How do I extract foo from the following URL and store it in a varialbe, using regex in php?
http://example.com/pages/foo/inside.php
I googled quite a bit for an answer but most regex examples were too complex for me to understand.
preg_match('~pages/(.+?)/~', "http://example.com/pages/foo/inside.php", $matches);
echo $matches[1];
Well, there could be multiple solutions, based on what rule you want the foo to be extracted. As you didn't specify it yet, I'll just guess that you want to get the folder name of the current file (if that's wrong, please expand your question).
<?php
$str = 'http://example.com/pages/foo/inside.php';
preg_match( '#/([^/]+)/[^/]+$#', $str, $match );
print_r( $match );
?>
If the first part is invariant:
$s = 'http://example.com/pages/foo/inside.php';
preg_match('#^http://example.com/pages/([^/]+).*$#', $s, $matches);
$foo = $matches[1];
The main part is ([^/]+) which matches everything which is not a slash (/). That is, we're matching until finding the next slash or end of the string (if the "foo" part can be the last).
$str = 'http://example.com/pages/foo/inside.php';
$s=parse_url($str);
$whatiwant=explode("/",$s['path']);
print $whatiwant[2];
Related
I'm new to regex and I am really bad at it.
I've been trying to solve this problem but still can't get the result. So, I'm hoping that someone is able to assist me. thanks!
$str = "/tqrfq_58533_13";
preg_match_all('/\d+(?>=_)*/', $str, $matches);
print_r($matches); // gets 58533, 13
but I only want '58533' and not both numbers. So I want the array of $matches to return '58533' as the only number
Use /(?<=_)(\d+)(?=_)/ as pattern in preg_match() that match digits between _
$str = "/tqrfq_58533_13";
preg_match('/(?<=_)(\d+)(?=_)/', $str, $matches);
echo $matches[0];
// 58533
Check result in demo
Also you can use preg_replace() if you don't want to get array as result
echo preg_replace('/.*?_(\d+)_.*/', "$1", $str);
// 58533
preg_match_all('/\d+(?=_)/', $str, $matches);
If you want to get only one number, remove * part since it means the result will be more than one. AFAIK, there is no such things like (?>=_). I use (?=_) to indicate that _ immediately follow the number.
You can see this link for more clarification.
I know this type of questions have been asked before but none solves my problem.
I want to capture numeric parts of this string INFORMATICS&SYSTEMS-58600 i.e. 58600.
I am trying to do substr(INFORMATICS&SYSTEMS-58600,-5) which returns ATICS which is substr of first part of string INFORMATICS but I want the last part.
Wherever & is appearing this is behaving same.
I know its a very basic mistake but what ??? I cant figure out.Please help me out.
$str = 'INFORMATICS&SYSTEMS-58600';
preg_match_all('!\d+!', $str, $matches);
print_r($matches);
Can refer Extract numbers from a string
Actully PHP substr is working fine.
1. I was passing this text as url query in ajax i.e. get_data.php?dept ='informatics& system' so anything after & was treated as second parameter.
I found this nice answer on link to pass ajax parameters in url as encoded.
The regex in this code matches a number at the end of a string.
<?php
$str = "INFORMATICS&SYSTEMS-58600";
$matches = array();
preg_match("/\d+$/", $str, $matches);
foreach($matches as $match) {
echo $match;
}
?>
Output:
58600
My webpage has a variable, $currentPage. This is a string of the php token name of the page I'm currently on.
Example: All categories under the user section have names such as:
uAdminNew, uAdminEdit, ect..
I would like for a way to parse out the uAdmin and just determine what is the last word (New and Edit) and call upon functions from there.
I have my navigation system working through these names, therefore I can't change the names or I would to make it easier to parse. Such as adding delimiters.
Is this something only Regex can solve or is there a simpler solution I'm missing? If this is Regex could you explain or provide a link as to how I would go about using it to test against a specific list of strings? I'm very new to it.
For example, so:
$str = 'uAdminEdit';
$ar = preg_match('/([A-Z][^A-Z]+$)/', $str, $m);
echo $m[1]; // Edit
Does the pagename always start with uAdmin? If so, you could split the string by "uAdmin" with explode():
$page = 'uAdminEdit';
echo explode('uAdmin', $page)[1]; //Output: Edit
Or simply remove "uAdmin" with str_replace():
$page = 'uAdminEdit';
echo str_replace('uAdmin', '', $page); //Output: Edit
If you just want the section after uAdmin, use the regex capture groups
preg_match('/uAdmin(.*)/', $sub, $matches);
echo $matches[1]
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)
I'm looking for a regex pattern that will return N slugs/chunks (all pieces of the URL, separated or split on the "/" char.) as matches from a "friendly" URL.
The pattern should not include the domain or a leading slash.
Also, the pattern should work with an unknown number of slugs and/or slashes.
For example, some example URLs and desired returned slugs/chunks:
"" = array()
"foo/bar/" = array('foo', 'bar')
"foo/bar/baz" = array('foo', 'bar', 'baz')
"foo-bar/baz" = array('foo-bar', 'baz')
Finally, I need to pass this regex pattern preg_match (or similar) and have it return the results via the function's $matches parameter.
For example:
<?php preg_match($your_pattern, $friendly_url, $your_pattern_matches); ?>
... similar results can be prduced using explode().
This pattern is being used in a much more complex scenario than my little old example; requiring the use/forcing me to use regex patterns via preg_match for the solution. Basically, I'm passing preg_match a pattern of choice, which is why I need a regex pattern as opposed to simply using explode.
Your help is GREATLY appreciated!
Cheers!
First of all, check the manual of preg_split
$segments = preg_split('[/]', $uri, 0, PREG_SPLIT_NO_EMPTY);
If you insist on preg_match take a look on this:
$uri = '/foo-bar/baz';
preg_match_all('%[^/]+%', $uri, $matches);
print_r($matches);
Sounds like explode() would do the job without having to bother with regexes:
$matches = explode('/', $url);
Sorry but I don't think you can do what you want with preg_match.
After reading the documentation
You can see that preg_match will stop at the first match. You want an array of the matches in a friendly url however this can only be achieved by multiple matches , in order to store the values in an array OR by a single match which would capture the whole thing. Both of these cases do not fit you so I am afraid that you would have to use something else than preg_match.