How to find nearest day of week in php? - php

How to find a speciefic nearest day of the week in PHP if initially I have a date string like: 07.05.2010? For example, I want to find the nearest Sunday (or any day of the week). How can I implement this? Thanks

Just in case you wanted the nearest day rather than the next one, here is a way to do that.
$target = "Sunday";
$date = "07.05.2010";
// Old-school DateTime::createFromFormat
list($dom, $mon, $year) = sscanf($date, "%02d.%02d.%04d");
$date = new DateTime("$year/$mon/$dom -4 days");
// Skip ahead to $target day
$date->modify("next $target");
echo $date->format("d.m.Y");
And as of PHP 5.3, that middle portion can be simply
$date = DateTime::createFromFormat("!d.m.Y", $date)
->modify("-4 days")->modify("next $target");

This should do:
echo date('d.m.Y', strtotime('next Sunday', strtotime('07.05.2010')));

/**
*
* #param \DateTime $date
* #param $dayOfWeek - e.g Monday, Tuesday ...
*/
public function findNearestDayOfWeek(\DateTime $date, $dayOfWeek)
{
$dayOfWeek = ucfirst($dayOfWeek);
$daysOfWeek = array(
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday',
'Sunday',
);
if(!in_array($dayOfWeek, $daysOfWeek)){
throw new \InvalidArgumentException('Invalid day of week:'.$dayOfWeek);
}
if($date->format('l') == $dayOfWeek){
return $date;
}
$previous = clone $date;
$previous->modify('last '.$dayOfWeek);
$next = clone $date;
$next->modify('next '.$dayOfWeek);
$previousDiff = $date->diff($previous);
$nextDiff = $date->diff($next);
$previousDiffDays = $previousDiff->format('%a');
$nextDiffDays = $nextDiff->format('%a');
if($previousDiffDays < $nextDiffDays){
return $previous;
}
return $next;
}
Alternatively you could create a map of what days of weeks are closer, e.g if you're after closest Monday to Wednesday, it would be faster to just find the previous Monday given that it's closer than the next Monday.

There are several answers posted and I keep seeing solutions that could give me either the next instance of a day of the week or the previous instance but not the closest. To address this, I came up with this function:
function closestDate($day){
$day = ucfirst($day);
if(date('l', time()) == $day)
return date("Y-m-d", time());
else if(abs(time()-strtotime('next '.$day)) < abs(time()-strtotime('last '.$day)))
return date("Y-m-d", strtotime('next '.$day));
else
return date("Y-m-d", strtotime('last '.$day));
}
Input: a day of the week ("sunday", "Monday", etc.)
Output: If I asked for the nearest "sunday" and today is:
"Sunday": I will get today's date
"Monday": I will get yesterday's date
"Saturday: I will get tomorrow's date
Hope this helps :)

strtotime is magical
echo date("d/m/y", strtotime("next sunday", strtotime("07.05.2010") ) );

This can be done using only strtotime() and a little trickery.
function findNearest($day, $date)
{
return strtotime("next $day", strtotime("$date - 4 days"));
}
echo date('d.m.Y', findNearest("Sunday", "07.05.2010")); // 09.05.2010
echo findNearest("Sunday", "07.05.2010"); // 1273377600
echo date('d.m.Y', findNearest("Sunday", "09.05.2010")); // 09.05.2010
echo findNearest("Sunday", "09.05.2010"); // 1273377600
echo date('d.m.Y', findNearest("Sunday", "05.05.2010")); // 02.05.2010
echo findNearest("Sunday", "05.05.2010"); // 1272772800

You can use Carbon library as well
$date = Carbon::create(2015, 7, 2); // 2015-07-02
// To get the first day of the week
$monday = $date->startOfWeek(); // 2015-06-29
$mondayTwoWeeksLater = $date->addWeek(2); // 2015-07-13

