Solving Dual URL Problem..? - php

Question

I am using cakephp I have 2 links:
<a href="#" tabindex="1" onclick="base_load_demo1('http://www.boxyourtvtrial.com/widget/beer/main/');" >beer</a>
cocktail
With the following JavaScript:
var Url1 = "http://www.boxyourtvtrial.com/widget/cocktail/main/";
var Url2 = "http://www.boxyourtvtrial.com/widget/beer/main/";
var Url3 = "http://www.boxyourtvtrial.com/widget/beer/mini/";
function base_load_demo(Url) {
remoteCall(Url1,"","mainLeftContent");
//remoteCall("SCRIPT_PATH","QUERY_STRING","TARGET_FUNCTION");
}
function base_load_demo1(Url2) {
remoteCall(Url2,"","mainLeftContent");
//remoteCall("SCRIPT_PATH","QUERY_STRING","TARGET_FUNCTION");
}
When I click on the first link it's showing its content through ajax call but when I click on the second link its giving error as follows:
Missing Controller
Error: Http:Controller could not be found.
Error: Create the class Http:Controller below in file: app/controllers/http:controller.php
<?php
class Http:Controller extends AppController {
var $name = 'Http:';
}
?>
Notice: If you want to customize this error message, create app/views/errors/missing_controller.ctp
and in FireFox console tab
POST http://www.boxyourtvtrial.com/widget/beer/main/http://www.boxyourtvtrial.com/widget/cocktail/main/
How can we solve this dual URL calling at the same time?
var xmlHttp;
var uri = "";
var callingFunc = "";
var sResponse = new Array();
function remoteCall(sUrl, sQueryStr, sCalledBy)
{
alert(sUrl);
var resStr = "";
var str = " { ";
if(sQueryStr != "") {
var arr1 = new Array();
arr1 = sQueryStr.split("&");
if(arr1){
for(i=0;i<=arr1.length;i++)
{
if(arr1[i] && arr1[i] != "")
{
var arr2 = new Array();
arr2 = arr1[i].split("=");
str += arr2[0]+":'"+arr2[1]+"' ,";
}
}
}
}
str += " tp: 'tp' } ";
$.ajax({
type: "GET",
url: sUrl,
data: sQueryStr,
dataType: "html",
success: function(data) {
$("#"+sCalledBy).html(data);
//jih(sCalledBy,data);
}
});
/* $.get(sUrl,sQueryStr,function(data) {
jih(sCalledBy,data);
});*/
}
function jih(divid,data)
{
if(document.getElementById(divid))
document.getElementById(divid).innerHTML=data;
}

Answer 1

After your first call to either of those pages it loads:
<script type="text/javascript" src="http://www.boxyourtvtrial.com/widget/cocktail/main/js/common.js"></script>
in the header. Inside common.js is a function called remoteCall, which is overwriting your local remoteCall function.
The remoteCall function inside common.js adds
var url= WIDGET_WEG_PATH+scr_url;
where WIDGET_WEG_PATH = "http://www.boxyourtvtrial.com/widget/beer/main/"
and scr_url = "http://www.boxyourtvtrial.com/widget/beer/main/" (the first parameter of the new remoteCall function)
This is why you are getting the url 'doubled' in the post.
Solution:
Rename local remoteCall function to something that is distinct.