In the following page, with Firefox the remove button submits the form, but the add button does not.
How do I prevent the remove button from submitting the form?
function addItem() {
var v = $('form :hidden:last').attr('name');
var n = /(.*)input/.exec(v);
var newPrefix;
if (n[1].length == 0) {
newPrefix = '1';
} else {
newPrefix = parseInt(n[1]) + 1;
}
var oldElem = $('form tr:last');
var newElem = oldElem.clone(true);
var lastHidden = $('form :hidden:last');
lastHidden.val(newPrefix);
var pat = '=\"' + n[1] + 'input';
newElem.html(newElem.html().replace(new RegExp(pat, 'g'), '=\"' + newPrefix + 'input'));
newElem.appendTo('table');
$('form :hidden:last').val('');
}
function removeItem() {
var rows = $('form tr');
if (rows.length > 2) {
rows[rows.length - 1].html('');
$('form :hidden:last').val('');
} else {
alert('Cannot remove any more rows');
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<html>
<body>
<form autocomplete="off" method="post" action="">
<p>Title:<input type="text" /></p>
<button onclick="addItem(); return false;">Add Item</button>
<button onclick="removeItem(); return false;">Remove Last Item</button>
<table>
<th>Name</th>
<tr>
<td><input type="text" id="input1" name="input1" /></td>
<td><input type="hidden" id="input2" name="input2" /></td>
</tr>
</table>
<input id="submit" type="submit" name="submit" value="Submit">
</form>
</body>
</html>
You're using an HTML5 button element. Remember the reason is this button has a default behavior of submit, as stated in the W3 specification as seen here:
W3C HTML5 Button
So you need to specify its type explicitly:
<button type="button">Button</button>
in order to override the default submit type. I just want to point out the reason why this happens.
Set the type on your buttons:
<button type="button" onclick="addItem(); return false;">Add Item</button>
<button type="button" onclick="removeItem(); return false;">Remove Last Item</button>
...that'll keep them from triggering a submit action when an exception occurs in the event handler. Then, fix your removeItem() function so that it doesn't trigger an exception:
function removeItem() {
var rows = $('form tr');
if ( rows.length > 2 ) {
// change: work on filtered jQuery object
rows.filter(":last").html('');
$('form :hidden:last').val('');
} else {
alert('Cannot remove any more rows');
}
}
Note the change: your original code extracted a HTML element from the jQuery set, and then tried to call a jQuery method on it - this threw an exception, resulting in the default behavior for the button.
FWIW, there's another way you could go with this... Wire up your event handlers using jQuery, and use the preventDefault() method on jQuery's event object to cancel the default behavior up-front:
$(function() // execute once the DOM has loaded
{
// wire up Add Item button click event
$("#AddItem").click(function(event)
{
event.preventDefault(); // cancel default behavior
//... rest of add logic
});
// wire up Remove Last Item button click event
$("RemoveLastItem").click(function(event)
{
event.preventDefault(); // cancel default behavior
//... rest of remove last logic
});
});
...
<button type="button" id="AddItem" name="AddItem">Add Item</button>
<button type="button" id="RemoveLastItem" name="RemoveLastItem">Remove Last Item</button>
This technique keeps all of your logic in one place, making it easier to debug... it also allows you to implement a fall-back by changing the type on the buttons back to submit and handling the event server-side - this is known as unobtrusive JavaScript.
Sometime ago I needed something very similar... and I got it.
So what I put here is how I do the tricks to have a form able to be submitted by JavaScript without any validating and execute validation only when the user presses a button (typically a send button).
For the example I will use a minimal form, only with two fields and a submit button.
Remember what is wanted:
From JavaScript it must be able to be submitted without any checking. However, if the user presses such a button, the validation must be done and form sent only if pass the validation.
Normally all would start from something near this (I removed all extra stuff not important):
<form method="post" id="theFormID" name="theFormID" action="">
<input type="text" id="Field1" name="Field1" />
<input type="text" id="Field2" name="Field2" />
<input type="submit" value="Send" onclick="JavaScript:return Validator();" />
</form>
See how form tag has no onsubmit="..." (remember it was a condition not to have it).
The problem is that the form is always submitted, no matter if onclick returns true or false.
If I change type="submit" for type="button", it seems to work but does not. It never sends the form, but that can be done easily.
