i have a really complex query (mysql + php) and i would like to know the easiest way to sum columns and rows of a table apart from using SUM(x).
Maybe a javascript could help.
Thanks in advance.
I would advise to use the SUM() function in MySQL. The only reason to not use it is if you have some complicated counting based on other values. Then I would do the counting in the PHP. Here is an example:
$result = mysql_query("... query here ...");
$cats = 0;
$dogs = 0;
while($row = mysql_fetch_array($result))
{
if($row['type'] == 'cat')
{
$cats++;
}
else
{
$dogs++;
}
}
echo "Cats: $cats Dogs: $dogs";
I would do this in the query itself. If you post the query, I can provide more information.
This is the query, i want to sum cols and rows. ( rows are the vars "svago" and "lavoro" ordered for each month of the year, while cols are the same values in the whole year )
$q = "SELECT DISTINCT DATE_FORMAT( TIMESTAMP, '%m%Y' ) AS derp FROM main LIMIT 0 , 30";
$qq = mysql_query($q);
while($res = mysql_fetch_array($qq)) {
$where = $res['derp'];
$q = "SELECT timestamp, SUM(moto) + SUM(mary) AS svago, SUM(lavoro) + SUM(affitto) AS lavoro FROM main WHERE DATE_FORMAT(timestamp, '%m%Y') = $where";
Related
Here's a simplified code similar to what I'm using. In this one, I'm pulling Names from ID's.
$counter = 0;
$select = "SELECT nID,nName WHERE nID = $counter";
$result = sqlsrv_query($connection, $select);
$maxusers = 10;
while($counter<$maxusers) {
while($row = sqlsrv_fetch_array($result)) {
echo $row['nName'];
}
$counter++
}
What I get is the same name, the counter in the select statement stays at 0.
I had to put the definition of the $select statement and the $result inside the loop, it redefines everything every time we enter the while loop, looks like the code below. That doesn't seem practical and optimal to me. What are the best work-around for situations like these? I'm not really familiar with variable scopes in PHP, I haven't found any good documentation on that matter when it comes to sql functions.
$counter = 0;
$maxusers = 10;
while($counter<$maxusers) {
$select = "SELECT nID,nName WHERE nID = $counter";
$result = sqlsrv_query($connection, $select);
while($row = sqlsrv_fetch_array($result)) {
echo $row['nName'];
}
$counter++
}
Here's the code that I've actually written.
$selectFirst = "SELECT TOP 1 nDateTime,nUserID FROM TB_EVENT_LOG WHERE nUserID = $usercounter AND nDateTime BETWEEN $today AND $tomorrow";
$selectLast = "SELECT TOP 1 nDateTime,nUserID FROM TB_EVENT_LOG WHERE nUserID = $usercounter DateTime BETWEEN $today AND $tomorrow DESC";
$resultFirst = sqlsrv_query($bscon, $selectFirst);
$resultLast = sqlsrv_query($bscon, $selectLast);
$selectnumberofUsers = "SELECT TOP 1 nUserIdn FROM TB_USER ORDER by nUserIdn DESC";
$usersmaxq = sqlsrv_query($bscon, $selectnumberofUsers);
$usersmax = sqlsrv_fetch_object($usersmaxq)->nUserIdn;
while($usercounter<$usersmax){
$usercounter = $usercounter + 1;
while($rowfirst = sqlsrv_fetch_array($resultFirst)) {
$intime = $rowfirst['nDateTime'];
}
echo $intime." ".$usercounter."<br />";
}
Your issue doesn't have to do with variable scope. The $select variable is set once as string with the current value of $counter. Your second example works because this value is reset every time.
In your second example however, you're creating a sql statement that gets 1 row (assuming nID is unique), then looping through your result retrieve that one row. You're doing 10 sql calls, but you only need one if you modify your query like so:
$minusers = 0;
$maxusers = 10;
$select = "SELECT nID,nName WHERE nID >= $minusers AND nID < $maxusers ORDER BY nID";
$result = sqlsrv_query($connection, $select);
while($row = sqlsrv_fetch_array($result)) {
echo $row['nName'];
}
For your actual code, you should be able to get one record per nUserId by using GROUP BY. Try this:
$selectFirst = "SELECT nDateTime,nUserID FROM TB_EVENT_LOG WHERE nUserID >= $usersmin AND nUserID <= $usersmax AND nDateTime BETWEEN $today AND $tomorrow GROUP BY nUserID";
I need to do a SELECT * FROM table_X , the problem is table_X is the result of another query, I don't know how to do it, perhaps with two loop, something like this :
<?php
$query1 = mysql_query("SELECT * FROM table_ref");
while ($row = mysql_fetch_array($query1))
{
$name = $row['table_name'];
$query2 = mysql_query(" SELECT * FROM '$name' ");
while ($row = mysql_fetch_array($query2))
{
$time = $data['itime'];
echo $time;
}
}
?>
The tables are all similar & I can't do joint there's no keys. So what I want is to show only the results of the second query from each results of the first query !
