getting image src in php - php

Question

how to get image source from an img tag using php function.

Answer 1

Or, you can use the built-in DOM functions (if you use PHP 5+):
$doc = new DOMDocument();
$doc->loadHTMLFile($url);
$xpath = new DOMXpath($doc);
$imgs = $xpath->query("//img");
for ($i=0; $i < $imgs->length; $i++) {
$img = $imgs->item($i);
$src = $img->getAttribute("src");
// do something with $src
}
This keeps you from having to use external classes.

Answer 2

Consider taking a look at this.
I'm not sure if this is an accepted method of solving your problem, but check this code snippet out:
// Create DOM from URL or file
$html = file_get_html('http://www.google.com/');
// Find all images
foreach($html->find('img') as $element)
echo $element->src . '<br>';
// Find all links
foreach($html->find('a') as $element)
echo $element->href . '<br>';

Answer 3

You can use PHP Simple HTML DOM Parser (http://simplehtmldom.sourceforge.net/)
// Create DOM from URL or file
$html = file_get_html('http://www.google.com/');
// Find all images
foreach($html->find('img') as $element) {
echo $element->src.'<br>';
}
// Find all links
foreach($html->find('a') as $element) {
echo $element->href.'<br>';
}

Answer 4

$path1 = 'http://example.com/index.html';//path of the html page
$file = file_get_contents($path1);
$dom = new DOMDocument;
#$dom->loadHTML($file);
$links = $dom->getElementsByTagName('img');
foreach ($links as $link)
{
$re = $link->getAttribute('src');
$a[] = $re;
}
Output:
Array
(
[0] => demo/banner_31.png
[1] => demo/my_code.png
)