I tried to just send some information to a php file using Jquery Ajax. I wanted to send some info to the php file every time a click is made.
<script>
$(document).ready(function() {
$('#checkbox').click(function() {
$.ajax({type : "POST",
url : "test.php",
data : "ffs=somedata&ffs2=somedata2",
succes : function() {
alert("something");
}
});
});
});
</script>
<body>
<input type = "checkbox" name = "checkbox" id = "checkbox">
</body>
The php file looks like this:
<?php
echo $_POST['ffs'];
?>
Now, I see the POST going, (using firebug). I get no errors, but nothing happens in the php file. Also success is never reached, so no alert is triggered. What should I do in the php file so that I can trigger success and also see the sent info?
Typo, change
succes : function() {
to
success : function() {
And to retrieve the response from the PHP use
success : function(data) {
alert(data);
}
For more info see this
Related
<form>
<input type="text" id="user"/>
<input type="button" value="Submit" onClick="post();" />
</form>
<div id="result"> </div>
<script type="text/javascript">
function post()
{
var username = $('#user').val();
$.post('battlephp.php',
{postuser:user}
)
}
</script>
Its a simple Ajax code.. It should take username and display the Php code!
But don't know why its not running?? Actually I am learning...so I cant rectify the error or fault??
I am running ii on localhost.. so is there any problem with using:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
display the Php code
No, it shouldn't.
First, you've changed your mind about the variable name you are using (user, username) half way through your script, so you are going to throw a reference error.
Second, you haven't provided a function (the third argument) to $.post, so you aren't doing anything (such as displaying it) with the returned data.
Third, the server should execute the PHP and return its output. You shouldn't get the actual PHP code.
function post() {
var username = $('#user').val();
$.post(
'battlephp.php',
{postuser:username}, // Be consistent about your variable names
function (data) {
alert(data);
}
);
}
Instead
document.ready()
you can use
jQuery(function($){...});
Try to do this:
<script>
$(document).ready(function() {
function post() {
var username = $('#user').val();
$.ajax({
type : 'post',
url : 'batttlephp.php',
data : {
postuser : user
},
success : function(data) {
alert(data);
},
error : function(data) {
alert(data);
}
});
});
});
</script>
if you're doing a ajax request then is good also handle success and error...
Also I suggest to you "to start the document".
Try the code above and let us know if worked
I am trying to use ajax in wordpress.
I don't get ajax response. If I have done mistake on code, please let me know.
Here is my jquery code
// ajax submitting for the name
$("#sendemp").submit(function(e) {
e.preventDefault();
var submit_val = $("#searchbox").val();
alert('submitval is ' + submit_val);
$.ajax( {
type : "POST",
url : "./wp-admin/admin-ajax.php",
data : {
action : 'deatils_search',
user_name : submit_val
},
success : function(data) {
alert('hhh');
$('#accordion3').html(data);
// $( "#searchbox" ).autocomplete({
// source: data
// });
}
});
});
Here is my php code
function deatils_search() {
$name=$_POST['user_name'];//retrive data from post array on form submitting
$jason =$name;
echo json_encode($jason) ;
//echo '</div>';
//wp_reset_query();
die();
} // end theme_custom_handler
add_action( 'wp_ajax_deatils_search', 'deatils_search' );
add_action( 'wp_ajax_nopriv_deatils_search', 'deatils_search');
I tried to print alert('hhh'); on success message in ajax call. But it doesn't print anything.
Where I have done the mistake?
Please check bellow network tab on chrome
Don't use $ as a jQuery shortcut within WordPress javascript. WordPress is set to run jQuery in noConflict mode. Replace $ with jQuery.
When I replace the following method with click method., Every thing started to work.
$("#sendemp").click(function(e) {
I am trying to pass two variables (below) to a php/MySQL "update $table SET...." without refreshing the page.
I want the div on click to pass the following variables
$read=0;
$user=$userNumber;
the div Basically shows a message has been read so should then change color.
What is the best way to do this please?
here's some code to post to a page using jquery and handle the json response. You'll have to create a PHP page that will receive the post request and return whatever you want it to do.