So, what's your structure? I don't understand. You have column table_name where are listed a lot of tables? If so, just use backquotes on your $name:
$query2 = mysql_query(" SELECT * FROM `$name` ");
Apart from the obvious that has been pointed out in the comments, you're overwriting $row in the second loop.
Also, you're trying to read an array ($data) that is not defined.
The following will work much better (but still isn't ideal):
$query1 = mysql_query("SELECT `table_name` FROM `table_ref`");
while ($row = mysql_fetch_array($query1))
{
$name = $row['table_name'];
$query2 = mysql_query("SELECT `itime` FROM `$name`");
while ($data = mysql_fetch_array($query2))
{
$time = $data['itime'];
echo $time;
}
}
just change your quotes to have the query ready to be started
change
$query2 = mysql_query(" SELECT * FROM '$name' ");
to
$query2 = mysql_query(" SELECT * FROM `".$name."` ");
i would also rather sugest to check this part
while ($row = mysql_fetch_array($query2))
{
$time = $data['itime'];
echo $time;
}
you already used variable $row to fetching previus query so better to change to something else, look like $data is matching your needs because you already used but you did not declare it
while ($data = mysql_fetch_array($query2))
{
$time = $data['itime'];
echo $time;
}
Try this query:
select x.* from ( SELECT table_name FROM table_ref) as x
I have 2 tables as follow :
table1 has these fields:
year,day,month,name
table2 has these fields:
years,gift
I want to return the rows where year = years. the two queries NEED to be run separately that is a condition.
I CANNOT join them into 1 query (I know how to do that but that's not how this should be done). Any suggestions? I thought of using a foreach loop but failed to implement, any ideas?
$sql1 = " SELECT * FROM table1 ORDER BY id ASC";
$result1 = mysql_query($sql1);
$rows = mysql_fetch_array($result1);
while($rows = mysql_fetch_array($result1))
{
$year[] = $rows['year'];
}
$sqlx = "SELECT * FROM table2";
$result = mysql_query($sqlx);
while($row = mysql_fetch_array($result))
{
$years[] = $rows['years'];
}
This is a strange requirement, since it should be done with a join. It is vastly less efficient to do this with multiple queries in a loop than a single query with a JOIN.
In any case if you must do it this way, you have retrieved the years into an array correctly from your first query -- use that array to populate the query for each loop iteration of your second query:
$year = array();
$sql1 = " SELECT * FROM table1";
$result1 = mysql_query($sql1);
if ($result1) {
$rows = mysql_fetch_array($result1);
while($rows = mysql_fetch_array($result1))
{
$year[] = $rows['year'];
}
}
// Will hold your output
$gifts = array();
// $year is now an array of years.
// Loop over it to query table2:
foreach ($year as $y) {
// Make sure it is an integer...
$y = intval($y);
// And query table2 using $y as a WHERE condition
$sql2 = "SELECT years, gift FROM table2 WHERE years = $y";
$result2 = mysql_query($sql2);
if ($result2) {
while($row = mysql_fetch_array($result2)) {
// Append all rows to the $gifts array
$gifts[] = $row;
}
}
}
// They're now all in the array $gifts.
var_dump($gifts);
Update:
years on table 1 is a period in years. year in table is a date of when the account was created. so I have to find the difference from today's date to year on table2. then see if it matches any of the rows on table1. and return the results that match
This can be accomplished with a creative JOIN using date functions. Assuming table2.years is a DATE or DATETIME, use YEAR() to return only the year portion from it, and compare it to YEAR(CURDATE()) for the current year. Join that against the number of years in table1.year.
SELECT
table1.*,
table2.*
FROM
table1
JOIN table2
ON table1.year = (YEAR(CURDATE()) - YEAR(table2.years))
I have database such as
I want to create an associative array such that each att_name value is associated with its possible values from att_value:
array('att_name' => array('att_value_1', 'att_value_2', 'att_value_3'))
What is the best way to achieve this?
While it is easily possible to do this simply by selecting the results you want and iterating them in PHP to create the data structure you want, you could sub some of the work out to MySQL with GROUP_CONCAT():
$query = "
SELECT att_name, GROUP_CONCAT(att_value SEPARATOR ',') AS values
FROM table_name
GROUP BY att_name
";
$result = mysql_query($query);
$array = array();
while ($row = mysql_fetch_assoc($result)) {
$array[$row['att_name']] = explode(',', $values);
}
print_r($array);
Of course, this only works if your values will never contain the character (or sequence of characters) you use for the SEPARATOR in the MySQL query, so the safer pure-PHP way would be:
$query = "
SELECT att_name, att_value
FROM table_name
";
$result = mysql_query($query);
$array = array();
while ($row = mysql_fetch_assoc($result)) {
$array[$row['att_name']][] = $row['att_value'];
}
print_r($array);
Try below:
$sql = "SELECT * from tablename";
$result = mysql_query($sql,$con);
$final_array=array();
while ($row = mysql_fetch_object($result))
{
$final_array[$row->att_name][0]=$row->att_value_1;
$final_array[$row->att_name][1]=$row->att_value_2;
....
