I want to send files through php using readfile()
What i've noticed is that readfile forces a download, but what if i want to show an image in the browser and not force a download?
Would readfile still force download even if the file is an image?
If it does, is there a solution so i can use tags with it when the file is an image?
Thanks!
You need to set the MIME type with the header() function. There should be info in the comments. Something like:
<?php
header('Content-type: image/png');
?>
Related
I want to have a PNG picture, but when accessing it, it runs a PHP script, the PHP script should decide what picture to send (using some if statements and whatever). Then the PHP script should read the image file from somewhere on my web server and output it.
Here is the issue, if I get a .png file, and put PHP code in it, it won't work, however, if I use the .php extension, it works, and I can even embed the image into other websites, and the PHP can decide what image to send, but if I want to view that image directly (copy it's URL into my address bar) it doesn't work, it gives me the images plain contents (random jibberish).
Anyone know what to do?
Also This is my first question on Stack Overflow - please tell me if I am doing something wrong.
You need to send Content-Type headers.
For png:
header('Content-Type: image/png');
For others change png to jpg or gif or bmp or whatever.
Please note that header() function must be used before anything is written to output.
First, make sure you have your image image.png somewhere accessible to php.
Then create a php script image.php:
<?php
header('Content-Type: image/png');
readfile('image.png');
The script now acts like it was a PNG image.
It sounds like you know how to send the image, your issue is that you want the URL to look like it's a PNG image.
There are a couple of things you can do. First, if your web server supports URL rewriting (like Apache's mod_rewrite module), you can use a rewrite rule so that the user access the script as something like http://example.com/generated_image.png but your server will translate/rewrite this URL to point directly to your PHP script, so something like /var/www/image_generator.php.
Another option would be to actually name your script "generated_image.png" but force your webserver to treat it like a PHP script. For instance, in Apache you could try something like:
<Location /generated_image.png>
ForceType application/x-httpd-php
</Location>
As a final note, if you're not actually worried about the URL, but worried about the file name that is used if the user decides to save it to disk, you can simply use the Content-Disposition HTTP header in your response. In PHP it would look something like this:
<?php
header("Content-Disposition: inline; filename="generated_image.png");
?>
With that, it doesn't matter what the URL is, if the user saves the image through their web browser, the web browser should offer "generated_image.png" as the default filename.
Simplest version I know...
<?php
header('Content-Type: image/png');
if(whatever)
{
$image=your_image_select_function();
}
// as suggested by sh1ftst0rm with correction of unmatched quotes.
header('Content-Disposition: inline; filename="'.$your_name_variable.'"');
readfile($image);
?>
Then, you treat it like an image file. That is, if this is "pngmaker.php" then, in your HTML document, you do
<img src="pngmaker.php">
You can even do
<img src="pngmaker.php/?id=123&user=me">
Trying to see what actions can be performed with a PHP script that is being called via an image src like so:
<img src="http://example.com/script.php" />
Now, I have tried to include the PHP header() function in script.php:
<?php
header("Location: http://example.com");
I have also tried to echo an image url expecting the img to display it, which it didn't:
<?php
echo 'http://example.com/image.png';
Are there any ways of doing such things with a PHP script that is being called in the img src attribute?
Are there any ways of doing such things with a PHP script that is being called in the img src attribute?
No. A resource that is used as a src for an img tag needs to output image data, nothing else.
There are some exceptions, eg. a header("location: ....") redirect, but the redirect needs to point to another valid image resource, not a web site as you show in your example.
Check out the readfile() as a way to output your image file from your script.php
readfile($file);
Read more about it here in the manual:
http://php.net/manual/en/function.readfile.php
where Example #1 gives an idea of how to set up the headers.
The manual also states that:
readfile() will not present any memory issues, even when sending large
files, on its own.
and
A URL can be used as a filename with this function
ps: This was the way Wordpress Multisite used to open user uploaded (e.g. images) files.
Your script.php should return the output of an image with the correct headers. For instance:
<img src="/html/img/script.php" />
// Script.php
$file = "tiger.jpeg";
$type = "image/jpeg";
header("Content-Type: $type");
header("Content-Length: " . filesize($file));
readfile($file);
You should keep in mind that the src tag should directly point to an image file. However, it is possible to use PHP to create an image, for exmaple by using the GD library:
http://php.net/manual/en/book.image.php
So using:
<img src="http://example.com/script.php" />
is possible, as long as script.php really outputs an image file, for example by using the example as described here:
http://www.php.net/manual/en/image.examples-png.php
I used this kind of processing in the past to overlay texts on JPG images for a broker website (e.g. new, sold, for rent, etc.).