So finally I used this:
<form method="post" id="theFormID" name="theFormID" action="">
<input type="text" id="Field1" name="Field1" />
<input type="text" id="Field2" name="Field2" />
<input type="button" value="Send" onclick="JavaScript:return Validator();" />
</form>
And on function Validator, where return True; is, I also add a JavaScript submit sentence, something similar to this:
function Validator(){
// ...bla bla bla... the checks
if( ){
document.getElementById('theFormID').submit();
return(true);
}else{
return(false);
}
}
The id="" is just for JavaScript getElementById, the name="" is just for it to appear on POST data.
On such way it works as I need.
I put this just for people that need no onsubmit function on the form, but make some validation when a button is press by user.
Why I need no onsubmit on form tag? Easy, on other JavaScript parts I need to perform a submit but I do not want there to be any validation.
The reason: If user is the one that performs the submit I want and need the validation to be done, but if it is JavaScript sometimes I need to perform the submit while such validations would avoid it.
It may sounds strange, but not when thinking for example: on a Login ... with some restrictions... like not allow to be used PHP sessions and neither cookies are allowed!
So any link must be converted to such form submit, so the login data is not lost.
When no login is yet done, it must also work. So no validation must be performed on links.
But I want to present a message to the user if the user has not entered both fields, user and pass. So if one is missing, the form must not be sent! there is the problem.
See the problem: the form must not be sent when one field is empty only if the user has pressed a button, if it is a JavaScript code it must be able to be sent.
If I do the work on onsubmit on the form tag, I would need to know if it is the user or other JavaScript. Since no parameters can be passed, it is not possible directly, so some people add a variable to tell if validation must be done or not. First thing on validation function is to check that variable value, etc... Too complicated and code does not say what is really wanted.
So the solution is not to have onsubmit on the form tag. Insead put it where it really is needed, on the button.
For the other side, why put onsubmit code since conceptually I do not want onsubmit validation. I really want button validation.
Not only the code is more clear, it is where it must be. Just remember this:
- I do not want JavaScript to validate the form (that must be always done by PHP on the server side)
- I want to show to the user a message telling all fields must not be empty, that needs JavaScript (client side)
So why some people (think or tell me) it must be done on an onsumbit validation? No, conceptually I am not doing a onsumbit validating at client side. I am just doing something on a button get pressed, so why not just let that to be implemented?
Well that code and style does the trick perfectly. On any JavaScript that I need to send the form I just put:
document.getElementById('theFormID').action='./GoToThisPage.php'; // Where to go
document.getElementById('theFormID').submit(); // Send POST data and go there
And that skips validation when I do not need it. It just sends the form and loads a different page, etc.
But if the user clicks the submit button (aka type="button" not type="submit") the validation is done before letting the form be submitted and if not valid not sent.
Well hope this helps others not to try long and complicated code. Just not use onsubmit if not needed, and use onclick. But just remember to change type="submit" to type="button" and please do not forget to do the submit() by JavaScript.
I agree with Shog9, though I might instead use:
<input type = "button" onClick="addItem(); return false;" value="Add Item" />
According to w3schools, the <button> tag has different behavior on different browsers.
You can simply get the reference of your buttons using jQuery, and prevent its propagation like below:
$(document).ready(function () {
$('#BUTTON_ID').click(function(e) {
e.preventDefault();
e.stopPropagation();
e.stopImmediatePropagation();
return false;
});});
$("form").submit(function () { return false; });
that will prevent the button from submitting or you can just change the button type to "button" <input type="button"/> instead of <input type="submit"/>
Which will only work if this button isn't the only button in this form.
Suppose your HTML form has id="form_id"
<form id="form_id">
<!--your HTML code-->
</form>
Add this jQuery snippet to your code to see result,
$("#form_id").submit(function(){
return false;
});
Buttons like <button>Click to do something</button> are submit buttons.
You must add type
This is an html5 error like has been said, you can still have the button as a submit (if you want to cover both javascript and non javascript users) using it like:
<button type="submit" onclick="return false"> Register </button>
This way you will cancel the submit but still do whatever you are doing in jquery or javascript function`s and do the submit for users who dont have javascript.
