I am trying to use url rewriting on my website and I want to use the list() and explode() functions to get the right content.
Currently my code looks like this:
list($dir, $act) = explode('/',$url);
In this case $url is equal to everything after the first slash in the absolute url i.e. http://example.com/random/stuff => $url = random/stuff/ this would work fine, but if I want to go to http://example.com/random/ then it will print a notice on the page. How do I stop the notice from showing up do I need to use something other than the list() function?
Right now the notice is "Notice: Undefined offset: 1..."
Thanks for the help!
Try this :
list($dir, $act) = array_pad(explode('/',$url), 2, '');
array_pad complete the array with your values, here is : ''.
You should check how many path segments the URL contains:
$segments = explode('/', $url);
if (count($segments) !== 2) {
// error
} else {
list($dir, $act) = $segments;
}
But maybe you should choose a more flexible approach than using list.
Check out parse_url
A solution would be to split your line of code in several, to ensure you never assign non-existing values to variables -- which is what you are doing when explode only returns one portion of URL.
For that, not using list seems like the right solution, as, with list, you must know how many elements the expression on the right of = will return...
And, in this situation, you don't know how many elements explode will return.
For instance, something like this might be OK :
$parts = explode('/', $url);
if (isset($parts[0])) {
$dir = $parts[0];
if (isset($parts[1])) {
$act = $parts[1];
}
}
Of course, up to you to deal with the situation in which $dir and/or $act are not set, later in your script.
Another solution would be to check how many elements explode will return (counting a number of / for instance) ; but you'll still have to deal with at least two cases.
to get rid of the notice:
list($dir, $act) = explode('/',$url);
but maybe a better solution would be:
$segments = explode ('/', $url);
$dir = array_shift ($segments);
$act = array_shift ($segments);
if there is no 2nd segment, $act would be null and you can also more than 2 segment this way
The correct way to suppress the E_NOTICE on list assignment as of PHP 5.4+ is the following:
#list($dir, $act) = explode('/', $url);
If $url contains no /, explode will return one element and $act will be NULL.
Instead of exploding the full URL, try $_SERVER['PATH_INFO'], assuming '/random' names the script.
The simple and ugly answer is to prefix the whole thing with a single '#' which suppresses error outputs. $act will be set to null in that case because under the hood, it's equivalent to:
$foo = explode('/',$url);
$dir = $foo[0];
$act = $foo[1]; // This is where the notice comes from
Related
Well sorry for the probably misleading title. Wasn't sure how to describe it better.
When accessing the status page I want to get the attached ID. But I don't want to use GET fields (wordpress makes /status?id=2134 to /status/?id=1234 - that's the only reason actually).
So this is my url
http://foo.bar.com/status/1234/
I want to get 1234
Okay fine. I could use something like $_SERVER["REQUEST_URI"] + trim() for example. Probably regex would be the key to get this job done since one could do something like /status/1234/foo/bar/baz/.. But I'm wondering if there is something builtin with PHP to get this part of the url.
Use the parse_url() function, and extract it:
$url = 'http://foo.bar.com/status/1234/';
$path = trim(parse_url($url, PHP_URL_PATH), '/');
$items = explode('/', $path);
$num = array_pop($items);
var_dump($num);
You can also use a regular expression, if that tickles your fancy:
$url = 'http://foo.bar.com/status/1234/';
$path = parse_url($url, PHP_URL_PATH);
preg_match('~/status/(?P<num>\d+)/?~', $path, $result);
$num = isset($result['num']) ? $result['num'] : null;
var_dump($num);
Try to parses a URL and returns an associative array containing any of the various components of the URL that are present using parse_url, explode it using explode and finally select status id using end
Try like this
$url = 'http://foo.bar.com/status/1234/';
$statusId = explode('/',trim(parse_url($url, PHP_URL_PATH), '/'));
print end($statusId);
Demo Ex http://ideone.com/34iDnh
trim- http://php.net/trim
explode-http://php.net/explode
parse_url-[1]: http://php.net/manual/en/function.parse-url.php
$url = explode('/', $articleimage);
$articleurl = array_pop($url);
I have used the above method to get the last part of a URL.Its working.But I want to remove the last part from the URL and display the remaining part.Please help me.Here I am mentioning the example URL.
http://www.brightknowledge.org/knowledge-bank/media/studying-media/student-media/image_rhcol_thin
Try this:
$url = explode('/', 'http://www.brightknowledge.org/knowledge-bank/media/studying-media/student-media/image_rhcol_thin');
array_pop($url);
echo implode('/', $url);
There is no need to use explode, implode, and array_pop.
