How to list the vehicle based on selected faculty - php

Question

i have a list box to show the list of vehicle when user select the faculty. i want to list only the vehicle based on the selected faculty by user.
<td>No</td>
<td>Registration No</td>
<?php
$count = 0;
$db = mysql_connect('localhost','root')
or die ("unable to connect");
mysql_select_db('fyp',$db) or die ("able to select");
$sql="SELECT * FROM vehicle_record";
$result = mysql_query($sql) or die ("Query failed!");
while($row = mysql_fetch_array($result)){
$count = $count + 1;
?>
<select name="faculty" >
<option value="" selected>-- Please Select --</option>
<option>City Campus</option>
<option>MFI</option>
<option>BMI</option>
<option>MSI</option>
<option>MIAT</option>
<option>MICET</option>
<option>MIMET</option>
<option>RCMP</option>
</select>

Answer 1

I could not get your question fully but I assume you want the vehicle facility to be selected after form is submitted, you put javascript to use for that:
<select name="faculty" id="faculty">
<option value="" selected>-- Please Select --</option>
<option>City Campus</option>
<option>MFI</option>
<option>BMI</option>
<option>MSI</option>
<option>MIAT</option>
<option>MICET</option>
<option>MIMET</option>
<option>RCMP</option>
</select>
<script type="text/javascripot">
document.getElementById("faculty").value = "<?php echo $_POST['faculty']?>";
</script>
However, if you meant how to show facilities coming from database, then you can go like this:
<select name="faculty" id="faculty">
<?php
while($row = mysql_fetch_array($result)){
echo '<option value="'.$row['field_name'].'">'.$row['field_name'].'</option>';
}
?>
</select>

Answer 2

I suppose you have 2 select one for faculty and one for vehicle
<select name="faculty" id="faculty" onchange="getVehicles()">
....
</select>
<select name="vehicle" id="vehicle">
</select>
Javascript Code
function getVechiles()
{
$.getJSON("getVechiles.php",{faculty: $("select#faculty").val()}, function(j){
if(j.length>0)
{
var options = '';
for (var i = 0; i < j.length; i++) {
options += '<option class="' + j[i].langClass + '" value="' + j[i].value + '">' + j[i].text + '</option>';
}
$("#vechile").html(options);
}
});
}
and getVechiles.php
SELECT * FROM TABLE
while($row = mysql_fetch_array($result)){
$js="{value:".row['id'].",text:\"".$row["field"]."\"}";
$rjson[] = $js;
}
if(is_array($rjson))
{
echo '[' . implode(',', $rjson) . ']';
}

Answer 3

<?php
$count = 0;
$i_faculty = $_POST['ifaculty'];
$db = mysql_connect('localhost','root') or die ("unable to connect");
mysql_select_db('fyp',$db) or die ("able to select");
$sql="SELECT * FROM vehicle_record WHERE faculty ='".$i_faculty."' ";
$result = mysql_query($sql) or die ("Query failed!");
while($row = mysql_fetch_array($result))
{
$count = $count + 1;
?>
<select name="ifaculty">
<option value="" selected="selected">-- Select Faculty --</option>
<option>City Campus</option>
<option>MFI</option>
<option>BMI</option>
<option>MSI</option>
<option>MIAT</option>
<option>MICET</option>
<option>MIMET</option>
<option>RCMP</option>
</select>