In html source
\xE6\x82\xA0
result is "\xE6\x82\xA0"
but in php
<?php echo "\xE6\x82\xA0"; ?>
result is "悠" (character for \xE6\x82\xA0 )
what can be done to make php echo \xE6\x82\xA0?
If you want to print the actual string \xE6\x82\xA0, simply replace the double quotes with single quotes. Strings in single quotes are not parsed for escape sequences.
<?php echo '\xE6\x82\xA0'; ?>
Try escaping your slashes.
<?php echo "\\xE6\\x82\\xA0"; ?>
or simply use single quotes instead of double quotes
<?php echo '\xE6\x82\xA0'; ?>
or you can simply output directly
?>\xE6\x82\xA0<?php
Escape the slash characters.
<?php echo "\\xE6\\x82\\xA0"; ?>
Or write the string directly in template mode.
?>\xE6\x82\xA0<?php
Related
Let's say this is my script down here, as you can see I've used multiple " and '. These quotations conflict in ending the current php variable, so it basically sees this:
$message = "<?php echo '<div class="
As a string, whilst the quotation is only to define the class, not to end the variable. I've tried using ' but then it conflicts with the echo, so I'm kinda stuck at the moment.
<?php
$message = "
<?php
echo '<div class="gebruiker">';
$fh = fopen('_gebruiker.txt','r');
while ($line = fgets($fh)) {
echo($line);
}
fclose($fh);
echo '</div>';
?>
";
**MORE PHP CODE HERE**
?>
How can I use multiple quotations in one PHP script without them having conflicts.
If you use single quotes outside, you need to escape all single quotes inside, but can use double quotes and the dollar char without escaping.
If you use double quotes outside, you need to escape all double quotes and dollar chars inside, but can use single quotes without escaping.
If you use a heredoc string, you need to escape dollar chars but can use both single and double quotes without escaping.
If you use a nowdoc string, you do not need to escape anything unless you have FOO; in the string at the beginning of a new line.
So the solution is to use a nowdoc string:
$message = <<<'EOF'
your stuff with " or ' or $ here!
EOF;
Adding a backslash so PHP can recognize just only double quotes or quotes when escaped.
Example:
echo "<div class=\"gebruiker\">";
I suggest using either Heredoc or Nowdoc
Example
$foo = 'test';
// Heredoc
$here = <<<HERE
I'm here, $foo!
HERE;
// Nowdoc
$now = <<<'NOW'
I'm now, $foo!
NOW;
Heredoc will print the contents of $foo when echoed while Nowdoc will simply echo $foo.
In the references I added below you can do more reading up on this subject.
References:
php.net - strings
stackoverflow - advantages of heredoc vs nowdoc
You can escape the quotes with a slash character like so: \"
This should work, you can't open Php tag without closing before.
<?php
$message = '<div class="gebruiker">';
$fh = fopen('_gebruiker.txt','r');
while ($line = fgets($fh)) {
$message .=$line.'<br/>';
}
fclose($fh);
$message.='</div>';
echo $message;
**MORE PHP CODE HERE**
?>
i have this problem i hope some of you can help me with. I try to make a html link that get the link from my database.
echo "<p><pre><a href=$Feed['socialfacebook']><img src=facebook-24.png></a></pre></p>
You need to put the link in '".$variable ."' and the image src should be in ' ', too.
echo "<p><pre><a href='".$Feed['socialfacebook']."'><img src='facebook-24.png'></a></pre></p>";
Double-quoted strings don't work with array elements quite like that. You should close and concatenate the strings.
echo "<p><pre><img src=facebook-24.png></pre></p>"
You might also want to put some quotes on your attributes.
