I need to connect to another database in Joomla! that's on another server. This is for a plugin and I need to pull some data from a table.
Now what I don't want is to use this database to run Joomla!, I already have Joomla! installed and running on its own database on its server but I want to connect to another database (ON TOP of the current one) to pull some data, then disconnect from that 3rd party database - all while keeping the original Joomla database connection in tact.
You can connect to an external database from your joomla instance without using the current ressource of your joomla DB.
Try this:
<?php
$option = array(); //prevent problems
$option['driver'] = 'mysql';
$option['host'] = 'dbase.host.com';
$option['user'] = 'login';
$option['password'] = 'pwd';
$option['database'] = 'anotherdb';
$db = & JDatabase::getInstance( $option );
?>
For more infromations regarding this, check the Joomla! Documentation
I had same problem before. Fond a good tutorial showing how to connect to multiple database and switch back and forth, it also has sample code. It explains how to connect to multiple (internal and external) databases factory style, without creating multiple connections per request. This means that if you create database instance in controller same connection will be used in the model. Improves performance.
Another good explanation is on Joomla Documentation site [http://docs.joomla.org/How_to_connect_to_an_external_database].
Can you create a generic mysql-php conection inside your plugin code to create a connection ?
like
mysql_connect("remot_server_ip:3306","user","pass");
mysql_select_db("your database");
//code goes here
:
:
:
mysql_close(connection);
Related
Objective: Update prices of products between databases: Shop's server DB has the latest prices and website's DB need to be updated accordingly with any "each 24 hours" script (I'll look this up later).
I'm using Ionos as hosting for the website, and The server is shared, so I can't touch php.ini or add files for php.
I'm trying to connect to a SQL server DB, but since it requires dll libraries to be installed and to modify the php.ini, I can't do that.
I can't either make it from the other side, If I make it from an external server in order to update the prices of the website, they don't allow to make connections out of the context of the server.
So, I know that the solution is to upgrade the hosting's plan and pay more and so on, so I have a virtual server for my own. But before doing that, is there any other way to establish this connection without using php? Is there something else that allows me to create a DB connection?
The fatal errors appears as soon as sqlsrv_connect is read as there is no library to load this function.
$serverName = "x, 0000";
$connectionInfo = array( "Database"=>"x", "UID"=>"x", "PWD"=>"xxx");
$conn = sqlsrv_connect( $serverName, $connectionInfo);
Edit: Comes to my mind... Maybe a solution would be to tell this php file to load php.ini and so on from another server if that's possible?
You could possibly call a JSON endpoint on your DB server (secure the endpoint though (out of scope for my answer)) https://3v4l.org/Gpi28
<?php
// MSSQL server side
$data = [
1 => 'hello',
2 => 'world',
];
// Imagine $data above is the array of rows returned by the db query
header('Content-Type: application/json');
echo json_encode($data);
exit;
// IONOS Side
$json = file_get_contents('http://your-database-server/some/url/or/other');
$data = json_decode(true);
// Now do your updates
// NB This is an INSECURE example, people who know the URL can see this data!
I'm a total beginner when it comes to PHP, I have a fair grasp of the syntax but I'm not sure about the safest way to utilise it to connect to my server. I apologise that this is a sort of generic question rather than a code problem, since my code technically works.
I have a .php site doc with a basic comment submission form. The only way I can think of to connect to the server is to allow a "dummy" user with select only privelege to call a stored function to accept the comment.
If my dummy account is called siteuser then am I going round this the right way? This is the section of the PHP that I'm using to connect. I believe this code is only visible server side so nobody can ever see it and use the password or username to connect some other way? Or is there a sort of default string I can use in my php without creating the dummy user, seeing as the php and server is all hosted via the same provider?
$sqlserv = "localhost";
$sqlname = "siteuser";
$sqlpass = "mypassword";
$sqldbdb = "comments_table";
$conn = new mysqli($sqlserv, $sqlname, $sqlpass, $sqldbdb);
What i do is this to connect to my DB
db.php:
<?php
// Load configuration as an array. Use the actual location of your configuration file
$config = parse_ini_file('/somepath/config.ini');
//Mysqli Connection
$conn = new mysqli($config['host'], $config['user'], $config['pass'], $config['dbname']);
if($conn->connect_errno > 0){
die('Unable to connect to database [' . $conn->connect_error . ']');
//Set encoding
mysqli_set_charset($conn, "utf8") or die;
}
?>
and in config.ini:
[database]
user = johndoe
pass = someweirdpassword
dbname = the_name
host = localhost
both files have 700 permissions, so only user (and no one else can access it)
also the config.ini file is placed somewhere outside the public_html directory, i'm not totally sure if that helps or not but i do it that way.
