PHP & MySQL Pagination - php

I have a MySQL query
SELECT * FROM 'redirect'
WHERE 'user_id'= \''.$_SESSION['user_id'].' \'
ORDER BY 'timestamp'`
I want to paginate 10 results per page. How Can I do it?

Here is a nice starting point:
<?php
// insert your mysql connection code here
$perPage = 10;
$page = (isset($_GET['page'])) ? (int)$_GET['page'] : 1;
$startAt = $perPage * ($page - 1);
$query = "SELECT COUNT(*) as total FROM redirect
WHERE user_id = '".$_SESSION['user_id']."'";
$r = mysql_fetch_assoc(mysql_query($query));
$totalPages = ceil($r['total'] / $perPage);
$links = "";
for ($i = 1; $i <= $totalPages; $i++) {
$links .= ($i != $page )
? "<a href='index.php?page=$i'>Page $i</a> "
: "$page ";
}
$r = mysql_query($query);
$query = "SELECT * FROM 'redirect'
WHERE 'user_id'= \''.$_SESSION['user_id'].' \'
ORDER BY 'timestamp' LIMIT $startAt, $perPage";
$r = mysql_query($query);
// display results here the way you want
echo $links; // show links to other pages

Use LIMIT.
SELECT *
FROM redirect
WHERE user_id = '35251'
ORDER BY timestamp
LIMIT 40, 10
40 is how many records to skip, 10 is how many to display.
There are also a few problems with your PHP. You use backticks (not single quotes) to surround table and column names. And you shouldn't use string concatenation to build your query.

Here is my code
which contains next and Previous button
<?php
$limit = 3; //set Number of entries to show in a page.
// Look for a GET variable page if not found default is 1.
if (isset($_GET["page"])) {
$page = $_GET["page"];
}
else { $page=1;
}
//determine the sql LIMIT starting number for the results on the displaying page
$page_index = ($page-1) * $limit; // 0
$All_Users=mysqli_query($con,"select * from users limit $page_index, $limit");
while($row=mysqli_fetch_array($All_Users))
{
//show data in table or where you want..
}
$all_data=mysqli_query($con,"select count(*) from users");
$user_count = mysqli_fetch_row($all_data); // say total count 9
$total_records = $user_count[0]; //9
$total_pages = ceil($total_records / $limit); // 9/3= 3
if($page >= 2){
echo "<a href='blog.php?page=".($page-1)."' class='btn
customBtn2'>Previous</a>";
}
if($page<$total_pages) {
echo "<a href='blog.php?page=".($page+1)."' class='btn customBtn2'>NEXT</a>";
}
?>

Use the LIMIT clausule of the query to limit the amount of results you retrieve from the database.
See: http://dev.mysql.com/doc/refman/5.1/en/select.html

Related

Pagination script last page

I created php script following the tutorial, but it has a mistake. It displays in the last page information which is in the previous page - it's because $perpage. How can I display only data which wasn't display yet.
EXAMPLE - If I set $perpage to 3 and I have 7 records (named 1,2,3,4,5,6,7) on page one is 1,2,3 on page two is 4,5,6 and on the last page is 5,6,7 (I want to display only record 7)
$query = mysql_query("SELECT ID FROM clanek");
$count = mysql_num_rows($query);
$perpage = 3; // řádků na stránku
$pages_count = ceil($count / $perpage); //celkem stránek zaokrohleno
$page = isset($_GET['page']) ? $_GET['page'] : 1;
$is_first = $page == 1; //první stránka
$is_last = $page == $pages_count;
$prev = max(1, $page - 1);
$next = min($pages_count , $page + 1); /
$data = mysql_query("SELECT DATE_FORMAT(datum_pridani_c,'%d.%m.%Y %H:%i:%s')as datumcas,nazev,kratky_popis,ID FROM clanek ORDER BY datum_pridani_c DESC LIMIT ".($page - 1).", ".$perpage); /
while ($zaznam = mysql_fetch_array($data)) {
//some info her
}
if($pages_count>0) {
if(!$is_first) {
echo '<a class="predchozistranka" href="index.php?page='.$prev.'">Předchozí</a>';
}
echo '<span class="stranka">Stránka '.$page.' / '.$pages_count.'</span>';
if(!$is_last) {
echo '<a class="dalsistranka" href="index.php?page='.$next.'">Další</a>';
}
}
$data = mysql_query("SELECT DATE_FORMAT(datum_pridani_c,'%d.%m.%Y %H:%i:%s')as datumcas,nazev,kratky_popis,ID FROM clanek ORDER BY datum_pridani_c DESC LIMIT ".($page - 1).", ".$perpage);
It has been a while since I have used MySQL but I fired up my Workbench just now and I see that the syntax for LIMIT is LIMIT offset,rowcount. The doc says so too http://dev.mysql.com/doc/refman/5.0/en/select.html
For your query to work then, instead of ($page - 1), $perpage, it should be ($page - 1)*$perpage, $perpage
$query = mysql_query("SELECT ID FROM clanek");
$count = mysql_num_rows($query);
Irrelevant but the above code is highly inefficient for getting the total number of rows. It would be better if you use SELECT count(id) FROM clanek