Related

Get first monday of month for a given set of datetimes

What I Require
I have a certain list of datetimes. I want to get the first monday of each datetimes.
eg: Suppose the given datetimes are
2013-07-05 2013-08-05, 2013-09-13 etc.
I want to get the first monday of all these datetimes such that the output results in
2013-07-01, 2013-08-05, 2013-09-02 respectively
I am actually stuck with this using stftime.
strftime("%d/%m/%Y", strtotime("first Monday of July 2012"));
Using php Datetime class:
$Dates = array('2013-07-02', '2013-08-05', '2013-09-13');
foreach ($Dates as $Date)
{
$test = new DateTime($Date);
echo $test->modify('first monday')->format('Y-m-d');
}
<?php
function find_the_first_monday($date)
{
$time = strtotime($date);
$year = date('Y', $time);
$month = date('m', $time);
for($day = 1; $day <= 31; $day++)
{
$time = mktime(0, 0, 0, $month, $day, $year);
if (date('N', $time) == 1)
{
return date('Y-m-d', $time);
}
}
}
echo find_the_first_monday('2013-07-05'), "\n";
echo find_the_first_monday('2013-08-05'), "\n";
echo find_the_first_monday('2013-09-13'), "\n";
// output:
// 2013-07-01
// 2013-08-05
// 2013-09-02
the first monday would be within the first 7 days of a month,
DAYOFWEEK(date) returns 1=sunday, 2=monday, and so on
also see the hack#23
http://oreilly.com/catalog/sqlhks/chapter/ch04.pdf
I know this is an old question and my answer is not 100% solution for this question, but this might be usefull for someone, this will give "first Saturday of the given year/month":
date("Y-m-d", strtotime("First Saturday of 2021-08")); // gives: 2021-08-07
You can manipulate this in many ways.
obviously you can put "Second Saturday of year-month" and it will find that as well.
Works with PHP 5.3.0 and above (tested at https://sandbox.onlinephpfunctions.com/).
You could loop through the array of dates and then break out of the loop and return the $Date when you first encounter Monday
PHPFIDDLE
$Dates = array('2013-07-02', '2013-08-05', '2013-09-13');
foreach ($Dates as $Date)
{
$weekday = date('l', strtotime($Date));
if($weekday == 'Monday') {
echo "First Monday in list is - " . $Date;
break;
}
}
Output
First Monday in list is - 2013-08-05

PHP: Week starts on Monday, but "monday this week" on a Sunday gets Monday next week

Here's a summary of the issue: On Sundays, strtotime('this week') returns the start of next week.
In PHP, the week seems to start on Monday. But, on any day except Sunday, this code
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
Outputs the date of this week's Monday, when it seems like it should be outputting last weeks Monday. It seems like, in this case, PHP is treating both Sunday and Monday as the the start of the week. It's now Monday, Dec 10, 2012, or 2012-12-10. date('Y-m-d', strtotime('sunday last week')) returns 2012-12-09 - yesterday.
Is this a bug, or am I missing something? It seems like a bug this obvious should be fairly well known, but I can't find anything about it. Is the only way to get the start of the week to use some special handling for Sundays?
$week_offset = (int) 'sunday' == date('l');
$week_start = strtotime("-$week_offset monday"); // 1 or 0 Mondays ago