Just add e.preventDefault(); in your method should prevent your page from submitting forms.
function myFunc(e){
e.preventDefault();
}
According to the MDN Web Docs
The preventDefault () method of the Event interface tells the user
agent that if the event is not explicitly processed, its default
action should not be taken into account as it would normally be. The
event continues to propagate as usual, unless one of its listeners
calls stopPropagation () or stopImmediatePropagation (), either of
which terminates the propagation.
The return false prevents the default behavior. but the return false breaks the bubbling of additional click events. This means if there are any other click bindings after this function gets called, those others do not Consider.
<button id="btnSubmit" type="button">PostData</button>
<Script> $("#btnSubmit").click(function(){
// do stuff
return false;
}); </Script>
Or simply you can put like this
<button type="submit" onclick="return false"> PostData</button>
I am sure that on FF the
removeItem
function encounter a JavaScript error, this not happend on IE
When javascript error appear the "return false" code won't run, making the page to postback
Set your button in normal way and use event.preventDefault like..
<button onclick="myFunc(e)"> Remove </button>
...
...
In function...
function myFunc(e){
e.preventDefault();
}
return false;
You can return false at the end of the function or after the function call.
Just as long as it's the last thing that happens, the form will not submit.
if you have <input />
use it
<input type="button"/>
if you have <button>btn</button>
use it
<button type="button">btn</button>
Here's a simple approach:
$('.mybutton').click(function(){
/* Perform some button action ... */
alert("I don't like it when you press my button!");
/* Then, the most important part ... */
return false;
});
I'm not able to test this right now, but I would think you could use jQuery's preventDefault method.
The following sample code show you how to prevent button click from submitting form.
You may try my sample code:
<form autocomplete="off" method="post" action="">
<p>Title:
<input type="text" />
</p>
<input type="button" onclick="addItem()" value="Add Item">
<input type="button" onclick="removeItem()" value="Remove Last Item">
<table>
<th>Name</th>
<tr>
<td>
<input type="text" id="input1" name="input1" />
</td>
<td>
<input type="hidden" id="input2" name="input2" />
</td>
</tr>
</table>
<input id="submit" type="submit" name="submit" value="Submit">
</form>
<script language="javascript">
function addItem() {
return false;
}
function removeItem() {
return false;
}
</script>
The function removeItem actually contains an error, which makes the form button do it's default behaviour (submitting the form). The javascript error console will usually give a pointer in this case.
Check out the function removeItem in the javascript part:
The line:
rows[rows.length-1].html('');
doesn't work. Try this instead:
rows.eq(rows.length-1).html('');
https://developer.mozilla.org/pt-BR/docs/Web/API/HTMLFormElement/submit_event
Do your logic on the form onsubmit event
submitter Read only
An HTMLElement object which identifies the button or other element which was invoked to trigger the form being submitted.
onsubmit="(evt) => console.log(evt)"
The event itself will bring along the caller and some usefull info.
Just use evt.preventDefault(); (default submit) evt.stopPropagation(); (submit bubbling) if the caller is a
I've got multiple forms like this on one page:
<form method="post" action="#">
<input type="hidden" name="product_id" value="'.$item['articlenumber'].'" />
<input type="text" name="update_quantity" value="'.$pg->quantity.'" />
<input type="hidden" name="packing" value="'.$item['packing'].'" />
<input type="hidden" name="unit" value="'.$item['unit'].'" />
<input type="submit" name="addtocart" value="Update" />
</form>
And I've got one submit button at the bottom:
<input name='placeorder' type='submit' value='Place order' />
How can I check all forms when I press the submit button? I need to validate that the input that was given is the correct quantity.
UPDATE
I now got all the values from the forms in JavaScript and the validation is correct. Now I want to store the variables into PHP SESSIONS. I saw the answer from Ben and that would work if the values where in PHP, they are now in JavaScript. I need them on other pages so I thought Sessions would be the best thing here (if not, other suggestions are welcome).
I saw this answer and there they say it is not possible on one page. I understand that because PHP is server side and Javascript client side. Is this the only possible way to send Javascript variables to PHP?
Alright, first you should remove the type='submit' on the input. So change it to :
<input name='placeorder' value='Place order' />
Then you just need to add a javascript function to validate.
