pls i want to convert this 06-29-2010 04:00PM to this format Y-m-d h:i:s in php
thanks
Use strtotime:
$date = '06-29-2010 04:00PM';
$date = str_replace('-', '/', $date);
echo date('Y-m-d h:i:s', strtotime($date));
Result:
2010-06-29 04:00:00
I'll go ahead and offer PHP's date() manual as a second resource.
If you need to convert one timestamp or check your calculations you can use a web tool like www.unixstamp.com (just keep in mind it uses GMT)
Related
I have a string "3/6/2019 3:40:19 PM" that I want to convert to a Laravel/Eloquent datetime type.
Is there a way to do that without retrieve all small pieces of the string and rebuild again to the desired format?
You can use Carbon, which is already part of any Laravel install.
http://carbon.nesbot.com/docs/#api-getters
If you have a datetime string and you want to use it with a Carbon instance you can do:
$date = \Carbon\Carbon::createFromFormat('j/n/Y g:i:s A', '3/6/2019 3:40:19 PM');
Then you can do something like:
$date->format('Y-m-d')
$date->format('H:i:s')
One line solution:
date('Y-m-d H:i:s', strtotime('3/6/2019 3:40:19 PM')));
If you want to use Laravel's Carbon you can take a look at the api docs:
I've found an example similar to your situation that also parses the 'pm'
$date = Carbon::createFromIsoFormat('!YYYY-MMMM-D h:mm:ss a', '2019-January-3 6:33:24 pm', 'UTC');
echo $date->isoFormat('M/D/YY HH:mm'); // 1/3/19 18:33
Use the PHP strtotime() function.
strToTime($string)
And if you want to change the format you can use the date() function.
date('Y-m-d H:i:s', strtotime($string))
This saves you the hassle of installing new libraries and you can change the date format in any way you want in the date function
I am trying to convert some date 'date' (created with current_timestamp()), and displaying 2013-02-13 17:38:08, and I don't want the seconds to appear. But when I use date('Y-m-d H:i', $date), I get
1970-01-01 01:33
I think I am not using the right php methods, someone could help ?
Best,
Mehdi
date accepts a parameter as a timestamp, so use strtotime to convert first:
date('Y-m-d H:i', strtotime($date))
might it just be easier to use substr?
I store the date and time in mysql as a date/time field which has this format: 2012-03-12 14:51:26, what i am trying to do is simply rearrange the DD/MM/YY to look like this.
When i use the following code, it just gives me a date wrong format warning.
echo date_format($date, 'Y-m-d H:i:s');
If you are just displaying the date you can supply a certain format in the SQL query
SELECT DATE_FORMAT("%d/%m/%Y", date_column) FROM table
If you convert the MySQL timestamp to a unix timestamp, then you can use the date() function to output it in whatever format you like:
$unixTimestamp = strtotime($mysqlDate);
echo date($dateFormat, $unixTimestamp);
See the date format strings here: http://php.net/manual/en/function.date.php
First, convert it to a Unix timestamp (which I find to be all around better than a date_time field for a lot of reasons), then use PHP's date function.
echo date('Y-m-d h:i:s', strtotime($date));
Simply do:
date("d/m/Y", strtotime($date));
And read about strtotime function.
this will work.
$date = date_create("2012-03-24 17:45:12");
echo date_format($date, 'Y-m-d H:i:s');
I currently have a datetimestamp in the following format when posted from a form: dd/mm/yyyy hh:mm however I am trying to convert it to the appropriate format before MySQL insertion which is in the following format: yyyy-mm-dd hh:mm:ss. The ss seconds will always be 0.
Is it correct to use strtotime?
I think it's safer to use strptime, because of month-day-year / day-month-year inconsistence.
print_r(strptime($date_in_mdy_format, '%m/%d/%Y %H:%M'));
yes so you should use the following:
$form_date = $_POST['form_date'];
$date_insert = date('Y-m-d H:mm:0', strtotime($form_date));
Yes you can use strtotime, and that would be
$mysqldate = date('Y-m-d H:i:s', strtotime($mydate));
Then you put the $mysqldate in the SQL query.
Also see the manual .