As far as I can tell, this is a bug. I see no logical reason why strtotime('this week'); should return a future date. This is a pretty major bug. In my particular case, I had a leaderboard that showed the users with the most points since the beginning of the week. But on Sundays, it was empty because strtotime returned a timestamp for a future date. I was doubtful, because just I don't know how this could have gone unnoticed, but I couldn't find any other reports of this bug.
Thanks for all your time and help, folks.
This answer is late, but it's something that I've been struggling with. Every solution I've tried so far has malfunctioned for one reason or another. This is what I ended up with that worked for me. (though it may be look pretty, it at least works).
$thisMonday = strtotime('next Monday -1 week', strtotime('this sunday'));
Here is how you can get Monday of current week:
echo date("Y-m-d", strtotime(date('o-\\WW')));
It's not ideal but this is what I resorted to using:
if(date('N') == 7) {
$date = date('Y-m-d',strtotime('monday last week'));
} else {
$date = date('Y-m-d',strtotime('monday this week'));
}
I think the only problem with your coding is TimeZone.
Solution:
Set your own time Zone. Here is the example of my own time zone:
Example
date_default_timezone_set('Asia/Kolkata');
Set the above line before calling any time function.
Have a nice day.
I think instead of trying
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
you should try
echo date('Y-m-d', strtotime('monday last week'));
Try this code
// set current date
$date = date("m/d/Y");
$ts = strtotime($date); // also $ts = time();
// find the year and the current week
$year = date('o', $ts);
$week = date('W', $ts);
// print week for the current date
$i = 1; // 1 denotes the first day of week
$ts = strtotime($year.'W'.$week.$i);
echo $day = date("l", $ts); // generate the name of day
echo "<br>";
echo $day = date("Y-m-d", $ts); // generate the date
You will get the the date of current week, whether you are on monday you will get the date of that monday.
If you want the most recent monday:
function mostRecentMonday(){
if(date("w") == 1){
return strtotime("midnight today");
} else {
return strtotime("last monday");
}
}
Easy to modify to use DateTime, or, to even specify a different date to use as the base.
Based on Bryant answer :
$first_week_date = date('d F Y', strtotime('next Monday -1 week', strtotime('this sunday')));
$last_week_date = date('d F Y', strtotime('next Monday -1 week + 6 days', strtotime('this sunday')));
This is for thos looking for a friendly solution that works with any day.
function getWeekStart($week_start_day = "Monday") {
$week_days = array("Sunday"=>0,"Monday"=>1,"Tuesday"=>2,"Wednesday"=>3,"Thursday"=>4,"Friday"=>5,"Saturday"=>6,);
if(!isset($week_days[$week_start_day])) {
return false;
} else {
$start_day = $week_days[$week_start_day];
$today = date("w");
$one_day = (60 * 60 * 24);
if($today < $start_day) {
$days_difference = 7 - ($start_day - $today);
} else {
$days_difference = ($today - $start_day);
}
$week_starts = strtotime(date("Y-m-d 00:00:00")) - ($one_day * $days_difference);
return $week_starts;
}
}
//Test: If today is Monday, it will return today's date
echo date("Y-m-d H:i:s", getWeekStart("Monday"));