$(document).ready(function() {
$("input [name='placeorder']").click(function() {
var formOK = true;
$("form input").each(function(index, element) {
var value = $(element).val();
if (value != "OK") {
formOK = false;
}
});
if (formOK) {
submitForms();
} else {
alert("Form Input Inccorect");
}
});
});
function submitForms() {
$("#form1").add("#form2").submit();
}
With regards to your question about storing form data in a session variable Try something along these lines:
session_start();
if (isset($_POST['placeorder'])) {
$_session['ProductID'] = $_POST['product_id'];
$_session['UpdateQuantity'] = $_POST['update_quantity'];
$_session['Packing'] = $_POST['packing'];
$_session['Unit'] = $_POST['unit'];
}
Hope that helps
Both answers helped me a little bit but I needed to combine them so I ended up with a solution like the following. I got the values from the inputs by their unique name like this:
var sizeS25 = parseInt($("input[name='size-s25']").val(), 10) || 0;
var sizeM25 = parseInt($("input[name='size-m25']").val(), 10) || 0;
Then I send the variables to a PHP file:
window.location.href = "phpsessions.php?sizeS25=" + sizeS25 + "&sizeM25=" + sizeM25;
In the PHP file I set the variables as sessions:
$_SESSION['sizeS25'] = $_GET['sizeS25'];
$_SESSION['sizeM25'] = $_GET['sizeM25'];
As the title says This is the code that I tried with. The forms must appear one by one because information from previous forms determine how the next ones will look.
$(document).ready(function(){
$('#first_form').submit(function(){
$('#first_form').fadeOut('fast');
$('#second_form').fadeIn('fast');
});
});
<form action="new_patch.php" method="POST" id="first_form">
Title: <input type="text" name="patch" placeholder="Patch 4.20">
<br/>
Number of Champions: <input type="number" name="champ_number" min="1" max="99">
<br/>
<input type="submit" value="submit">
</form>
<form action="new_patch.php" method="POST" id="second_form" style="display: none;" >
<input type="text" value="text">
<input type="submit" value="submit">
<?php
$champ_number = null;
if(isset($_POST['champ_number']))
{
$champ_number = $_POST['champ_number'];
for($champ_number;$champ_number>0;$champ_number--)
{
echo "<br/>Champion ".$champ_number."<input type=\"number\" name=".$champ_number." min=\"1\" max=\"99\">";
}
}
?>
</form>
You're mixing client-side and server-side form code. Submitting the form will reload the page entirely, so from the looks of your code it will fade in the new form when the old form is submitted, but then reload the page so the old form will show again anyway.
You could either:
Let the PHP determine how the next form appears based on the submission of the first form, e.g. if (isset($_POST["First_form_submit"]) { Show second form... }
Probably better and more user-friendly: make the second form appear below once the user has filled in the relevant inputs on the first form before they've submitted
you can use:
$('#first_form').submit(function(){
$('#first_form').fadeOut(function() {
$('#second_form').fadeIn('fast');
});
return false;
});
From the jQuery documentation the syntax is fadeIn( [duration ] [, complete ] ) it accepts a duration and a onComplete callback that you can use to execute the next action when the first is completed.
I did this once too, just add a submit class to the button and make it like this:
<input type="submit" value="submit" class="submit">
Change script to a click function.
$(document).ready(function(event){
event.preventDefault();
$('.submit').click(function(){
$('#first_form').fadeOut(400);
$('#second_form').fadeIn(400);
});
});
PS, also you need to prevent submit default...otherwise it will just submit the form, see this JSfiddle
I have a HTML form which when the user clicks submit, all information is sent to email via a php script using the POST method. What i want to do is disable all user input after the submit button is clicked or grey out all text box input fields. How can i go about doing this?
the code for the submit button at the moment looks like this:
<input type="submit" value=" Continue " style="width:200px;height:40px">
Add below to each HTML input element you want to disabled. Since you have not mentioned I assume that you can use PHP for this.
