These outputs are dynamically generated, but the scheme will always be the same.
What I need to do is return true/false if the words from $current_view match the view=orders in the URLs from $command->href. The issue with my code is, that it doesnt match anything.
What is the correct way to do this?
Please note that the $command->href and the whole code is inside a while function, that pass multiple URLs and this only needs to match the same ones.
Breaking it down to a simple example, using your code and variable values.
$current_view = 'orders';
$command = '/path/index.php?option=com_component&view=orders';
if(strpos($command,$current_view) !== false){
echo '<pre>true</pre>';
}
else {
echo '<pre>false</pre>';
}
The oputput is "true".
Now, go and debug the REAL values of $command->href and $current_view...
I'm pretty confident that the values are not what you think they are.
Does something like:
if(substr($command->href, strrpos($command->href, '&') + 6) == $current_view)
accomplish what you are after?
To explain, strpos get the last instance of a character in a string (& for you, since you said it always follows the scheme). Then we move over 6 characters to take "&view=" out of the string.
You should now be left with "orders" == "orders".
Or do you sometimes include some arguments after the view?
Try parsing url, extracting your view query string value and compare it to $current_view
$query= [];
parse_str(parse_url($command->href)['query'], $query);
if($current_view === $query["view"])
echo '<pre>true</pre>';
} else {
echo '<pre>false</pre>';
}
I'm having php script that deals with thousands of queries starting just like (i.e. http://localhost:1234/browse.php?cat=2) so I don't want to write thousands of URLs in an array to deal with if and else condition such as below,
Please guide me how can i make it possible to use "?" sign in my url to distinguish between what command to process if url contains "?" sign.
I used "/browse.php?*" in code as shown in below example but it's not working for me still...Please guide because I'm new in php and search and lot regarding this answer but unable to find a single authentic answer for it, thanks
if(in_array($_SERVER['REQUEST_URI'],array('/browse.php','/browse.php?*')))
{
echo "<Something Like this 1>";
}
elseif ($url == "")
{
echo "<Something Like this 2>";
};
in_array would only check for a full match here and is not appropriate for what you are trying to do. PHP has many String Functions you should look at.
if (strpos($_SERVER['REQUEST_URI'], '?') !== false) {
//URL has '?' mark
}
else{
//URL has no '?' mark
}
I believe you are only concerned with the cat URL search parameter? If so, you can access this parameter in your browse.php script using the $_GET array:
<?php
if (array_key_exists('cat', $_GET)) {
echo "cat parameter: {$_GET['cat']}"; // display ?cat=value
} else {
echo 'No cat URL parameter'; // ?cat was not in the URL
}
?>
http://localhost:1234/browse.php -> No cat URL parameter
http://localhost:1234/browse.php?cat=57890 -> cat parameter: 57890
I used to code with Groovy ... I found that this 'feature' (no idea what they called it) so fun n nice (I heard they implemented this on C# too).
for example ... I want to display person neighbour name
I just type
println person?.neigbour?.name ;
it means if the neighbour is empty / blank .. it didn't display anything .
how to do this in php 5/yii?
example:
instead of typing long codes like
'/>
Would it be better to type like
'/>
In the first place I think this is no Yii issue, but simply PHP. Assuming, that you use Yii with nice models, there it would go sth like this:
if($person && $person->neighbour && !empty($person->neighbour->name)) {
echo $person->neighbour->name;
}
a shortcut for this may be (not so nice):
echo $person ? ($person->neighbour ? ($person->neighbour->name ? $person->neighbour->name : "" ) : "" ) : "";
use empty()
check:
if(!empty($variable))
{
//show fields here
}
I’ve tried for some time now to solve what probably is a small issue but I just can’t seem get my head around it. I’ve tried some different approaches, some found at SO but none has worked yet.
The problem consists of this:
I’ve a show-room page where I show some cloth. On each single item of cloth there is four “views”
Male
Female
Front
Back
Now, the users can filter this by either viewing the male or female model but they can also filter by viewing front or back of both gender.
I’ve created my script so it detects the URL query and display the correct data but my problem is to “build” the URL correctly.
When firstly enter the page, the four links is like this:
example.com?gender=male
example.com?gender=female
example.com?site=front
example.com?site=back
This work because it’s the “default” view (the default view is set to gender=male && site=front) in the model.
