Evening guys.
Firstly to say, I have read How do I parse XML containing custom namespaces using SimpleXML?.
I'm parsing an XML document from a source not mind, and they use a custom namespace.
<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:moshtix="http://www.moshtix.com.au">
<channel>
<item>
<link>qweqwe</link>
<moshtix:genre>asdasd</moshtix:genre>
...
For example. When I parse using SimpleXML, none of the mostix: namespace elements are on show or accessible. Probably a really simple solution, but any ideas guys?
Usually, people use children().
$rss = simplexml_load_string(
'<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:moshtix="http://www.moshtix.com.au">
<channel>
<link>qweqwe</link>
<moshtix:genre>asdasd</moshtix:genre>
</channel>
</rss>'
);
foreach ($rss->channel as $channel)
{
echo 'link: ', $channel->link, "\n";
echo 'genre: ', $channel->children('moshtix', true)->genre, "\n";
}
Related
I'd like to get the content of the attribute xsi:schemaLocation. It's works perfectly with getElementsByTagName in php (and foreach after) but it's ugly, right ?
How to get the same content with a simple Xpath query ?
Here a short example of the xml content :
<?xml version="1.0" encoding="utf-8"?>
<gpx xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="1.0" creator="blabla" xsi:schemaLocation="http://www.topografix.com/GPX/1/0 http://www.topografix.com/GPX/1/0/gpx.xsd http://www.groundspeak.com/cache/1/0/1 http://www.groundspeak.com/cache/1/0/1/cache.xsd" xmlns="http://www.topografix.com/GPX/1/0">
...
</gpx>
Thanks!
Typically you need to register the namespaces you want to use with the XPath library first. Then you can query the attribute by including namespace prefix along with the name.
So let's assume you're using DOMXPath, you might register the following namespaces:
$xpath = new DOMXPath($doc);
$xpath->registerNamespace("xsi","http://www.w3.org/2001/XMLSchema-instance");
$xpath->registerNamespace("gpx", "http://www.topografix.com/GPX/1/0");
And then you can query the schemaLocation attribute with something like this:
$xpath->query("/gpx:gpx/#xsi:schemaLocation",$doc);
Using the SimpleXMLElement class you can easily get the attribute xsi:schemaLocation's value:
<?php
$xml = <<<XML
<?xml version="1.0" encoding="utf-8"?>
<gpx xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" version="1.0" creator="blabla" xsi:schemaLocation="http://www.topografix.com/GPX/1/0 http://www.topografix.com/GPX/1/0/gpx.xsd http://www.groundspeak.com/cache/1/0/1 http://www.groundspeak.com/cache/1/0/1/cache.xsd" xmlns="http://www.topografix.com/GPX/1/0">
</gpx>
XML;
$sxe = new SimpleXMLElement($xml);
$schemaLocation = $sxe->attributes('xsi', true)->schemaLocation;
echo (string) $schemaLocation;
This is what my XML looks like
<?xml version="1.0" encoding="UTF-8"?>
<item>
<date>May 2013</date>
<html>http://www.link.to/html.html</html>
</item>
I do this in the PHP and it kind of works
$file = '../modules/xml/nl-archive.xml';
$xml = simplexml_load_file($file);
$string = '';
foreach($xml as $item){
$string .= '<a href="'.$item->html .'" ><li>'.$item->date .'</li></a>';
}
Just trying to get the contents of the date tag and html tag to show up for each of the item tags. Been googling and tinkering, can't get it right. What am I doing wrong?
Try changing your XML to have a root with children like:
<?xml version="1.0" encoding="UTF-8"?>
<items>
<item>
<date>May 2013</date>
<html>http://www.link.to/html.html</html>
</item>
</items>
Php is just fine as you have it.
Here is the XML that I am working on :
<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:noo="http://www.myscheme.com/schema">
<channel>
<item>
<title>A Simple Title</title>
<noo:subcategory>the sub category</noo:subcategory>
<noo:relatedInfos>
<noo:teams>
<noo:team id="3">New York</noo:team>
<noo:team id="4">Las Vegas</noo:team>
</noo:teams>
</noo:relatedInfos>
</item>
</channel>
</rss>
I am doing this php code to get the two "team" but it does not work ($xml has the previous content) :
$xml_datas = simplexml_load_string($xml);
foreach($xml_datas->channel->item as $item){
$noo = $item->children('noo');
echo $noo->team;
}
Do you have any idea why it is not working ?