<?php if(isset($_POST['submit'])) echo 'disabled="disabled"'; ?>
If you are using AJAX, when the event is fired, inside particular event
$("input").prop('disabled', true);
Onclick of submit button make all input to disabled
$("input").attr('disabled', true);
Since whether mail has been sent is server side processing, its better if you handle this from server end than from client side like jQuery and javascript :
$form_state = ($is_mail_sent)?"":"disabled='disabled'";
<input type="submit" <?php echo $form_state ?> value=" Continue " style="width:200px;height:40px">
without db interaction you can't do this out, have a flag in db table. Set the flag 1 if user submit a form, by default 0. Based on the flag value you can disable the form.
if(mailsent_status_of_the_user == 1){
$status = "disabled='disabled'";
}else{
$status = "";
}
<input type="submit" value=" Continue " <?php echo $status; ?> >
By using jQuery : $("input").prop('disabled', true);
But in pure Html is not possible without refreshing page !
Edit :
Javascript :
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(document).ready(function(e) {
$("#yourFormID").submit(function() {
$("#theInputToDisable").prop('disabled', true);
//Or to disable all inputs
//$(this).children("input").prop('disabled', true);
//$(this).children("input").attr('disabled', 'disabled');
return false;
})
});
</script>
HTML
<form id="yourFormID">
<input type="text" />
<input type="submit" value="Send"/>
</form>
Web site: www.matka-opas.com/ahaa4.php
If i push SEARCH-1 and then SEARCH-2 it works ok,
but how it could do by one search button ?
<?php
$depairport = $_POST['depairport'];
$ddestination = $_POST['ddestination'];
$ddday = $_POST['ddday'];
$depmonth = $_POST['depmonth'];
$depyear = $_POST['depyear'];
$retday = $_POST['retday'];
$retmonth = $_POST['retmonth'];
$retyear = $_POST['retyear'];
$aikuisia = $_POST['aikuisia'];
$osoite = $depairport . $ddestination . $ddday . $depmonth . $retday . $retmonth;
?>
<form method="post">
<input type="submit" value="SEARCH 1">
thanks ! ;]
If i push SEARCH-1 and then SEARCH-2
it works ok, but how it could do by
one search button ?
Just specify one search button and it will submit the form it is under. And you shouldn't be specifying more than one submit button for a particular form.
Here is what you should have:
<form method="post" action="">
.............
.............
.............
<input type="submit" value="SEARCH">
</form>
if you want to submit your form to http://www.travelstart.fi/combo/ you should put the url in the action attribute of the form. Your form will be posted to that url when it is submitted with <input type="submit" value="SEARCH">
<form method="post" action="http://www.travelstart.fi/combo/">
You also might want to learn more about semantic web and the separation of content and markup. I can understand you want to use tables in this kind of layout but 3 <br> to create a top margin? I saw you included a stylesheet in your page so...
EDIT: Now that your question is updated I think I understand it better. If you don't need any server-side functionality to calculate the url it might be better to put this functionality in javascript. This means it will be executed inside the browser. This saves you a round-trip to the server and so makes your page navigate a lot faster. This is a quick setup to get you started:
<form id="myForm">
...
<input type="submit" />
</form>
<script type="text/javascript">
myForm.onsubmit = function() {
window.location = 'http://www.travelstart.fi/combo/' + myForm.depairport + myForm.ddestination + myForm.ddday + myForm.depmonth + myForm.depyear + myForm.retday + myForm.retmonth + myForm.retyear + myForm.aikuisia;
return false;
}
</script>
As a disclaimer: this is not the best way to program it, it is just a short example to guide you in the right direction. Getting the right javascript code for what you want to achieve is a different question on SO.
It will probably not work right away since I don't think that will result in a valid url but I hope you get the picture. To make it cross-browser compatible you might want to use a javascript library like JQuery.
if you are trying to submit data
<input type="submit" value="SEARCH 1">
and then go to different url
to combine this you can use php that would detect a submit and redirect user to a different page...
as example:
$depairport = $_POST['depairport'];
$ddestination = $_POST['ddestination'];
$ddday = $_POST['ddday'];
$depmonth = $_POST['depmonth'];
$depyear = $_POST['depyear'];
$retday = $_POST['retday'];
$retmonth = $_POST['retmonth'];
$retyear = $_POST['retyear'];
$aikuisia = $_POST['aikuisia'];
$osoite = $depairport . $ddestination . $ddday . $depmonth . $retday . $retmonth;
if (isset($_POST['Submit'])) {
header( 'http://www.travelstart.fi/combo/'.$osoite ) ; }
you might want to change html just to:
<input type="submit" name="Submit" value="SEARCH 1">
thats all - make sure You are using POST method submiting the data