Do you have any idea why i get this:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '``, `title` varchar(255) collate latin1_general_ci NOT NULL default ``,' at line 3
The code is like this (the part im having problem with...)
$sql = 'CREATE TABLE `forum` (
`postid` bigint(20) NOT NULL auto_increment,
`author` varchar(255) collate latin1_general_ci NOT NULL default ``,
`title` varchar(255) collate latin1_general_ci NOT NULL default ``,
`post` mediumtext collate latin1_general_ci NOT NULL,
`showtime` varchar(255) collate latin1_general_ci NOT NULL default ``,
`realtime` bigint(20) NOT NULL default `0`,
`lastposter` varchar(255) collate latin1_general_ci NOT NULL default ``,
`numreplies` bigint(20) NOT NULL default `0`,
`parentid` bigint(20) NOT NULL default `0`,
`lastrepliedto` bigint(20) NOT NULL default `0`,
`author_avatar` varchar(30) collate latin1_general_ci NOT NULL default `default`,
`type` varchar(2) collate latin1_general_ci NOT NULL default `1`,
`stick` varchar(6) collate latin1_general_ci NOT NULL default `0`,
`numtopics` bigint(20) NOT NULL default `0`,
`cat` bigint(20) NOT NULL,
PRIMARY KEY (`postid`)
);';
mysql_query($sql,$con) or die(mysql_error());
Help would be greatly appreciated!
`author` varchar(255) collate latin1_general_ci NOT NULL default ``,
'author' is a column name, hence why it goes it backticks.
But the default '' is a value so it should be in quotation marks, not backticks, methinks.
If this is the case, same goes for all other defaults.
You are using backticks instead of quotes for strings. Change this:
default ``
to this:
default ''
The full statement should be:
CREATE TABLE `forum` (
`postid` bigint(20) NOT NULL auto_increment,
`author` varchar(255) collate latin1_general_ci NOT NULL default '',
`title` varchar(255) collate latin1_general_ci NOT NULL default '',
`post` mediumtext collate latin1_general_ci NOT NULL,
`showtime` varchar(255) collate latin1_general_ci NOT NULL default '',
`realtime` bigint(20) NOT NULL default '0',
`lastposter` varchar(255) collate latin1_general_ci NOT NULL default '',
`numreplies` bigint(20) NOT NULL default '0',
`parentid` bigint(20) NOT NULL default '0',
`lastrepliedto` bigint(20) NOT NULL default '0',
`author_avatar` varchar(30) collate latin1_general_ci NOT NULL default 'default',
`type` varchar(2) collate latin1_general_ci NOT NULL default '1',
`stick` varchar(6) collate latin1_general_ci NOT NULL default '0',
`numtopics` bigint(20) NOT NULL default '0',
`cat` bigint(20) NOT NULL,
PRIMARY KEY (`postid`)
);
Thanks for responses. I had actually done this before (putting ' instead of ` ), but it just showed me a blank page....
I figured out my problem. I either had to put backslash before each ' or just change the
$sql = 'CREATE TABLE `forum` (
to
$sql = "CREATE TABLE `forum` (
(note the quotes)
Thanks anyway, it helped me figure it out!
Related
I'm trying to move my website from my old server to the new server at Vultr.
However, while importing the database I encountered a very annoying issue, which I spent and hours on and still couldn't fix it.
The error is happening due to the DateTime which I think needs to be converted to timestamp, however, the database is too large to be converted one by one.
Here is the error anyway:
Error at the line 111680: ) ENGINE=MyISAM DEFAULT CHARSET=utf8mb4
COLLATE=utf8mb4_unicode_ci;
Query: --
--
CREATE TABLE `mvmnvu_links` (
`link_id` bigint(20) UNSIGNED NOT NULL,
`link_url` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT '',
`link_name` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT '',
`link_image` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT '',
`link_target` varchar(25) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT '',
`link_description` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT
'',
`link_visible` varchar(20) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT 'Y',
`link_owner` bigint(20) UNSIGNED NOT NULL DEFAULT '1',
`link_rating` int(11) NOT NULL DEFAULT '0',
`link_updated` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
`link_rel` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT '',
`link_notes` mediumtext COLLATE utf8mb4_unicode_ci NOT NULL,
`link_rss` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL DEFAULT ''
) ENGINE=MyISAM DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci
MySQL: Invalid default value for 'link_updated'
Stopped on error
Any quick solutions for this?