increment date by one month

Let's say I have a date in the following format: 2010-12-11 (year-mon-day)
With PHP, I want to increment the date by one month, and I want the year to be automatically incremented, if necessary (i.e. incrementing from December 2012 to January 2013).
Regards.
$time = strtotime("2010.12.11");
$final = date("Y-m-d", strtotime("+1 month", $time));
// Finally you will have the date you're looking for.
I needed similar functionality, except for a monthly cycle (plus months, minus 1 day). After searching S.O. for a while, I was able to craft this plug-n-play solution:
function add_months($months, DateTime $dateObject)
{
$next = new DateTime($dateObject->format('Y-m-d'));
$next->modify('last day of +'.$months.' month');
if($dateObject->format('d') > $next->format('d')) {
return $dateObject->diff($next);
} else {
return new DateInterval('P'.$months.'M');
}
}
function endCycle($d1, $months)
{
$date = new DateTime($d1);
// call second function to add the months
$newDate = $date->add(add_months($months, $date));
// goes back 1 day from date, remove if you want same day of month
$newDate->sub(new DateInterval('P1D'));
//formats final date to Y-m-d form
$dateReturned = $newDate->format('Y-m-d');
return $dateReturned;
}
Example:
$startDate = '2014-06-03'; // select date in Y-m-d format
$nMonths = 1; // choose how many months you want to move ahead
$final = endCycle($startDate, $nMonths); // output: 2014-07-02
Use DateTime::add.
$start = new DateTime("2010-12-11", new DateTimeZone("UTC"));
$month_later = clone $start;
$month_later->add(new DateInterval("P1M"));
I used clone because add modifies the original object, which might not be desired.
strtotime( "+1 month", strtotime( $time ) );
this returns a timestamp that can be used with the date function
You can use DateTime::modify like this :
$date = new DateTime('2010-12-11');
$date->modify('+1 month');
See documentations :
https://php.net/manual/en/datetime.modify.php
https://php.net/manual/en/class.datetime.php
UPDATE january 2021 : correct mistakes raised by comments
This solution has some problems for months with 31 days like May etc.
Exemple : this jumps from 31st May to 1st July which is incorrect.
To correct that, you can create this custom function
function addMonths($date,$months){
$init=clone $date;
$modifier=$months.' months';
$back_modifier =-$months.' months';
$date->modify($modifier);
$back_to_init= clone $date;
$back_to_init->modify($back_modifier);
while($init->format('m')!=$back_to_init->format('m')){
$date->modify('-1 day') ;
$back_to_init= clone $date;
$back_to_init->modify($back_modifier);
}
}
Then you can use it like that :
$date = new DateTime('2010-05-31');
addMonths($date, 1);
print_r($date);
//DateTime Object ( [date] => 2010-06-30 00:00:00.000000 [timezone_type] => 3 [timezone] => Europe/Berlin )
This solution was found in PHP.net posted by jenspj : https://www.php.net/manual/fr/datetime.modify.php#107592
(date('d') > 28) ? date("mdY", strtotime("last day of next month")) : date("mdY", strtotime("+1 month"));
This will compensate for February and the other 31 day months. You could of course do a lot more checking to to get more exact for 'this day next month' relative date formats (which does not work sadly, see below), and you could just as well use DateTime.
Both DateInterval('P1M') and strtotime("+1 month") are essentially blindly adding 31 days regardless of the number of days in the following month.
2010-01-31 => March 3rd
2012-01-31 => March 2nd (leap year)
Please first you set your date format as like 12-12-2012
After use this function it's work properly;
$date = date('d-m-Y',strtotime("12-12-2012 +2 Months");
Here 12-12-2012 is your date and +2 Months is increment of the month;
You also increment of Year, Date
strtotime("12-12-2012 +1 Year");
Ans is 12-12-2013
I use this way:-
$occDate='2014-01-28';
$forOdNextMonth= date('m', strtotime("+1 month", strtotime($occDate)));
//Output:- $forOdNextMonth=02
/*****************more example****************/
$occDate='2014-12-28';
$forOdNextMonth= date('m', strtotime("+1 month", strtotime($occDate)));
//Output:- $forOdNextMonth=01
//***********************wrong way**********************************//
$forOdNextMonth= date('m', strtotime("+1 month", $occDate));
//Output:- $forOdNextMonth=02; //instead of $forOdNextMonth=01;
//******************************************************************//
Just updating the answer with simple method for find the date after no of months. As the best answer marked doesn't give the correct solution.
<?php
$date = date('2020-05-31');
$current = date("m",strtotime($date));