....
}
This way :
SELECT
item,
att_name,
GROUP_CONCAT(att_value SEPARATOR "<!>") AS att_value
FROM
table
GROUP BY
att_name
Will give you something like that :
item att_name att_value
-----------------------------
books height 150 mm<!>250 mm
books price rs:20<!>Rs:20
books size 15 pg<!>30 pg<!>60 pg
books width 300 mm<!>400 mm
You have to explode the result from att_value by a <!>. I use this <!> so it highly impossible to have a value inside att_value with this. If you think you would someday use this, take another separator. Example : [{--}], _SEPARATOR_, [_-CUT-_], etc. Something you are sure at 100% you won't use a choice but always as a separator to split the text.
So example :
$SQL = 'SELECT item, att_name, GROUP_CONCAT(att_value SEPARATOR "<!>") AS att_value FROM table GROUP BY att_name';
$Query = mysql_query($SQL) or die('MySQL Error : '.mysql_error());
while($Assoc = mysql_fetch_assoc($Query)){
$Assoc['att_value'] = ($Assoc['att_value'] != '' ? explode('<!>', $Assoc['att_value']) : NULL);
print_r($Assoc);
}
Suppose I have a while loop like:
$sql = mysql_query("SELECT * FROM tablename");
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$sql_2 = mysql_query("SELECT * FROM secondtable WHERE id != $id ");
while($ro = mysql_fetch_array($sql_2)){
$id2 = $ro["id2"];
echo $id2;
}
}
then if first query return 5 results i.e 1-5 and second query returns 3 results than if i want to echo out second query it gives me like this..........
111112222233333
than how can i fix to 123 so that the second while loop should execute according to number of times allowed by me........!! how can i do that.........!!
I'm not sure I 100% understand your question - it's a little unclear.
It's possible you could solve this in the query with a GROUP BY clause
$sql_2 = mysql_query("SELECT id FROM secondtable WHERE id != $id GROUP BY id");
But that would only work if you need just secondtable.id and not any of the other columns.
When you say "number of time allowed by me" do you mean some sort of arbitrary value? If so, then you need to use a different loop mechanism, such as Greg B's solution.
Do you want to explicitly limit the number of iterations of the inner loop?
Have you considered using a for loop?
$sql = mysql_query("SELECT * FROM tablename");
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$sql_2 = mysql_query("SELECT * FROM secondtable WHERE id != $id ");
for($i=0; $i<3; $i++){
$ro = mysql_fetch_array($sql_2);
$id2 = $ro["id2"];
echo $id2;
}
}
Your first while loop is iterating over all 5 results, one at a time.
Your second while loop is iterating over each of the 5 results, producing it's own set of results (i.e. 3 results for each of the 5 iterations, totaling 15 results).
I believe what you are trying to do is exclude all IDs found in your first loop from your second query. You could do that as follows:
$sql = mysql_query("SELECT * FROM tablename");
$exclude = array();
while($row = mysql_fetch_array($sql)) {
array_push($exclude, $row['id']);
}
// simplify query if no results found
$where = '';
if (!empty($exclude)) {
$where = sprintf(' WHERE id NOT IN (%s)', implode(',', $exclude));
}
$sql = sprintf('SELECT * FROM secondtable%s', $where);
while($row = mysql_fetch_array($sql_2)) {
$id2 = $row["id2"];
echo $id2;
}
$sql = mysql_query("SELECT * FROM tablename");
$tmp = array();
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
if(!in_array($id, $tmp)) {
$sql_2 = mysql_query("SELECT * FROM secondtable WHERE id != $id ");
while($ro = mysql_fetch_array($sql_2)){
$id2 = $ro["id2"];
echo $id2;
}
$tmp[] = $id;
}
}
Saving all queried $id's in an array to check on the next iteration if it has already been queried. I also think that GROUPing the first query result would be a better way.
I agree with Leonardo Herrera that it's really not clear what you're trying to ask here. It would help if you could rewrite your question. It sounds a bit like you're trying to query one table and not include id's found in another table. You might try something like:
SELECT * FROM secondtable t2
WHERE NOT EXISTS (SELECT 1 FROM tablename t1 WHERE t1.id = t2.id);