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I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";
I have dates that are being stored in the database like this:
08-11-2013
(That's Day, Month year BTW) Is there a way (without changing the database entries) to output this on a page like this instead...
8th November, 2013
Cheers.
FYI, this would be a lot easier if you stored your dates in MySQL standard Date format.
Use MySQL's DATE_FORMAT() with STR_TO_DATE()
SELECT DATE_FORMAT(STR_TO_DATE(datecol, "%d-%m-%Y"), "%D %M, %Y")
But if you have to do it with PHP you can use DateTime::createFromFormat()
$dt = DateTime::createFromFormat('08-11-2013', "d-m-Y");
echo $dt->format('jS M, Y');
While other's answers are valid, this will output the date in the exact format you asked for in your question.
$date = '08-11-2013';
$prettydate = date('jS F, Y', strtotime($date));
echo $prettydate;
In PHP try
<?php
$olddate = '2012-07-18';
$date = new DateTime($olddate);
echo $date->format('jS F, Y');
?>
Also try to read Convert date format yyyy-mm-dd => dd-mm-yyyy
Enjoy coding! :D
This question already has answers here:
Convert from MySQL datetime to another format with PHP
(18 answers)
Closed 2 years ago.
I have a date time in a variable. My format is 08/04/2010 22:15:00. I want to display this like 10.15 PM. How to do this in PHP?
You need to convert it to a UNIX timestamp (using strtotime) and then back into the format you require using the date function.
For example:
$currentDateTime = '08/04/2010 22:15:00';
$newDateTime = date('h:i A', strtotime($currentDateTime));
$dateString = '08/04/2010 22:15:00';
$dateObject = new DateTime($dateString);
echo $dateObject->format('h:i A');
Use strtotime() to make the date a UNIX timestamp.
For output, check out the various options of date().
$timestamp = strtotime("08/04/2010 22:15:00");
date("h.i A", $timestamp);
<?php
$dateTime = new DateTime('now', new DateTimeZone('Asia/Kolkata'));
echo $dateTime->format("d/m/y H:i A");
?>
You can use this to display the date like this
22/06/15 10:46 AM
Like this:
$date = '08/04/2010 22:15:00';
echo date('h:i A', strtotime($date));
Result:
10:15 PM
More Info:
date
strtotime
for flexibility with different formats, use:
$dt = DateTime::createFromFormat('m/d/Y H:i:s', '08/04/2010 22:15:00');
echo $dt->format('g:i A')
Check the php manual for additional format options.
PHP Code:
date_default_timezone_set('Asia/Kolkata');
$currentDateTime=date('m/d/Y H:i:s');
$newDateTime = date('h:i A', strtotime($currentDateTime));
echo $newDateTime;
Output: 05:03 PM
$currentDateTime = $row['date'];
echo $newDateTime = date('l jS \of F Y h:i:s A', strtotime($currentDateTime));
Perfect answer for AM/PM live time solution
<?php echo date('h:i A', time())?>
Just simply right A
{{ date('h:i A', strtotime($varname->created_at))}}
For (PHP >= 5.2.0):
You can use DateTime class. However you might need to change your date format. Didn't try yours.
The following date format will work for sure: YYYY-MM-DD HH-MM-SS
$date = new DateTime("2010-04-08 22:15:00");
echo $date->format("g"). '.' .$date->format("i"). ' ' .$date->format("A");
//output
//10.15 PM
However, in my opinion, using . as a separator for 10.15 is not recommended because your users might be confused either this is a decimal number or time format. The most common way is to use 10:15 PM
It is quite easy. Assuming you have a field(dateposted) with the type "timestamp" in your database table already queried and you want to display it, have it formated and also have the AM/PM, all you need do is shown below.
<?php
echo date("F j, Y h:m:s A" ,strtotime($row_rshearing['dateposted']));
?>
Note: Your OUTPUT should look some what like this depending on the date posted
May 21, 2014 03:05:27 PM
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";