$next = date("m",strtotime($date."+1 month"));
if($current==$next-1){
$needed = date('Y-m-d',strtotime($date." +1 month"));
}else{
$needed = date('Y-m-d', strtotime("last day of next month",strtotime($date)));
}
echo "Date after 1 month from 2020-05-31 would be : $needed";
?>
If you want to get the date of one month from now you can do it like this
echo date('Y-m-d', strtotime('1 month'));
If you want to get the date of two months from now, you can achieve that by doing this
echo date('Y-m-d', strtotime('2 month'));
And so on, that's all.
Thanks Jason, your post was very helpful. I reformatted it and added more comments to help me understand it all. In case that helps anyone, I have posted it here:
function cycle_end_date($cycle_start_date, $months) {
$cycle_start_date_object = new DateTime($cycle_start_date);
//Find the date interval that we will need to add to the start date
$date_interval = find_date_interval($months, $cycle_start_date_object);
//Add this date interval to the current date (the DateTime class handles remaining complexity like year-ends)
$cycle_end_date_object = $cycle_start_date_object->add($date_interval);
//Subtract (sub) 1 day from date
$cycle_end_date_object->sub(new DateInterval('P1D'));
//Format final date to Y-m-d
$cycle_end_date = $cycle_end_date_object->format('Y-m-d');
return $cycle_end_date;
}
//Find the date interval we need to add to start date to get end date
function find_date_interval($n_months, DateTime $cycle_start_date_object) {
//Create new datetime object identical to inputted one
$date_of_last_day_next_month = new DateTime($cycle_start_date_object->format('Y-m-d'));
//And modify it so it is the date of the last day of the next month
$date_of_last_day_next_month->modify('last day of +'.$n_months.' month');
//If the day of inputted date (e.g. 31) is greater than last day of next month (e.g. 28)
if($cycle_start_date_object->format('d') > $date_of_last_day_next_month->format('d')) {
//Return a DateInterval object equal to the number of days difference
return $cycle_start_date_object->diff($date_of_last_day_next_month);
//Otherwise the date is easy and we can just add a month to it
} else {
//Return a DateInterval object equal to a period (P) of 1 month (M)
return new DateInterval('P'.$n_months.'M');
}
}
$cycle_start_date = '2014-01-31'; // select date in Y-m-d format
$n_months = 1; // choose how many months you want to move ahead
$cycle_end_date = cycle_end_date($cycle_start_date, $n_months); // output: 2014-07-02
function dayOfWeek($date){
return DateTime::createFromFormat('Y-m-d', $date)->format('N');
}
Usage examples:
echo dayOfWeek(2016-12-22);
// "4"
echo dayOfWeek(date('Y-m-d'));
// "4"
$date = strtotime("2017-12-11");
$newDate = date("Y-m-d", strtotime("+1 month", $date));
If you want to increment by days you can also do it
$date = strtotime("2017-12-11");
$newDate = date("Y-m-d", strtotime("+5 day", $date));
For anyone looking for an answer to any date format.
echo date_create_from_format('d/m/Y', '15/04/2017')->add(new DateInterval('P1M'))->format('d/m/Y');
Just change the date format.
//ECHO MONTHS BETWEEN TWO TIMESTAMPS
$my_earliest_timestamp = 1532095200;
$my_latest_timestamp = 1554991200;
echo '<pre>';
echo "Earliest timestamp: ". date('c',$my_earliest_timestamp) ."\r\n";
echo "Latest timestamp: " .date('c',$my_latest_timestamp) ."\r\n\r\n";
echo "Month start of earliest timestamp: ". date('c',strtotime('first day of '. date('F Y',$my_earliest_timestamp))) ."\r\n";
echo "Month start of latest timestamp: " .date('c',strtotime('first day of '. date('F Y',$my_latest_timestamp))) ."\r\n\r\n";
echo "Month end of earliest timestamp: ". date('c',strtotime('last day of '. date('F Y',$my_earliest_timestamp)) + 86399) ."\r\n";
echo "Month end of latest timestamp: " .date('c',strtotime('last day of '. date('F Y',$my_latest_timestamp)) + 86399) ."\r\n\r\n";
$sMonth = strtotime('first day of '. date('F Y',$my_earliest_timestamp));
$eMonth = strtotime('last day of '. date('F Y',$my_earliest_timestamp)) + 86399;
$xMonth = strtotime('+1 month', strtotime('first day of '. date('F Y',$my_latest_timestamp)));
while ($eMonth < $xMonth) {
echo "Things from ". date('Y-m-d',$sMonth) ." to ". date('Y-m-d',$eMonth) ."\r\n\r\n";
$sMonth = $eMonth + 1; //add 1 second to bring forward last date into first second of next month.
$eMonth = strtotime('last day of '. date('F Y',$sMonth)) + 86399;
}
I find the mtkime() function works really well for this:
$start_date="2021-10-01";
$start_date_plus_a_month=date("Y-m-d", mktime(0, 0, 0, date("m",strtotime($start_date))+1, date("d",strtotime($start_date)), date("Y",strtotime($start_date))));