$data['user']['time'] = '2011-03-07 00:33:45';
how can we add 1 year to this date ?
something like $newdata = $data['user']['time'] + 1 year ?
or
$newdata = 2012-03-07 00:33:45
Thanks
Adam Ramadhan
strtotime() is the function you're looking for:
$data['user']['seal_data'] = date('Y-m-d H:i:s', strtotime('+1 year', strtotime($data['user']['time'])));
First, you have to convert the MySQL datetime to something that PHP can understand. There are two ways of doing this...
Use UNIX_TIMESTAMP() in your query to tell MySQL to return a UNIX timestamp of the datetime column.
SELECT whatever, UNIX_TIMESTAMP(myTime) AS 'myUnixTime' FROM myTable;
Use DateTime::createFromFormat to convert your string time to something PHP can understand.
$date = DateTime::createFromFormat('Y-m-d H:i:s', $data['user']['time']);
Once that is done, you can work with the time... Depending on the method you used above, you can use one of the following.
If you have a unix timestamp, you can use the following to add a year:
$inAYear = strtotime('+1 year', $data['user']['unixTime']);
If you have a DateTime object, you can use the following:
$inAYear = $date->add(new DateInterval('P1Y'));
Now, to display your date in a format that is respectable, you must tell PHP to return a string in the proper format.
If you have a unix timestamp, you can use the following:
$strTime = date('Y-m-d H:i:s', $inAYear);
If you have a DateTime object, you can use the following:
$strTime = $inAYear->format('Y-m-d H:i:s');
Alternatively, if you don't want to deal with all of that, you can simply add one year when you query.
SELECT whatever, DATE_ADD(myTime, INTERVAL 1 YEAR) AS 'inAYear' FROM myTable;
Current (2017) Practice is to use DateTime
This question is top on a google search for "php datetime add one year", but severely outdated. While most of the previous answers will work fine for most cases, the established standard is to use DateTime objects for this instead, primarily due strtotime requiring careful manipulation of timezones and DST.
TL;DR
Convert to DateTime: $date = new DateTime('2011-03-07 00:33:45', [user TZ]);
Use DateTime::modify: $date->modify('+1 year');
Format to needs.
Change the timezone with DateTime::setTimezone from the list of supported timezones: $date->setTimezone(new DateTimeZone('Pacific/Chatham'));
Convert to string with DateTime::format: echo $date->format('Y-m-d H:i:s');
Following this pattern for manipulating dates and times will handle the worst oddities of timezone/DST/leap-time for you.
Just remember two final notes:
Life is easier with your system timezone set at UTC.
NEVER modify the system timezone outside of configuration files.
I've seen too much code that relies on date_default_timezone_set. If you're doing this, stop. Save the timezone in a variable, and pass it around your application instead, please.
More Reading
How to calculate the difference between two dates using PHP?
Convert date format yyyy-mm-dd => dd-mm-yyyy
PHP - strtotime, specify timezone
I think you could use strtotime() to do this pretty easily. Something like:
$newdata = date('c', strtotime($data['user']['time'] . ' +1 year'));
Though the 'c' format string isn't the same as your input format. You could consult date()'s docs for how to construct the correct one.
'Y-m-d H:i:s' — as Tim Cooper suggests — looks correct.
This should do the trick (not tested).
$data = "2011-03-07 00:33:45";
echo 'Original date +1 year: ' . date('Y-m-d H:i:s', strtotime(date("Y-m-d H:i:s", strtotime($data)) . " +1 year"));
First-of-all if your date format is separated by a slash (/), like '2019/12/31' then you should convert it in dash (-) format, like '2019-12-31', to do so use str_replace() function.
$string = str_replace('/', '-', '2019/12/31'); //output: 2019-12-31
To add time/day/month/year do not use strtotime() function, because it can't add a time which is beyond year 2038.
So here I would prefer to use DateTime() function.
$string = '2000-01-01';
$date = new DateTime($string);
$date->add(new DateInterval('P60Y5M2DT6H3M25S')); //60 Years 5 Months 2 Days 6 Hours 3 Minutes 25 Seconds
echo $date->format('Y-m-d H:i:s'); //output: 2060-06-03 06:03:25