PHP and MySQL problems - php

Question

I'm trying to count how many times a certain article has been graded for example how many times have users_articles_id 3 been graded by my members.
I'm also trying to count the points for a certain article for example users_articles_id 3 is related to the ratings database by its ratings_id the rating points should be a total of 13.
I was wonder if I was doing this right because to me it looks all wrong? I was hoping if some one can help me fix this? And where should my code go exactly?
I'm using PHP and MySQL?
Here is my MySQL tables
CREATE TABLE articles_grades (
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
ratings_id INT UNSIGNED NOT NULL,
users_articles_id INT UNSIGNED NOT NULL,
user_id INT UNSIGNED NOT NULL,
date_created DATETIME NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE ratings (
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
points FLOAT UNSIGNED NOT NULL DEFAULT 0,
PRIMARY KEY (id)
);
Database Input
articles_ratings
id ratings_id users_articles_id user_id date_created
1 3 2 32 2010-01-13 02:22:51
2 1 3 3 2010-01-13 02:23:58
3 2 3 45 2010-01-13 02:24:45
ratings
id points
1 10
2 3
3 5
Here is the PHP code I'm trying to fix.
// function to retrieve rating
function getRating(){
$sql1 = "SELECT COUNT(*)
FROM articles_ratings
WHERE users_articles_id = '$page'";
$result = mysql_query($sql1);
$total_ratings = mysql_fetch_array($result);
$sql2 = "SELECT COUNT(*)
FROM ratings
JOIN ratings ON ratings.id = articles_ratings.ratings_id
WHERE articles_ratings.users_articles_id = '$page'";
$result = mysql_query($sql2);
$total_rating_points = mysql_fetch_array($result);
if(!empty($total_rating_points) && !empty($total_ratings)){
// set the width of star for the star rating
$rating = (round($total_rating_points / $total_ratings,1)) * 10;
echo $rating;
} else {
$rating = 100;
echo $rating;
}
}

Answer 1

Well I think there are several issues here.
1) You are defining a table called articles_grades, not articles_ratings, as in your code.
2) Why do articles_grades and ratings need to be in separate tables? There is a one-to-one correspondence between those tables.
3) You need to do sum(points) in your second query.
4) You can combine both queries into a single query.
Here's how I would do it if you don't change the schema:
<?php
mysql_connect('localhost','root','fake123123');
mysql_select_db('test');
$result = mysql_query('SELECT users_articles_id,count(*),sum(r.points)
FROM articles_grades ag,ratings r
WHERE ag.ratings_id = r.id
GROUP BY users_articles_id');
if (!$result)
die('invalid');
else{
echo '<table><tr><th>Article Id</th><th>#Ratings</th><th>#Points</th></tr>';
$a = mysql_fetch_row($result);
while($a){
echo '<tr><td>'.implode('</td><td>',$a).'</td></tr>';
$a = mysql_fetch_row($result);
}
echo '</table>';
}
?>
You can run this as a CGI script. It should return a table of the results.
Let me know if this helps.