I have the following string: 2010-04-08T12:46:43+00:00
I want to convert that to:
8th April 2010 # 12:46
Is that easy enough?
Take a look at strtotime to create a UNIX timestamp from your time string, and then use date($format, $UNIXtimestamp); to create a normal date again:
$Timestamp = strtotime("2010-04-08T12:46:43+00:00");
echo date("your time format", $Timestamp);
You can look up the specific characters for the time format from PHP.net
Here you go.
EDIT : Exactly as you needed
Code:
$time_value = strtotime("2010-04-08T12:46:43+00:00");
$date_in_your_format = date( 'jS F Y # g:i', $time_value);
echo $date_in_your_format;
yep. use strtotime() + date()
Try taking a look at strtotime() and date().
Related
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";
I want to convert 12h time in php which is in this format: 05/31/2012 09:48 AM
to 24h time format : 2011-11-27 11:53:36
This is my code line that you can change:
$time= $_POST['time'];
You can use this:
// $time = 05/31/2012 09:48 AM
$time = $_POST['time'];
//output new time: 2012-05-31 09:48:00
$newTime = date("Y-m-d H:i:s", strtotime($time)) );
live example
Doc:
strtotime
date
http://psoug.org/snippet/Convert_12_to_24_hour_time_and_vice_versa_241.htm
You have to use strtotime like this:
$date="05/31/2012 09:48 AM";
echo date("Y-m-d H:i:s",strtotime($date));
go through below link for date functionality in PHP
http://php.net/manual/en/function.date.php
You can use strtotime and then date functions for that.
http://php.net/manual/en/function.date.php All the possible options are listed there.
The first argument to date is the format and the second is a timestamp (which you get with strtotime of the current date string you have).
date('Y-m-d H:i:s', strtotime($your_current_date_string));
The format is just off the top of my head and not exact. You can look up the format you need in the table in the link provided.
I have an sql database with a date column like this yyyymmdd (20111109), i usually sort my return queries by the date.
I would like to know how to convert this to the (D jS M) or (Wed 9th Nov).
For the month, date, and ordinal suffix, im using substr along with case. but its the weekday im getting frustrated with.
Is there a simpler method?
Thanks in advance.
If you are interested in something more sophisticated:
$date = DateTime::createFromFormat('Ymd', '20111109');
echo $date->format('D jS M');
This should be more reliable in the long run.
This should work:
date_default_timezone_set('America/Los_Angeles');
$date = strtotime($your_string);
$formatted_date = date('D jS M', $date);
echo $formatted_date;
Try using strtotime and the date() function
with a combination of those you can achieve:
echo date("D j, M", strtotime(20111109));
When I had UNIX timestamps, I'd write:
strftime("%A", $date)
But now I have datestamps, like "2011-08-02"
How can I make it output the weekday name, e.g "Sunday"?
You can convert the date stamp to a timestamp using the function strtotime.
Once you have the timestamp, you can just use the function date to show the date in the desired format.
First use the strtotime function to convert the '2011-08-02' to a UNIX timestamp, and then proceed as you usually would
For example, the following are equivalent:
$date = 1312243200; // A unix timestamp
$date = strtotime('2011-08-02'); // The date that it represents
You can then do whatever you would usually do with the result
The strtotime() function is fairly forgiving in what date formats it accepts and even accepts values such as '8pm tomorrow' or 'last Monday' - See http://www.php.net/strtotime
Use date('l'); Add more properties like so: date('l d-m-Y');.
More info here
(2nd August 2011 was a Tuesday, not a Sunday.)
<?php
echo strftime("%A", strtotime("2011-08-02"));
// Output: "Tuesday"
?>
Live demo
strtotime documentation
date('l',strtotime('2011-08-02'));
I am pulling the dates of various posts from a database. The dates are in the following format:
2009-08-12
Numeric Year - Numeric Month - Numeric Day
How can I reformat these dates to something more user friendly like:
August 12, 2009
Numeric Month Numeric Date, Numeric Year
Assuming that the date gotten from the mysql database is stored in a variable called:
$date = $row['date_selected'];
Unlike the strtotime based examples, this allows you to ensure the month and day are interpreted in the correct order regardless of locale settings specified on the server.
$date = DateTime::createFromFormat('Y-m-d', '2009-08-12');
$output = $date->format('F j, Y');
date("F d, Y", strtotime($input))
$new_format = date("Your Date String", strtotime($date));
See:
- http://php.net/strtotime
- http://php.net/date
Basically, if strtotime() can read it correctly, you can reformat it anyway you please.
In this case, Year - Month - Day is a properly recognized strtotime() format, this might not be the case for other formats.
You might consider doing your date formatting in MySQL with your select statement:
DATE_FORMAT(date,'%M %e, %Y') as date_selected
http://www.w3schools.com/sql/func_date_format.asp
<?php
echo date('F j, Y', strtotime($date));
You might want to look at the php function strtotime:
http://php.net/manual/en/function.strtotime.php
It'll parse a large number of date representations to a Unix timestamp.
Then use the date function.
Using strtodate or explode to split the date into its different components, you can then use the date function with the appropriate format string:http://php.net/manual/en/function.date.php
$date = "2009-08-12";
list($year,$month,$day) = explode("-",$date);
$formattedDate = date("F d, Y", mktime(0,0,0,$month,$day,$year));
Outputs: "August 12, 2009"
<?php
//Date Formatter
/*
date: date you want to convert
format: its current format ie m-d-Y, m/d/Y, Y-m-d, Y/m/d
delimS: Current delimiter ie - or / or .
delimF: The delimiter you want for the result
NOTE: this will only convert m-d-Y to Y-m-d and back
*/
function dtform($date,$format,$delimS,$delimF){
$dateFinal = '';
if($format == 'm'.$delimS.'d'.$delimS.'Y'){
$dateFinal_exp = explode($delimS,$date);
$dateFinal = $dateFinal_exp[2].$delimF.$dateFinal_exp[0].$delimF.$dateFinal_exp[1];
}else if($format == 'Y'.$delimS.'m'.$delimS.'d'){
$dateFinal_exp = explode($delimS,$date);
$dateFinal = $dateFinal_exp[1].$delimF.$dateFinal_exp[2].$delimF.$dateFinal_exp[0];
}
return $dateFinal;
}
?>
Use it like this:
// February 1, 2005
print date ("F j, Y", mktime (0,0,0,14,1,2004));