I have a string with hexvalues that I use with sha1()
echo sha1("\x23\x9A\xB9\xCB\x28\x2D\xAF\x66\x23\x1D\xC5\xA4\xDF\x6B\xFB\xAE\x00\x00\x00\x01");
ab94fcedf2664edfb9b291f85d7f77f27f2f4a9d
now I have another string with the same value only not hex.
$string2=strtoupper("239ab9cb282daf66231dc5a4df6bfbae00000001");
I want to convert this string so that it is read as above and that the sha1-value is the same as above.
echo sha1(do_something($string2));
ab94fcedf2664edfb9b291f85d7f77f27f2f4a9d
Does anybody know how to convert a string to real hexvalues?
I've tried with pack, sprinft, hexdec, but nothing worked (couldn't find typecasting in hex)
$s = "239ab9cb282daf66231dc5a4df6bfbae00000001";
echo sha1(pack('H*', $s));
Output:
ab94fcedf2664edfb9b291f85d7f77f27f2f4a9d
Related
I've got a string representing an IPv4 address:
$ip = '\x7F\0\0\x01';
When I try to pass that to inet_ntop($ip) it's giving me grief:
PHP Warning: inet_ntop(): Invalid in_addr value
If I declare the variable manually using double quotes it works:
$ip = "\x7F\0\0\x01";
inet_ntop($ip); // "127.0.0.1"
However, I am not declaring these variables manually. I'm working with what is given to me in an object.
How can I convert '\x7F\0\0\x01' into a string that inet_ntop() will accept?
In other words, how can I make PHP parse a string literally as if I were manually declaring it with double quotes?
Some interesting facts:
gettype('\x7F\0\0\x01'); // string
gettype("\x7F\0\0\x01"); // string
ord('\x7F\0\0\x01'); // 92
ord("\x7F\0\0\x01"); // 127
implode(unpack('H*', '\x7F\0\0\x01')); // 5c7837465c305c305c783031
implode(unpack('H*', "\x7F\0\0\x01")); // 7f000001
mb_detect_encoding('\x7F\0\0\x01'); // ASCII
mb_detect_encoding("\x7F\0\0\x01"); // UTF-8
"\x7F\0\0\x01" == '\x7F\0\0\x01'; // false
// and for the haters
long2ip('\x7F\0\0\x01'); // PHP Warning: long2ip() expects parameter 1 to be integer, string given
One possibility is to parse the string into its component pieces (starting with \); convert them to the decimal equivalent and use chr to get back the original characters. These can then be joined into a string which is suitable for inet_ntop:
$ip = '\x7F\0\0\x01';
preg_match_all('/\\\x?([\dA-F]+)/', $ip, $parts);
$ip = implode('', array_map(function ($v) { return chr(hexdec($v)); }, $parts[1]));
echo inet_ntop($ip);
Another alternative is to use pack, after stripping out the \x parts and replacing \0 with 00:
$ip = '\x7F\0\0\x01';
$ip = pack('H*', str_replace(array('\x', '\0'), array('', '00'), $ip));
echo inet_ntop($ip);
In both cases the output is:
127.0.0.1
Demo on 3v4l.org
The problem is that you've got the literal ASCII output of a binary string and not the real binary value you expect it to be. I'm not sure how you got the literal ASCII value. There is a way to convert it, but you're not going to like it.
You can use eval() to accomplish what you're trying to do. All arguments for eval() being evil still apply.
$ip = '\x7F\0\0\x01';
eval("\$ip = \"$ip\";");
echo inet_ntop($ip);
This will print out 127.0.0.1.
Since binary doesn’t always result in literal ASCII characters, I worry you’ll see literal characters like � in the strings, and these won’t convert properly to the binary value you expect them to be.
For example, here are the characters printed to screen in Psysh:
>>> hex2bin('7f000001') // This is 127.0.0.1
=> "\x7F\0\0\x01"
>>> hex2bin('ffffffff') // This is 255.255.255.255
=> b"ÿÿÿÿ"
The first value looks familiar, right? That's the string literal that we can convert back into a binary string using eval(), like we did in the example above. But the binary value for ffffffff is a different story. If we try to convert it, it doesn't give us the 255.255.255.255 value we expect.
$ip = 'ÿÿÿÿ';
eval("\$ip = \"$ip\";");
echo inet_ntop($ip);
In this case, inet_ntop() returns false, but we know it should work:
>>> inet_ntop(hex2bin('ffffffff'));
=> "255.255.255.255"
So, I worry that any attempt to convert these values from string literals into binary strings is not going to work in all cases, whether using eval() or any of the other answers provided here.