$(document).ready(function () {
$.post("/yourpath/page.php", { read: "value1", user: $userNumber}, function (data) {
if (data.success) {
//do something with the returned json
} else {
//do something if return is not successful
} //if
}, "json"); //post
});
create a php/jsp/.net page that takes two arguments
mywebsite.com/ajax.php?user=XXX&secondParam=ZZZZ
attache onClick event to DIV
$.get("ajax.php?user=XXX&secondParam=ZZZZ". function(data){
// here you can process your response and change DIV color if the request succeed
});
I'm not sure I understand.
See $.load();
Make a new php file with the update code, then just return a json saying if it worked or not. You can make it with the $.getJSON jQuery function.
To select an element from the DOM based on it's ID in jQuery, just do this:
$("#TheIdOfYourElement")
or in your case
$("#messageMenuUnread")
now, to listen for when it's been clicked,
$("#messageMenuUnread").click(function(){
//DO SOMETHING
}
Now, for the AJAX fun. You can read the documentation at http://api.jquery.com/category/ajax/ for more technical details, but this is what it boils down to
$("#TheIdOfYourImage").click(function(){
$.ajax({
type: "POST", // If you want to send information to the PHP file your calling, do you want it to be POST or GET. Just get rid of this if your not sending data to the file
url: "some.php", // The location of the PHP file your calling
data: "name=John&location=Boston", // The information your passing in the variable1=value1&variable2=value2 pattern
success: function(result){ alert(result) } // When you get the information, what to do with it. In this case, an alert
});
}
As for the color changing, you can change the CSS using the.css() method
$("#TheIdOfAnotherElement").css("background-color","red")
use jQuery.ajax()
your code would look like
<!DOCTYPE html>
<head>
</head>
<body>
<!-- your button -->
<div id="messageMenuUnread"></div>
<!-- place to display result -->
<div id="frame1" style="display:block;"></div>
<!-- load jquery -->
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
//attach a function to messageMenuUnread div
$('#messageMenuUnread').click (messageMenuUnread);
//the messageMenuUnread function
function messageMenuUnread() {
$.ajax({
type: "POST",
//change the URL to what you need
url: "some.php",
data: { read: "0", user: "$userNumber" }
}).done(function( msg ) {
//output the response to frame1
$("#frame1").html("Done!<br/>" + msg);
});
}
}
</script>
</body>
I have a link that looks like this:
<p class="half_text">
<?php echo $upvotes; ?>
<strong><a class="vote_up" style="color: #295B7B; font-weight:bold;" href="#">Vote Up</a></strong> |
<?php echo $downvotes; ?>
<strong><a class="vote_down" style="color: #295B7B; font-weight:bold;" href="#">Vote Down</a></strong>
</p>
and I have the jQuery code that looks like this:
<script type="text/javascript">
$(document).ready(function()
{
$('.vote_up').click(function()
{
alert("up");
alert ( "test: " + $(this).attr("problem_id") );
// $(this).attr("data-problemID").
$.ajax({
type: "POST",
url: "/problems/vote.php",
dataType: "json",
data: dataString,
success: function(json)
{
// ? :)
}
});
//Return false to prevent page navigation
return false;
});
$('.vote_down').click(function()
{
alert("down");
//Return false to prevent page navigation
return false;
});
});
</script>
How can I get the parameter value which is problem_id ? If I add a url in the href parameter, I think the browser will just go to the url, no? Otherwise - how can I pack parameter values into the jQuery?
Thanks!
Because your $.ajax is defined in the same scope of the variable, you can use problem_id to obtain the variable value.
An overview of your current code:
var problem_id = "something"; //Defining problem_id
...
$.ajax(
...
success: function(){
...
//problem_id can also be accessed from here, because it has previously been
// defined in the same scope
...
}, ...)
....
If what you're trying to figure out is how to embed the problem ID in the link from your PHP so that you can fetch it when the link it clicked on, then you can put it a couple different places. You can put an href on the link and fetch the problem ID from the href. If you just do a return(false) from your click handler, then the link will not be followed upon click.
You can also put it as a custom attribute on the link tag like this:
<a class="vote_up" data-problemID="12" style="color: #295B7B; font-weight:bold;" href="#">Vote Up</a>
And, then in your jQuery click handler, you can retrieve it with this:
$(this).attr("data-problemID").
do you mean, getting variables from the php page posted?
or to post?
anyway here's a snippet to replace the $.ajax
$.post('/problems/vote.php', {problem_id: problem_id, action: 'up'}, function(data) {
// data here is json, from the php page try logging or..