result: 2021-11-01
I like to subtract 1 from the 'day' to produce '2021-10-31' which can be useful if you want to display a range across 12 months, e.g. Oct 1, 2021 to Sep 30 2022
$start_date_plus_a_year=date("Y-m-d", mktime(0, 0, 0, date("m",strtotime($start_date))+12, date("d",strtotime($start_date))-1, date("Y",strtotime($start_date))));
result: 2022-09-30
The correct answer to the exact question asked is Giuseppe Canale's answer from earlier. I'm going to answer a slightly more generic question of how to increment the date by an arbitrary number of months, however.
<?php
/**
* Will return a timestamp corresponding to first day of the month that is N months into the future.
* #param int $months_later number of months into the future: 0 for current one
* #param string $today if supplied will be used as the "now" time
* #return int
*/
function rel_month_to_time($months_later, $today=null) {
if ($months_later===0) {
return is_null($today) ? time() : strtotime($today);
}
return strtotime('first day of next month', rel_month_to_time($months_later-1, $today));
}
As is many times the case, you can use recursion for these "human problems" like calendars. The above can be used to return a timestamp corresponding to "next month" -- the way we humans think of it.
<?php echo date('Y-m-d', rel_month_to_time(1, '2023-01-30'));
// 2023-02-01
As pointed by #NetVicious i corrected the code, it should work with all dates, some example:
2013-01-30 will be 2013-02-28
2013-05-15 will be 2013-05-15
2013-05-31 will be 2013-06-30
This code uses the DateTime class to create a new date object, then it adds 1 month to the date using the modify method. Next, it gets the day of the next month using the format method. If the next month's day doesn't match the original day, it modifies the date to the last day of the previous month using the modify method.
$original_date = "2013-01-30";
$original_day = date("d", strtotime($original_date));
$date = new DateTime($original_date);
$date->modify('+1 month');
$next_month_day = $date->format('d');
if ($next_month_day != $original_day) {
$date->modify('last day of previous month');
}
$new_date = $date->format('Y-m-d');
echo $new_date;
All presented solutions are not working properly.
strtotime() and DateTime::add or DateTime::modify give sometime invalid results.
Examples:
- 31.08.2019 + 1 month gives 01.10.2019 instead 30.09.2019
- 29.02.2020 + 1 year gives 01.03.2021 instead 28.02.2021
(tested on PHP 5.5, PHP 7.3)
Below is my function based on idea posted by Angelo that solves the problem:
// $time - unix time or date in any format accepted by strtotime() e.g. 2020-02-29
// $days, $months, $years - values to add
// returns new date in format 2021-02-28
function addTime($time, $days, $months, $years)
{
// Convert unix time to date format
if (is_numeric($time))
$time = date('Y-m-d', $time);
try
{
$date_time = new DateTime($time);
}
catch (Exception $e)
{
echo $e->getMessage();
exit;
}
if ($days)
$date_time->add(new DateInterval('P'.$days.'D'));
// Preserve day number
if ($months or $years)
$old_day = $date_time->format('d');
if ($months)
$date_time->add(new DateInterval('P'.$months.'M'));
if ($years)
$date_time->add(new DateInterval('P'.$years.'Y'));
// Patch for adding months or years
if ($months or $years)
{
$new_day = $date_time->format("d");
// The day is changed - set the last day of the previous month
if ($old_day != $new_day)
$date_time->sub(new DateInterval('P'.$new_day.'D'));
}
// You can chage returned format here
return $date_time->format('Y-m-d');
}
Usage examples:
echo addTime('2020-02-29', 0, 0, 1); // add 1 year (result: 2021-02-28)
echo addTime('2019-08-31', 0, 1, 0); // add 1 month (result: 2019-09-30)
echo addTime('2019-03-15', 12, 2, 1); // add 12 days, 2 months, 1 year (result: 2019-09-30)
put a date in input box then click the button get day from date in jquery
$(document).ready( function() {
$("button").click(function(){
var day = ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"];
var a = new Date();
$(".result").text(day[a.getDay()]);
});
});
<?php
$selectdata ="select fromd,tod from register where username='$username'";
$q=mysqli_query($conm,$selectdata);
$row=mysqli_fetch_array($q);
$startdate=$row['fromd'];
$stdate=date('Y', strtotime($startdate));
$endate=$row['tod'];
$enddate=date('Y', strtotime($endate));
$years = range ($stdate,$enddate);
echo '<select name="years" class="form-control">';
echo '<option>SELECT</option>';
foreach($years as $year)
{ echo '<option value="'.$year.'"> '.$year.' </option>'; }
echo '</select>'; ?>