Are there any ways of doing such things with a PHP script that is being called in the img src attribute?
Yes, but the PHP Script has to output image data only, as stated in various other answers.
With that being said, just read the image and output it to the stream with readfile
header('Content-Type: image/png');
readfile($file);
exit();
I know I might be a couple years late to really help you, but the accepted answer just isn't true (anymore).
I'm currently displaying images and hiding the src code by having a php file output the image. But when I right click on the image displayed and go down to 'Save As' it prompts me to download the php file not the actual image (obviously because it points to that src).
What can I do to download the actual image instead of displayImage.php?
It doesn't prompt you to download the PHP file, it simply uses that as the file name, because that is the file name from which it got the image data. If you manually input a valid image file name and try to open what you saved, it should still be a valid image.
You may also be able to give it a sensible name by including the file name in a Content-Disposition: header from your PHP file, e.g.
$filename = 'image.jpg';
header('Content-Disposition: inline; filename="'.$filename.'"');
// Don't forget the Content-Type as well...
// Output image here
...however this relies on the browser handling this sensibly, which not all of them do :-(
You can send a filename in the header.
header("Content-Type: image/png");
header('Content-Disposition: inline; filename="some.png"');
Send the correct content type in the image generator script:
header('Content-type: image/jpg');
If you want to have the .jpg extension when a PHP script is outputting an image, you'll need to do a htaccess or httpd.conf rewrite, where you can rewrite a .jpg request, to your php image generator script.
See mod_rewrite http://httpd.apache.org/docs/current/mod/mod_rewrite.html
I'm using http://undesigned.org.za/2007/10/22/amazon-s3-php-class/documentation to access private files using php. I can get the data of the file by saying $object->body. I actually want to see the image in the browser or play the video in a video player. Is there a way to do that?
I think I need something like readfile. The problem is readfile is I need the path to the file. The path is private so I cannot use that. Is there a way to do a readfile of the binary data?
I put this in the php thinking this would help but it still displays the binary data.
header('Content: image/jpeg');
header('Content-Disposition: inline; filename=IMAG0108.jpg');
echo $object->body;
You just set the content-type header and output the readfile to the browser. What I do is create a new php file, like "showimage.php", that accepts an ID or some such to know what image to display. Then I use it in a browser page: .
In showimage.php, something like:
<?php
header('Content-type: image/png');
readfile('/var/images/' . $_GET['id'] . '.png');
// or
// echo $object->body;
?>
That would read a file from the local system and output it as an image. Off the top of my head, so I might have messed up that code!
header('Content: image/jpeg');
echo $object->body;
Should work fine (for JPEGs), you need know what filetype is in question and then send appropriate content headers.
Basically I wrote a script that generates a xml file based on user input. After the file is generated a download link appears like so:
Download File
But when clicked it opens the xml in the browser, I want it to start downloading when the link it clicked instead. Is there any way to achieve that?
Yeah, there is. It does require specifying some headers. Exactly how it works depends on what language you're using, but here's an example using php, taken off of php.net:
<?php
// We'll be outputting a PDF
header('Content-type: application/pdf');
// It will be called downloaded.pdf
header('Content-Disposition: attachment; filename="downloaded.pdf"');
// The PDF source is in original.pdf
readfile('original.pdf');
?>
Basically, first we tell the client what type of file we're sending, then we tell the client that what we're sending is an attachment, and it's name, instead of it being a page to display, and then finally we print/read the file to the output.
Given that you're already using php to generate the xml file, I would suggest adding the header commands above to the code that generates the xml file, and see if that does the trick.
If you happen to be using Apache for your web server, and you always want to force downloading of XML files, there is a more efficient way to do what #chigley suggested. Just add the following to a .htaccess file.
<Files *.xml>
ForceType application/xml
Header set Content-Disposition attachment
</Files>
What happens when a browser sees a link is not dependent on the link, but rather on the target of the link. Your web server should send the appropriate header: Content-Disposition: attachment;filename="file.xml" to tell the browser that it should prompt to save the file instead of displaying it.
It depends on what the client computer does with XML files. If you doubleclick on a XML file, it will open in your browser probably.
download.php:
header('Content-Type: text/xml');
header('Content-Disposition: attachment; filename="file.xml"');
readfile('/path/to/file.xml');
HTML:
Download