Just use dirname($path). It's a lot more efficient and cleaner code.
Use the following string manipulation from PHP
$url_without_last_part = substr($articleimage, 0, strrpos($articleimage, "/"));
For Laravel
dirname(url()->current())
In url()->current() -> you will get current URL.
In dirname -> You will get parent directory.
In Core PHP:
dirname($currentURL)
after the array_pop you can do
$url2=implode("/",$url)
to get the url in a string
Change this:
$articleurl = array_pop($url);
Into this:
$articleurl = end($url);
$articleurl will then hold the last array key.
Missed the part where you want to remove the value, you can use the function key() to get the key and then remove the value using that key
$array_key = key($articleurl);
unset(url[$array_key])
Pretty simple solution add in the end of your code
$url = implode('/', $url);
echo $url;
Notice that array_pop use reference argument passing so array will be modifed implode() function does the opposite to explode function and connects array elements by first argument(glue) and returns the string.
It looks like this may be what you are looking for. Instead of exploding and imploding, you can use the parsing functions which are designed to handle exactly this kind of URL manipulation.
$url = parse_url( $url_string );
$result =
$url['scheme']
. "://"
. $url['host']
. pathinfo($url['path'], PATHINFO_DIRNAME );
Here's the simple way to achieve
str_replace(basename($articleimage), '', $articleimage);
For the one-liners:
$url = implode('/', array_splice( explode('/', $articleimage), 0, -1 ) );
$url[''] and enter the appropriate number
i have this URI.
http://localhost/index.php?properties&status=av&page=1
i am fetching basename of the URI using following code.
$basename = basename($_SERVER['REQUEST_URI']);
the above code gives me following string.
index.php?properties&status=av&page=1
i would want to remove the last variable from the string i.e &page=1. please note the value for page will not always be 1. keeping this in mind i would want to trim the variable this way.
Trim from the last position of the string till the first delimiter i.e &
Update :
I would like to remove &page=1 from the string, no matter in which position it is on.
how do i do this?
Instead of hacking around with regular expression you should parse the string as an url (what it is)
$string = 'index.php?properties&status=av&page=1';
$parts = parse_url($string);
$queryParams = array();
parse_str($parts['query'], $queryParams);
Now just remove the parameter
unset($queryParams['page']);
and rebuild the url
$queryString = http_build_query($queryParams);
$url = $parts['path'] . '?' . $queryString;
There are many roads that lead to Rome. I'd do it with a RegEx:
$myString = 'index.php?properties&status=av&page=1';
$myNewString = preg_replace("/\&[a-z0-9]+=[0-9]+$/i","",$myString);
if you only want the &page=1-type parameters, the last line would be
$myNewString = preg_replace("/\&page=[0-9]+/i","",$myString);
if you also want to get rid of the possibility that page is the only or first parameter:
$myNewString = preg_replace("/[\&]*page=[0-9]+/i","",$myString);
Thank you guys but i think i have found the better solution, #KingCrunch had suggested a solution i extended and converted it into function. the below function can possibly remove or unset any URI variable without any regex hacks being used. i am posting it as it might help someone.
function unset_uri_var($variable, $uri) {
$parseUri = parse_url($uri);
$arrayUri = array();
parse_str($parseUri['query'], $arrayUri);
unset($arrayUri[$variable]);
$newUri = http_build_query($arrayUri);
$newUri = $parseUri['path'].'?'.$newUri;
return $newUri;
}
now consider the following uri
index.php?properties&status=av&page=1
//To remove properties variable
$url = unset_uri_var('properties', basename($_SERVER['REQUEST_URI']));
//Outputs index.php?page=1&status=av
//To remove page variable
$url = unset_uri_var('page', basename($_SERVER['REQUEST_URI']));
//Outputs index.php?properties=&status=av
hope this helps someone. and thank you #KingKrunch for your solution :)
$pos = strrpos($_SERVER['REQUEST_URI'], '&');
$url = substr($_SERVER['REQUEST_URI'], 0, $pos - 1);
Documentation for strrpos.
