problem with enable/disable button using javascript - php

Question

Im am trying to add a check box that will enable/disable the edit button. Im retrieving a price list and displaying it inside a table. When i add the javascript into the php code it doesn't work. Below is my code
<table border="1">
<tr>
<td width="100">Fee % </td>
<td width="100">Price</td>
<td width="100">Total</td>
<td width="102"> </td>
</tr>
<tr>
<?php
$sql1="select * from pricelist";
$result1=mysql_query($sql1) or die(mysql_error());
while ($row=mysql_fetch_array($result1)) {
$id=$row['id'];
$price=$row['h_price'];
$a=0;
print "<form id='form1' name='$a+' method='post' action=''>";
print "<td><input name='fees' value ='$fees' type='text' size='4' /></td>";
print "<td><input name='price' value ='$price' type='text' size='15' /></td>";
echo "<td><input type='checkbox' onclick='this.$a+.disabled = !this.checked;'><td>";
print"<td><input type='submit' name='$a+' value='Submit' disabled='disabled' /></td>";
print "</tr>";
print "</form>";
}
?>
</table>
Can someone please tell me what am i doing wrong?
Thanks

Answer 1

take out the following code out of loop... it creates multiple form tag...
print "<form id='form1' name='$a+' method='post' action=''>";
Place "<tr></tr>" inside the loop...
final code looks like:
<form id='form1' name='fm1' method='post' action=''> <tr>
<?php
$sql1="select * from pricelist";
$result1=mysql_query($sql1) or die(mysql_error());
while ($row=mysql_fetch_array($result1)) {
$id=$row['id'];
$price=$row['h_price'];
$a=0;
print "<tr>";
print "<td><input name='fees' value ='$fees' type='text' size='4' /></td>";
print "<td><input name='price' value ='$price' type='text' size='15' /></td>";
echo "<td><input type='checkbox' onclick='this.$a+.disabled = !this.checked;'><td>";
print"<td><input type='submit' name='$a+' value='Submit' disabled='disabled' /></td>";
print "</tr>";
}
print "</form>";
?>
Next if u want to control the button only then
<input type='checkbox' onclick='document.$a.submit.disabled = !this.checked;' />
and make sure of the following things:
1.) form name should be $a
i.e <form name='$a' ...>
2.) submit buttons name should be submit
i.e <input type='submit' name='submit'...>
3.) increase the $a variable only at the end of loop
i.e
$a++;
}

Answer 2

i think $a+ will cause syntax error. you need to increment $a at the end of loop like $a++. Also see page source and see what is coming from server.

Answer 3

I would recommend using following format for html + php output
<form id='form1' name='<?=$a++?>' method='post' action=''>
<tr>
<td><input name='fees' value ='<?=$fees?>' type='text' size='4' /></td>
<td><input name='price' value ='<?=$price?>' type='text' size='15' /></td>
<td><input type='checkbox' onclick='this.disabled = !this.checked;'><td>
<td><input type='submit' name='<?=$a++?>' value='Submit' disabled='disabled' /></td>
</tr>
</form>
<?
you also need to have < tr > to be in the while loop.

Answer 4

In your html part where you set up the formular you have to use " " to escape the php code. example:
print "<form id='form1' name='".$a+."' method='post' action=''>";
But as Adeel said already, what is $a+ ?
And you have to edit all prints and echoes in the way, that php expressions are excaped from the HTML source.