Close your string with a double quote and end your statement with a semi-colon,
When getting array elements inside a string literal like you're doing, leave out the key quotes,
Use single quotes around your attribute in case of any spaces:
echo "<p><pre><a href='$Feed[socialfacebook]'><img src=facebook-24.png></a>";
Eval.in
u need to put the variable $Feed['socialfacebook'] in " . $Feed['socialfacebook'] ."
echo "<p><pre><a href=" . $Feed['socialfacebook'] . "<img src=facebook-24.png></a></pre></p>";
and don't forget the ;
Shouldn't it be:
echo "<p><pre><a href='$Feed["socialfacebook"]'><img src=facebook-24.png></a>";
Don't forget that is href="".
i'm using php on_start and ob_get_contents to echo html and store in a variable. However when I json encode and check the output it doesn't output the entire string. Could anyone help point out what I'm doing wrong
ob_start();
echo'<img src=\"images/editphotohover.png\"/>\"';
$photo = ob_get_contents();
ob_end_clean();
I get only get the ending anchor tag
in the json encode output
There is no need to escape double quotes here
echo'<a href=\"javascri...
just write this:
echo'<a href="javascri...
Double quotes are kept while in single quotes!
Additionally, note that escaping within single quotes has no effect:
"\t" renders as a TABULATOR character
'\t' renders as \t
The PHP documentation states this:
To specify a literal single quote, escape it with a backslash (\).
To specify a literal backslash before a single quote, or at the end of the string, double it (\\).
Note that attempting to escape any other character will print the backslash too.
Therefore, how about this code:
echo'<a href="javascript:pixlr.edit(
{ image: \'http://mywebite.com/uploads/$photo\',
title: \'' . $photoFileNameProper . '\',
service: \'express\',
exit:\'http://mywebsite.com/home\',
method: \'get\',
locktarget: \'true\',
target: \'http://mywebsite.com/plixr.php\',
locktitle: \'true\'
});"
id = "uploadedPhoto"
title = "click to enhance photo">
<img src="images/editphotohover.png"/>
</a>'
;
how can i make sure these quotation marks become valid in PHP?
<?
echo "oaktree.addItem('test1<img src='img.png'>', branch1, '');";
echo "oaktree.addItem('test2<img src='img.png'>', branch1, '');";
?>
the problem is in the tag...
thanks
Your original code is correct as far as PHP syntax is concerned, but it does not output correctly formatted JavaScript, as you are already aware. You can use double quotes inside double quotes in PHP as long as you escape them properly. You can do
<?
echo "oaktree.addItem('test1<img src=\"img.png\">', branch1, '');";
echo "oaktree.addItem('test2<img src=\"img.png\">', branch1, '');";
?>
Try this:
<?php
echo <<<EOT
oaktree.addItem('test1<img src="img.png">', branch1, '');
oaktree.addItem('test2<img src="img.png">', branch1, '');
EOT;
?>
simple problem baffling me...
i have a function:
function spitHTML() {
$html = '
<div>This is my title</div>\n
<div>This is a second div</div>';
return $html
}
echo $spitHTML();
Why is this actually spitting out the \n's?
Backslashes used in single quote strings do not work as escape characters (besides for the single quote itself).
$string1 = "\n"; // this is a newline
$string2 = '\n'; // this is a backslash followed by the letter n
$string3 = '\''; // this is a single quote
$string3 = "\""; // this is a double quote
So why use single quotes at all? The answer is simple: If you want to print, for example, HTML code, in which naturally there are a lot of double quotes, wrapping the string in single quotes is much more readable:
$html = '<div class="heading" style="align: center" id="content">';
This is far better than
$html = "<div class=\"heading\" style=\"align: center\" id=\"content\">";
Besides that, since PHP doesn't have to parse the single quote strings for variables and/or escaped characters, it processes these strings a bit faster.
Personally, I always use single quotes and attach newline characters from double quotes. This then looks like
$text = 'This is a standard text with non-processed $vars followed by a newline' . "\n";
But that's just a matter of taste :o)
Because you're using single quotes - change to double quotes and it will behave as you expect.
See the documentation for Single quoted strings.
Change ' to " :) (After that, all special chars and variable be noticed)
$html = "
<div>This is my title</div>\n
<div>This is a second div</div>";