Multiple page results with sql and php

I'm having trouble with the following code from a tutorial, it seems very simple but there must be something I'm missing. There is nothing at all where my numbered page menu should be, can anyone see why?
if (isset($_GET["page"])) { // get page number for query
$page = $_GET["page"];
}
else {
$page = 1; // no page number? set it
};
$start_from = ($page-1) * 20;
$query = "SELECT * FROM posts";
$query.= " WHERE isstart = 'y' AND iscomplete = 'n' ORDER BY date DESC LIMIT $start_from, 20";
$start_from, 20"; // use LIMIT (and options) to make sure only 20 are displayed
$result = mysql_query($query);
$query_count = "SELECT COUNT(post_ID) FROM posts WHERE isstart = 'y'";
$count_result = mysql_query($query_count);
$count_results = mysql_fetch_row($count_result);
$total_posts = $count_results[0];
$total_pages = ceil($total_posts / 20); // get total pages needed for page menu
for ($i=1; $i<=$total_pages; $i++) { // set the page numbers
$pagelink = "Page: <a href='index_test.php?page=".$i."'>".$i."</a>"; // make the page menu
};
$top_body_text = '<p align="left">'.$pagelink.'</p>';
Currently my statement echo'ing $pagelink creates noting.
First thing, there is a error on this line
$start_from, 20";
It should be
$start_from = 20;
and lastly, you need to echo '$pagelink' inside the for loop in order to see each pages number listed out. Example below:
if (isset($_GET["page"]))
{ // get page number for query
$page = $_GET["page"];
}
else {
$page = 1; // no page number? set it
};
$start_f = 20; // use LIMIT (and options) to make sure only 20 are displayed
$start_from = ($page-1) * $start_f;
$query = "SELECT * FROM posts";
$query.= " WHERE isstart = 'y' AND iscomplete = 'n' ORDER BY date DESC LIMIT $start_from, 20";
$result = mysql_query($query);
$query_count = "SELECT COUNT(post_ID) FROM posts WHERE isstart = 'y'";
$count_result = mysql_query($query_count);
$count_results = mysql_fetch_row($count_result);
$total_posts = $count_results[0];
$total_pages = ceil($total_posts / 20); // get total pages needed for page menu
for ($i=1; $i<=$total_pages; $i++)
{ // set the page numbers
echo $pagelink = "Page: <a href='index_test.php?page=".$i."'>".$i."</a>"; ///Echo here
};
$top_body_text = '<p align="left">'.$pagelink.'</p>';
Remove this line -- it's not doing anything:
$start_from, 20"; // use LIMIT (and options) to make sure only 20 are displayed
You'd already defined $start_from here:
$start_from = ($page-1) * 20;
Then check out your results and see if you are all set.

limit page links based on the current page

I have this code which splits the mysql results into 10 results per page. but I want to edit it so that it limits links based on what the current page is. so on pages 1-10 it only shows page links 1-10 on pages 11-20 it only shows page links 11-20 and so on. how could I achieve this? Thanks.
if (isset($_GET["page"]))
{
$page = $_GET["page"];
}
else
{
$page=1;
};
$start_from = ($page-1) * 10;
$message = "SELECT * FROM document WHERE email='$_SESSION[email]' ORDER BY id DESC LIMIT $start_from , 10";
// echo results
// make page links for results
$sql = "SELECT id FROM document WHERE email = '$_SESSION[email]'";
$rs_result = $db->query($sql);
$total_records = $rs_result->num_rows;
$total_pages = ceil($total_records / 10);
if($rs_result->num_rows >10) {
$page = "<p class = 'page'>";
for ($i=1; $i<=$total_pages; $i++)
{
$page .="<a href='results.html?page=".$i."'>".$i."</a> ";
}
$page .="</p>";
echo $page;
}
Do this
"SELECT * FROM document WHERE email='$_SESSION[email]' ORDER BY id DESC LIMIT 10 OFFSET $start_from";
Tell me if it works.

how to use paging in displaying records from the database?

