Is there a quicker way of creating a date such as:
echo date('Y-m-d', mktime(0, 0, 0, date("m"), date("d")+3, date("Y")));
Thanks if you can help.
How about strtotime():
date('Y-m-d', strtotime('+3 days'));
You will have to look into strtotime(). I'd imagine your final code would look something like this:
$currentDate = strtotime('today');//your date variable goes here
$futureDate = date('Y-m-d', strtotime('+ 2 days', $currentDate));
echo $futureDate;
Live Demo
If you are using PHP version >= 5.2 I strongly suggest you use the new DateTime object. For example like below:
$futureDate = new DateTime("today");
$futureDate->modify("+2 days");
echo $futureDate->format("Y-m-d");
Live Demo
Related
I want to have the date of tomorrow stored as a parameter in php.
$vandaag = date(DATE_ATOM);
$morgen = mktime(0, 0, 0, date("m"), date("d")+1, date("Y"));
$morgen = date(DATE_ATOM, $morgen);
This is the code that I have and it works but I'm not sure if this will give problems at the end of a month. Is mktime smart enough to avoid such problems or do I need to do this another way?
Use DateTime() from PHP
Code will look something like:
$vandaag = new DateTime();
$vandaag->modify('+1 day');
Ref.: http://php.net/manual/en/class.datetime.php
I suggest you use the following:
$morgen = (new DateTime())->modify("+1 day");
This will always give you the date exactly 24 hours from now.
I am working on a task where I need the user to provide exact number of months it will take them to complete a task and then i need to convert that number to an exact date, so lets suppose a user enters 6, this should give me a date 6 months from now.
I tried the following code looking at different examples on line but I have a feeling the following examples treats the $monthNum as the actual month of a year rather than what I need it to do.
$monthNum = 5;
$monthName = date("F", mktime(0, 0, 0, $monthNum, 10));
echo $monthName;
I will really appreciate any assistance here.
Demo here
Pop in your month in the modify() method.
$monthNum = 6;
$date = new DateTime();
$date->modify(" +{$monthNum} month");
echo $date->format("Y-m-d");
Outputs
2015-05-14
You can try:
$time = new \DateTime('+5 months');
You can use strtotime:
$date = date("Y-m-d", strtotime("+5 months"));
in php 5.4+
echo (new DateTime())->modify('+6 months')->format('d M Y');
I a using PHP and would like the date of third day before the script is called in the format of YYYYMMDD. How can I do this?
Try this
$result = date('Y.m.d',strtotime("-3 days"));
Use DateTime:
$date = new \DateTime('-3 days');
echo $date->format('Ymd');
// Alternatively, store the string in a variable
$result = $date->format('Ymd');
try this easy way
echo date('Ymd', strtotime("-3 days"));
Atleast visit php.net once before such questions
<?php
$date = mktime(0, 0, 0, date("m") , date("d")-3, date("Y"));
echo date('Ymd', strtotime($date));
?>
I don't know how to explain this correctly but just some sample for you guys so that you can really get what Im trying to say.
Today is April 09, 2010
7 days from now is April 16,2010
Im looking for a php code, which can give me the exact date giving the number of days interval prior to the current date.
I've been looking for a thread which can solve or even give a hint on how to solve this one but I found none.
If you are using PHP >= 5.2, I strongly suggest you use the new DateTime object, which makes working with dates a lot easier:
<?php
$date = new DateTime("2006-12-12");
$date->modify("+7 day");
echo $date->format("Y-m-d");
?>
Take a look here - http://php.net/manual/en/function.strtotime.php
<?php
// This is what you need for future date from now.
echo date('Y-m-d H:i:s', strtotime("+7 day"));
// This is what you need for future date from specific date.
echo date('Y-m-d H:i:s', strtotime('01/01/2010 +7 day'));
?>
The accepted answer is not wrong but not the best solution:
The DateTime class takes an optional string in the constructor, which can define the same logic as the modify method.
<?php
$date = new DateTime("+7 day");
For example:
<?php
namespace DateTimeExample;
$now = new \DateTime("now");
$inOneWeek = new \DateTime("+7 day");
printf("Now it's the %s", $now->format('Y-m-d'));
printf("In one week it's the %s", $inOneWeek->format('Y-m-d'));
For a list of available relative formats (for the DateTime constructor) take a look at http://php.net/manual/de/datetime.formats.relative.php
If you are using PHP >= 5.3, this could be an option.
<?php
$date = new DateTime( "2006-12-12" );
$date->add( new DateInterval( "P7D" ) );
?>
You will have to look into strtotime(). I'd imagine your final code would look something like this:
$future_date = "April 16,2010";
$seconds = strtotime($future_date) - time();
$days = $seconds /(60 * 60* 24);
echo $days; //Returns "6.0212962962963"
You can use mktime with date. (http://php.net/manual/en/function.date.php)
Date gives you the current date. This is better than simply adding/subtracting to a timestamp since it can take into account daylight savings time.
<?php
# this gets you 7 days earlier than the current date
$lastWeek = mktime(0, 0, 0, date("m") , date("d")-7, date("Y"));
# now pretty-print it out (eg, prints April 2, 2010.)
echo date("F j, Y.", $lastWeek), "\n";
?>
I've rarely touched PHP date functions,
and now I need to do the follows:
get current date,
get date of three days later
get date of three weeks later
get date of three month later
get date of three years later
and finally to implement such a function:
function dage_generate($number,$unit)
{
}
$unit can be day/week/month/years
http://uk.php.net/strtotime can do most of that:
strtotime("today")
strtotime("+ 3 days")
strtotime("+ 3 weeks")
strtotime("+ 3 months")
strtotime("+ 3 years")
The function would be something like:
function dage_generate($number,$unit)
{
return strtotime("+ ".$number." ".$unit);
}
http://us.php.net/manual/en/function.date.php
Note towards the bottom of the page:
Example #3 date() and mktime() example
<?php
$tomorrow = mktime(0, 0, 0, date("m") , date("d")+1, date("Y"));
$lastmonth = mktime(0, 0, 0, date("m")-1, date("d"), date("Y"));
$nextyear = mktime(0, 0, 0, date("m"), date("d"), date("Y")+1);
?>
Using strtotime() you can do this easily.
$now = time();
$threeDays = strtotime("+3 days");
$threeWeeks = strtotime("+3 weeks");
$threeMonths = strtotime("+3 months");
$threeYears = strtotime("+3 years");
Each of those variables will be an integer which represents the unix timestamp at that point in time. You can then format it into a human readable string using date().
echo date('r', $threeWeeks);
// etc...
Use date_create() to create a DateTime object, then use the add method.
See the examples on the page for the add() method, they contain all you need.
PHP Date/Time Functions with examples