Get date for monday and friday for the current week (PHP)

How can I get the date for monday and friday for the current week?
I have the following code, but it fails if current day is sunday or saturday.
$current_day = date("N");
$days_to_friday = 5 - $current_day;
$days_from_monday = $current_day - 1;
$monday = date("Y-m-d", strtotime("- {$days_from_monday} Days"));
$friday = date("Y-m-d", strtotime("+ {$days_to_friday} Days"));
Best solution would be:
$monday = date( 'Y-m-d', strtotime( 'monday this week' ) );
$friday = date( 'Y-m-d', strtotime( 'friday this week' ) );
These strtotime inputs work very well:
strtotime( "next monday" );
strtotime( "previous monday" );
strtotime( "today" );
strtotime( "next friday" );
strtotime( "previous friday" );
All you need to do is to wrap the logic inside some if statements.
This question needs a DateTime answer:-
/**
* #param String $day
* #return DateTime
*/
function getDay($day)
{
$days = ['Monday' => 1, 'Tuesday' => 2, 'Wednesday' => 3, 'Thursday' => 4, 'Friday' => 5, 'Saturday' => 6, 'Sunday' => 7];
$today = new \DateTime();
$today->setISODate((int)$today->format('o'), (int)$today->format('W'), $days[ucfirst($day)]);
return $today;
}
Usage:
var_dump(getDay('Monday')->format('l dS F Y'));
var_dump(getDay('Friday')->format('l dS F Y'));
Output:
string 'Monday 30th September 2013' (length=26)
string 'Friday 04th October 2013' (length=24)
See it working
i use :
$first_week_date = date('d F Y', strtotime('next Monday -1 week', strtotime('this sunday')));
$last_week_date = date('d F Y', strtotime('next Monday -1 week + 4 days', strtotime('this sunday')));
This really depends on how you define a week but I came up with this function that will give you the date for the nearest "monday" or "friday" (or any day for that matter):
function closestDate($day){
$day = ucfirst($day);
if(date('l', time()) == $day)
return date("Y-m-d", time());
else if(abs(time()-strtotime('next '.$day)) < abs(time()-strtotime('last '.$day)))
return date("Y-m-d", strtotime('next '.$day));
else
return date("Y-m-d", strtotime('last '.$day));
}
Input: a day of the week ("sunday", "Monday", etc.)
Output: If I asked for the nearest "sunday" and today is:
"Sunday": I will get today's date
"Monday": I will get yesterday's date
"Saturday: I will get tomorrow's date
Hope this helps :)
As the top answer suggests, using PHP's strtotime() function is the easiest way.
However, instead of using if statements as he suggests, you could simply reset back to the previous Sunday and grab the dates you require from there.
$monday = strtotime('next monday', strtotime('previous sunday'));
$friday = strtotime('next friday', strtotime('previous sunday'));
I needed a definition of the current week per ISO 8601. I want Monday to always be defined as the Monday that started this current week.
The following solution works excellent for me:
$monday = strtotime(date('o-\WW'));
$friday = strtotime("next friday",$monday);
For $monday, this method will always return the Monday that started this calendar week. unfortunately, this method relies on PHP 5.1 to parse the o date format.
To get any day of the week, you could try:
function time_for_week_day($day_name, $ref_time=null){
$monday = strtotime(date('o-\WW',$ref_time));
if(substr(strtoupper($day_name),0,3) === "MON")
return $monday;
else
return strtotime("next $day_name",$monday);
}
Usage:
time_for_week_day('wednesday');
time_for_week_day('friday',strtotime('2014-12-25'));
I was looking for a similar thing, except I wanted any Monday, not just this week. This is what I came up with:
function getSunday(DateTime $date){
$outdate = clone($date);
$day = $date->format("w"); // get the weekday (sunday is 0)
$outdate->sub(new DateInterval("P".$day."D")); // subtracting the weekday from the date always gives Sunday
return $outdate;
}
It accepts an arbitrary date and gives the Sunday. Then you can easily add back days to get Monday through Saturday.
get the current week
$week = [];
$saturday = strtotime('saturday this week');
foreach (range(0, 6) as $day) {
$week[] = date("Y-m-d", (($day * 86400) + $saturday));
}