I am displaying some records from the database. Currently I am displaying the top twenty records but I want to show all records with twenty records per page.
How will I use the paging in php to display all records?'
Any Idea about this?
Something like this might work:
$posts_per_page = 10;
$page = isset($_GET['page']) ? intval($_GET['page']) : 0;
$query = sprintf("SELECT * FROM <table> LIMIT %d, %d",
$page * $post_per_page,
$posts_per_page);
$result = mysql_query($query);
The above query will select 10 records with a offset based on the current page.
You will also have to get the total number of pages based on the $posts_per_page:
$query = "SELECT COUNT(*) c FROM <table>";
You will have to keep track of the total number of posts divided with $posts_per_page and also the current page, then you can display a prev and next link:
if ($current_page > 0) {
echo '<a href="index.php?page=' . ($current_page - 1) . '>prev</a>';
}
if ($current_page < $max_pages - 1) {
echo '<a href="index.php?page=' . ($current_page + 1) . '>next</a>';
}
The basic idea is to send a page variable, for example $page, to your script and then customize your MySQL query to retrieve only that page's results.
Here is an example so you can see what I mean:
$page = $_GET['page'];
$resultsPerPage = 20;
$start = ($page - 1) * $resultsPerPage;
$query = "SELECT `results` FROM `table` WHERE ... ORDER BY `date` LIMIT $start, $resultsPerPage"
You can see how if $page = 1, then $start = 0 and this query will retrieve the 20 results, offset at 0. For $page = 2, $start = 20 so the query will retrieve the results from 20 - 40, which should show on the second page.
This is assuming your first page is 1. If you want the first page to be 0, then you need to change $start:
$start = $page * $resultsPerPage;

How can I do pagination of HABTM data?

i have a table where a Collection has many Entities and an Entity has and belongs to many colections..now for a particular collection there are many entities..how can i paginate those entities belonging to a particular collection..
my find query says..,
$this->Collection->find('first', array('condition'=>array('uid'=>$uid)),
'contains(array('Entity')));
now how to paginate the result of entities..
In your controller action
$this->paginate=array('Entity' => array(
'conditions' => "Entity.collection_id=$id",
'fields' => array('Entity.*')
)
);
$this->set('entities', $this->paginate($this->Collection->Entity));
I'm assuming here that you're using an SQL database.
Now i haven't tested the code, but i think it should work.
// First query to get some info.
$testquery = mysql_query("SELECT * FROM `table` WHERE `entity` = 'something'");
if(!$testquery) die(mysql_error());
$total_items = mysql_num_rows($testquery); // Count the total number of entity's that match the criteria.
$limit = 10; // Maximun number of entity's on page.
$page = $_GET['page'];
//calcuate total pages
$total_pages = ceil($total_items / $limit); // ceil is used to round up fractions to the next int
$set_limit = $page * $limit - ($limit);
$query2 = mysql_query("SELECT * FROM `table` WHERE `entity` = 'something' LIMIT $set_limit, $limit");
if(!$query2) die(mysql_error());
//show data matching query:
while($code = mysql_fetch_object($query2)) {
echo("item: ".$code->title."<BR>");
}
// This displays the "previous page" link if there is a previous page.
$prev_page = $page - 1;
if($prev_page >= 1) {
echo("<a href=yourpagename.php?page=$prev_page>Previous</a>");
}
//Display middle pages:
$mid_page = 1;
while ($total_pages >= $mid_page) {
if ($page == $midpage){
echo ("<b>$mid_page</b> | ");
}
else {
echo (" <a href=yourpagename.php?page=$mid_page> $mid_page </a> | ");
$midpage++;
}
}
// This page will display a "next page" link if there is one.
$next_page = $page + 1;
if($next_page <= $total_pages) {
echo("<a href=yourpagename.php?page=$next_page>Next</a>");
}

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