Thank you.
i have my database sql query file and i wanna run it in php by the code below
$query = file_get_contents('./sqlquery.txt');
print $query;
$conn->query($query);
but it return this error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE IF NOT EXISTS `ads` ( `id` int(11) NOT NULL AUTO_INCREMENT, `ur' at line 2
i copied the print output in to the phpmyadmin and everything work well, what's wrong here?
my sql query is the this
DROP TABLE IF EXISTS `ads`;
CREATE TABLE IF NOT EXISTS `ads` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`url` varchar(300) NOT NULL,
`path` varchar(200) NOT NULL,
`width` int(11) NOT NULL,
`height` int(11) NOT NULL,
`priority` int(11) NOT NULL,
`adsalter` varchar(200) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`adstitle` varchar(200) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=12 ;
DROP TABLE IF EXISTS `comment`;
CREATE TABLE IF NOT EXISTS `comment` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(120) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`comment` text CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`contentid` int(11) NOT NULL,
`parentid` int(11) NOT NULL DEFAULT '0',
`date` varchar(250) NOT NULL,
`haschild` int(1) NOT NULL DEFAULT '0',
`visible` int(1) NOT NULL DEFAULT '0',
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ;
DROP TABLE IF EXISTS `files`;
CREATE TABLE IF NOT EXISTS `files` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(200) NOT NULL,
`size` int(14) NOT NULL,
`type` varchar(50) NOT NULL,
`newsid` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ;
DROP TABLE IF EXISTS `frgpss`;
CREATE TABLE IF NOT EXISTS `frgpss` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`email` varchar(100) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`ip` varchar(31) CHARACTER SET utf8 COLLATE utf8_polish_ci NOT NULL,
`token` varchar(27) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`date` int(15) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
DROP TABLE IF EXISTS `news`;
CREATE TABLE IF NOT EXISTS `news` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`titrimage` varchar(100) NOT NULL,
`titr` varchar(100) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`titralter` varchar(160) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`newsshurt` varchar(200) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`text` text CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`keywords` text CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`description` text CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`author` varchar(200) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`branch` int(11) NOT NULL,
`date` varchar(160) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
`visible` int(1) NOT NULL DEFAULT '0',
`visited` int(11) NOT NULL DEFAULT '0',
`titrtitle` varchar(200) CHARACTER SET utf8 COLLATE utf8_persian_ci NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ;
DROP TABLE IF EXISTS `signup`;
CREATE TABLE IF NOT EXISTS `signup` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(50) NOT NULL,
`family` varchar(50) NOT NULL,
`email` varchar(80) NOT NULL,
`gender` varchar(50) NOT NULL,
`username` varchar(80) NOT NULL,
`picture` varchar(80) NOT NULL,
`password` varchar(60) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
DROP TABLE IF EXISTS `users`;
CREATE TABLE IF NOT EXISTS `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(60) NOT NULL,
`lastname` varchar(60) NOT NULL,
`email` varchar(100) NOT NULL,
`password` varchar(40) NOT NULL,
`userregistereddate` varchar(60) NOT NULL,
`key` varchar(60) NOT NULL,
`type` varchar(20) NOT NULL,
`userphoto` varchar(50) NOT NULL,
`usergroup` varchar(300) NOT NULL,
`ipaddress` text NOT NULL,
`telnumber` varchar(14) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
you're executing multiple queries here, it won't work simply, I'm pretty sure that in query function($conn->query($query);) you're using mysql_query() or mysqli_query(), but you'll have to do is to use mysqli_multi_query() instead. Have a look here at docx
$con = mysqli_connect($host, $user, $pass, $db) OR die(mysqli_error($con));
$query = file_get_contents('./sqlquery.txt');
mysqli_multi_query($con, $query);
mysqli_close($con);
Hope this will help you
Note: Assuming that all queries are working fine while executing in PHPMyAdmin.
I've got two tables (NewProducts and OldProducts) that are being compared. NewProducts has about 68,000 records and OldProducts about 51,000. I'm using a covering index on each table, however the query is taking 20 minutes to execute, so I'm not using it properly. Does a covering index really apply with multiple tables? What am I doing wrong? Thank you.
Here is my query code and the indexes:
$querystring = "SELECT newProducts.Id, newProducts.SKU,
newProducts.Title, oldProducts.Title, oldProducts.product_Id
FROM
newProducts, oldProducts
WHERE
trim(newProducts.SKU)=trim(oldProducts.SKU) and
trim(newProducts.Title)=trim(oldProducts.Title) and
oldProducts.Position=1 and
oldProducts.Customer=$shop";
Indexes for NewProducts:
Primary: Id
Index: SKU, Title, customer (not unique)
Indexes for OldProducts:
Primary: Id
Index: Product_id (not unique)
Index: SKU, Title, Postition, Customer (not unique)
?>
CREATE TABLE `NewProducts` (
`Id` bigint(11) NOT NULL,
`Title` varchar(120) COLLATE utf8_unicode_ci NOT NULL,
`Category` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`Office` varchar(150) COLLATE utf8_unicode_ci NOT NULL,
`Rehashed` smallint(6) NOT NULL,
`Quantity` smallint(6) NOT NULL,
`Price1` decimal(7,2) NOT NULL,
`Price2` decimal(7,2) NOT NULL,
`Price3` decimal(7,2) NOT NULL,
`Price4` decimal(7,2) NOT NULL,
`created_at` varchar(30) COLLATE utf8_unicode_ci DEFAULT NULL,
`OldQuantity` int(11) NOT NULL,
`SKU` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`Source` varchar(12) COLLATE utf8_unicode_ci NOT NULL,
`customer` varchar(70) COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`Id`),
UNIQUE KEY `I-T-S` (`ItemId`,`Title`,`SKU`),
KEY `customer` (`customer`),
KEY `Title` (`Title`,`Rehashed`),
KEY `SKU` (`SKU`),
KEY `Title_2` (`Title`,`SKU`,`customer`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci
CREATE TABLE `OldProducts` (
`barcode` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`compare_at_price` decimal(10,2) DEFAULT NULL,
`created_at` varchar(30) COLLATE utf8_unicode_ci DEFAULT NULL,
`fulfillment` varchar(35) COLLATE utf8_unicode_ci DEFAULT NULL,
`grams` decimal(10,2) DEFAULT NULL,
`id` bigint(11) NOT NULL,
`management` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`policy` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`size` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`color` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`type` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`position` int(11) DEFAULT NULL,
`price` varchar(15) COLLATE utf8_unicode_ci DEFAULT NULL,
`product_id` bigint(11) NOT NULL,
`SKU` varchar(55) COLLATE utf8_unicode_ci DEFAULT NULL,
`Title` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,
`quantity` int(11) DEFAULT NULL,
`customer` varchar(70) COLLATE utf8_unicode_ci NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `P-S-T-PO-CUST`
(`product_id`,`SKU`,`Title`,`position`,`customer`),
KEY `product_id` (`product_id`),
TRIM is the villain. When you hide an indexed column (eg, SKU) inside a function (eg, TRIM), the the index cannot be used.