How to find day of week in php in a specific timezone

I am confused while using php to handle date/time.
What I am trying to do is this: When a user visits my page I am asking his timezone and then displaying the 'day of week' in his timezone.
I don't want to use the browser's day.
I want to do this calculation in php.
This is how I am trying to achieve it:
The timezone entered by user
Unix time stamp calculated by php time() function.
But I dont know how to proceed...
How would i get the 'day of week' in this timezone.
$dw = date( "w", $timestamp);
Where $dw will be 0 (for Sunday) through 6 (for Saturday) as you can see here:
http://www.php.net/manual/en/function.date.php
My solution is this:
$tempDate = '2012-07-10';
echo date('l', strtotime( $tempDate));
Output is: Tuesday
$tempDate = '2012-07-10';
echo date('D', strtotime( $tempDate));
Output is: Tue
I think this is the correct answer, just change Europe/Stockholm to the users time-zone.
$dateTime = new \DateTime(
'now',
new \DateTimeZone('Europe/Stockholm')
);
$day = $dateTime->format('N');
ISO-8601 numeric representation of the day of the week (added in PHP 5.1.0)
1 (for Monday) through 7 (for Sunday)
http://php.net/manual/en/function.date.php
For a list of supported time-zones, see
http://php.net/manual/en/timezones.php
Thanks a lot guys for your quick comments.
This is what i will be using now.
Posting the function here so that somebody may use it.
public function getDayOfWeek($pTimezone)
{
$userDateTimeZone = new DateTimeZone($pTimezone);
$UserDateTime = new DateTime("now", $userDateTimeZone);
$offsetSeconds = $UserDateTime->getOffset();
//echo $offsetSeconds;
return gmdate("l", time() + $offsetSeconds);
}
Report if you find any corrections.
Another quick way:
date_default_timezone_set($userTimezone);
echo date("l");
If you can get their timezone offset, you can just add it to the current timestamp and then use the gmdate function to get their local time.
// let's say they're in the timezone GMT+10
$theirOffset = 10; // $_GET['offset'] perhaps?
$offsetSeconds = $theirOffset * 3600;
echo gmdate("l", time() + $offsetSeconds);
$myTimezone = date_default_timezone_get();
date_default_timezone_set($userTimezone);
$userDay = date('l', $userTimestamp);
date_default_timezone_set($myTimezone);
This should work (didn't test it, so YMMV). It works by storing the script's current timezone, changing it to the one specified by the user, getting the day of the week from the date() function at the specified timestamp, and then setting the script's timezone back to what it was to begin with.
You might have some adventures with timezone identifiers, though.
"Day of Week" is actually something you can get directly from the php date() function with the format "l" or "N" respectively. Have a look at
the manual
edit: Sorry I didn't read the posts of Kalium properly, he already explained that. My bad.
Check date is monday or sunday before get last monday or last sunday
public function getWeek($date){
$date_stamp = strtotime(date('Y-m-d', strtotime($date)));
//check date is sunday or monday
$stamp = date('l', $date_stamp);
$timestamp = strtotime($date);
//start week
if(date('D', $timestamp) == 'Mon'){
$week_start = $date;
}else{
$week_start = date('Y-m-d', strtotime('Last Monday', $date_stamp));
}
//end week
if($stamp == 'Sunday'){
$week_end = $date;
}else{
$week_end = date('Y-m-d', strtotime('Next Sunday', $date_stamp));
}
return array($week_start, $week_end);
}
Based on one of the other solutions with a flag to switch between weeks starting on Sunday or Monday
function getWeekForDate($date, $weekStartSunday = false){
$timestamp = strtotime($date);
// Week starts on Sunday
if($weekStartSunday){
$start = (date("D", $timestamp) == 'Sun') ? date('Y-m-d', $timestamp) : date('Y-m-d', strtotime('Last Sunday', $timestamp));
$end = (date("D", $timestamp) == 'Sat') ? date('Y-m-d', $timestamp) : date('Y-m-d', strtotime('Next Saturday', $timestamp));
} else { // Week starts on Monday
$start = (date("D", $timestamp) == 'Mon') ? date('Y-m-d', $timestamp) : date('Y-m-d', strtotime('Last Monday', $timestamp));
$end = (date("D", $timestamp) == 'Sun') ? date('Y-m-d', $timestamp) : date('Y-m-d', strtotime('Next Sunday', $timestamp));
}
return array('start' => $start, 'end' => $end);
}
echo date('l', strtotime('today'));

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