Regex that works on every possible situation: /(&|(?<=\?))page=.*?(?=&|$)/. Here's example code:
$regex = '/(&|(?<=\?))page=.*?(?=&|$)/';
$urls = array(
'index.php?properties&status=av&page=1',
'index.php?properties&page=1&status=av',
'index.php?page=1',
);
foreach($urls as $url) {
echo preg_replace($regex, '', $url), "\n";
}
Output:
index.php?properties&status=av
index.php?properties&status=av
index.php?
Regex explanation:
(&|(?<=\?)) -- either match a & or a ?, but if it's a ?, don't put it in the match and just ignore it (you don't want urls like index.php&status=av)
page=.*? -- matches page=[...]
(?=&|$) -- look for a & or the end of the string ($), but don't include them for the replacement (this group helps the previous one find out exactly where to stop matching)
You could use a RegEx (as Chris suggests) but it's not the most efficient solution (lots of overhead using that engine... it's easy to do with some string parsing:
<?php
//$url="http://localhost/index.php?properties&status=av&page=1";
$base=basename($_SERVER['REQUEST_URI']);
echo "Basename yields: $base<br />";
//Find the last ampersand
$lastAmp=strrpos($base,"&");
//Filter, catch no ampersands found
$removeLast=($lastAmp===false?$base:substr($base,0,$lastAmp));
echo "Without Last Parameter: $removeLast<br />";
?>
The trick is, can you guarantee that $page will be stuck on the end? If it is - great, if it isn't... what you asked for may not always solve the problem.
Having a brain freeze...
Have a URL which may be in any of the formats :
http://url.com/stuff
url.com/somestuff
www.url.com/otherstuff
https://www.url.com/morestuff
You get the picture.
How do I remove the .com part to leave just the various 'stuff' parts ? For example, the above would end up :
stuff
somestuff
otherstuff
morestuff
You could achieve that using the following code:
$com_pos = strpos($url, '.com/');
$stuff_part = substr($url, $com_pos + 5);
Click here to see the working code.
This should do the trick for you!
<?php
$url = "http://url.com/stuff";
$querystring = preg_replace('#^(https|http)?(://)?(www.)?([a-zA-Z0-9-]+)\.[a-zA-Z]{2,6}/#', "", $url);
echo $querystring;
I submitted this answer because I'm not very fond of solutions using explode() to handle this. Maybe your query string contains more slashes so, you'd have to write exceptions for those cases.
You can use explode to make an array, then get the last element from the array.
$str = 'http://url.com/stuff';
$arr = explode('/', $str);
echo end($arr); // 'stuff'
$path = parse_url('http://url.com/stuff', PHP_URL_PATH);
If you leave the second parameter unspecified you can return an array including the domain etc.
Use explode function to divide the string.
<?php
$url = "http://url.com/stuff";
$stuff = explode("/", $url);
echo $stuff[sizeof($stuff) - 1];
?>
I used sizeof to access to last element.
preg_replace("/^(https?:\/\/)?[^\/]+/" ,"", $url);
index.php?option=com_virtuemart&Itemid=210&category_id=12&lang=is&limit=20&limitstart=180&page=shop.browse
and I would like to retrieve the Page parameter from the string and if that page parameter is equal to "shop.browse" than return a true boolean.
edit: ps. the string does not always look like this but it does always contain the page= parameter
Ive been messing with strpos function and others and I can't get this working and I need this code quickly so if anyone can point me in there right direction of the best approach.
Thanks
Use parse_url first to get just the query part, then use parse_str to get the values:
$query = parse_url($str,PHP_URL_QUERY);
parse_str($query, $match);
if ($match['page'] === 'shop.browse') {
// page=shop.browse
}
Note that this assumes your string is stored in a variable $str.
Check the parse_url() function.
$str = explode("?",$url);
$str = explode("&",$str[1]);
foreach($str as $k=>$v) {
$xxx = explode("=",$v);
$output[$xxx[0]] = $output[$xxx[1]];
}
echo $output["page"];
this way you get all the parameters mapped to their keys. you obtain something like the $_GET/$_POST stuff is rendered.
the whole thing:
<?php
$url = "index.php?option=com_virtuemart&Itemid=210&category_id=12&lang=is&limit=20&limitstart=180&page=shop.browse";
$url = parse_url($url);
parse_str($url['query'], $output);
if($output['page'] == "shop.browse")
{
//stmts
}
else
{
//stmts
}