// console.log(data);
// alert(data.title);
}, 'json');
{problem_id: problem_id, action: 'up'} are the variables posted... use $_POST['problem_id'] and $_POST['action'] to process..
use simple variables names with jQuery.data and make sure you have latest jQuery..
let me try to round it up..
up
down
<script type="text/javascript">
$('.votelink').click(function() {
$.post('/problems/vote.php', {problem_id: $(this).data('problemid'), action: $(this).data('action')}, function(data) {
// data here is json, from the php page try logging or..
// console.log(data);
// alert(data.title);
}, 'json');
});
</script>
I am using php/ajax to submit a form without page refresh. Here are my files-
coupon.js
jQuery(document).ready(function(){
jQuery(".appnitro").submit( function(e) {
$.ajax({
url : "http://174.132.194.155/~kunal17/devbuzzr/wp-content/themes/street/sms.php",
type : "post",
dataType: "json",
data : $(this).serialize(),
success : function( data ) {
for(var id in data) {
jQuery('#' + id).html( data[id] );
}
}
});
//return false or
e.preventDefault();
});
});
sms.php
<?php
//process form
$res = "Message successfully delivered";
$arr = array( 'mess' => $res );
echo json_encode( $arr );//end sms processing
unset ($_POST);
?>
and here is code for my html page -
<form id="smsform" class="appnitro" action="http://174.132.194.155/~kunal17/devbuzzr/wp-content/themes/street/sms.php" method="post">
...
</form>
<div id="mess" style="background:green;"></div>
Now when i click on submit button nothing happens and firebug shows following under console panel -
POST http://174.132.194.155/~kunal17/devbuzzr/wp-content/themes/street/sms.php
404 Not Found 1.29s `jquery.min.js (line 130)`
Response
Firebug needs to POST to the server to get this information for url:
http://174.132.194.155/~kunal17/devbuzzr/wp-content/themes/street/sms.php
This second POST can interfere with some sites. If you want to send the POST again, open a new tab in Firefox, use URL 'about:config', set boolean value 'extensions.firebug.allowDoublePost' to true
This value is reset every time you restart Firefox This problem will disappear when https://bugzilla.mozilla.org/show_bug.cgi?id=430155 is shipped
When i set 'extensions.firebug.allowDoublePost' to true then following results show up -
POST http://174.132.194.155/~kunal17/devbuzzr/wp-content/themes/street/sms.php
404 Not Found 1.29s `jquery.min.js (line 130)`
Response -
{"mess":"Message successfully delivered"}
CaN anyone help me in fixing this firebug error of 404 not found. And why is it showing jquery.min.js (line 130) along side?
P.S -do not worry about http://174.132.194.155/~kunal17/devbuzzr/wp-content/themes/street this is my base url
You may want to try putting the e.preventDefault() statement before the $.ajax call.
EDIT:
My x.html, corresponds to your HTML page
<!DOCTYPE html>
<html>
<head>
<title>x</title>
<script
type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js">
</script>
<script type="text/javascript" src="/so/x.js"></script>
</head>
<body>
<form id="smsform" class="appnitro" action="/so/x.php">
<input type="text" name="zz">
<input type="submit">
</form>
<div id="mess" style="background:green;"></div>
</body>
</html>
My x.js, corresponds to your coupon.js
jQuery(document).ready(function(){
jQuery(".appnitro").submit( function(e) {
e.preventDefault();
$.ajax({
url : "/so/x.php",
type : "post",
dataType: "json",
data : $(this).serialize(),
success : function( data ) {
for(var id in data) {
jQuery('#' + id).html( data[id] );
}
}
});
//return false or
//e.preventDefault();
});
});
My x.php, corresponds to your sms.php
<?php
$res = "Message successfully delivered.";
$arr = array('mess'=>$res);
echo json_encode($arr);
unset($_POST);
?>
This actually works in my environment, although I do not have the rest of the HTML markup or the additional PHP form processing code. The "Message successfully delivered." shows up in green directly below the input field.
When inside the Ajax call this refers to the Ajax object you need to do this
var __this = this;
Before going into the Ajax call, then it would be
data : __this.serialize()
Or look up the use of context within an Ajax call in Google. Or serialise your data into a variable before going into the Ajax call.