But if I choose to view ?gender=female the users should be able to filter it once more by adding &site=back so the complete URL would be: example.com?gender=female&site=back
And if I then press the link to see gender=male it should still keep the URL parameter &site=back.
What I’ve achived so far is to append the parameters to the existing URL but this result in URL strings like: example.com?gender=male&site=front&gender=female and so on…
I’ve tried but to use the parse_url function, the http_build_query($parms) method and to make my “own” function that checks for existing parameters but it does not work.
My latest try was this:
_setURL(‘http://example.com?gender=male’, ‘site’, ‘back’);
function _setURL($url, $key, $value) {
$separator = (parse_url($url, PHP_URL_QUERY) == NULL) ? '?' : '&';
$query = $key."=".$value;
$url .= $separator . $query;
var_dump($url); exit;
}
This function works unless the $_GET parameter already exists and thus should be replaced and not added.
I’m not sure if there is some “best practice” to solve this and as I said I’ve looked at a lot of answers on SO but none which was spot on my issue.
I hope I’ve explained myself otherwise please let me know and I’ll elaborate.
Any help or advice would be appreciated
You can generate the links dynamically using the following method:
$frontLink = (isset($_GET['gender'])) ? 'mydomain.com?gender='.$_GET['gender'].'&site=front':'mydomain.com?site=front';
$backLink = (isset($_GET['gender'])) ? 'mydomain.com?gender='.$_GET['gender'].'&site=back':'mydomain.com?site=back';
This is a 1 line if statement which will set the value of the variables $frontLink and $backlink respectively. The syntax for a 1 line if statement is $var = (if_statement) ? true_result:false_result; this will set the value of $var to the true_result or false_result depending on the return value of the if statement.
You can then do the same for the genders:
$maleLink = (isset($_GET['site'])) ? 'mydomain.com?gender=male&site='.$_GET['site']:'mydomain.com?gender=male';
$femaleLink = (isset($_GET['site'])) ? 'mydomain.com?gender=female&site='.$_GET['site']:'mydomain.com?gender=female';
Found this by searching for a better solution then mine and found this ugly one (That we see a lot on the web), so here is my solution :
function add_get_parameter($arg, $value)
{
$_GET[$arg] = $value;
return "?" . http_build_query($_GET);
}
<?php
function requestUriAddGetParams(array $params)
{
$parseRes=parse_url($_REQUEST['REQUEST_URI']);
$params=array_merge($_GET, $params);
return $parseRes['path'].'?'.http_build_query($params);
}
?>
if(isset($_GET['diagid']) && $_GET['diagid']!='') {
$repParam = "&diagid=".$_GET['diagid'];
$params = str_replace($repParam, "", $_SERVER['REQUEST_URI']);
$url = "http://".$_SERVER['HTTP_HOST'].$params."&diagid=".$ID;
}
else $url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']."&diagid=".$ID;
<?php echo isset($areas['footer']) ? $areas['footer'] : null; ?>
Any way to improve that?
Note that you are echoing and in false condition it would be null which does not have any effect. You could say like 'empty' or ' ' or 'not found' instead. Other alternative is to get the return value of isset:
$return = isset($areas['footer']) ? $areas['footer'] : null;
if ($return)
{
// $return contains footer info
}
else
{
// footer was not set :(
}
Depending on where $areas comes from it might be cleaner to assign it to a variable:
$footer = isset($areas['footer']) ? $areas['footer'] : null;
Then you can use $footer without any additional isset checks.
You can also spare the else branch, by setting a default:
$footer = null;
if (isset($areas['footer'])) {
$footer = $areas['footer'];
}
echo $footer;
No, this is the most concise way of handling this sort of output.
"i'm using this kind of code very often"
Maybe you should avoid the issue altogether by using a template language, or encapsulating this behavior in a function?
like this:
function get_area($area) {
if... //your code
return $area
One shorter version i can think of would be:
<?php !isset($areas['footer']) or print $areas['footer']; ?>
But i'm not sure if it is faster or more elegant.
What do you guys think?
echo $areas['footer'];
Simple and has the exact same effect as the original line.
Edit in reply to Felix
This gives a notice, but unless you're supposed to turn this in as ultra-perfect homework, it doesn't really matter. You can either fill your code with isset calls or ignore small stuff like this. I'd worry about it if I was working in say... Java, but pragmatically nobody is going to care if PHP code that works produces notices.