Clean up your data:
Fix the insertion code to TRIM before inserting (or as it inserts).
UPDATE tbl SET SKU = TRIM(SKU), title = TRIM(title); -- for each table
Change the SELECT: TRIM(SKU) --> SKU etc.
Even Better
oldProducts should have, in this order,
`INDEX(`position`,`customer` ,`SKU`,`Title`, `product_id`)
With this, the WHERE need look only at old rows for position=1 and customer =.... (Actually, the first 2 columns can be in any order; the last 3 in any order.)
While inserting first time it gives following error: "Result consisted of more than one row". When i try to insert record second time it gives error with message duplicate entry.
SQL=INSERT INTO `master_user` (`name`,`user_name`,`email`,`password`,`system_name_of_friend`,`system_no_of_friend`,`registered_from_site`,`registered_on`,`is_existing_user`) VALUES ('FirstName LastName','username','demo#mail.com','8c71eede42e38709e9e836021b0b9b9b','','','site','','1')
any one help will be appropriated and following is the table structure which will be get help to tracking this issue very easily and get the solution for this.
CREATE TABLE IF NOT EXISTS `master_user` (
`master_user_id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`user_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,
`email` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
`system_name_of_friend` varchar(100) COLLATE utf8_unicode_ci NOT NULL,
`system_no_of_friend` varchar(50) COLLATE utf8_unicode_ci NOT NULL,
`registered_from_ip` varchar(25) COLLATE utf8_unicode_ci DEFAULT NULL,
`registered_from_site` varchar(25) COLLATE utf8_unicode_ci DEFAULT NULL,
`registered_on` datetime DEFAULT NULL,
`is_existing_user` bit(1) NOT NULL DEFAULT b'0',
PRIMARY KEY (`master_user_id`),
UNIQUE KEY `ukMasterUser_email` (`email`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1293 ;
I have changed the few words from column Which are conflicting and resolved.
this code tested with both server and local phpmyadmin
on localhost it returned results as expected
on server it returned a good result but when passing the dr_name it returns empty result
here is the code:
SELECT * FROM doctor WHERE dr_name LIKE '%غا%' AND specialization=12 AND state=6
the only deference between server and local is that the server mysql engine is myisam and innodb on localhost
this is the create table statement:
CREATE TABLE IF NOT EXISTS `doctor` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`dr_name` varchar(65) NOT NULL,
`dr_name_e` varchar(65) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL,
`unique_name` varchar(75) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL,
`pass` char(40) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL,
`nickname` varchar(100) CHARACTER SET utf8 COLLATE utf8_unicode_ci DEFAULT NULL,
`specialization` int(11) NOT NULL,
`state` tinyint(4) NOT NULL,
`scientific_degree` int(11) DEFAULT NULL,
`university` int(11) DEFAULT NULL,
`grad_year` smallint(6) DEFAULT NULL,
`show_degree` tinyint(1) DEFAULT NULL,
`show_univ` tinyint(1) DEFAULT NULL,
`show_grad_year` tinyint(1) DEFAULT NULL,
`appendices` varchar(1000) CHARACTER SET utf8 COLLATE utf8_unicode_ci DEFAULT NULL,
`picture` varchar(255) CHARACTER SET utf8 COLLATE utf8_unicode_ci DEFAULT NULL,
`active` tinyint(1) NOT NULL DEFAULT '0',
`views` bigint(20) DEFAULT '0',
`search_result` bigint(20) DEFAULT '0',
`gender_male` tinyint(1) DEFAULT NULL,
`agent` int(11) DEFAULT NULL,
`next_step` tinyint(4) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `unique_name` (`unique_name`),
KEY `university` (`university`),
KEY `scientific_degree` (`scientific_degree`),
KEY `specialization` (`specialization`),
KEY `agent` (`agent`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=31 ;