So I've got a simple query in MySQL that sets a new member's expiration date once they pay their dues:
UPDATE members SET joined=CURDATE(), expires=DATE_ADD(CURDATE(), INTERVAL 1 YEAR), active='1' WHERE id=1000
this query has run 200+ times, normally with the correct result - the current date is put in the joined field, and a year from that date in the expires field. However, in about 10 instances, the expires date has been set to 00-00-0000 with no obvious explanation. I started writing the query to a text file every time to make sure the syntax was correct and I hadn't missed anything - and I didn't - it's exactly that query (with only the ID varying) for every query, those that work, and those that don't.
The only thing I can think here is that there must be an issue with MySQL's DATE_ADD function. Has anyone else experienced anything like this?
UPDATE:
I should add that the joined field is correct with the current date in the cases where the expires date is incorrect.
I'm using MySQL 5.0.81.
There are no triggers.
The table is using MyISAM.
IMPORTANT UPDATE:
I'm an idiot - when I say 11-30-1999 that's not actually what's in the database. I absent-mindedly wrote that, but in fact the database contains the value 00-00-0000 - 11-30-1999 is just how it gets rendered by PHP onto my page. Sorry about that, hopefully that will make this problem less difficult to figure out.
Just a thought.... those "wrong" dates didn't happen to be leap year dates did they.... Feb. 29th for example?
It shouldn't matter, but it may be a bug.
Related
Hi I have a MySQL table of Facebook pages (fbpagesfancount) that has the total fan count by day since 01 Jan 2016.
The structure is like this:-
Pageid, Pagename, Updated_Date, Fan_Count
There are a number of specific days that are missing and do not therefore have fancount values due to Facebook API issues.
The days that are missing are usually single days, for example, there is a value for the day before and the day after.
I'd like to create a new table that has a record for every day since 01/01/2016 for each page (750 pages) and then update the days that are missing by averaging the day before and the day after the missing date.
Is this possible using MySQL only or should I write a script in PHP that performs this task and if so, any suggestions on the logic would be helpful.
Any other suggestions on how to tackle this issue would be welcome.
Thanks
Jonathan
Yes, it is possible in SQL only.
No, you should not attempt it as it is more complicated and for a single shot there's no need.
Yes, write a script in any language you know, for instance PHP.
I'm not sure why you even want to create a new table? You could add a flag to your current table saying its an origional count vs an average, and just find the missing numbers and add them in a script.
I'm in the planning stages of creating a historical database. I will be using PHP, MYSQL and JavaScript for the website.
Often someone will know what year a person was born or picture was taken, but not the month or the day.
Is it possible for a PHP DATE variable and MYSQL DATE to be:
1920-00-00 or 1845-12-00 ?
If not, unless someone has a better idea, I'll have to create a column for year, another column for month, and yet another for day then do a bunch of value checking and combining.
Thoughts?
Thanks.
You need exakt dates for using date in mysql, so you probably have to bite down and filter everything for validating and then some code to combine it.
I'm new to MySQL and PHP but was wondering if someone could help me with a little project I'm doing for my boss.
I have a SQL database (MyDB) and a table in there (mytable) with two columns - the first column (index) is an auto-incrementing integer from 1-10, the second column (date) has different dates and timestamps in the format of Year-month-day time 2013-04-12 1326
I'm trying to create a simple PHP page that first gets the current date (easy enough) then looks at the table and shows the number of rows that fall within yesterday's date. For example, if I have 3 rows with 2013-04-11 XXXX and 2 rows with 2013-04-12 XXXX (and today is the 12th April 2013) the page will display 3. (The time is not important but we can't remove it from the table as it's auto created by one of the other staff's programs and he refuses to change it).
So far I've got my php page, done a connection to the DB and defined two variables:
$startdate = date('Y'."-".'n'."-".'d'." "."0000");
$enddate = date('Y'."-".'n'."-".'d'." "."2359");
As the timestamp doesn't matter I've gone for the min/max possible on the variables. I realise this will only give the current date, trying to work out how to get it to display the previous day as the date in the variable.
Now I'm trying to create a sql query that will count the number of rows where the date field falls within the startdate and enddate variables (-1 day) but not too sure where to start or how this would look. I then need to output this as a variable in PHP so I can echo it later in the page.
Anyone able to point me in the right direction? Hope any of this makes sense.
You could write a query with no params to do this (if its always just yesterday).
SELECT * FROM <table>
WHERE DATE_FORMAT(<date column>,'%j-%Y') = DATE_FORMAT(DATE_SUB(now(),INTERVAL 1 DAY), '%j-%Y');
Date functions in the where clause might not be super awesome performance wise
I'm running into a weird issue where I'm posting a date in Y-m-d format yet it's being changed to a completely different date once I view in the actual MySQL table.
Here's the query
UPDATE $admins_table
SET expire=$expireu
WHERE identity='$donation_row[steam_id]
The expire field is what I'm having issues with. The field itself is a varchar, and the $expireu variable is always a date in Y-m-d format ex. 2013-11-16
When that query is run, with the date I gave as an example above, I get a weird result in the actual MySQL table. If I go to view the table, instead of it storing 2013-11-16 it has stored 1986 as the date. No month or day, just 1986.
I may have made a very stupid/silly mistake, but at this point I'm unsure of what I've flubbed. Any help in the right direction would be much appreciated, thank you.
haha, use quotes!
UPDATE $admins_table SET expire='$expireu' WHERE identity='$donation_row[steam_id]'
mysql substracts 2013-11-16 == 1986
the use of ' and " are your friends. you are passing a math problem into mysql which it is solving and then saving the result of. wrap that date in quotes.
Description:
I am doing purchasing function, whenever the users make purchases, it will add 1 month privilege to my access special page of my site. I have received some complaints from my users, please read the problem section.
Problem:
Out of 500 users, there are few users, that for example: make purchase today, but the expiration day goes backward, 1 or 2 days, or even months. For example: He purchased on 3 August 2010, the expiration date is 25 May 2010.
My Php code:
The code that I am using to add 1 month before insert into mysql database is:
// I already set the default timezone
$expiryDate = date("Y-m-d H:i:s",strtotime("+1 month"));
I am not sure if its the code is wrong, my server is wrong or the third-party payment gateway is wrong, please advise me how to solve it.
!important question!
What are the possible causes, that can cause the expiration date goes backward?
If you're storing the expiry time in the database as a date or datetime field, then you should do the update there:
UPDATE table SET expiry=DATE_ADD(expiry, INTERVAL 1 MONTH) WHERE ...;
Full details here.
There are issues using +1 month with strtotime, there are some solutions on the function document page. However if i were you i would use a tested library like Zend_Date. You could use the sql as suggested but im going to guess thats going to depart from how you organized your DB specific code.