How to make a tree view from MySQL and PHP and jquery - php

Question

i need to show a treeview of my categories , saved in my mysql database .
Database table :
table : cats :
columns: id,name,parent
problem is in php part :
//function to build tree menu from db table test1
function tree_set($index)
{
global $menu;
$q=mysql_query("select * from cats where parent='$index'");
if(!mysql_num_rows($q))
return;
$menu .= '<ul>'."\n";
while($arr=mysql_fetch_assoc($q))
{
$menu .= '<li>';
$menu .= '<span class="file">'.$arr['name'].'</span>';//you can add another output there
$menu .=tree_set("".$arr['id']."");
$menu .= '</li>'."\n";
}
$menu.= '</ul>'."\n";
return $menu;
}
//variable $menu must be defined before the function call
$menu = '
<link rel="stylesheet" href="modules/Topics/includes/jquery.treeview.css" />
<script src="modules/Topics/includes/lib/jquery.cookie.js" type="text/javascript"></script>
<script src="modules/Topics/includes/jquery.treeview.js" type="text/javascript"></script>
<script type="text/javascript" src="modules/Topics/includes/demo/demo.js"></script>
<ul id="browser" class="filetree">'."\n";
$menu .= tree_set(0);
$menu .= '</ul>';
echo $menu;
i even asked in this forum :
http://forums.tizag.com/showthread.php?p=60649
problem is in php part of my codes that i mentioned . i cant show sub menus , i mean , really i dont know how to show sub menus
is there any chance of a pro php coder helping me here ?

Answer 1

It looks like you are sending duplicate data to your menu variable, which doesn't need to be there.
I would change your function to do this:
function tree_set($index)
{
//global $menu; Remove this.
$q=mysql_query("select * from cats where parent='$index'");
if(mysql_num_rows($q) === 0)
{
return;
}
// User $tree instead of the $menu global as this way there shouldn't be any data duplication
$tree = $index > 0 ? '<ul>' : ''; // If we are on index 0 then we don't need the enclosing ul
while($arr=mysql_fetch_assoc($q))
{
$subFileCount=mysql_query("select * from cats where parent='{$arr['id']}'");
if(mysql_num_rows($subFileCount) > 0)
{
$class = 'folder';
}
else
{
$class = 'file';
}
$tree .= '<li>';
$tree .= '<span class="'.$class.'">'.$arr['name'].'</span>';
$tree .=tree_set("".$arr['id']."");
$tree .= '</li>'."\n";
}
$tree .= $index > 0 ? '</ul>' : ''; // If we are on index 0 then we don't need the enclosing ul
return $tree;
}
//variable $menu must be defined before the function call
$menu = '....<ul id="browser" class="filetree">'."\n";
$menu .= tree_set(0);
$menu .= '</ul>';
echo $menu;
updated based on comments on question