We have multiple masters that are synced into a slave. We have decided to create a database for each master (let say MDB0001; MDB0002; MDB0003, etc...). This will allow to not corrupt the entire database if one replication fails or has corrupted data... The slave is used to show information to the people that are on the web (the master is only available in the local network)
The purpose is: we want to have a website (in php) on the server (slave) that shows the content for each database depending who is logged in. So if the user MDB0001 is connected, we have to read the data from the database MDB0001.
How can this be done? Is it a good way to do that? Or, do I have to duplicate the website for each database?
I hope I'm clear in my explanation. Thanks
assuming you get a variable from the login you could put a key->value array together on your db.php page;
$userDBs = array('login1'=>'db1','login2'=>'db2');
$dbName = $userDBs[$loggedinID]; // if login1 logs in, db1 would be result.
$db = new PDO('mysql:host=localhost;dbname='.$dbName, 'someUser', 'somePass');
or have a seperate db for the associations:
$sel = "Select dbName from databases where userId='".$loggedInID."'";
$stmt = $db->query($sel);
while($r = $stmt->fetch()){
$dbName = $r['dbName'];
}
$db = new PDO('mysql:host=localhost;dbname='.$dbName, 'someUser', 'somePass');
How can I detect what type of database I'm connecting to in drupal (using php code)? I am trying to write a module which exposes some database functionality which only works on postgres or sql server. Currently, I'm doing it by trying to detect the database version, since the syntax appears to be different for each database but it doesn't seem very robust. Is there a php function which will report this?
You should use the global variable: $databases and check the driver value.
global $databases;
dpm($databases);
https://drupal.stackexchange.com/questions/48882/how-to-get-database-credentials
I don't fully understand what you're trying at the moment but
db_driver()
returns he currently connected database in Drupal as a string (e.g. "pgsql").
This may be helpfull to you. Use db_set_active() API to set your database before executing the query.
This will help you to keep away from errors
<?php
//set your configurations
$db_url['default'] = 'mysql://drupal:drupal#localhost/drupal';
$db_url['mydb'] = 'mysql://user:pwd#localhost/anotherdb';
$db_url['db3'] = 'mysql://user:pwd#localhost/yetanotherdb';
//set the active database and then process your queries in this case you can always knows which database is connected now.
db_set_active('mydb');
db_query('SELECT * FROM table_in_anotherdb');
Setting multiple databases
<?php
// ... header of the settings.php file
$db_url = array (
"default" => "mysql://user:pass#host/db",
"second" => "pgsql://user:pass#host/db"
);
db_set_active('second');
Ref: https://drupal.org/node/18429
I am rather new to the PDO library, so I apologize for my inexperience. I am writing a class that uses the PDO library to build and execute queries and return the results, no matter what they are.
Within the class, I detect whether there is an open connection to a database, and if it is the same as the one being configured, it uses this one instead. This is really easy to do using the MsSQL library as the PDO::getAttribute() function returns 'CurrentDatabase' and 'SQLServerName', so I can just apply a condition like so:
if(!empty($this->PDO)){
// Get the current connection information
$current_connection = $this->PDO->getAttribute(PDO::ATTR_SERVER_INFO);
// Return if the connection is the same
if($this->connection_parameters['hostname']==$current_connection['SQLServerName']&&$this->connection_parameters['database']==$current_connection['CurrentDatabase']){
return;
}
}
However, when it comes to MySQL, the data returned from PDO::getAttribute is completely different and I cannot seem to get the database name from the current connection.
Does any body know a function or method to get the currently connected database of a MySQL connection using the PDO library in PHP?
I order to connect to both MySQL and MsSQL, you must have 2 connections. However, changing the database on a live connection is very simple.
The following simply checks if a PDO instance already exists and whether or not it is using the required database. If so then it continues with this connection, if not it changes the database.
// Test if the PDO object already exists
if(!empty($this->PDO)){
// If connection is the same then select the database
if($this->connection_engine==$this->PDO->getAttribute(PDO::ATTR_DRIVER_NAME)){
// Get the current database in use
$database = $this->PDO->query("SELECT {$this->select_db_function}");
$database = $database->fetchAll(PDO::FETCH_NUM);
$database = $database[0][0];
// If the current database matches the new database then return
if($database==$this->connection_parameters['database']){
return;
}
}
}
I see no point in looking for the opened connection and - especially - in checking for the current database.
Why can't you just open the connection, select the database for it and then use this connection all the time throughout your class - just like everyone does?
See comments on the MySQL manual page for 'USE database'