Thanks
See if this helps:
<?php // RAY_temp_userco.php
error_reporting(E_ALL);
$xml = <<<ENDXML
<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:noo="http://www.myscheme.com/schema">
<channel>
<item>
<title>A Simple Title</title>
<noo:subcategory>the sub category</noo:subcategory>
<noo:relatedInfos>
<noo:teams>
<noo:team id="3">New York</noo:team>
<noo:team id="4">Las Vegas</noo:team>
</noo:teams>
</noo:relatedInfos>
</item>
</channel>
</rss>
ENDXML;
$obj = simplexml_load_string($xml);
$ns = $obj->getNamespaces(TRUE);
foreach($obj->channel->item as $item){
$noo = $item->children($ns['noo']);
var_dump($noo);
}
"noo" is just a local alias for that namespace, and the ->children() method (and most XML handling functions) want to know its actual global identifier, which is the URI in the xmlns attribute.
You need to either specify the full identifier of the namespace (i.e. ->children('http://www.myscheme.com/schema')) or set the optional second parameter to tell SimpleXML to look up the prefix (->children('noo', true). The second may be more readable, but it will break if a future document has the same schema, but gives the namespace a different local alias.
Additionally, the team nodes aren't directly under the item node, so you need to traverse further to get them:
// Give the namespace a readable name that won't change
define('NS_NOO', 'http://www.myscheme.com/schema');
$xml_datas = simplexml_load_string($xml);
foreach($xml_datas->channel->item as $item){
$teams = $item->children(NS_NOO)->relatedInfo->teams;
echo $teams->team[0];
}
In my php script, I try to parse a online - xml file.
That´s how I load it into my script:
$xml = simplexml_load_file($filename);
Now, I want to make a test output. I try it with
echo $xml->title;
but there is no result. When I try print_r($xml) I get the right XML file.
It looks like that:
<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0">
<channel>
<title>testtitle</title>
and so on
Why is there no result?
It is because of the nesting of the elements.
<rss>
-> $xml
<channel>
-> $xml->channel
<title>
-> $xml->channel->title
So if u use:
<?php
echo $xml->channel->title;
?>
That will output your title
//test.xml
<?xml version="1.0"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0">
<channel>
<title>testtitle</title>
</channel>
</rss>
//test.php
<?php
$xml = simplexml_load_file('test.xml');
echo $xml->channel->title;
?>
I have a php variable that contains xml code. I would like to get only one value from that xml and go along.
The xml is:
<?xml version="1.0" encoding="UTF-8" ?> <response> <status>SUCCESS</status> <data><count>1</count> <subscriberlist> <item> <subscriberid>4</subscriberid> <emailaddress>bbbbbb#bbbbbb.bb</emailaddress> <format>h</format> <subscribedate>1314903006</subscribedate> <confirmed>1</confirmed> <unsubscribed>0</unsubscribed> <bounced>0</bounced> <listid>3</listid> </item> </subscriberlist></data></response>
I would like to create the var $subscriberid and get the value (in this case 4)
Can someone explain me?
This doc on php.net will tell you how: http://php.net/manual/en/simplexml.examples-basic.php
For the following xml:
<?xml version="1.0" encoding="UTF-8" ?>
<response>
<status>SUCCESS</status>
<data>
<count>1</count>
<subscriberlist>
<item>
<subscriberid>4</subscriberid>
<emailaddress>bbbbbb#bbbbbb.bb</emailaddress>
<format>h</format>
<subscribedate>1314903006</subscribedate>
<confirmed>1</confirmed>
<unsubscribed>0</unsubscribed>
<bounced>0</bounced>
<listid>3</listid>
</item>
</subscriberlist>
</data>
</response>
If the xml was inside of $xmlstr then to get the subscriberid you would need the following php code:
<?php
$xml = new SimpleXMLElement($xmlstr);
$subscriberid = $xml->data->subscriberlist->item->subscriberid;
?>
You can use simplexml_load_string then parse the data
<?php
$xml = simplexml_load_string('<?xml vers...');
$subscriberid = $xml->data->subscriberlist->item->subscriberid;
?>