However, if everything is coming to you in the format \0\0\0\0, where each "segment" is either a zero or a hex value in the format x00, then you should be in good shape, because these are the same:
>>> "\xFF\xFF\xFF\xFF"
=> b"ÿÿÿÿ"
You can make your own function like this
function convertStringToInAddr(string $string) {
$return = null;
$exploded = explode("\\", $string);
foreach($exploded as $hex) {
if( $hex != "" ) {
$return .= chr(hexdec(str_replace("x", "", $hex)));
}
}
return $return;
}
I am trying to convey $string to float. The type of $string is string in the format of "0.0111455667". I have the following code in php.I have tried all these methods and I got 0 for all of them. how can I convert the string to float?why I always get 0?
PS: please do not assume my question as duplicate, I have already tried all the methods in the similar questions and none of them worked for me.
$float = (float) $string;
//$float2 = $string + 0.0; //this works as well.
$floatval = floatval($string);
$double = (double) $string;
// TEST
echo $string;
echo $float;
//echo $float2;
echo $floatval;
echo $double;
Your problem is the content of $string.
In PHP, every time you convert a string to a float, be it by casting (float) $string, or floatval($string), you will always get 0 if the first character of the string is not numeric.
From PHP docs: String conversion to numbers
The value is given by the initial portion of the string. If the string starts with valid numeric data, this will be the value used. Otherwise, the value will be 0 (zero)
Double-check the content of $string. Probably you have some spurious characters at its beginning.
I have a string which value is 123, like: $string = '123'; and my hex value, which is $hex = bin2hex($string); and the return is 313233. When i convert to string again, using hex2bin(), it returns 123 correctly. But when i try to make a "compare" it always returns both like a hexadecimal value.
I know that each number, both 1, 2 and 3 are part of hexadecimal table, but, is there a way that can i differentiate each one ? I'd already searched something about it, but i got no solution.
I'm sorry if this question is poor. But it will really helped me. Besides, it's a doubt that i have.
My php code:
<?php
$string = '123';
$hex = bin2hex($string);
if(hex2bin($hex)){
echo 'hex';
}else{
echo 'not hex';
}
?>
As far as I understand, you are looking for the ctype_xdigit() function, which returns true if all the individual letters in your string are hexadecimal digits, otherwise false.
You just have to pass the string as a parameter:
if (ctype_xdigit($hex_string)){
echo 'hex';
} else {
echo 'not hex';
}
What you did in your original code was converting binary numbers to hexadecimals and then the other way round. It's no surprise that it didn't give you the expected results, as 123 is not a binary number, in the input there couldn't be any other digits than 0 and 1.
firstly, functions don't work as you think they do, i.e. if(hex2bin($hex)) is kind of nonsense when used like that. (it returns "123" which will always evaluate as "true")
secondly, consider using ctype_xdigit which does what you want
<?php
$string = '123';
$hex = bin2hex($string);
if(ctype_xdigit($hex)){
echo 'is a hex value (was originally '+hex2bin($hex)+')';
}else{
echo 'not hex';
}
?>
I have the hex representation and I'm trying to convert this to the type of hex. For example if you execute:
echo "\xFF\xAA";
echo '<br>';
$first = "FF";
$second = "AA";
echo "\x$first\x$second";
die();
The result you get is:
So the first line is weird symbols. This indicates to me this is actually of type hex. Where the second result although is valid representations of hex, they are in fact not actually hex.
So my question is how can I make the actual result hex? I want to be able to use a variable as the representation but actually convert it to hex. (I want line two to show up as symbols)
hex2bin — Decodes a hexadecimally encoded binary string
<?php
$hex = hex2bin("6578616d706c65206865782064617461");
echo $hex;
?>
Output:
example hex data
Source: http://php.net/manual/en/function.hex2bin.php
So just use
echo hex2bin("$first$second");
I have the following string which i need to convert to integer or bigint.
$test="99999977706";
I tried:
echo (int)$test;
echo (integer)$test;
echo intval($test);
But they are all returning me 2147483647.
How do i convert the above string to a number or bigint?
Many many thanks for all suggestions.
MySQL isn't going to know the difference. Just feed the string into your query as though it is a number without first type casting it in PHP.
For example:
$SQL = "SELECT * FROM table WHERE id = $test";
working solution :
<?php
$str = "99999977706";
$bigInt = gmp_init($str);
$bigIntVal = gmp_intval($bigInt);
echo $bigIntVal;
?>
It will return : 99999977706
In your snippet $test is already a number, more specifically a float. PHP will convert the contents of $test to the correct type when you use it as a number or a string, because the language is loosely typed.
For arbitrary length integers use GMP.
You can treat the string as string without converting it.
Just use a regex to leave only numbers:
$test = "99999977706";
$test = preg_replace('/[^0-9]/', '', $test);
It can help you,
$token= sprintf("%.0f",$appdata['access_token'] );
you can refer with this link